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GATE ECE (Electronics) Test: Differential Amplifiers Free Online Test 2026


MCQ Practice Test & Solutions: Test: Differential Amplifiers (10 Questions)

You can prepare effectively for Electronics and Communication Engineering (ECE) GATE ECE (Electronics) Mock Test Series 2027 with this dedicated MCQ Practice Test (available with solutions) on the important topic of "Test: Differential Amplifiers". These 10 questions have been designed by the experts with the latest curriculum of Electronics and Communication Engineering (ECE) 2026, to help you master the concept.

Test Highlights:

  • - Format: Multiple Choice Questions (MCQ)
  • - Duration: 30 minutes
  • - Number of Questions: 10

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Test: Differential Amplifiers - Question 1

For an amplifier, which parameter is calculated with Vs = 0?

Detailed Solution: Question 1

Concept:

VT & IT method:
Deactivate all the independent sources and do not disturb the dependent sources.
Rth = VT / IT

Deactivate source:
voltage source →  short circuit  i.e V = 0
current  source → open  circuit  i.e I = 0

Analysis:
While calculating Ro in the amplifier we apply VT  & IT method at the output.
Apply VT  & IT method to calculate R0
R0 = VT / IT While deactivating sources 
R0 is calculated when V0 is short circuit i.e  Vs = 0. 

Test: Differential Amplifiers - Question 2

When voltage gain Av is greater than 1, the voltage gain in dB is ______.

Detailed Solution: Question 2

Concept:
Voltage gain (Av):
Voltage gain (Av) is given as 

Av in dB is given as
AvdB = 20 log(Av)
Analysis:
AV dB = 20 log(Av
We know that for x >1, log(x) is always positive 
Therefore Av >1, log(Av) is always positive 
For  Av > 1
AvdB is positive

Test: Differential Amplifiers - Question 3

A signal that is applied with equal strength to both inputs of a differential amplifier or an operational amplifier

Detailed Solution: Question 3

Concept:
Common mode signal:

  • A common-mode signal is one that drives both inputs of a differential amplifier equally
  • The common-mode signal is interference, static and other kinds of undesirable pickup etc

Application:

  • The transistors in the differential amplifier are chosen to be closely matched
  • If both the transistors were matched in all respects then the balanced output would be theoretically zero
  • This is the important characteristic of a differential amplifier
  • It discriminates against common-mode input signals i.e. it refuses to amplify the common-mode signals

Test: Differential Amplifiers - Question 4

The negative feedback _______ input impedance of an amplifier.

Detailed Solution: Question 4

  • Negative feedback reduces the gain of the system by a factor of (1 + Aβ).
  • Thus, because of feedback configuration, voltage gain will be decreased by a factor (1 + Aβ).
  • Voltage series type feedback tells us that the input of the system is series connected with the feedback loop and series connection corresponds to increased impedance.
  • Therefore the input impedance will be increased by a factor (1 + Aβ).

Test: Differential Amplifiers - Question 5

Effect of cascading several amplifier stages is to

Detailed Solution: Question 5

Multistage amplifier:

  • In practical applications, the output of a single-stage amplifier is usually insufficient, though it is a voltage or power amplifier .hence they are replaced by multi-stage amplifiers.
  • In multi-stage amplifiers, the output of the first stage is coupled to the input of the next stage using a coupling device.
  • These coupling devices usually be a capacitor or a transformer, this process of joining two amplifier stages using a coupling device is called cascading
  • Now the overall gain is equal to the product of individual gains and hence the gain increases.
  • The frequency and bandwidth gets reduced.

Test: Differential Amplifiers - Question 6

An amplifier has a gain of 20 without feedback. If 10% of the output voltage is fed back by means of a resistance negative feedback circuit, the overall gain would be:

Detailed Solution: Question 6

Concept:
For the negative feedback amplifier, the closed-loop gain is given by:

For the positive feedback amplifier, the closed-loop gain is given by:

Where AOL is the open-loop gain
β is the gain of the feedback
Calculation:
The gain of feedback (β) = 10/100 = 0.1
Gain without feedback = 20
Gain with negative feedback:


⇒ 6.67
Gain with feedback = 6.67

Test: Differential Amplifiers - Question 7

In a common emitter amplifier the unbypassed emitter resistance provides:

Detailed Solution: Question 7

CE amplifier with unbypassed emitter resistance:

Performance parameters:

  • Lower voltage gain which provides better bias stabilization.
  • It works as a current series feedback network.
  • Input impedance increases.
  • Provide linear (undistorted) operation for larger input signals.

Test: Differential Amplifiers - Question 8

Which of the following characteristics is NOT desirable for the DC amplifier?

Detailed Solution: Question 8

An op-amp has the following characteristics:

  • Input impedance (Differential or Common-mode) = very high (ideally infinity)
  • Output impedance (open loop) = very low (Ideally zero)
  • Voltage gain = very high (ideally infinity)
  • Common-mode voltage gain = very low (ideally zero), i.e. Vout = 0 (ideally), when both the inputs are at the same voltage, i.e. (zero "offset voltage")
  • Output can change instantaneously (Infinite Slew Rate)
  • The purpose of bias current is to achieve the ideal behavior in op-amp which is high CMRR, high differential gain, and high input impedance

Test: Differential Amplifiers - Question 9

In the figure shown below, what is the expected power level at the input to the receiver?

Detailed Solution: Question 9

Concept:
Expected power level = Input power – Losses + Total Gain
Note: In dB, the gains are simply added.
To convert dBm to dBW and vice-versa:
P(dBm) = P(dBW) + 30
Calculation:
Given:
Input Power = -10 dBm
- 10 = P + 30
Input power = -40 dBW
Net losses = – 2 – 3 – 5 = –10 dBW
Net Gain = 20 + 30 = 50 dBW
Expected power level  will be:
= –40 – (2) + 30 – (3) + 20 – 5 = 0 dBW
P(dBm) = 0 + 30 
∴ 30 dBm will be the correct answer.

Test: Differential Amplifiers - Question 10

In an ideal CC amplifier circuit, output voltage is_______ its input voltage.

Detailed Solution: Question 10

Concept:
Ideal common collector (CC) amplifier: cc amplifier is also known as 
(1) unity gain amplifier (AV≈ 1)
(2) voltage follower
(3) voltage-Buffer
(4) Impedance matching
Analysis:
In an ideal cc amplifier voltage gain is 1

Vo = Vi

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