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Test: Enthalpy of Combustion - NEET MCQ


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17 Questions MCQ Test - Test: Enthalpy of Combustion

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Test: Enthalpy of Combustion - Question 1

Direction (Q. Nos. 1-11) This section contains 11 multiple choice questions. Each question has four choices (a), (b), (c) and (d), out of which ONLY ONE option is correct.

Q. Calorific value of H2 is - 143 kJ g-1.Thus, ΔfH° of H2O is

Detailed Solution for Test: Enthalpy of Combustion - Question 1

Calorific value is given for 1 gram and enthalpy of formation is defined for one mole of substance formed so for one mole of water formed we need two gram of hydrogen so the enthalpy of formation of H2O will be 2×Calorific value. Or 2×(-143) = -286 kJ/ mol

Test: Enthalpy of Combustion - Question 2

In the complete combustion of C2H6, 54 g of H2O is formed and 370 kcal of heat is evolved. Thus, ΔCH° of C2H6 is

Detailed Solution for Test: Enthalpy of Combustion - Question 2

54 gram of water is formed or three moles of water is formed.
C2H6 + (7/2)O2 → 2CO2 + 3H2O
So it indicates that only one mole of C2H6 is used in the combustion so the heat released is itself the value of heat of combustion of Ethane.

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Test: Enthalpy of Combustion - Question 3

The enthalpy of combustion of methane, graphite and dihydrogen at 298 K are - 890.3 kJ mol-1, - 393.5 kJ mol-1 and - 285.8 kJ mol-1 respectively. Enthalpy of formation of CH4(g) will be

Detailed Solution for Test: Enthalpy of Combustion - Question 3


Test: Enthalpy of Combustion - Question 4

The reaction of cyanamide, NH2CN (s) was carried out in a bomb calorimeter, and ΔU was found to be - 742.7 kJ mol-1 at 298 K. Thus, ΔrH° at 298 K for

Detailed Solution for Test: Enthalpy of Combustion - Question 4

Test: Enthalpy of Combustion - Question 5

Based on the following thermochemical reactions at 298 K and 1 bar

Q. Enthalpy of vaporisation of H2O (l) is 

Detailed Solution for Test: Enthalpy of Combustion - Question 5

Enthalpy of vaporization is defined for a substance when one mole of the substance is converted into the gaseous state. To obtain the enthalpy of vaporization of H2O liquid we will add reaction 1 and reaction 2 and then divide the enthalpy of x to since we need to calculate the enthalpy of vaporization for single mole of H2O

Test: Enthalpy of Combustion - Question 6

For the following combustion reaction of benzoic acid at 298 K

Q. Thus enthalpy of combustion ΔCH° at 298 K is

Test: Enthalpy of Combustion - Question 7

The standard enthalpies of formation of CO2(g), H2O (l) and glucose (s) at 25°C are - 400 kJ mol-1, - 300 kJ mol-1 and - 1300 kJ mol-1 respectively. The standard enthalpy of combustion per gram of glucose at 25°C is

[JEE Advanced 2013]

Detailed Solution for Test: Enthalpy of Combustion - Question 7

Test: Enthalpy of Combustion - Question 8

For the complete combustion of ethanol,

the amount of heat produced as measured in bomb calorimeter is 1364.47 kJ mol-1 at 25°C. Assuming ideality, the enthalpy of combustion, ΔCH° for the reaction Will be (R = 8.314 JK-1 mol-1)

[JEE Main 2014]

Detailed Solution for Test: Enthalpy of Combustion - Question 8

∆H = ∆E + ∆ngRT
∆E = -1364.47 kJ mol-1 and T = 298 K
∆ng = 2-3 = -1
∆H = -1364.47 -1(8.314)289/1000 = -1366.95 kJ mol-1

Test: Enthalpy of Combustion - Question 9

Given, 

Q. Thus, ΔfH° of (C6H6) (l) is

Detailed Solution for Test: Enthalpy of Combustion - Question 9

C6H6(l) + 15/2O2(g) → 6CO2(g) + 3H2O(l)
∆Hr = (∆Hc)C6H6 ⇒-3261  = ∑Hproduct - ∑Hreactant = 6(-393.5) -3(-283.83) - ∆fHC6H6
∆Hf = 48 kJ mol-1

Test: Enthalpy of Combustion - Question 10

ΔfU° of formation of CH4(g) at a certain temperature is - 393 kJ mol-1. The value of ΔfH° is

Detailed Solution for Test: Enthalpy of Combustion - Question 10

The balanced equation for combustion of methane is:
CH4(g)+2O2(g)→CO2(g)+2H2O(l)Here, Δng=1−3=−2
ΔH0=ΔU0+ΔngRT
ΔH=−393−2RT
∴ΔH0<ΔU0

Test: Enthalpy of Combustion - Question 11

Heat of combustion of H2(g) is - 58 kcal mol-1 at 298 K and constant pressure.

Q. Temperature of a hydrogen-oxygen flame if H2(g) is used as fuel is 

Test: Enthalpy of Combustion - Question 12

Direction (Q. Nos. 12-15) This section contains a paragraph, wach describing  theory, experiments, data etc. three Questions related to paragraph have been  given.Each question have only one correct answer among the four given  ptions  (a),(b),(c),(d).

Passage I

Octane (C8H18), a primary constituent of gasoline, burns in air

A 1.00 g sample of octane is burned in a constant volume calorimeter containing 1.20 kg of water. The temperature of water and the bomb rises by 8.2 K. The heat capacity of the bomb is 837.0 JK-1. Molar heat capacity of water is 4.184 J g-1 K-1. Initial temperature is 298 K.

 

Q. ΔCU° (per mol of C8H18) is

Detailed Solution for Test: Enthalpy of Combustion - Question 12

Test: Enthalpy of Combustion - Question 13

Passage I

Octane (C8H18), a primary constituent of gasoline, burns in air

A 1.00 g sample of octane is burned in a constant volume calorimeter containing 1.20 kg of water. The temperature of water and the bomb rises by 8.2 K. The heat capacity of the bomb is 837.0 JK-1. Molar heat capacity of water is 4.184 J g-1 K-1. Initial temperature is 298 K.

 

Q. ΔCH° (per mol of C8H18) is

Test: Enthalpy of Combustion - Question 14

Passage II

Heat of combustion of sucrose under standard state is - 5640 kJ mol-1. A healthy person takes 20 breaths per minute, and each breath consumer 480 mL of air. Inhaled and exhaled air contains 20% and 15% of oxygen by volume.

 

Q. If oxygen retained in the body is used in the combustion of sucrose, number of moles of sucrose combusted per day is

Test: Enthalpy of Combustion - Question 15

Passage II

Heat of combustion of sucrose under standard state is - 5640 kJ mol-1. A healthy person takes 20 breaths per minute, and each breath consumer 480 mL of air. Inhaled and exhaled air contains 20% and 15% of oxygen by volume.

 

Q. Heat evolved as a result of combustion of sucrose is

*Answer can only contain numeric values
Test: Enthalpy of Combustion - Question 16

Direction (Q. Nos. 16 and 17) This section contains 2 questions. when worked out will result in an integer from 0 to 9 (both inclusive).

Q. Given, ΔfH° of the following in kJ mol-1.

Determine the ratio taking derived values per unit volume of fuel


*Answer can only contain numeric values
Test: Enthalpy of Combustion - Question 17

ΔCH° (cyclopropane) = - 2091.97 kJ mol-1
ΔCH° (propene) = - 2058.32 kJ mol-1

Q. What is ΔrH° (in kcal) propenecyclopropane?


Detailed Solution for Test: Enthalpy of Combustion - Question 17

Cyclopropane + O2 → CO2(g) + H2O(l)  ΔCH°(cyclopropane) = -2091.97 kJmol-1 -----(i)
Propene + O2 → CO2(g) + H2O(l)  ΔCH°(propene) = -2058.32 kJmol-1 -----(ii)
On (ii)-(i), we get 
Propene → Cyclopropane     ∆H = 33.65 kJ ml-1
1 cal = 4.18 J
So, we have 33.65/4.18 = 8 kcal

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