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Case Based Questions Test: Coordination Compounds - NEET MCQ


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15 Questions MCQ Test - Case Based Questions Test: Coordination Compounds

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Case Based Questions Test: Coordination Compounds - Question 1

Read the passage given below and answer the following questions:

The crystal field theory (CFT) is an electrostatic model which considers the metal-ligand bond to be ionic arising purely from electrostatic interactions between the metal ion and the ligand. Ligands are treated as point charges in case of anions or dipoles in case of neutral molecules. The five d orbitals in an isolated gaseous metal atom/ion have same energy, i.e., they are degenerate. This degeneracy is maintained if a spherically symmetrical field of negative charges surrounds the metal atom/ ion. However, when this negative field is due to ligands (either anions or the negative ends of dipolar molecules like NH3 and H2O) in a complex, it becomes asymmetrical and the degeneracy of the d orbitals is lifted. It results in splitting of the d orbitals.

The following questions are multiple choice questions. Choose the most appropriate answer:

Q. The colour of the coordination compounds depends on the crystal field splitting. What will be the correct order of absorption of wavelength of light in the visible region, for the complexes, [Co(NH3)6]3+, [Co(CN)6]3−, [Co(H2O)6]3+

Detailed Solution for Case Based Questions Test: Coordination Compounds - Question 1
[Co(H2O)6]3+ > [Co(NH3)6]3+> [Co(CN)6]3−
Case Based Questions Test: Coordination Compounds - Question 2

Read the passage given below and answer the following questions:

The crystal field theory (CFT) is an electrostatic model which considers the metal-ligand bond to be ionic arising purely from electrostatic interactions between the metal ion and the ligand. Ligands are treated as point charges in case of anions or dipoles in case of neutral molecules. The five d orbitals in an isolated gaseous metal atom/ion have same energy, i.e., they are degenerate. This degeneracy is maintained if a spherically symmetrical field of negative charges surrounds the metal atom/ ion. However, when this negative field is due to ligands (either anions or the negative ends of dipolar molecules like NH3 and H2O) in a complex, it becomes asymmetrical and the degeneracy of the d orbitals is lifted. It results in splitting of the d orbitals.

The following questions are multiple choice questions. Choose the most appropriate answer:

Q. An aqueous pink solution of cobalt(II) chloride changes to deep blue on addition of excess of HCl. This is because _____________.

Detailed Solution for Case Based Questions Test: Coordination Compounds - Question 2
[Co(H2O)6]2+ is transformed into [CoCl4]2−.
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Case Based Questions Test: Coordination Compounds - Question 3

Read the passage given below and answer the following questions:

The crystal field theory (CFT) is an electrostatic model which considers the metal-ligand bond to be ionic arising purely from electrostatic interactions between the metal ion and the ligand. Ligands are treated as point charges in case of anions or dipoles in case of neutral molecules. The five d orbitals in an isolated gaseous metal atom/ion have same energy, i.e., they are degenerate. This degeneracy is maintained if a spherically symmetrical field of negative charges surrounds the metal atom/ ion. However, when this negative field is due to ligands (either anions or the negative ends of dipolar molecules like NH3 and H2O) in a complex, it becomes asymmetrical and the degeneracy of the d orbitals is lifted. It results in splitting of the d orbitals.

The following questions are multiple choice questions. Choose the most appropriate answer:

Q. The CFSE for octahedral [CoCl6]4− is 18,000 cm−1. The CFSE for tetrahedral [CoCl4]2− will be

Detailed Solution for Case Based Questions Test: Coordination Compounds - Question 3

Case Based Questions Test: Coordination Compounds - Question 4

Read the passage given below and answer the following questions:

The crystal field theory (CFT) is an electrostatic model which considers the metal-ligand bond to be ionic arising purely from electrostatic interactions between the metal ion and the ligand. Ligands are treated as point charges in case of anions or dipoles in case of neutral molecules. The five d orbitals in an isolated gaseous metal atom/ion have same energy, i.e., they are degenerate. This degeneracy is maintained if a spherically symmetrical field of negative charges surrounds the metal atom/ ion. However, when this negative field is due to ligands (either anions or the negative ends of dipolar molecules like NH3 and H2O) in a complex, it becomes asymmetrical and the degeneracy of the d orbitals is lifted. It results in splitting of the d orbitals.

The following questions are multiple choice questions. Choose the most appropriate answer:

Q. A chelating agent has two or more than two donor atoms to bind to a single metal ion. Which of the following is not a chelating agent?

Detailed Solution for Case Based Questions Test: Coordination Compounds - Question 4
Thiosulphato is a monodentate ligand whereas Oxalato, glycinato and ethylene diamine are bidentate ligands and can form rings with the central metal ion. So, they are also chelating ligands. Thiosulphato is a monodentate ligand and hence, cannot form chelate rings. Hence, it is not a chelating ligand
Case Based Questions Test: Coordination Compounds - Question 5

Read the passage given below and answer the following questions:

According to Valence Bond Theory, the metal atom or ion under the influence of ligands can use its (n−1)d, ns, np or ns, np, nd orbitals for hybridisation to yield a set of equivalent orbitals of definite geometry such as octahedral, tetrahedral, square planar and so on. These hybridised orbitals are allowed to overlap with ligand orbitals that can donate electron pairs for bonding. In these questions a statement of assertion followed by a statement of reason is given. Choose the correct answer out of the following choices.

Assertion (A): In the diamagnetic octahedral complex, [Co(NH3)6]3+, the cobalt ion is in +3 oxidation state.

Reason (R): Six pairs of electrons, one from each NH3 molecule, occupy the six hybrid orbitals.

Detailed Solution for Case Based Questions Test: Coordination Compounds - Question 5
In the diamagnetic octahedral complex, [Co(NH3)6]3+, the cobalt ion is in +3 oxidation state and has the electronic configuration 3d6.
Case Based Questions Test: Coordination Compounds - Question 6

Read the passage given below and answer the following questions:

According to Valence Bond Theory, the metal atom or ion under the influence of ligands can use its (n−1)d, ns, np or ns, np, nd orbitals for hybridisation to yield a set of equivalent orbitals of definite geometry such as octahedral, tetrahedral, square planar and so on. These hybridised orbitals are allowed to overlap with ligand orbitals that can donate electron pairs for bonding. In these questions a statement of assertion followed by a statement of reason is given. Choose the correct answer out of the following choices.

Assertion (A): [NiCl4]2− is an inner orbital complex.

Reason (R): An inner orbital or low spin or spin paired complex uses inner d orbitals of the metal ion for hybridisation.

Detailed Solution for Case Based Questions Test: Coordination Compounds - Question 6
[NiCl4]2− is high spin complex.
Case Based Questions Test: Coordination Compounds - Question 7

Read the passage given below and answer the following questions:

According to Valence Bond Theory, the metal atom or ion under the influence of ligands can use its (n−1)d, ns, np or ns, np, nd orbitals for hybridisation to yield a set of equivalent orbitals of definite geometry such as octahedral, tetrahedral, square planar and so on. These hybridised orbitals are allowed to overlap with ligand orbitals that can donate electron pairs for bonding. In these questions a statement of assertion followed by a statement of reason is given. Choose the correct answer out of the following choices.

Assertion (A): In the square planar complexes, the hybridisation involved is dsp2.

Reason (R): In [Ni(CN)4]2−. Here nickel is in +2 oxidation state and has the electronic configuration 3d8.

Detailed Solution for Case Based Questions Test: Coordination Compounds - Question 7
The dsp2 hybrid orbitals are inner orbital complexes in which the electrons get paired up due to the presence of a strong field ligand. So, the electron pairs of the ligands occupy one d orbital, one s orbital and then 2p orbitals in a square planar geometry.

The 2s orbital is mixed with all three of the 2p orbitals, creating four hybridized sp3 orbitals. Each of these has 25% s and 75% p character; electron repulsion favours a tetrahedral shape, so the orbitals are 109.5° apart from each other.

Case Based Questions Test: Coordination Compounds - Question 8

Read the passage given below and answer the following questions:

According to Valence Bond Theory, the metal atom or ion under the influence of ligands can use its (n−1)d, ns, np or ns, np, nd orbitals for hybridisation to yield a set of equivalent orbitals of definite geometry such as octahedral, tetrahedral, square planar and so on. These hybridised orbitals are allowed to overlap with ligand orbitals that can donate electron pairs for bonding. In these questions a statement of assertion followed by a statement of reason is given. Choose the correct answer out of the following choices.

Assertion (A): The paramagnetic octahedral complex, [CoF6]3− uses outer orbital (4d) in hybridisation (sp3d2).

Reason (R): It is a high spin complex.

Detailed Solution for Case Based Questions Test: Coordination Compounds - Question 8
The paramagnetic octahedral complex, [CoF6]3− uses outer orbital (4d) in hybridisation (sp3d2). It is a low spin complex.
Case Based Questions Test: Coordination Compounds - Question 9

Read the passage given below and answer the following questions:

The existence of coordination compounds with the same formula but different arrangements of the ligands was crucial in the development of coordination chemistry. Two or more compounds with the same formula but different arrangements of the atoms are called isomers. Isomers are compounds with the same molecular formula but different structural formulas and do not necessarily share similar properties. There are many different classes of isomers, like stereoisomers, enantiomers, and geometrical isomers. There are two main forms of isomerism: structural isomerism and stereoisomerism. The different chemical formulas in structural isomers are caused either by a difference in what ligands are bonded to the central atoms or how the individual ligands are bonded to the central atoms.

The following questions are multiple choice questions. Choose the most appropriate answer:

Q. What kind of isomerism exists between [Cr(H2O)6]Cl3 (violet) and [Cr(H2O)5Cl]Cl2.H2O (greyish green)?

Detailed Solution for Case Based Questions Test: Coordination Compounds - Question 9
Solvate (or hydrate) isomerism exists between [Cr(H2O)6]Cl3 ​(violet) and [Cr(H2 O)5Cl]Cl2.H2O (greyish-green).

For [Cr(H2O)6]Cl3(violet), the number of water molecules inside the coordination sphere is six and the number of water molecules outside the coordination sphere is 0.

For, [Cr(H2O)5Cl]Cl2.H2O (greyish-green), the number of water molecules inside the coordination sphere is five and the number of water molecules outside the coordination sphere is one.

Case Based Questions Test: Coordination Compounds - Question 10

Read the passage given below and answer the following questions:

The existence of coordination compounds with the same formula but different arrangements of the ligands was crucial in the development of coordination chemistry. Two or more compounds with the same formula but different arrangements of the atoms are called isomers. Isomers are compounds with the same molecular formula but different structural formulas and do not necessarily share similar properties. There are many different classes of isomers, like stereoisomers, enantiomers, and geometrical isomers. There are two main forms of isomerism: structural isomerism and stereoisomerism. The different chemical formulas in structural isomers are caused either by a difference in what ligands are bonded to the central atoms or how the individual ligands are bonded to the central atoms.

The following questions are multiple choice questions. Choose the most appropriate answer:

Q. Due to the presence of ambidentate ligands, coordination compounds show isomerism. Palladium complexes of the type [Pd(C6H5)2(SCN)2] and [Pd(C6H5)2(NCS)2] are

Detailed Solution for Case Based Questions Test: Coordination Compounds - Question 10
Linkage isomerism arises in a coordination compound containing ambidentate ligand. A simple example is by complexes containing the thiocyanate ligand, NCS−, which may bind through the nitrogen to give M−NCS or through sulphur to give M−SCN.
Case Based Questions Test: Coordination Compounds - Question 11

Read the passage given below and answer the following questions:

The existence of coordination compounds with the same formula but different arrangements of the ligands was crucial in the development of coordination chemistry. Two or more compounds with the same formula but different arrangements of the atoms are called isomers. Isomers are compounds with the same molecular formula but different structural formulas and do not necessarily share similar properties. There are many different classes of isomers, like stereoisomers, enantiomers, and geometrical isomers. There are two main forms of isomerism: structural isomerism and stereoisomerism. The different chemical formulas in structural isomers are caused either by a difference in what ligands are bonded to the central atoms or how the individual ligands are bonded to the central atoms.

The following questions are multiple choice questions. Choose the most appropriate answer:

Q. Which of the following complexes show linkage isomerism?

Detailed Solution for Case Based Questions Test: Coordination Compounds - Question 11
Linkage isomerism is the existence of coordination compounds that have the same composition differing with the connectivity of the metal to a ligand. Typical ligands that give rise to linkage isomers are: thiocyanate, SCN −, isothiocyanate, NCS −
Case Based Questions Test: Coordination Compounds - Question 12

Read the passage given below and answer the following questions:

Coordination compounds are formulated and named according to the IUPAC system.

Few rules for naming coordination compounds are:

(I) In an ionic complex, the cation is named first and then the anion.

(II) In the coordination entity, the ligands are named first and then the central metal ion.

(III) When more than one type of ligands are present, they are named in alphabetical order of preference with any consideration of charge

The following questions are multiple choice question. Choose the most appropriate answer:

Q. The IUPAC name of [Ni(CO)4] is

Detailed Solution for Case Based Questions Test: Coordination Compounds - Question 12
When we write the IUPAC name for a coordination complex, if the coordination entity is neutral, then the name of Ligands comes first followed by the name of the metal and the oxidation state in ().

Thus, the IUPAC name for [Ni(CO)4] is Tetracarbonylnickel (0).

Case Based Questions Test: Coordination Compounds - Question 13

Read the passage given below and answer the following questions:

Coordination compounds are formulated and named according to the IUPAC system.

Few rules for naming coordination compounds are:

(I) In an ionic complex, the cation is named first and then the anion.

(II) In the coordination entity, the ligands are named first and then the central metal ion.

(III) When more than one type of ligands are present, they are named in alphabetical order of preference with any consideration of charge

The following questions are multiple choice question. Choose the most appropriate answer:

Q. The IUPAC name of the complex [Pt(NH3)3Br(NO2)Cl]Cl is

Detailed Solution for Case Based Questions Test: Coordination Compounds - Question 13
We need to follow the alphabetical order while naming the compound. The oxidation number of metal is +4.

Hence the IUPAC name is- Triamminebromochloronitroplatinum (IV) chloride.

Case Based Questions Test: Coordination Compounds - Question 14

Read the passage given below and answer the following questions:

Coordination compounds are formulated and named according to the IUPAC system.

Few rules for naming coordination compounds are:

(I) In an ionic complex, the cation is named first and then the anion.

(II) In the coordination entity, the ligands are named first and then the central metal ion.

(III) When more than one type of ligands are present, they are named in alphabetical order of preference with any consideration of charge

The following questions are multiple choice question. Choose the most appropriate answer:

Q. Which of the following represents the correct formula of dichloridobis(ethane-1,2-diamine)cobalt(III) ion?

Case Based Questions Test: Coordination Compounds - Question 15

Read the passage given below and answer the following questions:

Coordination compounds are formulated and named according to the IUPAC system.

Few rules for naming coordination compounds are:

(I) In an ionic complex, the cation is named first and then the anion.

(II) In the coordination entity, the ligands are named first and then the central metal ion.

(III) When more than one type of ligands are present, they are named in alphabetical order of preference with any consideration of charge

The following questions are multiple choice question. Choose the most appropriate answer:

Q. As per IUPAC nomenclature, the name of the complex [Co(H2O)4(NH3)2]Cl3 is

Detailed Solution for Case Based Questions Test: Coordination Compounds - Question 15
The IUPAC name of the complex given is Diamminetetraaquacobalt (III) chloride. The charge on the central Co atom is +3.
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