Test: Oxidation State of central metal ions - Chemistry MCQ

x + 6 X 0 = + 3
x = + 3
Hence, the oxidation state of vanadium in [V (H₂O)₆] ³⁺ is + 3.
(The neutral molecule water has no overall oxidation state, and so vanadium's oxidation state is simply the charge on the ion.)

x + 6 X 0 = + 2
x = + 2
Hence, the oxidation state of iron in [Fe(H₂O)₆] ²⁺ is + 2.

All of the these

Explanation: The oxidation number of an element provides important information:

• It tells us the charge on the central metal atom in coordination compounds.
• It indicates the number of electrons gained, lost, or shared during a chemical reaction.
• It reflects the degree of oxidation of an element in a compound or ion.

To understand it better, first, we will calculate the oxidation state of HCl, HClO₄, and KClO₃.
The oxidation state of chlorine in HCl will be
1 + x = 0
x = – 1
The oxidation state of chlorine in HClO4 will be:
1 + x + 4 X ( -2) = 0
1 + x – 8 = 0
x – 7 = 0
x = + 7
The oxidation state of chlorine in KClO3 will be
1 + x + 3 X ( -2 ) = 0
1 + x – 6 = 0
x = + 5
Hence the oxidation state of chlorine is maximum in HClO4, i.e. equivalent to + 7.

x + 5 X 0 = 0
x = 0
Hence, the oxidation state of iron in Fe(CO)₅ is zero.

x + 6 X – 1 = – 2
x – 6 = – 2
x = 6 – 2
x = + 4
Hence, the oxidation state of cobalt in [CoCl₆]^2- is + 4.

x + 6 X – 1 = – 2
x – 6 = – 2
x = 6 – 2
x = + 4
Hence, the oxidation state of platinum in [PtCl₆]^2- is + 4.

The oxidation state of an element tells us about the number of electrons gained, lost, or shared, i.e. degree of oxidation of an element.

The ozone molecule comprises three oxygen atoms bonded together in elemental form. Since no electrons are transferred in the atom’s elemental form, thus, the oxidation state of oxygen in the ozone is equivalent to zero.

1 X 2 + x + 4 X (- 2) = 0
2 + x – 8 = 0
x – 6 = 0
x = + 6
Hence, the oxidation state of chromium in K₂CrO₄ is + 6.