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Arithmetic Operation - GATE ECE Engineering (ECE) Digital Circuits Free


MCQ Practice Test & Solutions: Test: Arithmetic Operation (10 Questions)

You can prepare effectively for Electronics and Communication Engineering (ECE) Digital Circuits with this dedicated MCQ Practice Test (available with solutions) on the important topic of "Test: Arithmetic Operation". These 10 questions have been designed by the experts with the latest curriculum of Electronics and Communication Engineering (ECE) 2026, to help you master the concept.

Test Highlights:

  • - Format: Multiple Choice Questions (MCQ)
  • - Duration: 30 minutes
  • - Number of Questions: 10

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Test: Arithmetic Operation - Question 1

What is the addition of the binary numbers 11011011010 and 010100101?

Detailed Solution: Question 1

The rules for Binary Addition are :
0 + 0 = 0
0 + 1 = 1
1 + 0 = 1
1 + 1 = 0 (Carry 1)

Test: Arithmetic Operation - Question 2

Perform binary subtraction: 101111 – 010101 = ?

Detailed Solution: Question 2

The rules for Binary Subtraction are :
0 – 0 = 0
0 – 1 = 1 ( Borrow 1)
1 – 0 = 1
1 – 1 = 0

Test: Arithmetic Operation - Question 3

Perform multiplication of the binary numbers: 01001 × 01011 = ?

Detailed Solution: Question 3

The rules for binary multiplication are:
0 * 0 = 0
0 * 1 = 0
1 * 0 = 0
1 * 1 = 1

Therefore, 01001 × 01011 = 001100011.

Test: Arithmetic Operation - Question 4

On multiplication of (10.10) and (01.01), we get ____________

Detailed Solution: Question 4

The rules for binary multiplication are:
0 * 0 = 0
0 * 1 = 0
1 * 0 = 0
1 * 1 = 1

Therefore, 10.10 x 01.01 = 011.0010.

Test: Arithmetic Operation - Question 5

Divide the binary number (011010000) by (0101) and find the quotient.

Detailed Solution: Question 5


Therefore, the quotient of 011010000 ÷ 1001 = 101001.

Test: Arithmetic Operation - Question 6

Perform binary addition: 101101 + 011011 = ?

Detailed Solution: Question 6

The rules for Binary Addition are :
0 + 0 = 0
0 + 1 = 1
1 + 0 = 1
1 + 1 = 0 ( Carry 1)

Therefore, the addition of 101101 + 011011 = 1001000.

Test: Arithmetic Operation - Question 7

Binary subtraction of 100101 – 011110 is?

Detailed Solution: Question 7

The rules for Binary Subtraction are :
0 – 0 = 0
0 – 1 = 1 ( Borrow 1)
1 – 0 = 1
1 – 1 = 0

Therefore, The subtraction of 100101 – 011110 = 000111.

Test: Arithmetic Operation - Question 8

100101 × 0110 = ?

Detailed Solution: Question 8

The rules for binary multiplication are:
0 * 0 = 0
0 * 1 = 0
1 * 0 = 0
1 * 1 = 1

Therefore, 100101 x 0110 = 011011110.

Test: Arithmetic Operation - Question 9

Divide the binary numbers: 111101 ÷ 1001 and find the remainder.

Detailed Solution: Question 9

Binary Division is accomplished using long division method.

Therefore, the remainder of 111101 ÷ 1001 = 0111.

Test: Arithmetic Operation - Question 10

Binary subtraction of 101101 – 001011 = ?

Detailed Solution: Question 10

The rules for binary subtraction are:
0 – 0 = 0
0 – 1 = 1 ( Borrow 1)
1 – 0 = 1
1 – 1 = 0

Therefore, the subtraction of 101101 – 001011 = 100010.

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