Civil Engineering (CE) > Practice Test: Civil Engineering (CE)- 14

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Practice Test: Civil Engineering (CE)- 14 - Question 1

There are two lines made by joining points A, B,C. B lies between the line joining A and C. Is the distance between the A and C passes through the B more then 7 Km.

I. The distance between A and B is 6 Km

II. Distance between B to C is 7 Km long,

Detailed Solution for Practice Test: Civil Engineering (CE)- 14 - Question 1

From Statement I

We know the distance between Points B and C but we do not know about the distance between A and B

Statement II

This statement tells us about the distance between A and B and by using Both statement we can calculate the distance between A and C that is longer than the 7 Km.

Practice Test: Civil Engineering (CE)- 14 - Question 2

Direction: In the given question, a word/phrase is given followed by three statements; I, II and III. Choose the pair of sentences which can be combined using the given word/ phrase when used at the beginning of the new sentence.

And

I: When Lionel Messi, Ronaldo and Neymar kick and dribble the football, they don’t remain confined to Argentina, Portugal or Brazil, respectively.

II: Let the entire world realise that through sports, especially football, we all can cement our bonds, wash away our bitterness and prejudices.

III: Live with a greater sense of closeness and joy with each other.

Detailed Solution for Practice Test: Civil Engineering (CE)- 14 - Question 2

‘And’ is used as a conjunction here which is used to introduce an additional comment or interjection.

Here sentences II and III are displaying same sense that is realizing the benefit of football in our lives whereas sentence I is providing entirely different aspect of football as a sport.

Hence option (B) will be the most appropriate choice.

New sentence: Let the entire world realise that through sports, especially football, we all can cement our bonds, wash away our bitterness and prejudices, and live with a greater sense of closeness and joy with each other.

Practice Test: Civil Engineering (CE)- 14 - Question 3

Which of the following is the MOST SIMILAR in meaning to Accreditation?

Detailed Solution for Practice Test: Civil Engineering (CE)- 14 - Question 3

Accreditation = an acknowledgement of a person's responsibility for or achievement of something.

Certification = an official document attesting to a status or level of achievement.

Meticulous = showing great attention to detail; very careful and precise.

Lurid = very vividly shocking.

Suppressive = tending or acting to suppress.

Agreement = harmony or accordance in opinion or feeling.

Practice Test: Civil Engineering (CE)- 14 - Question 4

In how many ways can you place 2 white bishops on an empty chess board?

Detailed Solution for Practice Test: Civil Engineering (CE)- 14 - Question 4

One white bishop can be placed on any of the 32 white boxes and the other white bishop can be placed on any of the 32 black boxes.

Ways of doing that = ^{32}C_{1} * ^{32}C_{1}

= 32 * 32 = 1024

Practice Test: Civil Engineering (CE)- 14 - Question 5

Direction: In the question below are given statements followed by some conclusions. You have to take the given statements to be true even if they seem to be at variance with commonly known facts. Read all the conclusions and then decide which of the given conclusions logically follows from the given statements disregarding commonly known facts.

Statement:

No physics is maths.

Some chemistry is maths.

All sciences are chemistry.

Conclusion:

I. No science is physics.

II. Some physics are science.

III. Some physics are chemistry

Detailed Solution for Practice Test: Civil Engineering (CE)- 14 - Question 5

The least possible Venn diagram for the given statements is as follows.

Conclusions:

I. No science is physics → False (It is possible but not definite).

II. Some physics are science → False (It is possible but not definite)

III. Some physics are chemistry → False (It is possible but not definite)

Conclusion I and II form complementary pair.

Hence, either conclusion I or II follows.

Practice Test: Civil Engineering (CE)- 14 - Question 6

Direction: Read the information carefully and give the answer of the following questions-

(This pie chart shows the percentage of students appear in six different exams in 2016)

(This bar graph shows the percentage of failed students which appear in these six different exams in 2016)

If in 2016, total number of failed students in exam F was 4080, then how many passed students appears in the exam B?

Detailed Solution for Practice Test: Civil Engineering (CE)- 14 - Question 6

14280 ( Let total number of students be = 100z.

Total number of students appears in exam F = 16% of 100z = 16z;

Total number of failed students in exam F = 30% of 16z = 4.8z = 4080;

=> z = 850;

Total number of passed students appears in the exam B = (100 – 30)% of 24% of 100z = 16.8z = 16.8 × 850 = 14280 ;)

Practice Test: Civil Engineering (CE)- 14 - Question 7

Direction: Two sentences with two blanks in each, followed by five alternatives with two words in each, are given. Choose that option as the answer which can fill both the blanks of both the sentences.

i. A sinking feeling of panic ________ over them and a temporary paralyzing fear engulfed them ________.

ii. Being a cleanliness freak, she ________ the floor and went down to the market only after the house was _________ clean.

Detailed Solution for Practice Test: Civil Engineering (CE)- 14 - Question 7

‘Sweep’ is to clean (an area) by brushing away dirt or litter. It fits the first blank of the second sentence, as the subject is cleaning the floor. Further, ‘sweep over’ means to overcome or overwhelm, thus fits in the first blank of the first sentence. The second blank of both the sentences can be filled by "completely", thus conveying an appropriate sense. Thus, option D is the correct answer.

Practice Test: Civil Engineering (CE)- 14 - Question 8

**Direction: **Five statements are given below, labelled 1, 2, 3, 4 and 5 which are supposed to be in a logical order. A statement labelled P is given thereafter. P can replace one of the five statements such that the four statements along with P would make a coherent paragraph. You have to identify which statement should P replace and then the find out the correct sequence from the options. If the five options are in logical order and form a coherent paragraph/passage, choose the fifth option “12345”.

1) The future of Germany’s coalition government is hanging in the balance after the country’s interior minister reportedly announced his intention to resign over a migration showdown with Angela Merkel.

2) Horst Seehofer, who is also leader of the Christian Social Union, on Sunday night offered to step down from his ministerial role and party leadership in a closed-door meeting in which he and fellow CSU leaders had debated the merits of the migration deal Merkel hammered out with fellow European Union leaders in Brussels.

3) But with CSU hardliners believed to have tried to talk the combative interior minister into staying, a press conference was postponed until Monday, with Seehofer seeking to go back to Merkel in search of a final compromise.

4) At a 2am media conference, Seehofer said he had agreed to meet again with Merkel’s party before he made his decision final.

5) “We’ll have more talks today with the CDU in Berlin with the hope that we can come to an agreement,” Seehofer said.

**Direction:** In the given question, a statement with a single blank is given. Choose the most effective word from the given options to complete the sentence meaningfully.

The fog was so thick during the morning, that it seemed like walking _________ a cloud.

Detailed Solution for Practice Test: Civil Engineering (CE)- 14 - Question 8

Here the sense conveyed is that the fog being too thick, appeared like clouds. You would walk "through" a fog or a tunnel, thus, option D is the best fit answer in the given context. 'Along' means to walk side by side and does not fit in the given context.

Practice Test: Civil Engineering (CE)- 14 - Question 9

4 identical solid spheres are melted and re-formed into a solid hemisphere. Then, the ratio of the curved surface area of the hemisphere to half of the surface area of a single sphere is -

Detailed Solution for Practice Test: Civil Engineering (CE)- 14 - Question 9

Let radius of sphere be ‘r’ and radius of hemisphere be ‘R’.

Then, ATQ, Volume of Spheres = Volume of Hemisphere

4 x (4/3)πr^{3} = (2/3)πR^{3}

Or, R / r = (8)^{1/3} = 2 …(1)

C.S.A of hemisphere = 2πR^{2}

And, Surface area of sphere = 4πr^{2}

ATQ, 2πR^{2} :( ½) of 4πr^{2}

= 2πR^{2} :2πr^{2} = R^{2} :r^{2} {using (1)}

= 4 :1

Practice Test: Civil Engineering (CE)- 14 - Question 10

A study of people who reduced the calories they consumed has found the strongest evidence yet that such restrictions slow down metabolism, raising hopes that a low calories lifestyle or treatments stimulating biological effects of restricted eating, could prolong health in old age. The report provides the most robust evidence to date that everything we have learnt in other animals can be applied to humans.

Which of the following argument will prove that the above conclusion is flawed?

Detailed Solution for Practice Test: Civil Engineering (CE)- 14 - Question 10

The given passage gives the benefits of reducing calories to attain a healthier lifestyle and out of the given options, option B seems to give a contradictory fact stating that the lack of required calories may cause problems to the body. Hence, option B is correct.

Detailed Solution for Practice Test: Civil Engineering (CE)- 14 - Question 11

Practice Test: Civil Engineering (CE)- 14 - Question 12

The order and degree of the differential equation, are respectively.

Detailed Solution for Practice Test: Civil Engineering (CE)- 14 - Question 12

After removing radical sign

The order is 4 since highest differential is d^{2}y/dx^{2 }and the degree is 2 since power of highest differential 2.

Practice Test: Civil Engineering (CE)- 14 - Question 13

The divergence of the vector field x^{2}i + 2y^{3}j + z^{4}k at x =1 , y= 2, z = 3 is

Detailed Solution for Practice Test: Civil Engineering (CE)- 14 - Question 13

Given

Practice Test: Civil Engineering (CE)- 14 - Question 14

Let , then the smallest positive integer I , such that is ______________

Detailed Solution for Practice Test: Civil Engineering (CE)- 14 - Question 14

so any integer less than 12 is not possible for this condition.

Detailed Solution for Practice Test: Civil Engineering (CE)- 14 - Question 15

Since this function has form, limit can be found by application of L’Hospitals Rule

Practice Test: Civil Engineering (CE)- 14 - Question 16

In levelling, if the sum of back sight and fore sight is 1.365 and 0.875 m and reduced level of B.M. is 100 m. then reduced level of end point will be-

Detailed Solution for Practice Test: Civil Engineering (CE)- 14 - Question 16

According to arithmetic check;

∑B.S - ∑F.S = first R.L – last R.L

So, last R.L = first R.L + ∑F.S - ∑B.S

= 100 + 0.875 – 1.365

= 99.51 m

Practice Test: Civil Engineering (CE)- 14 - Question 17

The maximum height of a low gravity dam of elementary profile made up of concrete of relative density 2.4 and safe allowable stress on foundation is 3.6MPa (Ignoring uplift force).

Detailed Solution for Practice Test: Civil Engineering (CE)- 14 - Question 17

Maximum height of dam is given by

H= F/(ϒ_{w} × (Sc – C+1))

Here F=3.6MPa

ϒ_{w} = 9.81KN/m^3

S_{c} =2.4

C=0

On solving H=107.93m hence correct option is A

*Answer can only contain numeric values

Practice Test: Civil Engineering (CE)- 14 - Question 18

The level of water in the reservoir is 1.25 m. If there is a rainfall of 38 cm occurring in a month, during this period evaporation as measured by the class A pan is 32 cm. What is the level of water in m at the end of the month.

Detailed Solution for Practice Test: Civil Engineering (CE)- 14 - Question 18

Evaporation in lake = Pan coefficient × Pan evaporation

= 0.7 × 32 = 22.4 cm

Initial level + Rainfall – Evaporation = Final level

Final level = 1.25 + 0.38 – 0.224 = 1.406 m

Practice Test: Civil Engineering (CE)- 14 - Question 19

The permeability coefficient of sand with void ratio of 0.65 is 3.048 cm/min. Estimate the permeability coefficient at a void ratio of 0.8 using casagrande empirical relationship.

Detailed Solution for Practice Test: Civil Engineering (CE)- 14 - Question 19

From the Casagrande relationship,

**Note:**

A, Casagrande has also given an empirical relation for k for the fine or medium clean sands with bulky grain as

K = 1.4e^{2}k_{0.85}Where k_{0.85} is the coefficient of permeability at a void ratio of 0.85

Practice Test: Civil Engineering (CE)- 14 - Question 20

A 12 m^{3} moist soil sample with volume of soil solid as 9m^{3} is examined and the laboratory results reveal that the porosity of the soil sample is 25 %. The relative porosity of the sample is _____.

Practice Test: Civil Engineering (CE)- 14 - Question 21

Which one of the following is correctly showing the level of manometer column.

Detailed Solution for Practice Test: Civil Engineering (CE)- 14 - Question 21

AV=constant

By applying Bernoulli's theorem, we know that if velocity increases then the pressure will decrease.

Lets take option 1

at the throat, the area will be less so velocity will increase and pressure will decrease. so the fluid will rise in the tube. Hence this option is right.

option 2

this can not be true as at the throat side fluid is falling which indicate a decrease in velocity and increase in pressure. That is wrong

Same concept follows for option 3 and 4. only option 4 depicts the continuity concept. So only case 1and 4 are right.

*Answer can only contain numeric values

Practice Test: Civil Engineering (CE)- 14 - Question 22

A singly reinforced rectangular beam has a width of 200 mm and an effective depth of 350 mm. The limiting value of the moment of resistance of the beam is _________ kN-m.

[Take M20 grade concrete and Fe415 grade steel and adopt the stress block for concrete as given in IS 456: 2000]

Detailed Solution for Practice Test: Civil Engineering (CE)- 14 - Question 22

For Feb 15,

Practice Test: Civil Engineering (CE)- 14 - Question 23

The slack of events 3 and 5 is from the project network given below?

Detailed Solution for Practice Test: Civil Engineering (CE)- 14 - Question 23

The earliest expected time and latest allowable time of event ‘3’ is 2 and 4 respectively. Thus slack = 4-2 =2.

Similarly, the earliest expected time and latest allowable time of event ‘5’ is 6 and 6 respectively. Thus slack = 6-6=0.

Practice Test: Civil Engineering (CE)- 14 - Question 24

Figure shows the network for a particular project which consists of four activities.

Normal duration time and crash time for each activity are given below

The velocity of fluid 2.234 m/s having a viscosity 0.023 Pa.s with density 2.345 is measured at a distance of 95 mm from the boundary. Find the shear stress at the boundary?

Detailed Solution for Practice Test: Civil Engineering (CE)- 14 - Question 24

From the boundary conditions:

We see that the gradient will be:

dV/dy = 2.234 m/s /0.095 m

= 23.5/s

Now we will see for shear stress by:

Ʈ = µ dV/dy = 0.023 Pa.s x 23.5 s = 0.540 Pa

Practice Test: Civil Engineering (CE)- 14 - Question 25

Which acid is used to distinguish the steel and the wrought iron on the field?

Detailed Solution for Practice Test: Civil Engineering (CE)- 14 - Question 25

Nitric acid (HNO_{3}) is used to distinguish. If a drop of nitric acid is placed on steel, it will produce a dark grey stain because of higher carbon content whereas in wrought iron, the stain will not be appreciable due to very low carbon content.

Practice Test: Civil Engineering (CE)- 14 - Question 26

The topmost layer is loose, clean sand, 1.5 meter thick. Its vertical permeability can be estimated using Hazen’s formula with C = 1.5 and D10 = 0.016mm. Its horizontal permeability is known to be 350% of the Kv. Below the sand stratum is a layer of marl, 3.5 meters thick, with a kv = Kh = 10^{-4} m/s. what is the Equivalent Horizontal permeability for the upper 5 m in cm/sec?

Detailed Solution for Practice Test: Civil Engineering (CE)- 14 - Question 26

Given that the vertical permeability in sand layer can be estimated using Allen- Hazen’s formula

Kv = C (D10)^{2}

C = 1.5 and D10 = 0.016mm

Kv = 0.0384 x 10^{-3} cm/sec

Horizontal permeability for sandy layer is 350% of Kv

i.e. K_{h} = 3.5 (0.0384 x10^{-3} ) = 0.134 x10^{-3} cm/sec

Kh(equ) =(K1H1+K2H2)/(H1+H2)

Here K_{1} = 0.134 x10-3 cm/sec; H1 = 1.5m

K_{2} = 10^{-4} cm/sec; H2 = 3.5m

On substituting, we get Kh(equ) = 1.102 x 10^{-4} cm/sec

Practice Test: Civil Engineering (CE)- 14 - Question 27

Cayley-Hamilton Theorem states that a square matrix satisfies its own characteristic equation. Consider a matrix A satisfies the relation

Detailed Solution for Practice Test: Civil Engineering (CE)- 14 - Question 27

Characteristic equation is given by, , | A - λ | = 0

As Cayley-Hamilton Theorem states, a square matrix satisfies this equation, then,

A^{2} + 3A + 2I = 0

Multiplying A^{–1} to both sides, we get

⇒ ? + 3? + 2? ^{−1} = 0

Practice Test: Civil Engineering (CE)- 14 - Question 28

The hardness of a ground water sample was found to be 420 mg/L as CaCO_{3} A softener containing ion exchange resins was installed to reduce the total hardness to 75 mg/L as CaCO_{3} before supplying to 4 households. Each household gets treated water at a rate of 540 L/day. If the efficiency of the softener is 100%, the bypass flow rate (expressed in L/day) is _____________.

Detailed Solution for Practice Test: Civil Engineering (CE)- 14 - Question 28

Since each household gets water = 540 L/day

So, total treated water = 540×4=2160 L/day

Let bypass flow rate is QL/day

So,

Practice Test: Civil Engineering (CE)- 14 - Question 29

Consider the matrix:

J6= [0 0 0 0 0 1 0 0 0 0 1 0 0 0 0 1 0 0 0 0 1 0 0 0 0 1 0 0 0 0 1 0 0 0 0 0 ]

Which is obtained by reversing the order of the columns of the identity matrix I6.

Let P=I_{6}+αJ_{6}, where α is a non-negative real number. The value of α for which det(P) = 0 is ___________.

Detailed Solution for Practice Test: Civil Engineering (CE)- 14 - Question 29

Consider, (I) Let

∵ α is non negative

∵ the value of (1 - α^{2}) = 0 given in the question

∴ α = 1

Practice Test: Civil Engineering (CE)- 14 - Question 30

A beam of uniform strength is to be produced for a special purpose of application. But the section of the beam needs to be varied, and this could be achieved by;

Detailed Solution for Practice Test: Civil Engineering (CE)- 14 - Question 30

Beam of uniform strength is one in which the maximum bending stress is same in every section along the longitudinal axis.

Uniform strength can be achieved by :

Keeping the width constant throughout the length and varying the depth. This is the most widely used method.

Keeping the depth constant throughout the length and varying the width

Or by varying both width and depth suitably.

Practice Test: Civil Engineering (CE)- 14 - Question 31

A flag post was erected on the top of a building. If vertical angle to bottom and top of the flag post are 8 ° and 9 ° respectively, then the height of the flag post is ___________ decimeter.

[Assume R.L. of top and bottom of building to be 184.4 m and 145.2 m respectively, height of instrument to be 1.2 m and width of the building is very less as compared to the distance to the building and the theodolite]

Detailed Solution for Practice Test: Civil Engineering (CE)- 14 - Question 31

Height of building above instrument,

from (I) and (ii)

Practice Test: Civil Engineering (CE)- 14 - Question 32

A distributed line load of 100 kN per meter run may occupy any position on the girder shown in the figure below. The ratio of the magnitude of the maximum positive bending moment to negative bending moment that can occur at the section marked at C (not hinge) is ___________.

Detailed Solution for Practice Test: Civil Engineering (CE)- 14 - Question 32

Influence line diagram

Position of load for maximum negative BM at C

Maximum positive BM at C,

Maximum negative BM at C,

Practice Test: Civil Engineering (CE)- 14 - Question 33

Curing period is minimum for concrete using _______.

Detailed Solution for Practice Test: Civil Engineering (CE)- 14 - Question 33

Curing period is minimum for concrete using Ordinary Portland cement

Rapid hardening cement requires more curing due to more heat of hydration in shorter time which may leads to shrinkage.

Practice Test: Civil Engineering (CE)- 14 - Question 34

A student began experiment for determination of 5–day, 20 °C BOD on Monday. Since the 5th day fell on Saturday, the final DO readings were taken on next Monday. On calculation, BOD (i.e. 7 days, 20 °C) was found to be 150 mg/L. What would be the 5–day, 20 °C BOD (in mg/L)? Assume value of BOD rate constant (k) at standard temperature of 20 °C as 0.23 / day (base e). ________

Detailed Solution for Practice Test: Civil Engineering (CE)- 14 - Question 34

Practice Test: Civil Engineering (CE)- 14 - Question 35

The F/M ratio is controlled in the activated sludge process by adjusting the

Detailed Solution for Practice Test: Civil Engineering (CE)- 14 - Question 35

F/M ratio is defined as

F/M = Daily BOD load supplied to the aerator system / Total microbial mass in the system

The effluent ROD to the plant cannot be changed by the operator. Hence it can be taken as constant. The mass of microorganisms can be regulated by the operator by adjusting the amount of sludge wasting. Greater sludge wasting will lower' in the F/M ratio.

Practice Test: Civil Engineering (CE)- 14 - Question 36

An isolated L beam, as shown below, is fixed at both ends and has a span of 20 m. The effective width of the flange is ____ mm.

Detailed Solution for Practice Test: Civil Engineering (CE)- 14 - Question 36

For isolated L-Beam,

Effective width of flange,

l_{0}= 0.7 x 20 (for fixed ends) = 14 m

∴ Effective width of flange

Practice Test: Civil Engineering (CE)- 14 - Question 37

For the single V unsealed butt welded joint shown in the figure, the permissible load will be _________ kN.

[Assume safe stress in weld to be 143 N/mm^{2}]

Detailed Solution for Practice Test: Civil Engineering (CE)- 14 - Question 37

Since the joint is as unsealed V-butt joint, the effective thickness of the throat of weld

Permissible load = Length of weld x Effective throat thickness x Permissible tensile stress in the weld

= 130 x 5 x 143 = 92950 N = 92.95 kN

Practice Test: Civil Engineering (CE)- 14 - Question 38

In two samples of water A and B, A has pH value of 6.5 and B has pH value of 8.5 respectively. Sample B is ___times more acidic than sample A.

Detailed Solution for Practice Test: Civil Engineering (CE)- 14 - Question 38

PH = - log_{10} [H^{+}]

- log^{10} [H+] = pH

[H^{+}]_{A} = 10^{-6.5}

and pH of sample B = 14 – pOH

= 14 – 8.5 = 5.5

Practice Test: Civil Engineering (CE)- 14 - Question 39

The leaching requirement of a soil is 10%. If the consumptive use requirement of the crop is 90 mm, then the depth of water required to be applied to the field is

Detailed Solution for Practice Test: Civil Engineering (CE)- 14 - Question 39

Leaching requirement in % is given by

Where, D_{i} = Total irrigation water depth to be applied

Cu=Consumptive use

Practice Test: Civil Engineering (CE)- 14 - Question 40

Which of the following statements are CORRECT about affecting the bactericidal efficiency of chlorine?

1) When the time of contact increases, bactericidal efficiency increases.

2) pH range 5-7 is the most effective, beyond this range, bactericidal efficiency decreases.

3) Bactericidal efficiency decreases with increase in turbidity.

Detailed Solution for Practice Test: Civil Engineering (CE)- 14 - Question 40

Factors affecting Bactericidal efficiency of Chlorine

1. **Turbidity:** The effect of turbidity in water is to make it difficult to obtain free residual chlorine. Also, the penetration of chlorine and therefore the destruction of bacteria in particles of suspended matter of a turbid water may be very uncertain.

2. **pH of water:** Increasing pH reduces effectiveness of chlorine. The effective sterilising compound, hypochlorous acid, is formed in greater quantities at low pH than(5 to 7) at high pH values.

3. **Time of Contact:** Bactericidal efficiency of chlorine increases with increases in time of contact in general also the bactericidal activity of chlorine is not spontaneous.

Practice Test: Civil Engineering (CE)- 14 - Question 41

For a fully developed laminar flow of water (dynamic viscosity 0.001 Pa-s) through a pipe of radius 5 cm. the axial pressure gradient is —10 Pa/m. The magnitude or axial velocity (in m/s) at a radial location of 0.2 cm is ___________ m/sec

Detailed Solution for Practice Test: Civil Engineering (CE)- 14 - Question 41

For incompressible laminar flows through pipes velocity distribution

Detailed Solution for Practice Test: Civil Engineering (CE)- 14 - Question 42

Converting the matrix into Echelon form,

Now since the matrix is in Echelon

Rank=Number of no-zero rows = 2

Practice Test: Civil Engineering (CE)- 14 - Question 43

A rod of length L having uniform cross-sectional area A is subjected to a tensile force P as shown in the figure below. If the Young’s modulus of the material varies linearly from E1 to E2 along the length of the rod, the normal stress developed at the section-SS is

Detailed Solution for Practice Test: Civil Engineering (CE)- 14 - Question 43

The normal stress across any section depends only on external force (P) & across-section area is independent of young's of material

Practice Test: Civil Engineering (CE)- 14 - Question 44

Given that one root of the equation x^{3} –10x^{2} + 31x –30 = 0 is 5, the other two roots are

Detailed Solution for Practice Test: Civil Engineering (CE)- 14 - Question 44

Given, x^{3}-10x^{2}+31x-30=

It's one root is 5, hence

(x-5) (x^{2}-5x+6)=0

⇒(x-5) (x^{2}-3x-2x+6)=0

⇒(x-5) (x-3)(x-2)=0

⇒x=5,3,2

Practice Test: Civil Engineering (CE)- 14 - Question 45

A steel column section ISHB 350 (width of flange is 250mm and thickness of flange 11.6mm) has to carry a factored load of 2400kN. The yield stress and the ultimate tensile stress of steel and welds are 250MPa and 410MPa respectively and partial safety factor governed by yield and ultimate tensile strength respectively are 1.10 and 1.25. The bearing strength of M25 grade concrete in limit state method of design as per IS 456:2000(inN/mm^{2}) is

Detailed Solution for Practice Test: Civil Engineering (CE)- 14 - Question 45

For ISHB 350 steel column,

b_{f}=250mm and t_{f}=11.6mm.

P=2400kN, f_{y}=250 MPa.

For M25 grade concrete Fck=25N/mm^{2}

Bearing strenght of concrete=0.45f_{ck}=11.25N/mm^{2}

Practice Test: Civil Engineering (CE)- 14 - Question 46

The magnitude of bending moment at fixed end of beam shown in figure above is _________ KNm

Detailed Solution for Practice Test: Civil Engineering (CE)- 14 - Question 46

Calculation of FEM

FINAL MOMENT AT FIXED END = -72KNm

Practice Test: Civil Engineering (CE)- 14 - Question 47

If the total float of an activity in CPM has a value ‘x’ units and the head event slack has a value ‘y’ units, find out the value of independent float if the tail event slack is 10. ?

Detailed Solution for Practice Test: Civil Engineering (CE)- 14 - Question 47

Reason: Free float = Total float – Head event slack

Free float =x-y

We know that,

Free float = Independent float + Tail event slack

x-y = Independent float + 10

Then, Independent float = x-y-10

Practice Test: Civil Engineering (CE)- 14 - Question 48

The data given below pertain to the design of a flexible pavement are Initial traffic = 1213 cvpd

Traffic growth rate = 8 per cent per annum

Design life = 12 years

Vehicle damage factor = 2.5

Distribution factor = 1.0

The design traffic in terms of million standard axles (msa) to be catered would be

Detailed Solution for Practice Test: Civil Engineering (CE)- 14 - Question 48

Cumulative number of standard axle load

A = Number of commercial vehicle or initial traffic = 1213 cvpd

r = Traffic growth rate = 8% per annum

n = design life = 2 years

f = vehicle damage factor = 2.5

Practice Test: Civil Engineering (CE)- 14 - Question 49

The velocity potential function in a two dimensional flow field is given by ∅=x^{2}-y^{2}. The magnitude of velocity at point (1, 1) is

Detailed Solution for Practice Test: Civil Engineering (CE)- 14 - Question 49

Practice Test: Civil Engineering (CE)- 14 - Question 50

The flow in a rectangular channel is subcritical. If width of the channel is reduced at a certain section, the water surface under no–choke condition will

Detailed Solution for Practice Test: Civil Engineering (CE)- 14 - Question 50

In the subcritical region of flow for a given specific energy, as the discharge per unit width q is increased due to reducing width at the section, the depth of flow will decrease.

Therefore water surface drop at a downstream section.

Alternately

From the discharge diagram, it can be seen that, for subcritical flow as q increases, depth decreases.

Therefore at the reduced section, depth decreases.

Practice Test: Civil Engineering (CE)- 14 - Question 51

Match List-I (End condition of the column) with List-II (Lowest critical load) and select the correct answer using the code given below the Lists:

List-I

A) Column with both ends hinged

B) Column with both ends fixed

C) Column with one end fixed and the other end hinged

D) Column with one end fixed and the other end free

List-II

Detailed Solution for Practice Test: Civil Engineering (CE)- 14 - Question 51

Euler’s Formula is given by Pe

where, E=Young'S Modulus of Elasticity

Imin=Min. Moment of inertia about centroid axis

le=Effective length = Original length × Effective length factor

Practice Test: Civil Engineering (CE)- 14 - Question 52

Consider the following statements:

1) There will be no defects in select grade timbers.

2) The codal values for strength of grade-II timer without defects may be reduced by 37.5%.

3) For timber used as columns, the permissible stress in ungraded timbers is adopted with a multiplying factor of 0.50.

4) In case of wind force and earthquakes, a modification factor of 1.33 is adopted.

Which of the above statements are correct?

Detailed Solution for Practice Test: Civil Engineering (CE)- 14 - Question 52

Some defects are permitted in all grades of timber and all other defects unlikely to affect any of the mechanical strength properties.

As IS: 1331 –1971 provides for reduction in strength of Grade-II timber without defects not by more than 37.5%.

Permissible stress in ungraded timbers is adopted with a multiplying factor of 0.80

Modification factor of 1.33 is adopted in case of wind and earthquake forces

Practice Test: Civil Engineering (CE)- 14 - Question 53

A tractor has a permissible loaded speed of 200 m/minute, which can increase by 25% when the load is removed/deposited. Generally, it is operated at 80% of the permissible speed (loaded unloaded). It works at a location where haul distance is 120 m. Rest allowance per round-trip is taken as 50 seconds on an average. Fixed time per trip, for loading and unloading and turnaround, etc., is 30 seconds.

What is its effective cycle time157 seconds

Detailed Solution for Practice Test: Civil Engineering (CE)- 14 - Question 53

Running speed of loaded tractor

= 200 x 0.8 x = 160m/minutes

Running speed of unloaded tractor

= 200 x 1.25 x 0.8

= 200m/minute total time for the trip

Practice Test: Civil Engineering (CE)- 14 - Question 54

A uniform ladder 24 m long weighs 400 N. It is placed against a vertical wall at an angle of 60° with the ground. How far along the ladder can a 1600 N man climb before the ladder is on the verge of slipping? The angle of friction at all contact surfaces is 15°.

Detailed Solution for Practice Test: Civil Engineering (CE)- 14 - Question 54

Practice Test: Civil Engineering (CE)- 14 - Question 55

A mass of 2 kg is hung by a string of length 1.5m as shown in the figure. The mass revolves in a circular path at 50 revolutions per minute. The tension in the string (in N) is

Detailed Solution for Practice Test: Civil Engineering (CE)- 14 - Question 55

Practice Test: Civil Engineering (CE)- 14 - Question 56

What is the value of the definite integral

Detailed Solution for Practice Test: Civil Engineering (CE)- 14 - Question 56

Given

Putting a-x=t, we get

Adding equations (i) and (ii), we have

Practice Test: Civil Engineering (CE)- 14 - Question 57

An effective rainfall of 2-hour duration produced a flood hydrograph peak of 200m^{3}/s. The flood hydrograph has a base flow of 20m^{3}/s. If the spatial average rainfall in the watershed for the duration of storm is 2cm and the average loss rate is 0.4cm/hour, the peak of 2-hour unit hydrograph (in m^{3}/s-cm, up to one decimal place) is_________(water resource engineering: hydrology)

Detailed Solution for Practice Test: Civil Engineering (CE)- 14 - Question 57

Peak of DRH =200-20=180m^{3}/s

let peak of UH beQ_{p}

So, Q_{p}×1.2=180

⇒Q_{p}=150m^{2}/s

Practice Test: Civil Engineering (CE)- 14 - Question 58

The peak discharge of a 4-hr unit hydrograph, triangular in shape, for a basin of 108〖km〗^{2}, is 20 cumecs. The time base (in hrs) of this hydrograph is

Detailed Solution for Practice Test: Civil Engineering (CE)- 14 - Question 58

Where b is the time base in seconds.

Volume in UH=Volume of runoff with 1 cm depth over the catchment

Practice Test: Civil Engineering (CE)- 14 - Question 59

A joist of 8 m span has to carry a load of 30kN/m. The permissible stress limit is 10N/mm2 and the depth of the joist has to be twice the width. Now, find the dimensions of the joist.

Detailed Solution for Practice Test: Civil Engineering (CE)- 14 - Question 59

Depth of joist =2×width

= 2 x b

Now, from the bending stress formula,

Permissible stress,

Practice Test: Civil Engineering (CE)- 14 - Question 60

The maximum size of sand particles (with relative density of 2.65) which will settle in water, according to Stoke’s law, is ___________mm.

(Density of water = 998kg/m^{3} , Dynamic viscosity = 1×10^{-3} Pa.s).

Detailed Solution for Practice Test: Civil Engineering (CE)- 14 - Question 60

Stoke’s law is valid up to

Re = 1.0

For maximum size particle that obey stoke’s law,

Also the setting velocity,

Substituting for V_{t}

Practice Test: Civil Engineering (CE)- 14 - Question 61

A catchment is idealized as a 25 km x 25 km square. It has five rain gauges, one at each corner and one at the center, as shown in the figure.

During a month, the precipitation at these gauges is measured as G_{1} = 300 mm, G_{2} = 285 mm, G_{3} = 272mm, G_{4} = 290mm and G_{5} =288mm. The average precipitation (in mm, up to one decimal place) over the catchment during this month by using the Thiessen polygon method is ______

Detailed Solution for Practice Test: Civil Engineering (CE)- 14 - Question 61

By thiessen polygon method

Practice Test: Civil Engineering (CE)- 14 - Question 62

For a given matrix where the inverse of matrix p is

Detailed Solution for Practice Test: Civil Engineering (CE)- 14 - Question 62

Practice Test: Civil Engineering (CE)- 14 - Question 63

Consider a non-homogeneous system of linear equations representing mathematically an over-determined system. Such a system will be

Detailed Solution for Practice Test: Civil Engineering (CE)- 14 - Question 63

Determined system In this system, the number of equations is more than number of unknown variables, i.e., (m>n)

So, in determined system it is necessary that the system should be consistent and having unique solution.

Practice Test: Civil Engineering (CE)- 14 - Question 64

Match List-I (Type of shear tests) with List-II (Mohr failure envelops of total stress) and select the correct answer using the codes given below the lists:

**List-I**

A) Undrained test on normally consolidated saturated clays.

B) Consolidated undrained test on normally consolidated saturated clays.

C) Drained tests on normally consolidated saturated cohesive soil.

D) Unconfined test on clays.

**List-II**

Detailed Solution for Practice Test: Civil Engineering (CE)- 14 - Question 64

A) If undrained test is done on a saturated soil, then the total stress envelope will have the same diameter for all tests, i.e., diagram 1.

C) In drained test, higher the confining stress higher will be the consolidation which increases soil’s shearing strength, hence, failure stress will be high and therefore diameter of Mohr failure envelope gets on increasing in size.

D) Unconfined test means confining pressure should be zero, hence, diagram 4 only.

**Note: **CU and CD tests will have similar diagram for normally consolidated clays.

Detailed Solution for Practice Test: Civil Engineering (CE)- 14 - Question 65

Applying L' Hospital rule

Applying L' Hospital rule

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