Test: Effect of Dielectric on Capacitance (NCERT) - NEET MCQ

# Test: Effect of Dielectric on Capacitance (NCERT) - NEET MCQ

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## 5 Questions MCQ Test - Test: Effect of Dielectric on Capacitance (NCERT)

Test: Effect of Dielectric on Capacitance (NCERT) for NEET 2024 is part of NEET preparation. The Test: Effect of Dielectric on Capacitance (NCERT) questions and answers have been prepared according to the NEET exam syllabus.The Test: Effect of Dielectric on Capacitance (NCERT) MCQs are made for NEET 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Effect of Dielectric on Capacitance (NCERT) below.
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Test: Effect of Dielectric on Capacitance (NCERT) - Question 1

### If dielectric constant and dielectric strength be denoted by K and X respectively, then a material suitable for the use as a dielectric in a capacitor must have

Detailed Solution for Test: Effect of Dielectric on Capacitance (NCERT) - Question 1

The material suitable for using as a dielectric must have high dielectric strength X and large dielectric constant K.

Test: Effect of Dielectric on Capacitance (NCERT) - Question 2

### A parallel plate capacitor with air between the plates has a capacitance of 10 pF. The capacitance, if the distance between the plates is reduced by half and the space between them is filled with a substance of dielectric constant 4 is

Detailed Solution for Test: Effect of Dielectric on Capacitance (NCERT) - Question 2

Here C1 = ε0A/d = 10pF …….(i)
(∵ K = 4)
= 8 × 10 (using (i))
= 80 pF

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Test: Effect of Dielectric on Capacitance (NCERT) - Question 3

### The capacitance of a parallel plate capacitor with air as medium is 3μF. With the introduction of a dielectric medium between the plates, the capacitance becomes 15μF. The permittivity of the medium is

Detailed Solution for Test: Effect of Dielectric on Capacitance (NCERT) - Question 3

Capacitance of a parallel capacitor with air is C = ε0A/d​
Capacitance of a same parallel plate capacitor with the introduction of a dielectric medium is C ′ = Kε0A/d​
where K is the dielectric constant of a medium
or C′/C ​= K or K = 15/3​ = 5 or K = ε0/ε ​
or ε = Kε0 ​= 5 × 8.854 × 10−12 = 0.44 × 10−10C2N −1 m−2

Test: Effect of Dielectric on Capacitance (NCERT) - Question 4

A parallel plate capacitor having area A and separated by distance d is filled by copper plate of thickness b. The new capacity is

Detailed Solution for Test: Effect of Dielectric on Capacitance (NCERT) - Question 4

As capacitance C0 = ε0A/d
∴ after inserting copper plate C = ε0A/d−b

Test: Effect of Dielectric on Capacitance (NCERT) - Question 5

A parallel plate capacitor of capacitance 5μF and plate separation 6 cm is connected to a 1 v battery and charged. A dielectric of dielectric constant 4 and thickness 4 cm is introduced between the plates of the capacitor. The additional charge that flows into the capacitor from the battery is

Detailed Solution for Test: Effect of Dielectric on Capacitance (NCERT) - Question 5

as Q = cv
initially c = 5μF, v = 1v
∴ Q = 5 × 10–6 c = 5μc
when dielectric is introduced, let capacitance be c'
∴ c' = [(A∈0)/{d – t + (t/k)}]
here k = 4, t = 4 cm, d = 6 cm
∴ c' = [{(A∈0)/d}/{{d – t + (t/k)}/d}] ------ dividing by d
As [(A∈0)/d] = initially capacitance = c = 5μF
∴ c' = [c/{{6 – 4 + (4/4)}/6}] = [c/(3/6)] = 2c = 10μF
∴ Q' = c'v = 10 × 10–6 × 1 = 10μc
∴ addition charge flowing = Q' – Q = 10 – 5 = 5μc

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