Test Level 1: Percentages - 2 Solved MCQs CAT

Ramakant spends 40% of the total income (let's say 'x') on food.
40% of x = Rs. 38,400

x = Rs. 96,000
He spends 50% on clothes.
Amount spent on clothes = 96,000/2 = Rs. 48,000
48,000 is the 60% of the marked price of clothes.
So, market price of clothes 

That is, Ramakant gets a discount of Rs. (40% of 80,000) on clothes.
Total discounted money = Rs. 32,000

Let's say that the male population is 300.
Let's say that the female population is 200.
Graduate male population

Graduate female population 

Non-graduate population = 500 - 110 = 390
Percentage of non-graduate population 

Value of machine after 3 years 

The bonus amount of Rs. 1000 increases his savings by 10%.
Since 1000 is 10% of 10,000, the previous month's savings were Rs. 10,000.
Now, as his previous month savings were Rs. 10,000,
Expenses = 15,000 – 10,000 = Rs. 5000

The given information is shown on two different scales as given below:

Difference of percentages of total marks = (6 + 2)
10% (40 - 30) of maximum marks = 8
Maximum marks = 80
Passing marks = 30% of 80 + 6 or 40% of 80 - 2 = 30

Each box contains 114 non-defective bulbs.
∴ 2000/114 = 17.54
So, the company has to purchase a minimum of 18 boxes to meet its requirement of bulbs.

Let 'x' be the salary and 0.6x be the expenses.
In April, the expenses increase by 10% and become 0.66x.
So, the savings decrease by 0.06x, and it is equal to 120.
Therefore, 0.06x = 120
⇒ x = $2000

Let the number be k.
Original answer should be 0.28k.
Her answer is 0.82k.
Difference = 0.54k
It is given as 540.
k = 1000
Actual answer = 0.28k = 280

Let the total money be Rs. x.
Money lost 


Thus, total money = Rs. 800

Let the original price of a candy be p dollars.
Let the number of candies originally be bought be n.
np = 10 ... (i)
New price of a candy = 0.80p
0.80p(n + 5) = 10
Or 0.80pn + 4p = 10 ... (ii)
Putting the value of pn from (i) into (ii), we get 8 + 4p = 10
Or p = 0.5
0.80p = 0.80 × 0.50 = 0.40
Thus, the original price was 50 cents, and the new price is 40 cents.
Thus, answer option 2 is correct.

It can be clearly seen that 40% of 400 = 160 is the highest number.

25% of x = 30% of 5000 or 0.25x = 1500 = 6000

Check the options. If you check with Option d = 90, you get → 108 – 20% of 90 = 108 – 18 = 90. This matches the given requirement and hence Option (d) is the correct answer.

The following PCG will give the answer:

Hence, the percentage reduction required is 33.33% (50/150).

If Shyam has inadvertently increased his height by 25% the correction he would need to make to go back to his original height would be to reduce the stated height by 20%.

Let the number be 100. Then, 200 should be the correct outcome. But instead the value got is 50. Change in value = 200 – 50 = 150. The percentage change in the value = 150 ¥ 100/200 = 75%. Alternately, you could think of this as the number being ‘x’ and the required result being 2x and the derived result being 0.5x. Hence, the percentage change in the result is 1.5x ¥ 100/2x. Clearly, the value would be 75%. (Note: In this case, the percentage change in the answer does not depend on the value of ‘x’).

From the first statement we get that out of 100 litres of the mixture, 25 litres must be milk. Since, we are adding water to this and keeping the milk constant, it is quite evident that 25 litres of milk should correspond to 20% of the total mixture. Thus, the amount in the total mixture must be 125, which means we need to add 25 litres of water to make 100 litres of the mixture.