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Test: Factorisation- 2 - Class 8 MCQ


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10 Questions MCQ Test - Test: Factorisation- 2

Test: Factorisation- 2 for Class 8 2024 is part of Class 8 preparation. The Test: Factorisation- 2 questions and answers have been prepared according to the Class 8 exam syllabus.The Test: Factorisation- 2 MCQs are made for Class 8 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Factorisation- 2 below.
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Test: Factorisation- 2 - Question 1

Factorise 12a2b+ 15ab2

Detailed Solution for Test: Factorisation- 2 - Question 1

Now, 12a2 b + 15ab2

= (3 * 2 * 2 * a * a * b) + (3 * 5 * a * b * b)

= (3 * a * b) {(2 *2 * a) + (5 * b)}

= 3ab (4a + 5b)

Test: Factorisation- 2 - Question 2

Factorise: x2+ 8x + 16

Detailed Solution for Test: Factorisation- 2 - Question 2

C ) (x2 +8x +16)
= (x2 + 4x + 4x + 16)
= ( x2 + 4x ) + (4x + 16 )
= x(x + 4 ) +4(x + 4 )
=(x + 4)(x + 4)
=(x + 4)2 

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Test: Factorisation- 2 - Question 3

Solve: –20(x)÷ 10(x)2

Detailed Solution for Test: Factorisation- 2 - Question 3

Test: Factorisation- 2 - Question 4

When we factorise an expression, we write it as a ________ of factors.

Detailed Solution for Test: Factorisation- 2 - Question 4

When we factorise an algebraic expression, we write it as a product of factors. These factors may be numbers, algebraic variables or algebraic expressions. 

Test: Factorisation- 2 - Question 5

Factorise 6xy – 4y + 6 – 9x.

Detailed Solution for Test: Factorisation- 2 - Question 5

Test: Factorisation- 2 - Question 6

Factorize x² + 8x + 12

Detailed Solution for Test: Factorisation- 2 - Question 6

x² + 8x + 12 
two no whose product is 12 and sum is 8
ie. 2 and 6 so;
x2+2x+6x+12
x(x+2)+6(x+2)
(x+2)(x+6)

Test: Factorisation- 2 - Question 7

Which of the following is quotient obtained on dividing –18 xyz2 by –3 xz?

Detailed Solution for Test: Factorisation- 2 - Question 7

–18 xyz2/–3 xz   x and x gets cancelled,-18 gets divided by -3 .and z2 gets divided by z so only one z remain in numerator So the quotient obtained is 6yz

Test: Factorisation- 2 - Question 8

Divide the given polynomial by the given monomial: (5x2− 6x) ÷ 3x

Detailed Solution for Test: Factorisation- 2 - Question 8

Test: Factorisation- 2 - Question 9

Divide as directed: 5 (2x + 1) (3x + 5) ÷ (2x + 1)

Detailed Solution for Test: Factorisation- 2 - Question 9

Test: Factorisation- 2 - Question 10

Factorise: p4– 81

Detailed Solution for Test: Factorisation- 2 - Question 10

We have  p4 - 81 = (p2)2 - (9)2 

 

Now using a2 - b2 = (a + b)(a - b), we have

 

         (p2)2 - (9)2 = (p2 + 9)(p2 -9)

 

We can factorise p2 - 9  further as

              p2 - 9 = (p)2 - (3)2

 

                       = (p + 3)(p - 3)

 

∴           p4 - 81 = (p + 3)(p - 3)(p2 + 9)

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