Runge Kutta Method - Free MCQ Practice Test with solutions, GATE MA Engineering
MCQ Practice Test & Solutions: Test: Runge Kutta Method (5 Questions)
You can prepare effectively for Engineering Mathematics Engineering Mathematics with this dedicated MCQ Practice Test (available with solutions) on the important topic of "Test: Runge Kutta Method". These 5 questions have been designed by the experts with the latest curriculum of Engineering Mathematics 2026, to help you master the concept.
Test Highlights:
- - Format: Multiple Choice Questions (MCQ)
- - Duration: 15 minutes
- - Number of Questions: 5
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If 
and h = 0.2, then solving by fourth order Runge-Kutta method:
and h = 0.2, then solving by fourth order Runge-Kutta method:Detailed Solution: Question 1
with condition y(x0) = y0
Consider the first order initial value problem
y’ = y + 2x – x2, y(0) = 1, (0 ≤ x < ∞) with exact solution y(x) = x2 + ex. For x = 0.1, the percentage diference between the exact solution and the solution obtained using a single iteration of the second-order Runge Kutta method with step size h = 0.1 is
y’ = y + 2x – x2, y(0) = 1, (0 ≤ x < ∞) with exact solution y(x) = x2 + ex. For x = 0.1, the percentage diference between the exact solution and the solution obtained using a single iteration of the second-order Runge Kutta method with step size h = 0.1 is
A gradually varied flow profile can be governed by equation 
where x is distance and y is the depth of water above the bed level. Which of the following methods can be used for solution?
where x is distance and y is the depth of water above the bed level. Which of the following methods can be used for solution?Detailed Solution: Question 3
for gradually varied flow profile is an ordinary differential equation. Consider an ordinary differential equation 
If x = xo at t = 0, the increment in x calculated using Runge Kutta fourth order multistep method with a step size of Δt = 0.2 is
If x = xo at t = 0, the increment in x calculated using Runge Kutta fourth order multistep method with a step size of Δt = 0.2 isRunge-Kutta fourth order method is used to solve the differential equation 
If the initial value y(0) = 2 and step-size is 0.1, then the value of k1, k2, k3, and k4 respectively is?
If the initial value y(0) = 2 and step-size is 0.1, then the value of k1, k2, k3, and k4 respectively is?Detailed Solution: Question 5
is as follows:
y(0) = 2 and step-size (h) = 0.1
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