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Case Based Questions Test: The s-Block Elements (Old NCERT) - NEET MCQ


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8 Questions MCQ Test - Case Based Questions Test: The s-Block Elements (Old NCERT)

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Case Based Questions Test: The s-Block Elements (Old NCERT) - Question 1

Lithium and Beryllium differ from other elements of their groups. The solubility of the ionic compounds depends upon lattice enthalpy and hydration energy. Smaller cations have greater hydration enthalpy. The salts of alkaline earth metals are extensively hydrated. Now, answer the given questions (i) to (iv):

Q. The order of solubility of lithium halide in polar solvents is:

Detailed Solution for Case Based Questions Test: The s-Block Elements (Old NCERT) - Question 1
In Lithium halides, Lithium Fluoride is least covalent whereas Lithium Iodide is most covalent. F is small in size and can not be easily distorted while Ihas larger size and can be easily distorted.
Case Based Questions Test: The s-Block Elements (Old NCERT) - Question 2

Lithium and Beryllium differ from other elements of their groups. The solubility of the ionic compounds depends upon lattice enthalpy and hydration energy. Smaller cations have greater hydration enthalpy. The salts of alkaline earth metals are extensively hydrated. Now, answer the given questions (i) to (iv):

Q. The incorrect trend in alkali metal is

Detailed Solution for Case Based Questions Test: The s-Block Elements (Old NCERT) - Question 2
On moving downward in a group, density increases but the density of K is lesser than Na. The correct order is Li < K < Na < Rb.
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Case Based Questions Test: The s-Block Elements (Old NCERT) - Question 3

Lithium and Beryllium differ from other elements of their groups. The solubility of the ionic compounds depends upon lattice enthalpy and hydration energy. Smaller cations have greater hydration enthalpy. The salts of alkaline earth metals are extensively hydrated. Now, answer the given questions (i) to (iv):

Q. The hydroxide which has maximum solubility in water?

Detailed Solution for Case Based Questions Test: The s-Block Elements (Old NCERT) - Question 3
In Ba(OH)2, the size of the cation increases and the lattice energies decreases.
Case Based Questions Test: The s-Block Elements (Old NCERT) - Question 4

Lithium and Beryllium differ from other elements of their groups. The solubility of the ionic compounds depends upon lattice enthalpy and hydration energy. Smaller cations have greater hydration enthalpy. The salts of alkaline earth metals are extensively hydrated. Now, answer the given questions (i) to (iv):

Q. Which of the following forms only the normal oxide M2O on heating in air?

Detailed Solution for Case Based Questions Test: The s-Block Elements (Old NCERT) - Question 4
Li with O2 form monoxide (Li2O). Na form peroxide (Na2O2) K and Rb form superoxide (MO2).
Case Based Questions Test: The s-Block Elements (Old NCERT) - Question 5

The lighter alkaline earth metals are very important in animal and plant physiology. Magnesium functions as the active center in some enzymes and calcium salts take a structural role in bones. The alkaline earth metals have the second lowest first ionisation energies in their respective periods. The ions of these elements perform important biological functions like maintenance of ion balance and nerve impulse conduction. The given questions (i) to (iv) consist of an assertion (A) and reason (R). Choose the correct option.

Assertion: The second ionisation enthalpies of the alkaline earth metals are smaller than the metals.

Reason: The second electron is to be removed from the cation have inert gas configuration.

Detailed Solution for Case Based Questions Test: The s-Block Elements (Old NCERT) - Question 5

The second ionization enthalpies of the alkaline earth metals are indeed smaller than those of the corresponding alkali metals. This is because the second electron in alkaline earth metals is removed from a cation that already has a noble gas configuration (i.e., a filled valence shell). The removal of this electron is therefore more difficult than the first electron, but easier than the subsequent electrons, which involve the removal of electrons from inner shells.

The reason given for the assertion is also correct. When an alkaline earth metal atom loses its first electron to form a cation, it attains a noble gas configuration (e.g., Mg+ has the same electron configuration as neon). Therefore, the second electron must be removed from a cation that has a noble gas configuration, which requires less energy than removing an electron from a neutral atom.

Thus, both the assertion and reason are correct, and the reason justifies the assertion.

Case Based Questions Test: The s-Block Elements (Old NCERT) - Question 6

Read the passage given below and answer the following questions.
Alkali metals have the lowest ionization energy in their corresponding period in periodic table because they have large size which results in a large distance between the nucleus and the outermost electron. Ionization energy of alkali metals decreases from Li to Cs due to increase in atomic size. First ionization energy of alkali metals is very low, but they have very high value of second ionization energy.

Q. Alkali metals displace hydrogen from water forming bases due to the reason that

Detailed Solution for Case Based Questions Test: The s-Block Elements (Old NCERT) - Question 6

In electrochemical series based on oxidation potential alkali metals are far below hydrogen, thus they displace hydrogen from water.

Case Based Questions Test: The s-Block Elements (Old NCERT) - Question 7

Read the passage given below and answer the following questions.
Alkali metals have the lowest ionization energy in their corresponding period in periodic table because they have large size which results in a large distance between the nucleus and the outermost electron. Ionization energy of alkali metals decreases from Li to Cs due to increase in atomic size. First ionization energy of alkali metals is very low, but they have very high value of second ionization energy.

Q. Metals dissolve in liquid ammonia giving coloured solutions which are conducting in nature. The colour of the solution and reason of its conductance is

Detailed Solution for Case Based Questions Test: The s-Block Elements (Old NCERT) - Question 7

Correct option is D. blue, ammoniated electron

Case Based Questions Test: The s-Block Elements (Old NCERT) - Question 8

The lighter alkaline earth metals are very important in animal and plant physiology. Magnesium functions as the active center in some enzymes and calcium salts take a structural role in bones. The alkaline earth metals have the second lowest first ionisation energies in their respective periods. The ions of these elements perform important biological functions like maintenance of ion balance and nerve impulse conduction. The given questions (i) to (iv) consist of an assertion (A) and reason (R). Choose the correct option.

Assertion: Alkaline earth metals are reducing agents.

Reason: They have low ionisation enthalpies and high negative values of E°.

Detailed Solution for Case Based Questions Test: The s-Block Elements (Old NCERT) - Question 8

The correct option is:

  1. A is true but R is false.

Explanation:

The assertion that "Alkaline earth metals are reducing agents" is true. This is because the alkaline earth metals have low ionization energies, which means they readily lose electrons to form positively charged ions. These ions can then act as reducing agents by donating electrons to other species in redox reactions.

However, the reason that "They have low ionisation enthalpies and high negative values of E°" is not correct. While alkaline earth metals do have low ionization energies, the second part of the reason is not directly related to their reducing properties. The negative values of E° (standard electrode potentials) indicate the tendency of a species to undergo reduction, but it is not the only factor that determines whether a species can act as a reducing agent. Other factors such as the availability of electrons and the stability of the resulting products also play a role.

Therefore, option 1 is the correct answer.

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