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NEET Practice Test - 5 - NEET MCQ


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30 Questions MCQ Test - NEET Practice Test - 5

NEET Practice Test - 5 for NEET 2024 is part of NEET preparation. The NEET Practice Test - 5 questions and answers have been prepared according to the NEET exam syllabus.The NEET Practice Test - 5 MCQs are made for NEET 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for NEET Practice Test - 5 below.
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NEET Practice Test - 5 - Question 1
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In a Wheatstone's bridge, three resistance P, Q and R connected in the three arms and the fourth arm is formed by two resistance S1 and S2 connected in parallel. The condition for bridge to be balanced will be

Detailed Solution for NEET Practice Test - 5 - Question 1
For balanced Wheatstone's bridge, P/Q = R/S

NEET Practice Test - 5 - Question 2
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If 13.6 eV energy is required to ionize the hydrogen atom, then the energy required to remove an electron from n = 2 is

Detailed Solution for NEET Practice Test - 5 - Question 2

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NEET Practice Test - 5 - Question 3
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In the experiment for the determination of the speed of sound in air using the resonance column method, the length of the air column that resonates in the fundamental mode, with a tuning fork is 0.1 m. When this length is changed to 0.35 m, the same tuning fork resonates with the first overtone. Calculate the end correction.

Detailed Solution for NEET Practice Test - 5 - Question 3

Let the end correction of given organ tube be e.

Fundamental frequency of first tube with end correction is given as,

where, l1 is original length of tube.

First overtone frequency of resonance tube with end correction is given as,

where, l2 is original length of second tube.

According to question, f1 = f2

NEET Practice Test - 5 - Question 4
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A uniformly wound solenoidal coil of self-inductance 1.8×10−4 H and resistance 6 Ω is broken up into two identical coils. These identical coils are then connected in parallel across a 15 V battery of negligible resistance. The steady-state current through the battery in ampere is
Detailed Solution for NEET Practice Test - 5 - Question 4
Inductance of the circuit

(in parallel)

Resistance of the circuit R = 3/2 = 1.5Ω(in parallel)

Therefore τL (time constant) L/R = 3⋅0 × 10−5s

Steady state current in the circuit through the battery

NEET Practice Test - 5 - Question 5
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A piece of metal weighs 45 g in air and 25 g in a liquid of density 1.5 x 103 kg-m-3 kept at 30°C. When the temperature of the liquid is raised to 40°C, the metal piece weighs 27 g. The density of liquid at 40°C is 1.25 x 103 kg-m-3. The coefficient of linear expansion of metal is
Detailed Solution for NEET Practice Test - 5 - Question 5
The volume of the metal at 30°C is

Similarly, volume of metal at 40°C is

= 14.40 cm3

= 8.03 x 10-3/ °C

Coefficient of linear expansion of the metal is

≈ 2.6 x 10-3/°C

NEET Practice Test - 5 - Question 6
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Two radioactive materials X1 and X2 have decay constants 10λ and λ respectively. If initially they have the same number of nuclei, then the ratio of the number of nuclei of X1 to that of X2 will be 1/e after time
Detailed Solution for NEET Practice Test - 5 - Question 6

⇒ t = 1/9λ

NEET Practice Test - 5 - Question 7
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A particle is released from rest from a tower of height 3h. The ratio of time taken to fall equal heights hh i.e., t1 : t2 : t3 is
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NEET Practice Test - 5 - Question 8
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An impulse J is applied on a ring of mass m along a line passing through its centre O. The ring is placed on a rough horizontal surface. The linear velocity of centre of ring once it starts rolling without slipping is
Detailed Solution for NEET Practice Test - 5 - Question 8
Let v be the velocity of COM of ring just

after the impulse is applied and v' its velocity when pure rolling starts. Angular velocity ω of the ring at this instant will be

ω = v’/r

From impulse = change in linear momentum

We have,

J = mv

v = J/m ...(1)

Between the two positions shown in the figure force of friction on the ring acts backwards. Angular momentum of the ring about the bottom most point will remain conserved.

∴ Li = Lf

mvr = mv' r + lω

NEET Practice Test - 5 - Question 9
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The rms value of the electric field of the light coming from the Sun is 720 N C−1. The average total energy density of the electromagnetic wave is
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NEET Practice Test - 5 - Question 10
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Three identical blocks of masses m = 2 kg are drawn by a force F = 10.2 N on a frictionless surface, then what is the tension (in N) in the string between the blocks B and C?
Detailed Solution for NEET Practice Test - 5 - Question 10

NEET Practice Test - 5 - Question 11
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A metallic square loop ABCD is moving in its own plane with velocity V in a uniform magnetic field perpendicular to its plane as shown in the figure. EMF is induced
Detailed Solution for NEET Practice Test - 5 - Question 11
Wire AB and DC are parallel to velocity. So, no emf will generate. while wire AD and BC are perpendicular to velocity and magnetic field so emf will be induced.
NEET Practice Test - 5 - Question 12
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What is the relation between the refractive indices μ1 and μ2? If the behaviour of light rays is as shown in the figure.
Detailed Solution for NEET Practice Test - 5 - Question 12
From first figure it is clear that

μ = μ2

From second figure it is clear that

μ < μ2

Therefore, μ1 < μ2

NEET Practice Test - 5 - Question 13
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In Young's double slit experiment, the 10th maximum of wavelength λ1 is at a distance of y1 from the central maximum. When the wavelength of the source is changed to λ2, 5th maximum is at a distance of y2 from its central maximum. The ratio y1/y2 is
Detailed Solution for NEET Practice Test - 5 - Question 13
Position of fringe from central maxima

Given, n = 10

For second source

NEET Practice Test - 5 - Question 14
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Young's modulus of steel is 19 × 1010 N/m2. Express it in dyne/cm2. Here dyne is the CGS unit of force.
Detailed Solution for NEET Practice Test - 5 - Question 14
The unit of Young's modulus is N/m2

This suggests that it has dimensions of

N/m2 is in SI units.

So, 1N/m2 = (1 kg) (1 m)-1 (1 s)-2

and 1 dyne/cm2 = (1 g) (1 cm)-1 (1 s)-2

or, 1 N/m2 = 10 dyne/cm2

or, 19 × 1010 N/m2 = 19 × 1011 dyne/cm2

NEET Practice Test - 5 - Question 15
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Ionisation potential of hydrogen atom is 13.6 eV. Hydrogen atoms in the ground state are excited by monochromatic radiation of photon energy 12.1 eV. The spectral lines emitted by hydrogen atoms according to Bohr's theory will be
Detailed Solution for NEET Practice Test - 5 - Question 15
Energy in excited state = −13.6 + 12.1 = −1.5 eV

Number of spectral lines

NEET Practice Test - 5 - Question 16
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The unit of permittivity of free space is
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NEET Practice Test - 5 - Question 17
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Choose the incorrect statement.
Detailed Solution for NEET Practice Test - 5 - Question 17
When the Gaussian surface encloses no charge, then the electric flux through that surface is zero. Electric field over the Gaussian surface need not be zero at every point on that surface.
NEET Practice Test - 5 - Question 18
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Three capacitors C1 = 3 μF, C2 = 6 μF and C3 = 12 μF are joined in series. This series combination is connected to a 14 volt source. The P.D across the plates of capacitor C2 is
Detailed Solution for NEET Practice Test - 5 - Question 18
Let CS is the effective capacitance.

Charge on C2 = Charge on CS

NEET Practice Test - 5 - Question 19
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In the circuit shown below, C1 = 3 μF ; C2 = 6 μF ; C3 = 6 μF ; C4 = 12 μF and C5 = 9 μF. The total energy stored in these five capacitors is
Detailed Solution for NEET Practice Test - 5 - Question 19
The Wheatstone bridge is in the balanced condition.

Ceff = 6 μF

Total energy stored,

NEET Practice Test - 5 - Question 20
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In the circuit shown, R1 = 10 Ω; R2 = 20 Ω; R3 = 30 Ω and R4 = 20 Ω. Potential difference between b and d (Vb - Vd) is
Detailed Solution for NEET Practice Test - 5 - Question 20

NEET Practice Test - 5 - Question 21
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For the circuit shown below, when the switch S is closed, then the total amount of charge that flows from point a to point b through the switch, is
Detailed Solution for NEET Practice Test - 5 - Question 21
Before switch S is closed, the charge on each of the 12 μF and 4 μF capacitors is

The current flowing through the 6 Ω and 3 Ω resistors is So P.D. across 6 Ω resistor = 6 V and P.D. across 3 Ω resistor = 3 V

Now, when the switch S is closed,

Charge on 4 μF capacitor is 4 x 3 = 12 μC and charge on 12 μF capacitor is 12 x 6 = 72 μC.

∴ Charge flowed from a to b through switch S is [(+72) - 12] = 60 μC

NEET Practice Test - 5 - Question 22
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In the infinite ladder network shown below, if R = 1.235 Ω, then the effective resistance between the points a and b (approximately) is (√5 = 2.235)
Detailed Solution for NEET Practice Test - 5 - Question 22
Let Re is the effective resistance between a and b. The equivalent circuit is

NEET Practice Test - 5 - Question 23
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In the circuit shown below, if the tap key K is pressed at time t = 0, then which of the following statements is false?
Detailed Solution for NEET Practice Test - 5 - Question 23
At time t = 0; capacitor offer zero opposition.

At time t = ∞, capacitor offers infinite opposition.

P.D. across 1000 Ω resistor = 2 x 10-3 x 1000 = 2 V

∴ Charge on 6 μF capacitor = 6 x 2 = 12 μC

NEET Practice Test - 5 - Question 24
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The electrostatic field lines
Detailed Solution for NEET Practice Test - 5 - Question 24
Electrostatic lines of force do not form closed loops, as electrostatic field is a conservative field.
NEET Practice Test - 5 - Question 25
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The electric field decreases most rapidly, with distance for
Detailed Solution for NEET Practice Test - 5 - Question 25
Electric field due to short dipole varies as

For point charge

For line charge

For large sheet E ∝ r°

NEET Practice Test - 5 - Question 26
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Eight identical spherical liquid drops each charged to potential of 2 volt. They coalesce to make one big spherical liquid drop, whose potential is
Detailed Solution for NEET Practice Test - 5 - Question 26
V' = n2l3V = 82/3 x 2 volt

= 4 x 2 volt

= 8 volt

NEET Practice Test - 5 - Question 27
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A uniform electric field of 50√2 Vm-1, exists in XY plane, making an angle of 45° with positive X axis as shown in below figure. The potential difference [VA - VB] is
Detailed Solution for NEET Practice Test - 5 - Question 27

= -300 volt

NEET Practice Test - 5 - Question 28
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A point charge Q is located at a distance R/2 From the centre of an uncharged conducting spherical shell as shown in below figure. The electric field at a distance 3R from the point charge is
Detailed Solution for NEET Practice Test - 5 - Question 28

The field at point P due to charge Q within the shell and charge induced on the inner surface of the shell is zero. The field at point P is only, due to the induced charge on the outer surface of shell.

NEET Practice Test - 5 - Question 29
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In the circuit shown, the effective resistance between the points a and b is
Detailed Solution for NEET Practice Test - 5 - Question 29
By symmetry, the given circuit can be drawn as

NEET Practice Test - 5 - Question 30
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In the circuit shown, the effective resistance between the points a and b is
Detailed Solution for NEET Practice Test - 5 - Question 30

By symmetry, currents through R1 and R4 must be same Also, currents through R2 and R3 must be same The loop equation for the left loop is

6i - 6i1 - 18i1 + 6i - 12i1 = 0

⇒ 12i = 36i1

⇒' = 3i1

Now Va - Vb = + 18(i1) + 6[i - i1] = 6i + 12i1

= 6i + 4i = 10i

But [Va - Vb] = i Reff

∴ Reff = 10 Ω

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