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Test: Oxidation Reduction & Disproportionation Reactions - NEET MCQ


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23 Questions MCQ Test - Test: Oxidation Reduction & Disproportionation Reactions

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Test: Oxidation Reduction & Disproportionation Reactions - Question 1

Direction (Q. Nos. 1-18) This section contains 18 multiple choice questions. Each question has four
choices (a), (b), (c) and (d), out of which ONLY ONE option is correct.

Q. Oxidation can be defined as the terms

I. gain of electron and hydrogen
II. gain of oxygen and loss of electron
III. increase in oxidation number
IV. decrease in oxidation number

Select the correct terms

Detailed Solution for Test: Oxidation Reduction & Disproportionation Reactions - Question 1


Oxidation number increases, oxygen gained and loss of electrons is oxidation.

Test: Oxidation Reduction & Disproportionation Reactions - Question 2

Reduction is defined in terms of

I. electronation and hydrogenation
II. deelectronation and gain of oxygen
III. increase in oxidation number
IV. decrease in oxidation number

Select the correct terms

Detailed Solution for Test: Oxidation Reduction & Disproportionation Reactions - Question 2

 

  • Reduction involves gaining electrons or hydrogen.
  • It is characterized by a decrease in oxidation number.
  • Therefore, options I (electronation) and IV (decrease in oxidation number) are correct.

Options II (deelectronation and gain of oxygen) and III (increase in oxidation number) describe oxidation, not reduction.

 

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Test: Oxidation Reduction & Disproportionation Reactions - Question 3

In balancing the half-reaction, CN→ CNO-

The number of electrons that must be added is 

Detailed Solution for Test: Oxidation Reduction & Disproportionation Reactions - Question 3

CN→ CNO-
4+ x = -1      4+ x-2 = -1
∴ x = -5    ∴ x = -3   
Oxidation number increases. This is oxidation.

CN→ CNO- + 2e-

Test: Oxidation Reduction & Disproportionation Reactions - Question 4

Select the set of compounds with oxidation-reduction duality.

Detailed Solution for Test: Oxidation Reduction & Disproportionation Reactions - Question 4

Com pounds having oxidising and reducing nature in given reaction are said to have oxidation-reduction duality. Such compounds are said to undergo disproportionation reaction.




(This is called Cannizzaro reaction.)

Note Such compounds have O.N. of the affected atoms intermediate of oxidation part and reduction part

Test: Oxidation Reduction & Disproportionation Reactions - Question 5

In the following balanced reaction,

Detailed Solution for Test: Oxidation Reduction & Disproportionation Reactions - Question 5

If balanced, then to balance charge
x = - 1

Test: Oxidation Reduction & Disproportionation Reactions - Question 6

I reduces IO3- and I2 and itself oxidised to I2 in acidic medium. Thus, final reaction is

Detailed Solution for Test: Oxidation Reduction & Disproportionation Reactions - Question 6


To balance oxidation number, cross-multiply by change in oxidation number

Test: Oxidation Reduction & Disproportionation Reactions - Question 7

H2O can be oxidised to

Detailed Solution for Test: Oxidation Reduction & Disproportionation Reactions - Question 7


H is reduced to H2 and O is oxidised to O2.

Test: Oxidation Reduction & Disproportionation Reactions - Question 8

Consider the following reactions,

I. Zn + dil. H2SO4 → ZnSO4 + H2
II. Zn + conc. H2SO4 → ZnSO4+ SO2 + H2O

Oxidising agents in I and II are

        

Detailed Solution for Test: Oxidation Reduction & Disproportionation Reactions - Question 8


Test: Oxidation Reduction & Disproportionation Reactions - Question 9

In the following reactions except in one, oxygen is the reducing agent. Exceptional reaction is

Detailed Solution for Test: Oxidation Reduction & Disproportionation Reactions - Question 9


Ag+ is reduced to Ag by oxygen



Thus, except in (b), oxygen behaves as reducing agent.

Test: Oxidation Reduction & Disproportionation Reactions - Question 10

In the following reaction,

Which ions are not balanced?

Detailed Solution for Test: Oxidation Reduction & Disproportionation Reactions - Question 10



To balance electron  (II)  is to be multiplied by (3). Thus,

Test: Oxidation Reduction & Disproportionation Reactions - Question 11


Coefficient x, y and z are respectively 

Detailed Solution for Test: Oxidation Reduction & Disproportionation Reactions - Question 11


Cross -multiply by change in oxidation number and balance H by H+ ions.

Thus, x = 2, y = 5 and z = 6 

Test: Oxidation Reduction & Disproportionation Reactions - Question 12

Which of the following species does not show disproportionation reaction?

Detailed Solution for Test: Oxidation Reduction & Disproportionation Reactions - Question 12

Maximum oxidation number of Cl = + 7

Thus, species with + 7 oxidation number can be reduced but not oxidised.

Test: Oxidation Reduction & Disproportionation Reactions - Question 13

Which is the intramolecular oxidation-reduction reaction?

Detailed Solution for Test: Oxidation Reduction & Disproportionation Reactions - Question 13



Test: Oxidation Reduction & Disproportionation Reactions - Question 14

Consider the following experimental facts,

I. When Cl2 gas is passed into Kl solution containing CHCI3, violet colour appears in CHCI3 layer.
II. When Cl2 gas is passed into KBr solution containing CHCI3, orange colour appears in CHCI3 layer.
III. When Cl2 gas is passed into a solution containing KBr, Kl and KCI, containing CHCI3, violet colour appears in CHCI3 layer.

Select the correct experimental facts.

Detailed Solution for Test: Oxidation Reduction & Disproportionation Reactions - Question 14

Oxidising power of F2 > CI2 > Br2 > l2


Thus, (II) is true.

In experiment (III), orange colour of Br2 does not appear, as it also oxidises Kl to l2. Hence , only violet colour appears in CHCI3 layer. Thus, (III) is also true.

Test: Oxidation Reduction & Disproportionation Reactions - Question 15

Based on the following reaction,

It can be concluded that

Detailed Solution for Test: Oxidation Reduction & Disproportionation Reactions - Question 15


Since, ΔG ° < 0, hence it is spontaneous in forward direction . Oxidation number of Xe decreases hence, it is an oxidising agent and oxidation number of F increases, hence it is a reducing agent.

Test: Oxidation Reduction & Disproportionation Reactions - Question 16

For the redox reaction,

x, y and z are 

Detailed Solution for Test: Oxidation Reduction & Disproportionation Reactions - Question 16


To balance a redox reaction , balance effected atoms

II. Take oxidation number of two Cr-atom

Take total (oxidation number) of each atom (oxidised, re duced ) cross - multiply by change in oxidation number and add
I x 6 + II x 1

Thus, x = 6
y = 1
z = 14

Test: Oxidation Reduction & Disproportionation Reactions - Question 17

In the following conversion of chromite into soluble chromium salt
4Fe(CrO2)2+ 8Na2CO3 + 7O2 --> 2Fe2O3 + 8Na2CrO4 + 8CO2 

There is 

Detailed Solution for Test: Oxidation Reduction & Disproportionation Reactions - Question 17


Fe 2+ and Cr3+ are oxidised (increase in oxidation number)
O2, is reduced .

Test: Oxidation Reduction & Disproportionation Reactions - Question 18

In which of the following reactions H2O2 acts as a reducing agent?




Detailed Solution for Test: Oxidation Reduction & Disproportionation Reactions - Question 18

A species which is oxidised (deelectronation) is a reducing agent.

Thus, (ii) and (iv) represent reducing behaviour of H2O2.

*Multiple options can be correct
Test: Oxidation Reduction & Disproportionation Reactions - Question 19

Consider the following reaction,

Detailed Solution for Test: Oxidation Reduction & Disproportionation Reactions - Question 19



Both elements are present in the same substance . Such reaction is called intramolecular redox reaction.

*Multiple options can be correct
Test: Oxidation Reduction & Disproportionation Reactions - Question 20

Following reaction,   is an example of

Detailed Solution for Test: Oxidation Reduction & Disproportionation Reactions - Question 20

(a) Zn is oxidised to Zn2+ in complex

(b) Au+ is reduced to Au — True
(c) Au (s) is displaced
(d) Since, it is a spontaneous reaction ΔG° < 0

*Multiple options can be correct
Test: Oxidation Reduction & Disproportionation Reactions - Question 21

Select the correct statement(s).

Detailed Solution for Test: Oxidation Reduction & Disproportionation Reactions - Question 21


Carbon is reducing agent (R) and oxygen is oxidising agent (O). CO with oxidation number of C (= + 2) is formed.
(R) is inexcess hence, product of lower (oxidation number) is formed.
Thus, (a) is correct.

(O) is in excess hence product of higher oxidation number is formed. Thus, (b) is also correct.

*Multiple options can be correct
Test: Oxidation Reduction & Disproportionation Reactions - Question 22

For the reaction, 

The correct statement(s) in the balanced equation is/are

[JEE Advanced 2014]

Detailed Solution for Test: Oxidation Reduction & Disproportionation Reactions - Question 22

*Multiple options can be correct
Test: Oxidation Reduction & Disproportionation Reactions - Question 23

Identify intramolecular oxidation-reduction reaction.

Detailed Solution for Test: Oxidation Reduction & Disproportionation Reactions - Question 23





In all of the above reactions, oxidised and reduced part are in same species, hence, intramolecular redox reactions.

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