Civil Engineering (CE) Exam  >  Civil Engineering (CE) Tests  >  Test: Runge Kutta Method - Civil Engineering (CE) MCQ

Test: Runge Kutta Method - Civil Engineering (CE) MCQ


Test Description

5 Questions MCQ Test - Test: Runge Kutta Method

Test: Runge Kutta Method for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Test: Runge Kutta Method questions and answers have been prepared according to the Civil Engineering (CE) exam syllabus.The Test: Runge Kutta Method MCQs are made for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Runge Kutta Method below.
Solutions of Test: Runge Kutta Method questions in English are available as part of our course for Civil Engineering (CE) & Test: Runge Kutta Method solutions in Hindi for Civil Engineering (CE) course. Download more important topics, notes, lectures and mock test series for Civil Engineering (CE) Exam by signing up for free. Attempt Test: Runge Kutta Method | 5 questions in 15 minutes | Mock test for Civil Engineering (CE) preparation | Free important questions MCQ to study for Civil Engineering (CE) Exam | Download free PDF with solutions
Test: Runge Kutta Method - Question 1

If  and h = 0.2, then solving by fourth order Runge-Kutta method:

Detailed Solution for Test: Runge Kutta Method - Question 1

Range-Kutta method (R-K method):
To solve  with condition y(x0) = y0
Let 'h' denotes the interval between equidistant values of x, if the initial values are (x0 , y0), then the first increment in y is computed from the formula given by:
y1 = y0 + Δy
where Δy is the change in y given by

y0 is the intial value of y
y1 is the changed value of y
Calculation:
Given:



y1 = y0 + Δy
y1 = 1 + 0.1959 = 1.1959

Test: Runge Kutta Method - Question 2

Consider the first order initial value problem
y’ = y + 2x – x2, y(0) = 1, (0 ≤ x < ∞) with exact solution y(x) = x2 + ex. For x = 0.1, the percentage diference between the exact solution and the solution obtained using a single iteration of the second-order Runge Kutta method with step size h = 0.1 is

1 Crore+ students have signed up on EduRev. Have you? Download the App
Test: Runge Kutta Method - Question 3

A gradually varied flow profile can be governed by equation  where x is distance and y is the depth of water above the bed level. Which of the following methods can be used for solution?

Detailed Solution for Test: Runge Kutta Method - Question 3


As we can see from the above table, the method used for solving an ordinary differential equation is the Runge Kutta method, and the above-given equation, i.e,    for gradually varied flow profile is an ordinary differential equation. 
So, the Runge Kutta method can be used for finding the solution to the above equation.

Test: Runge Kutta Method - Question 4

Consider an ordinary differential equation  If x = xo at t = 0, the increment in x calculated using Runge Kutta fourth order multistep method with a step size of Δt = 0.2 is

Test: Runge Kutta Method - Question 5

Runge-Kutta fourth order method is used to solve the differential equation  If the initial value y(0) = 2 and step-size is 0.1, then the value of k1, k2, k3, and k4 respectively is?

Detailed Solution for Test: Runge Kutta Method - Question 5

Working rule to find increment k of y corresponding to an increment h of x by Runge-Kutta method from  is as follows:

Calculation:
Given:
 y(0) = 2 and step-size (h) = 0.1
Ranga-Kutta fourth order equation is given by:
y1=y0+k
where k = 1/6(k1+2k2+2k3+k4) and 

Information about Test: Runge Kutta Method Page
In this test you can find the Exam questions for Test: Runge Kutta Method solved & explained in the simplest way possible. Besides giving Questions and answers for Test: Runge Kutta Method, EduRev gives you an ample number of Online tests for practice

Top Courses for Civil Engineering (CE)

Download as PDF

Top Courses for Civil Engineering (CE)