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Math Olympiad Test: Surface Area and Volume- 1 - Free MCQ with solutions


MCQ Practice Test & Solutions: Math Olympiad Test: Surface Area and Volume- 1 (10 Questions)

You can prepare effectively for Class 10 Mathematics (Maths) Class 10 with this dedicated MCQ Practice Test (available with solutions) on the important topic of "Math Olympiad Test: Surface Area and Volume- 1". These 10 questions have been designed by the experts with the latest curriculum of Class 10 2026, to help you master the concept.

Test Highlights:

  • - Format: Multiple Choice Questions (MCQ)
  • - Duration: 10 minutes
  • - Number of Questions: 10

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Math Olympiad Test: Surface Area and Volume- 1 - Question 1

Marbles of diameter 1.4 cm are dropped into a cylindrical beaker of diameter 7 cm containing some water. What is the number of marbles that should be dropped into the beaker so that the water level rises by 5.6 cm?

Detailed Solution: Question 1

Let the no. of marbles = x
Radius of marble = 1.4/2 = 0.7 cm
Radius of cylinder = 7/2 = 3.5 cm

⇒ x = 150

Math Olympiad Test: Surface Area and Volume- 1 - Question 2

A hollow sphere of internal and external diameter 4 cm and 8 cm respectively is melted into a cone of base diameter 8 cm. Find the height of the cone.

Detailed Solution: Question 2

The volume of cone = Volume of metal in the sphere

Math Olympiad Test: Surface Area and Volume- 1 - Question 3

A solid cylinder has height 12 cm and diameter 10 cm. A conical cavity of same height and same diameter is hollowed out. What is the total surface area of the remaining solid?

Detailed Solution: Question 3

Total surface area of the remaining solid = curved surface area of the cylinder + curved surface area of the cone + area of upper base of the cylinder 
= 2πrh + πrl + πr2

Math Olympiad Test: Surface Area and Volume- 1 - Question 4

The surface area of the cylinder is 2992 cm2 and its height is 20 cm, what is the diameter of the cylinder?

Detailed Solution: Question 4

Let r be the radius of the cylinder Total surface area = 2πr (h + r)

⇒ r2 + 20r - 476 = 0
⇒ r2 + 34r - 14r - 476 = 0
⇒ r(r + 34) - 14(r + 34) = 0
⇒ (r - 14) (r + 34) = 0
⇒ r = 14; r = -34 (Not possible)
diameter = 2 × 14 = 28 cm

Math Olympiad Test: Surface Area and Volume- 1 - Question 5

The curved surface area of a cylindrical pillar is 264 m2 and its volume is 924 m3. What is the height of the pillar?

Detailed Solution: Question 5

Curved surface area of cylindrical pillar = 264

From (1) and (2)

264r = 924 × 2

Math Olympiad Test: Surface Area and Volume- 1 - Question 6

A solid iron hemisphere is melted and a number of solid iron balls of equal size are made. The radius of each ball is one-fourth the radius of the hemisphere. What are the number of balls that can be made?

Detailed Solution: Question 6

The radius of hemisphere = R
∴ Volume of hemisphere = 2/3 πR3
radius of spherical balls = R/4
Let the no. of spherical balls casted be x
∴ Volume of resulting spheres

Now,
Initial volume = Final volume,

Math Olympiad Test: Surface Area and Volume- 1 - Question 7

A solid sphere of copper of radius 10.5 cm is melted and right cones of radius 3.5 cm and height 3 cm are made from the material. What is the number of cones made?

Detailed Solution: Question 7

Let the number of cones made be n. The volume of solid sphere = volume of resulting cones

Math Olympiad Test: Surface Area and Volume- 1 - Question 8

The weight of a metallic spherical shell is 11.176 kg. If the inner radius of the cell is 6 cm. 1 cm3 of the metal weights 21 g then what is the thickness of the shell?

Detailed Solution: Question 8

Let the thickness of the shell be t
Inner radius = r, outer radius = R
∴ Volume of spherical shell = 4/3 π(R3 - r3)

∴ Weight of spherical shell

= 11.1786 kg
⇒ R3 = 343 ⇒ R = 7 cm
∴ Thickness = t = (R - r) = (7 - 6) = 1 cm

Math Olympiad Test: Surface Area and Volume- 1 - Question 9

The ratio of the volumes of two spheres is 27 : 8. Find the ratio of their surface areas.

Detailed Solution: Question 9

Ratio of volumes of spheres of radii r1 and r2 respectively

Similarly,
ratio of surface areas

According to condition

∴ Ratio of surface areas

Math Olympiad Test: Surface Area and Volume- 1 - Question 10

The surface area of a sphere is 616 cm2, what is the diameter of the sphere?

Detailed Solution: Question 10

Surface area of sphere = 4πr2 = 616

∴ diameter = 2r = 2 × 7 = 14 cm

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