Test: Control structures in C - Computer Science Engineering (CSE) MCQ

Expression value2%5 is equal to 0 and this value assigned to value1.
Therefore if condition reduces to if(0) so it fails.
Therefore body of if will not be executed i.e num = 5 will not be assigned.
So at printf num = 100 , value1 = 0 and value2 = 100.

When we give scanf() a "%f" format string, that means "We want you to try and get us a floating point number. When we provide input like 'xyz', it's not going to match anything, because 'xyz' is not a valid floating-point number.

As the value of variable value is zero so, it evaluates to false in the if condition.

When we give scanf() a "%f" format string, that means "We want you to try and get us a floating point number. When we provide input like 'xyz', it's not going to match anything, because 'xyz' is not a valid floating-point number.

1. Initial values:

   • a = 11
   • b = 5

2. Condition in if statement:

   • if(a=5) is an assignment, not a comparison. This assigns 5 to a, so a becomes 5. The condition if(a=5) evaluates to true (non-zero), so the code inside the if block executes, incrementing b by 1.
   • After if block: b = 6.

3. After if block:

   • a = 5
   • b = 6

4. printf statement:

   • ++a increments a before its value is used, so ++a becomes 6.
   • b++ uses the current value of b (which is 6), then increments b after its value is used.
   • Therefore, b++ results in 6, and b becomes 7 after the statement.

5. Output:

   • ++a results in 6
   • b++ results in 6

So, the output of the program is:

3. 6 6

1. Initial declaration:

   • int i = 10; declares and initializes i to 10.
   • The first printf statement prints i as 10.

2. Inner block:

   • A new variable i is declared inside the block and initialized to 20. This i shadows the outer i.
   • The second printf statement prints the inner i as 20.
   • The statement i++; increments the inner i to 21.
   • The third printf statement prints the incremented inner i as 21.

3. After the inner block:

   • The control exits the inner block, and the inner i goes out of scope. The outer i is still 10.
   • The last printf statement prints the outer i as 10.

So, the output of the program is:

3. 10 20 21 10

for loop can be initialized outside of the loop. Since until -1 value of i remain a non-zero value and hence the condition is true up to -1. But when i is further increases its value becomes 0 and condition becomes false and loop stops there.

Note:In C any non-zero value(positive or negative) evaluates to true and only zero value is evaluates to false.

since this program isn't having any syntax error so program is executed. It is clearly seen that 99 is not divisible by 5. So if statement will not execute and program will terminate.

• The loop condition i < 10, j < 20 uses the comma operator, evaluating both i < 10 and j < 20. Only j < 20 is used, meaning the loop continues until j becomes 20.
• In each iteration, both i and j are incremented.
• The loop runs 20 times, printing i and j values from 0 to 19.
• After the loop ends, both i and j are 20.
  so correct option is c

.

compiler error switch expression is not integral. switch statement cannot work on float value.