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Test - 9 - SAT MCQ


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15 Questions MCQ Test - Test - 9

Test - 9 for SAT 2025 is part of SAT preparation. The Test - 9 questions and answers have been prepared according to the SAT exam syllabus.The Test - 9 MCQs are made for SAT 2025 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test - 9 below.
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Test - 9 - Question 1

Melvin, Chris, Enoch, Dave, Carey, Mike, Dan, and Peter are choosing dorm rooms for college. Each room holds four people. They have the following requirements:

I. Mike and Melvin refuse to live together.

II. Enoch will live with Chris or Carey (or possibly both).

III. If Dave and Dan live together, Peter will live with them.

When rooms are chosen, Melvin, Carey, and Dan live together. Which of the following groups must live in the other room?

Detailed Solution for Test - 9 - Question 1

Call the room shared by Melvin, Carey, and Dan room X, and the other room Y. Because Mike and Melvin won't live together, Mike must be in room Y. Now, if Dave and Dan live together, Peter will live with them, but you can't fit two more people into room X, so Dave and Dan must live apart, which puts Dave in room Y also. Similarly, because Enoch will live with Chris or Carey, Chris can't be in room X either, which puts Chris, Dave, and Mike in room Y.

Test - 9 - Question 2

In a set of five positive whole numbers, the mode is 90 and the average (arithmetic mean) is 80. Which of the following statements is false?

Detailed Solution for Test - 9 - Question 2

Take each statement one at a time. Choice (A) is true. The mode appears most often, which means the set has to have two, three, or four 90s. Choice (B) requires you to remember this formula: Total = Number × Mean. In this case, the five numbers must add up to 5 × 80 = 400. Because you know the set has at least two 90s, which add up to 180, the other three numbers must add up to 220. But because the numbers are all positive, you wouldn't have enough room for the last two numbers if 240 were in the set, which makes Choice (B) true. Choice (C) is false because making a list whose average is 80 without including any 80s in the list is easy. Try it yourself and see.

You could, of course, stop there (and you probably should, to save time, on the real test). But I want you to give you your money's worth, so I continue through the rest of the answer choices. Choice (D) is definitely true; you used this fact already when you checked Choice (A). In Choice (E), the median of an odd number of numbers is the middle number. So if the median were greater than 90, then three of the five numbers would have to be greater than 90. But you already know from Choice (A) that the set must include at least two 90s. You can't have a list with two 90s and three numbers greater than 90 and still have the average be 80. Thus, the median can't be greater than 90.

Test - 9 - Question 3

A bicycle has a front wheel radius of 18 inches. If the bicycle wheel travels 50 revolutions, approximately how many feet has the bicycle rolled?

Detailed Solution for Test - 9 - Question 3

Ah, yes, an SAT classic. Every time a wheel rotates, it covers the equivalent of one circumference of distance. The circumference equals 2πr, but you have to be careful about units. The wheel has a radius of 18 inches, but your answer needs to be in feet. The circumference is 2 × 18 × π inches = 36π inches = 3π feet = about 9.4248 feet. Therefore, 50 revolutions covers 50 × 9.4248 = 471 feet.

Test - 9 - Question 4

If 2a + 3b = 17 and 2a + b = 3, then a + b =

Detailed Solution for Test - 9 - Question 4

By adding the two expressions, you discover that 4a + 4b = 20, so a + b = 5. You can also solve for the variables to get a = -2 and b = 7, which gives you the same answer.

Test - 9 - Question 5

The number g is divisible by 3, but not by 9. Which of the following is a possible remainder when 7g is divided by 9?

Detailed Solution for Test - 9 - Question 5

Possible numbers for g are numbers like 3, 6, 12, 15, 21, and so on. If you try multiplying these numbers by 7 and then dividing by 9, you discover that the remainder is always 3 or 6. Because 3 isn't one of your choices, 6 is the right answer.

Test - 9 - Question 6

If ab = n, b + c = x, and n ≠ 0, which of the following must equal n?

Detailed Solution for Test - 9 - Question 6

Because b + c = x, b = x - c. So you can substitute (x - c) for b in the first equation, and write a(x - c) = n. Because of the parentheses, you have to use the distributive law to get ax - ac = n, which is Choice (C).

Test - 9 - Question 7

The number n satisfies the following properties:

I.It has three digits.

II.Its units digit is the sum of its tens digit and its hundreds digit.

III.It is a perfect square.

Which number could be n?

Detailed Solution for Test - 9 - Question 7

All the numbers have three digits. Only Choices (A), (D), and (E) have a units (ones) digit that equals the sum of the other two digits. And, using a calculator, you can see that the square roots of 156 and 516 are decimals, while the square root of 729 is 27, which makes it your answer.

Test - 9 - Question 8

Set S contains the numbers 20 to 40, inclusive. If a number is chosen at random from S, what is the probability that this number is even?

Detailed Solution for Test - 9 - Question 8

First off, you must realize that the set contains 21 numbers, not 20. Remember that to find the size of a list of numbers, you subtract the first and last numbers and then add one. (Count them if you don't believe me.) Now, the even numbers are 20, 22, . . . up to 40, which makes five numbers in the 20s, five in the 30s, and 40, which makes 11 numbers out of 21.

Test - 9 - Question 9

A certain radioactive element has a half-life of 20 years. Thus, a sample of 100 grams deposited in 1980 would have decayed to 50 grams by 2000 and to 25 grams by 2020. How much of this sample would remain in 2100?

Detailed Solution for Test - 9 - Question 9

The easiest way to solve this problem is to make a table, dividing by 2 every 20 years:

The final answer, 1.5625, is the same as 25/16.

Test - 9 - Question 10

Find x if 2(x + 4) = 6

Detailed Solution for Test - 9 - Question 10

As is the case with several math questions on the SAT, the best strategy here is to plug the answer choices into the equation given in the question. Lucky for you, the first answer, Choice (A), works in the equation, so you can stop right there. If you'd rather do algebra to solve this problem, though, start by distributing the 2, to get 2x + 8 = 6. Subtracting 8 from both sides gives you 2x = -2, and x = -1.

Test - 9 - Question 11

If an eight-slice pizza has a diameter of 12 inches, what is the area of one slice, in square inches?

Detailed Solution for Test - 9 - Question 11

The area of the pizza is πr2. The radius is 6, because the diameter is 12, and the area is 36π. Dividing by eight slices gives you 4.5π.

Test - 9 - Question 12

A square is changed into a rectangle by adding 3 meters to one side and subtracting 2 meters from the other side. The new rectangle has an area of 50 square meters. Find the original length of a side of the square.

Detailed Solution for Test - 9 - Question 12

As is often the case on the SAT, the trial-and-error method works great here. If you don't want to use trial and error, you can call the original side of the square x, making the rectangle's sides x + 3 and x - 2. Because the area is 50, you write (x + 3)(x - 2) = 50. Use the FOIL method to get x2 - 2x + 3x - 6 = 50, or x2 + x - 56 = 0. (Remember, to solve a quadratic equation, you must make one side equal zero.) You can factor this equation into (x + 8)(x - 7) = 0. This equation is true when x equals either -8 or 7, but it doesn't make sense for a square to have a side of -8. Therefore, 7 is your answer.

Test - 9 - Question 13

A number, n, is defined as a "tweener" if both n - 1 and n + 1 are prime. Which of the following numbers is a tweener?

Detailed Solution for Test - 9 - Question 13

Don't fall into the trap of thinking that 1 is prime. Two numbers, 1 and 0, are called -"special." Thus, 2 isn't a tweener because 2 - 1 = 1 and 1 isn't prime. The number 8 isn't a tweener, because 8 + 1 = 9 and 9 isn't prime, either. (It's 3 × 3.) But 30 is a tweener because 30 - 1 = 29, which is prime, and 30 + 1 = 31, which is also prime. After you've found the answer, you can move on to the next question; there's no need to check the last two options, which are wrong.

Test - 9 - Question 14

A batch of mixed nuts was created by adding 5 pounds of peanuts, costing $5.50 per pound, to 2 pounds of cashews, costing $12.50 per pound. What would be the cost, per pound, of the resulting mixture?

Detailed Solution for Test - 9 - Question 14

Five pounds of peanuts times $5.50 is $27.50, and two pounds of cashews times $12.50 is $25.00, so the total cost is $52.50 for seven pounds. $52.50 divided by 7 is $7.50.

Test - 9 - Question 15

If the square of x is 12 less than the product of x and 5, which of the following expressions could be used to solve for x?

Detailed Solution for Test - 9 - Question 15

Don't fall for the old "less than" trick. "Twelve less than something" is the thing minus 12 — not the other way around. So you want an expression that says "x squared is 5 times x minus 12," and (A) is the winner.

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