Practice Test: Quantitative Aptitude - 14 - SSC CGL MCQ

As we know share of marks will be proportional to share of angles in pie chart 
Hence Difference of marks in physics and chemistry is proportional to 15
and difference of marks in chemistry and social science is also proportional to 15 too.
So answer will be D

Clearly, in the year 2007, maximum production of 100 mil tonnes is observed.
While in the year 2008, minimum production of 40 mil tonnes is observed.
Hence, the ratio is 100 : 40 = 5 : 2

A : B = 2 : 3

B : C = 4 : 5

A : B : C = 8 : 12 : 15

amount received by A = 8/(8 + 12 + 15) * 700 = 160/-

amount received by B = 12/(8 + 12 + 15) * 700 = 240/-

amount received by C = 15/(8 + 12 + 15) * 700 = 300/-

so the answer is option B.

let A', B', C' are the midpoints of AC, BC, AB.

areas of all 4 small triangles are same, let it be x.

area of quadrilateral AA'B'B = 3x

area of ABC = 4x

RATIO = 3x : 4x
= 3 : 4

so the answer is option C.

Let's say we added x cc of water.
According to previous ratio amount of water in mixture is 240 × 1/4​ = 60
So after adding amount of water = 60 + x
amount of glycerine = 240 × 3/4 = 180
Hence new ratio will be = 
or x will be 60.

Distance² = diff. of x cordinates² + diff. of y coordinates²
13² = x² + 5²
Hence x = ±12

A and B will do in 1 day, 1/12​ amount of work
B and C will do in 1 day, 1/15​ amount of work
Hence adding up above two equations
A + 2B + C will do in 1 day, 9/60 amount of work
as it is mentioned A = 2C (i.e. efficiency of A is twice of C)
So 2C + 2B + C will do in 1 day 9/60 amount of work
or 2(B+C) + C = 9/60
or C = 1/60​ (as B + C = 1/15)

So B alone will do work in 20 days.

Drum is 3/4​ full.
When 30 liters are drawn out of it, it becomes 1/2​ full.
Therefore 3/4 - 1/2​ of drum = 30
1/4 of drum = 30
Total capacity of drum = 30 × 4 = 120 litres

After cutting off squares of sides 4cm. from rectangular sheet of 40cm × 15cm and making a rectangular box 
New dimentions of rectangular will be:
Base = 32cm × 7cm
Height = 4 cm
Hence volume will be 32 × 7 × 4 = 896 cm³

Volume of water in time t to reach at 8 cm. height will be equal to volume of tank till height 8 cm.
hence volume of water in time t to reach at height 8 cm. = .3 × .2 × 2000/6 ​× (speed in per minute)
which is equal to volume of tank = 200 × 150 × 8/100​

equating both and after solving we will get t = 120 min.

Taking cosθ outside in numerator and in denominator and making tanθ
hence eq will be
As it is given that 5tanθ = 4
after putting values and solving we will get the equation reduced to 1/7.

For asin θ + bcos θ + c,

for  sin θ + cos θ , a = 1, b = 1, c = 0

so the answer is option B.

Similarly y = sinθcosθ
x² + y² + 3 = (sec²θ + cosec²θ)
Now putting above values in given equation, and after solving it will be reduced to 1

Expression: sin² 22° + sin² 68° + cot² 30°

We know that sin(90° − θ) = cosθ

=> sin22° = sin(90° − 68°) = cos68°

=> cos²68° + sin²68° + (√3​)²

=> 1 + 3 = 4

Euler's polyhedral formula states that the number of vertices V, faces F and edges E in a polyhedron satisfy:

V + F - E = 2

=> Ans - (B)

Initially, sum of ages of the jury = 200,
then man aged 35 resigns, sum of ages = 200 - 35
then man aged 25 joins, sum of ages = 200 - 35 + 25
Final number of members in the jury = 5
So, average age of the jury = (200 - 35 + 25)/5 = 38

Let's say son's age is x
hence father's present age will be 3x
after 15 years son's age will be x + 15 and father's age will be 3x + 15 and it is twice the age of son
so 3x + 15 = 2 (x + 15)
solve for x

=> 4.3 + 0.43 + 0.043 = 4.773

It is given that √6 × √15 = x×√10

√6 × √15 = √(3×2) × √(3 × 5) = √(9 × 10) = 3 √10

Hence x = 3

given that x + y = 15

So rearranging the above equation

(x - 10 ) + (y - 5) =0

Now , x - 10 = -(y - 5)

On cubing both sides
(x − 10)³ = - (y − 5)³
And hence
(x − 10)³ + (y − 5)³ = 0

We need to find value of 

= 0.519 ~ 0.52

It is given that


x = 16

it is given that a + 1/a = 1

and we need to find value of

= 1² - 2 = -1

It is given that 5% of √2x is 0.01

x = 0.02

For 3 * 5 put a = 3 and b = 5 in given equation
and for 5 * 3 put a = 5 and b = 3 in equation
now add both values