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Test: Potential due to an Electric Dipole (NCERT) - NEET MCQ


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5 Questions MCQ Test - Test: Potential due to an Electric Dipole (NCERT)

Test: Potential due to an Electric Dipole (NCERT) for NEET 2024 is part of NEET preparation. The Test: Potential due to an Electric Dipole (NCERT) questions and answers have been prepared according to the NEET exam syllabus.The Test: Potential due to an Electric Dipole (NCERT) MCQs are made for NEET 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Potential due to an Electric Dipole (NCERT) below.
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Test: Potential due to an Electric Dipole (NCERT) - Question 1

The electric field and the potential of an electric dipole vary with distance r as

Detailed Solution for Test: Potential due to an Electric Dipole (NCERT) - Question 1

Electric field and electric potential at a general point at a distance r from the centre of the dipole is

Test: Potential due to an Electric Dipole (NCERT) - Question 2

An electric dipole is placed at the centre of a hollow conducting sphere. Which of the following is correct?

Detailed Solution for Test: Potential due to an Electric Dipole (NCERT) - Question 2

When electric dipole is held in the sphere, electric field is not zero anywhere on the sphere. However, net electric flux through the sphere is zero.

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Test: Potential due to an Electric Dipole (NCERT) - Question 3

Which of the following is not true?

Detailed Solution for Test: Potential due to an Electric Dipole (NCERT) - Question 3

The electric dipole potential varies as 1/r at large distance is not true.

Test: Potential due to an Electric Dipole (NCERT) - Question 4

The distance between H + and Cl − ions in HCl molecules is 1.38 Å. The potential due to this dipole at a distance of 10Å on the axis of dipole is

Detailed Solution for Test: Potential due to an Electric Dipole (NCERT) - Question 4

Here, 2a = 1.38 × 10−10m, r = 10 × 10−10 m charge, q = 1.6 × 10−19C
As potential,

Test: Potential due to an Electric Dipole (NCERT) - Question 5

Four points a, b, c and d are set at equal distance from the centre of a dipole as shown in the figure.

The magnitudes of electrostatic potential Va, Vb, Vc and Vd would satisfy the following relation

Detailed Solution for Test: Potential due to an Electric Dipole (NCERT) - Question 5



Vb = 0
∴ Va = Vc > Vb = Vd
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