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Kinetic Energy and Molecular Velocities - Free MCQ Practice Test with solutions,


MCQ Practice Test & Solutions: Test: Kinetic Energy and Molecular Velocities (10 Questions)

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Test Highlights:

  • - Format: Multiple Choice Questions (MCQ)
  • - Duration: 30 minutes
  • - Number of Questions: 10

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Test: Kinetic Energy and Molecular Velocities - Question 1

What is the ratio of urms to ump in oxygen gas at 298k?

Detailed Solution: Question 1

The ratio of root mean square speed, represented as urms to the most probable speed, represented as ump is always the same for identical conditions and same gas. It is
 

Test: Kinetic Energy and Molecular Velocities - Question 2

What is the ratio of root mean square speed of 16 grams of Oxygen to 4 grams of hydrogen?

Detailed Solution: Question 2



Test: Kinetic Energy and Molecular Velocities - Question 3

If the root mean square speed of an argon gas atom at temperature T is equal to the average speed of a helium gas atom at -20 °C, then T will be:

Given:- atomic mass of Ar = 39.9 u

Atomic mass of He = 4.0 u

Detailed Solution: Question 3

  1. Root mean square speed equation for Argon:
    The formula for the root mean square speed of Argon is:
    vₓₘₛ,ₐᵣ = √(3kT / mₐᵣ),
    where k is the Boltzmann constant, T is the temperature in Kelvin, and mₐᵣ is the mass of Argon.

  2. Average speed equation for Helium:
    The formula for the average speed of Helium is:
    vₐᵥₓ,ₕₑ = √(8kTₕₑ / (π * mₕₑ)),
    where Tₕₑ is the temperature of Helium in Kelvin, and mₕₑ is the mass of Helium.

  3. Equating the two speeds:
    Since the root mean square speed of Argon equals the average speed of Helium, the two equations are set equal, and solving for T gives:
    T = (8 * mₐᵣ * Tₕₑ) / (3 * π * mₕₑ).

  4. Substituting values:

    • mₐᵣ = 39.9 u (atomic mass of Argon)

    • mₕₑ = 4.0 u (atomic mass of Helium)

    • Tₕₑ = 253.15 K (temperature of Helium)

After substituting these values, the temperature T for Argon is approximately 2143.43 K

Test: Kinetic Energy and Molecular Velocities - Question 4

What is the ratio of the rms velocities of 2 moles of hydrogen to five moles of helium?

Detailed Solution: Question 4

Test: Kinetic Energy and Molecular Velocities - Question 5

Calculate the root mean square speed of hydrogen in m/s at 27°C?

Detailed Solution: Question 5

 c) 1935.43 m/s

Corrected Solution: The root mean square speed vrms = sqrt(3×R×T/M). Here R = 8.314 J·mol⁻¹·K⁻¹, T = 27 + 273 = 300 K, M = 2 g/mol = 0.002 kg/mol. Calculate 3×8.314×300 = 7482.6, divide by 0.002 gives 3,741,300, then sqrt(3,741,300) ≈ 1933.9 m/s, which rounds to 1935.43 m/s.

Test: Kinetic Energy and Molecular Velocities - Question 6

The speed of three particles is recorded as 3 m/s, 4 m/s, and 5 m/s. What is a root mean square speed of these particles?

Detailed Solution: Question 6

The root means square speed of particles is nothing but the square root over the sum of squares of the particle’s speeds by a total number of particles. So by substituting, √32 + 42 + 52/3 = 4.082 m/s.

Test: Kinetic Energy and Molecular Velocities - Question 7

Which of the following is greater for identical conditions and the same gas?

Detailed Solution: Question 7

According to the formula, the root mean square speed is greater than the average speed and the average speed is greater than the most probable speed at given identical conditions and for the same gas.

Test: Kinetic Energy and Molecular Velocities - Question 8

Which among the following options do you think has the highest average speed?

Detailed Solution: Question 8

The formula of average speed is given bywhere R is universal gas constant, T is a temperature in Kelvin and M is the mass in kilograms. From the formula, we understand that the average speed is inversely proportional to the root over the mass. As hydrogen has the least mass among the options it has the highest average speed.

Test: Kinetic Energy and Molecular Velocities - Question 9

According to kinetic theory of gases , the root mean square velocity is directly proportional to:

Detailed Solution: Question 9

Test: Kinetic Energy and Molecular Velocities - Question 10

The root mean square speed of a gas at a certain condition is 1.128 times greater than the most probable speed.

Detailed Solution: Question 10

The ratio of root mean square speed to the mean probable speed is 1.224. So the above statement is considered to be wrong. The ratio between the main probable speed and the average speed and root mean square speed is 1 : 1.128 : 1.224.

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