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Test: Colligative Properties and Determination of Molar Mass (NCERT) - NEET MCQ


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25 Questions MCQ Test - Test: Colligative Properties and Determination of Molar Mass (NCERT)

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Test: Colligative Properties and Determination of Molar Mass (NCERT) - Question 1

The relative lowering in vapour pressure is proportional to the ratio of number of

Detailed Solution for Test: Colligative Properties and Determination of Molar Mass (NCERT) - Question 1

Test: Colligative Properties and Determination of Molar Mass (NCERT) - Question 2

Vapour pressure of a pure liquid X is 2 atm at 300 K. It is lowered to 1 atm on dissolving 1 g of Y in 20 g of liquid X. If molar mass of X is 200, what is the molar mass of Y?

Detailed Solution for Test: Colligative Properties and Determination of Molar Mass (NCERT) - Question 2

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Test: Colligative Properties and Determination of Molar Mass (NCERT) - Question 3

An aqueous solution of 2% non - volatile solute exerts a pressure of 1.004 bar at the normal boiling point of the solvent. What is the molar mass of the solute?

Detailed Solution for Test: Colligative Properties and Determination of Molar Mass (NCERT) - Question 3

Vapour pressure of pure water at boiling point (P) = 1 atm = 1.013 bar
Vapour pressure of solution (Ps) = 1.004 bar
Let Mass of solution = 100g
Mass of solute = (w) = 2g
Mass of solvent = 100 - 2 = 98g

Test: Colligative Properties and Determination of Molar Mass (NCERT) - Question 4

In the graph plotted between vapour pressure (V.P) and temperature (T).

Detailed Solution for Test: Colligative Properties and Determination of Molar Mass (NCERT) - Question 4

PQ corresponds to increase in vapour pressure of solvent with temperature and XY corresponds to increase in vapour pressure of solution with temperature. ΔT is the elevation in boiling point of a solution.

Test: Colligative Properties and Determination of Molar Mass (NCERT) - Question 5

A solution containing 12.5g of non-electrolyte substance in 185g of water shows boiling point elevation of 0.80K. Calculate the molar mass of the substance. (Kb ​= 0.52K kg mol−1)

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Test: Colligative Properties and Determination of Molar Mass (NCERT) - Question 6

If 1g of solute (molar mass = 50g mol−1) is dissolved in 50g of solvent and the elevation in boiling point is 1K. The molar boiling constant of the solvent is?

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Test: Colligative Properties and Determination of Molar Mass (NCERT) - Question 7

2 g of sugar is added to one litre of water to give sugar solution. What is the effect of addition of sugar on the boiling point and freezing point of water?

Detailed Solution for Test: Colligative Properties and Determination of Molar Mass (NCERT) - Question 7

When a non-volatile solute is added to water there is elevation in boiling point and depression is freezing point.

Test: Colligative Properties and Determination of Molar Mass (NCERT) - Question 8

Sprinkling of salt helps in clearing the snow-covered roads in hills. The phenomenon involved in the process is

Detailed Solution for Test: Colligative Properties and Determination of Molar Mass (NCERT) - Question 8

When salt is spread over snow covered roads, snow starts melting from the surface because of the depression in freezing point of water and it helps in clearing the roads.

Test: Colligative Properties and Determination of Molar Mass (NCERT) - Question 9

Equimolar solutions in the same solvent have

Detailed Solution for Test: Colligative Properties and Determination of Molar Mass (NCERT) - Question 9

Equimolal solutions show same colligative properties i.e., equal elevation in boiling point and equal depression in freezing point.

Test: Colligative Properties and Determination of Molar Mass (NCERT) - Question 10

A 5% solution (w/W) of cane sugar (molar mass = 342 g mol-1) has freezing point of 271 K. What will be the freezing point of a 5% glucose (molar mass = 18 g mol-1) in water if freezing point of pure water is 273.15 K?

Detailed Solution for Test: Colligative Properties and Determination of Molar Mass (NCERT) - Question 10


For cane sugar solution, 2.15 K = 
For glucose solution,


Freezing point of glucose solution = 273.15 - 4.085 = 269.07 K

Test: Colligative Properties and Determination of Molar Mass (NCERT) - Question 11

What weight of glycerol should be added to 600g of water in order to lower its freezing point by 10C? (Kf = 1.86Cm−1)

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Test: Colligative Properties and Determination of Molar Mass (NCERT) - Question 12

The osmotic pressure of a solution can be increased by

Detailed Solution for Test: Colligative Properties and Determination of Molar Mass (NCERT) - Question 12


Hence, π ∝ n

Test: Colligative Properties and Determination of Molar Mass (NCERT) - Question 13

Answer the following questions on the basis of given paragraph.
Osmotic pressure is widely used to determine molar masses of proteins and polymers. Two solutions having same osmotic pressure are called isotonic solutions. Water can flow in or out from substance depending on if it is kept in hypotonic or hypertonic solutions. The direction of the osmosis can be reversed if a pressure larger than osmotic pressure is applied on solution side.

Q. People taking lot of salt experience puffiness or swelling of the body due to

Detailed Solution for Test: Colligative Properties and Determination of Molar Mass (NCERT) - Question 13

Due to osmosis water moves into the tissues and intercellular spaces causing retention of water.

Test: Colligative Properties and Determination of Molar Mass (NCERT) - Question 14

Answer the following questions on the basis of given paragraph.
Osmotic pressure is widely used to determine molar masses of proteins and polymers. Two solutions having same osmotic pressure are called isotonic solutions. Water can flow in or out from substance depending on if it is kept in hypotonic or hypertonic solutions. The direction of the osmosis can be reversed if a pressure larger than osmotic pressure is applied on solution side.

Q. The preservation of meat by salting and of fruits by adding sugar protects them from bacterial action because

Detailed Solution for Test: Colligative Properties and Determination of Molar Mass (NCERT) - Question 14

The bacteria on salted meat or candid fruit loss water through osmosis, shrink and die.

Test: Colligative Properties and Determination of Molar Mass (NCERT) - Question 15

Answer the following questions on the basis of given paragraph.
Osmotic pressure is widely used to determine molar masses of proteins and polymers. Two solutions having same osmotic pressure are called isotonic solutions. Water can flow in or out from substance depending on if it is kept in hypotonic or hypertonic solutions. The direction of the osmosis can be reversed if a pressure larger than osmotic pressure is applied on solution side.
Q. Sea water is desalinated to get fresh water by which of the following methods?

Detailed Solution for Test: Colligative Properties and Determination of Molar Mass (NCERT) - Question 15

Reverse osmosis is used for desalination of sea water.

Test: Colligative Properties and Determination of Molar Mass (NCERT) - Question 16

Which of the following statements is not correct?

Detailed Solution for Test: Colligative Properties and Determination of Molar Mass (NCERT) - Question 16

With different solvents, the colligative properties change.

Test: Colligative Properties and Determination of Molar Mass (NCERT) - Question 17

10% solution of urea is isotonic with 6% solution of a non-volatile solute X.What is the molecular mass of solute X?

Detailed Solution for Test: Colligative Properties and Determination of Molar Mass (NCERT) - Question 17

No. of moles of urea = 10/60 = 16
Weight of solute, X = 6 g
No. of moles of X = 6/M
For isotonic solutions, n1 = n2
or 1/6 = 6/M or M = 36 g mol−1

Test: Colligative Properties and Determination of Molar Mass (NCERT) - Question 18

A solution containing 10.2g glycerine per litre is isotonic with a 2% solution of glucose. What is the molecular mass of glycerine?

Detailed Solution for Test: Colligative Properties and Determination of Molar Mass (NCERT) - Question 18

πglycerine = πglucose


(Density of water = 1g/cm3)

Test: Colligative Properties and Determination of Molar Mass (NCERT) - Question 19

What will be the osmotic pressure in pascals exerted by a solution prepared by dissolving 1.0 g of polymer of molar mass 150,000 in 500 mL of water at 37C?

Detailed Solution for Test: Colligative Properties and Determination of Molar Mass (NCERT) - Question 19

No. of moles of polymer

Test: Colligative Properties and Determination of Molar Mass (NCERT) - Question 20

Osmotic pressure of a solution containing 2g dissolved protein per 300cm2 of solution is 20mm of Hg at 27oC. The molecular mass of protein is

Detailed Solution for Test: Colligative Properties and Determination of Molar Mass (NCERT) - Question 20


= 6239.6 g mol−1

Test: Colligative Properties and Determination of Molar Mass (NCERT) - Question 21

A solution is made by dissolving 20g of a substance in 500mL of water. Its osmotic pressure was found to be 600mm of Hg at 15C. Find the molecular weight of the substance.

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Test: Colligative Properties and Determination of Molar Mass (NCERT) - Question 22

Which of the following statements is not correct?

Detailed Solution for Test: Colligative Properties and Determination of Molar Mass (NCERT) - Question 22

Both NaCl and KCl have different molecular masses.

Test: Colligative Properties and Determination of Molar Mass (NCERT) - Question 23

Grapes placed in three beakers X, Y and Z containing different type of solutions are shown in figures.

If beaker X contains water, Y and Z contains:

Detailed Solution for Test: Colligative Properties and Determination of Molar Mass (NCERT) - Question 23

In hypotonic solution, the water is drawn in and the grape swells while in hypertonic solution the water is drawn out and the grape shrinks.

Test: Colligative Properties and Determination of Molar Mass (NCERT) - Question 24

A plant cell shrinks when it is kept in a

Detailed Solution for Test: Colligative Properties and Determination of Molar Mass (NCERT) - Question 24

Hypertonic solution has high osmotic pressure. When a plant cell is placed in hypertonic solution water will diffuse out of the cell resulting in shrinking of the cell.

Test: Colligative Properties and Determination of Molar Mass (NCERT) - Question 25

Which of the following statements is correct?

Detailed Solution for Test: Colligative Properties and Determination of Molar Mass (NCERT) - Question 25

Solubility changes with temperature. A plant cell shrinks in hypertonic solution. Relative lowering of vapour pressure is a colligative property.

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