Concept:
The conductivity for a doped semiconductor is obtained as:
σ = q n0 μn = q p0 μp
where,
ni = Intrinsic carrier concentration.
μn = electron mobility
μp = Hole mobility
When a semiconductor crystal is optically excited, one hole is created for every electron, i.e. electron-hole pass are created.
Application:
When the light is ON, excess electron and holes are generated in pairs, i.e.
Δp = Δn = 1016 cm3
Before Illumination:
NA = 1017 cm-3 and ni = 2.2 × 106 cm-3
Since NA ≫ ni, the excess hole concentration at thermal equilibrium will be:
p0 = NA = 1017 cm-3
The electron concentration using mass-action law is obtained as:
The electron concentration before illumination is negligible.
After illumination:
When an electron is generated optically, one hole is also created, i.e. they always occur in pairs.
∴ The excess hole concentration and excess electron concentration will be the same, i.e.
Δp = Δn = 1016 cm-3
Now, the electron and hole concentration after illumination will be:
n = n0 + Δn
n = 4.8 × 10-5 + 1016
n = 1016
Similarly,
p = p0 + Δp
p = 1017 + 1016 cm-3
p = 11 × 1016 cm-3
∴ the conductivity of the given sample when the light is ON will be:
σ = q(n0 + Δn)μn + q(p0 + Δp)μp
σ = q[(1016)μn + (11 × 1016)μp]
= (1.6 × 10-19) (1016 × 5300 + (11 × 1016) (230))
= 1.6 × 10-19 (5.3 × 1019 + 2.53 × 1019)
= 1.6 × (5.3 + 2.53)
σ = 12.528 (Ω-cm)-1