Test: Data Handling- 2 - Class 8 MCQ

Upper limit is the highest number of the interval. Hence upper limit is 40 in the interval 30-40.

Class interval refers to the numerical width of any class in a particular distribution. It is defined as the difference between the upper-class limit and the lower class limit. Class Interval = Upper-Class limit – Lower class limit.

Lower limit is the least number of the interval. Hence 40 is the lowest limit.

Answer is B because it is asking Highest frequency and the highest frequency is 20 - 30 

When a die is thrown, the total number of possible outcomes is:

• Each face of a standard die is numbered from 1 to 6.
• When you throw the die, it can land on any one of these six faces.
• This means there are six different possible outcomes.

So, the correct answer is:
A: 6

We know that in a single thrown of two die, the total number of possible outcomes is (6 × 6) = 36. Let S be the sample space. Then, n(S) = 36
 

When two dice are thrown, each die has 6 faces, numbered from 1 to 6. To find the total number of outcomes when both dice are thrown, you can use the multiplication principle.

1. Outcomes for the first die: There are 6 possible outcomes (1, 2, 3, 4, 5, 6).
2. Outcomes for the second die: Similarly, there are also 6 possible outcomes.

To find the total number of outcomes when both dice are thrown, multiply the number of outcomes for the first die by the number of outcomes for the second die:

Total Outcomes=Outcomes for the first die×Outcomes for the second die=6×6=36\text{Total Outcomes} = \text{Outcomes for the first die} \times \text{Outcomes for the second die} = 6 \times 6 = 36Total Outcomes=Outcomes for the first die×Outcomes for the second die=6×6=36

Conclusion

So, when two dice are thrown, there are a total of 36 possible outcomes. Each outcome can be represented as an ordered pair (x, y), where x is the result from the first die and y is the result from the second die. For example, (1, 1), (1, 2), ..., (6, 6).

Non - red ball = 8
Probability = No of non red balls/Total no. of outcomes
= 8/10 = 4/5

Given - Number of different balls
Find - Probability of getting red ball
Solution - Probability of getting red ball = number of red balls / total number of balls.
Number of red balls = 2
Total number of balls = 2 + 3 + 5
Performing addition
Total number of balls = 10
Keep the values in formula to find the probability of getting red ball.

total no of black ball / total no of balls
5 / 10 
1 / 2

Total out comes are=2+3+5=10

So, Probability of getting a non blue ball is = 7/10

just subtract lower limit from upper limit
150 - 125 = 25

clearly for class 300-325  frequency is 20

Correct answer is C. 275