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Test: Oxidation Number in Redox Reaction - NEET MCQ


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19 Questions MCQ Test - Test: Oxidation Number in Redox Reaction

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Test: Oxidation Number in Redox Reaction - Question 1

Direction (Q. Nos. 1-12) This section contains 12 multiple-choice questions. Each question has four
choices (a), (b), (c) and (d), out of which ONLY ONE option is correct.

Consider the following reactions.
I. Zn + dil. H2So4 → ZnSO4 + H2
II. Zn + conc. H2SO4 → ZnSO4 + SO4 + H2O
III. Zn + HNO3 → Zn(NO3)2 + H2O + NH4NO3

Q.  Oxidation number of H changes in: 

Detailed Solution for Test: Oxidation Number in Redox Reaction - Question 1



Test: Oxidation Number in Redox Reaction - Question 2

In which case change of oxidation number of V is maximum? 

Detailed Solution for Test: Oxidation Number in Redox Reaction - Question 2



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Test: Oxidation Number in Redox Reaction - Question 3

In which of the following set of compounds oxidation number of oxygen is not (- 2)?

Detailed Solution for Test: Oxidation Number in Redox Reaction - Question 3


OF2 Fluorine is most electronegative atom with oxidation number = - 1
x - 2 = 0
x = + 2
H2O2   2 + 2x = 0 ⇒ x = - 1 

Test: Oxidation Number in Redox Reaction - Question 4

Which is chlorate (I) ion?

Detailed Solution for Test: Oxidation Number in Redox Reaction - Question 4
  • ClO3: A very reactive inorganic anion.
  • The term chlorate can also be used to describe any compound containing the chlorate ion, normally chlorate salts. 
  • Example: Potassium chlorate, KClO3
Test: Oxidation Number in Redox Reaction - Question 5

Which of the following is not an example of redox reaction?

Detailed Solution for Test: Oxidation Number in Redox Reaction - Question 5

a) BaCl2 + H2SO4 → BaSO4 + 2HCl is not a redox reaction, as there is no change in the oxidation state of any element.
It is an example of double displacement reactions.

Test: Oxidation Number in Redox Reaction - Question 6

Which of the following atom has been assigned only single oxidation number?

Detailed Solution for Test: Oxidation Number in Redox Reaction - Question 6
  • Fluorine is the most electronegative element. It can gain one electron.​
    Thus, Oxidation number = -1
    F+ e- → F-
  • Due to very high (IE), it cannot lose electrons.

(a) H- (-1), (H+ (+1)
(b) O -2 in oxide, -1 in peroxide, and +2 in OF2
(c) +3 in N2O3, -3 in NH3, +3 in HNO2, +5 in HNO3, + 1 in N2O

Test: Oxidation Number in Redox Reaction - Question 7

The oxidation number of P in Ba(H2PO2)2, Ba(H2PO3)2 and Ba(H2PO4)2 are respectively

Detailed Solution for Test: Oxidation Number in Redox Reaction - Question 7



Test: Oxidation Number in Redox Reaction - Question 8

the oxidation number of sulphur in S8,S2F2,H2S respectively are

Detailed Solution for Test: Oxidation Number in Redox Reaction - Question 8

(i) Oxidation state of element in its free state is zero.

(ii) Sum of oxidation states of all atoms in compound is zero.

O.N of S in S8=0;    O.N of S in S2F2=+1

O.N of S in H2S=-2

Test: Oxidation Number in Redox Reaction - Question 9

In which of the following reactions oxidation number of chromium has been affected?

Detailed Solution for Test: Oxidation Number in Redox Reaction - Question 9


Oxidation number of Cr changes from +6 to +3.

Test: Oxidation Number in Redox Reaction - Question 10

Prussian blue is represented by KFex[Fe(CN)6]. Value of x is

Detailed Solution for Test: Oxidation Number in Redox Reaction - Question 10

Test: Oxidation Number in Redox Reaction - Question 11

In the following reaction, , oxidation number of

Detailed Solution for Test: Oxidation Number in Redox Reaction - Question 11

In NH4NO2, the oxidation number of N in NH4+ is -3, and of N in NO2- is +3. 

Test: Oxidation Number in Redox Reaction - Question 12

Select the set of compounds having fractional oxidation number in one or more atoms.

Detailed Solution for Test: Oxidation Number in Redox Reaction - Question 12

*Multiple options can be correct
Test: Oxidation Number in Redox Reaction - Question 13

Direction (Q. Nos. 13 and  14) This section contains 2 multiple choice questions. Each question has four choices (a), (b), (c) and (d), out of which ONE or  MORE THANT ONE  is correct.

Q. Which of the following species has/have oxidation number of the metal as + 6 ?

Detailed Solution for Test: Oxidation Number in Redox Reaction - Question 13




Test: Oxidation Number in Redox Reaction - Question 14

Oxidation numbers of P in PO4−3, of S in SO42− and that of Cr in Cr2O72− are respectively,

Detailed Solution for Test: Oxidation Number in Redox Reaction - Question 14

The correct answer is option A
(I) xPO43−​ ⇒ x + 4 × (−2) = −3
                ⇒x = −3 + 8 = +5
                ⇒x = +5
Oxidation number of P = +5
(II) xSO42−​ ⇒ x + 4 × (−2) = −2
                ⇒x = −2 + 8
                  ⇒x = +6
Oxidation number of S=+6
(III) xCr2​O72− ​    ⇒2x + 7 × (−2) = −2
                        ⇒2x =−2+14
                        ⇒2x=12
                        ⇒x= 12/2​ = +6

*Multiple options can be correct
Test: Oxidation Number in Redox Reaction - Question 15

Direction (Q. Nos. 15-16) This section contains  a paragraph, wach describing theory, experiments, data etc. three Questions related to paragraph have been given.Each question have only one correct answer among the four given options (a),(b),(c),(d)

The complex [Fe(H2O)5NO]2+ is formed in the ring-test for nitrate ion when freshly prepared FeSO4 solution is added to aqueous solution of followed by the addition of conc. H2SO4. NO exists as NO(nitrosyl).

Q.Oxidation number of the Fe in the ring is

Detailed Solution for Test: Oxidation Number in Redox Reaction - Question 15

Let, oxidation number of Fe = x

*Multiple options can be correct
Test: Oxidation Number in Redox Reaction - Question 16

The complex [Fe(H2O)5NO]2+ is formed in the ring-test for nitrate ion when freshly prepared FeSO4 solution is added to aqueous solution of followed by the addition of conc. H2SO4. NO exists as NO(nitrosyl).

Q. Magnetic moment  of Fe in the ring is 

Detailed Solution for Test: Oxidation Number in Redox Reaction - Question 16

Fe2+ is added asFeSO4
Fe+ is formed by charge transfer from NO to Fe2+ 



Fe+ has three unpaired electrons (N).

Test: Oxidation Number in Redox Reaction - Question 17

Direction (Q. Nos. 17) Choice the correct combination of elements and column I and coloumn II are given as option (a), (b), (c) and (d), out of which ONE option is correct.

Match the compounds/ions having underlined atoms of different oxidation number (in Column I) with values (in Column II).



Detailed Solution for Test: Oxidation Number in Redox Reaction - Question 17

(i) CaOCI2 has



Oxidation number = + 6
Oxidation number = - 2
(ii) → (p,u)


(iii) → (q.v)


*Answer can only contain numeric values
Test: Oxidation Number in Redox Reaction - Question 18

Direction (Q. Nos. 18 and 19) This section contains 2 questions. when worked out will result in an integer from 0 to 9 (both inclusive)

Q.   S2O32- has two types of sulphur atoms. What is the difference in the oxidation states of two types of sulphur atoms?


Detailed Solution for Test: Oxidation Number in Redox Reaction - Question 18

 The two sulfur atoms of thiosulfate exist in the oxidation state of sulfate (+6) and sulfide (−2) and do not change their respective oxidation states upon disproportionation.  

So difference in the oxidation states of two types of sulphur atoms will be

= (+6)- (-2) 

= +8

                                              

Test: Oxidation Number in Redox Reaction - Question 19

The difference in the oxidation number of the two types of sulphur atoms in Na2S4O6 is _________. [HTJEE2011]

Detailed Solution for Test: Oxidation Number in Redox Reaction - Question 19

the difference of oxidation states of two S is 5−0 = 5

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