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Test: Tetravalence of Carbon: Shapes of Organic Compounds (NCERT) - NEET MCQ


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5 Questions MCQ Test - Test: Tetravalence of Carbon: Shapes of Organic Compounds (NCERT)

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Test: Tetravalence of Carbon: Shapes of Organic Compounds (NCERT) - Question 1

Which type of hybridisation of each carbon is there in the compound?
CH3 - CH = CH - CN

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From left 1-sp3, 2-sp2, 3-sp2, 4-sp

Test: Tetravalence of Carbon: Shapes of Organic Compounds (NCERT) - Question 2

Which of the followingrepresents the givensequence of hybridisation of carbon atoms from left to right sp2, sp2, sp, sp?

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Test: Tetravalence of Carbon: Shapes of Organic Compounds (NCERT) - Question 3

How many σ and π bonds are present in HC≡C−CH=CH−CH3?

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Test: Tetravalence of Carbon: Shapes of Organic Compounds (NCERT) - Question 4

Arrange in increasing order of basicity. HC≡C−, CH3​CH=CH−, CH3​CH2​−

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Test: Tetravalence of Carbon: Shapes of Organic Compounds (NCERT) - Question 5

What are the hybridization and shapes of the following molecules?
(i) CH3F
(ii) HC ≡ N

Detailed Solution for Test: Tetravalence of Carbon: Shapes of Organic Compounds (NCERT) - Question 5

CH3F - sp3 hybridised carbon, tetrahedral shape
(ii) HC = N - sp hybridised carbon, linear shape.

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