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Test: Static and Dynamic Load Carrying Capacity - Civil Engineering (CE) MCQ


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4 Questions MCQ Test - Test: Static and Dynamic Load Carrying Capacity

Test: Static and Dynamic Load Carrying Capacity for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Test: Static and Dynamic Load Carrying Capacity questions and answers have been prepared according to the Civil Engineering (CE) exam syllabus.The Test: Static and Dynamic Load Carrying Capacity MCQs are made for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Static and Dynamic Load Carrying Capacity below.
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Test: Static and Dynamic Load Carrying Capacity - Question 1

The rated life of a ball bearing varies

Detailed Solution for Test: Static and Dynamic Load Carrying Capacity - Question 1

Life of a bearing is given by:

where
L10 = basic life rating in million revolutions
C = dynamic load-carrying capacity
W = equivalent dynamic load
n = constant = 3 for ball bearing and 10/3 for roller bearing

Thus, The rated life of a ball bearing varies Inversely as the cube of the load.
So, option (4) is the correct answer.

Test: Static and Dynamic Load Carrying Capacity - Question 2

Find the dynamic load-carrying capacity of a roller bearing if the shaft rotates at 1500 rpm, the radial load acting on the bearing is 6 kN and the expected life for 90% life of the bearing is 8100 hours.

Detailed Solution for Test: Static and Dynamic Load Carrying Capacity - Question 2

Load-life relationship:
The approximate rating of the service life of a ball or roller bearing is based on the given fundamental equation.

L10 = Rated bearing life (in million revolutions)
C = Dynamic load capacity.
P = Load acting in bearing.
k = 3 for ball bearing and k = 10/3 for the roller bearing.
The relation between life in million revolutions and life in hours is given by:

where, L10h = rated bearing life in hours and N = speed of rotation in rpm.
Calculation:
Given:
N = 1500 rpm, P = 6 kN, L10h = 8100 hours, roller bearing k = 10/3
We know that;

Combining both equations:

C = 43.34 kN

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Test: Static and Dynamic Load Carrying Capacity - Question 3

In single row angular contact ball bearings, the basic static load relates to the: 

Detailed Solution for Test: Static and Dynamic Load Carrying Capacity - Question 3

Bearing Loads

  • Magnitude of Load
    • This is normally the most important factor in determining the size of the bearing.
    • Generally, roller bearings can carry greater loads than ball bearings of the same external dimensions.
    • Ball bearings are mostly used to carry light and medium loads, while roller bearings are often the only choice for heavy loads and large diameter shafts.
  • Direction of load
    • Cylindrical roller bearings having one ring without flanges and needles roller bearings can only carry radial loads.
    • Other types of radial bearings can carry both radial and axial loads.

Single row angular contact ball bearing

  • In angular contact ball bearings the line of action of the load, at the contacts between balls and raceways, forms an angle with the bearings axis.
  • The single row bearing is of non-separable design, suitable for high speeds, and carries an axial load in one direction only.
  •  In single row angular contact ball bearings, the basic static load can carry full radial and partial axial component of the load

Test: Static and Dynamic Load Carrying Capacity - Question 4

A self-aligning ball bearing has a basic dynamic load rating (C10, for 106 revolutions) of 35 kN. If the equivalent radial load on the bearing is 45 kN, the expected life (in 106 revolutions) is

Detailed Solution for Test: Static and Dynamic Load Carrying Capacity - Question 4

The approximate rating of service life of a ball or roller bearing is based on the fundamental equation.

where L is rating life, C is basic dynamic load, W is equivalent dynamic load
k = 3 for ball bearing
k = 10/3 for roller bearing
The relationship between the life in revolutions (L) and the life in working hours (LH)  is given by:
L = 60 N.LH  revolutions
where N is the speed in rpm
Calculation:
Given: C = 35 kN, W = 45 kN

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