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Test: Radar Graphs - Banking Exams MCQ


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10 Questions MCQ Test - Test: Radar Graphs

Test: Radar Graphs for Banking Exams 2024 is part of Banking Exams preparation. The Test: Radar Graphs questions and answers have been prepared according to the Banking Exams exam syllabus.The Test: Radar Graphs MCQs are made for Banking Exams 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Radar Graphs below.
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Test: Radar Graphs - Question 1

Directions: Study the radar chart given below and answer the following questions.
Radar chart shows the markup % and discount % on five different articles sold by a shopkeeper.

 

Note:-1. Mark up % on any article=[(Marked Price-Cost Price) of that article)/Cost Price of that article]*100
2.Discount % on any article=[(Marked Price-Selling Price) of that article)/Marked Price of that article]*100

Q. If ratio of selling price of A to that of C is 40 : 27, then find marked price of C is what percent of cost price of A?

Detailed Solution for Test: Radar Graphs - Question 1

Let selling price of A and that C be Rs 40x & Rs 27x respectively.
So, marked price of C = 27x *100/90 = Rs 30x
And, cost price of A = 40x * 100/80 * 100/125 =  Rs 40x
Required% = 30x/40x *100 = 75%

Test: Radar Graphs - Question 2

Direction: Study the following graph carefully to answer the questions that follow.
Number of Students (In thousands) in Two Different Universities in Six Different Years

Q. In which year was the difference between the number of students in university 1 and the number of students in university 2 highest?

Detailed Solution for Test: Radar Graphs - Question 2

Difference between the students of university 1 and university 2 in 2007 = 2000 – 1000 = 1000
Difference in number of students in 2008 = 25000 – 15000 = 10000
Difference in number of students in 2009 = 35000 – 25000 = 10000
Difference in number of students in 2010 = 20000 – 15000 = 5000
Difference in number of students in 2011 = 30000 – 25000 = 5000
Difference in number of students in 2012 = 35000 – 20000 = 15000

It is clear from above that the difference between the number of students in university 1 and the number of students in university 2 is highest in the year 2012.

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Test: Radar Graphs - Question 3

Directions: Study the following graph carefully to answer the questions that follow.
Number of Students (In thousands) in Two Different Universities in Six Different Years

Q. What was the difference between the number of students in university 1 in the year 2010 and the number of students in university 2 in year 2012?

Detailed Solution for Test: Radar Graphs - Question 3

Number of students in university 1 in 2010 = 20000
Number of students in university 2 in 2012 = 20000
Required difference = 20000 – 20000 = 0.

Test: Radar Graphs - Question 4

Directions: Study the following graph carefully to answer the questions that follow.
Number of Students (In thousands) in Two Different Universities in Six Different Years

Q. If 25% of the students in university 2 in the year 2010 were females, what was the number of male students in the university 2 in the same year?

Detailed Solution for Test: Radar Graphs - Question 4

Total students in university 2 in 2010 = 15000
∴  Number of girls = 15000 × 25/100 = 3750
and number of boys = 15000 – 3750 = 11250.

Test: Radar Graphs - Question 5

Directions: Study the following graph carefully to answer the questions that follow.
Number of Students (In thousands) in Two Different Universities in Six Different Years

Q. What is the sum of the number of students in university 1 in the year 2007 and the number of students in university 2 in the year 2011 together?

Detailed Solution for Test: Radar Graphs - Question 5

Number of students in university 1 in 2007 = 10000 
Number of students in university 2 in 2011 = 30000
∴  Required sum = 10000 + 30000 = 40000.

Test: Radar Graphs - Question 6

Directions: In the question below, the sales of TV and laptop in the subsequent years from 2004 to 2009 is given. The figures given to you is in million. Based on the figure answer the questions below.

Q. How many times do the sales of a laptop less than the TV in the given years?

Detailed Solution for Test: Radar Graphs - Question 6

Here the sales of televisions and laptops of six different years are given. You need to see that in which year the sale of TV was greater than the sale of the laptop. The values of different sales of units are given to you in the radar diagram above.
From the figure you can see that sales of the laptops in 2004 were lower than the sales TVs in 2004, similarly, sales of a laptop in 2005, 2008, and 2009 was lower than the sale of TVs in that year. So, there are four years where the sale of the laptop was lower than the sale of TV. Thus, the correct answer is D.

Test: Radar Graphs - Question 7

Directions: In the question below, the sales of TV and laptop in the subsequent years from 2004 to 2009 is given. The figures given to you is in million. Based on the figure answer the questions below.

Q. Which item and for which year shows the highest percentage increase in the sales in the previous year?

Detailed Solution for Test: Radar Graphs - Question 7

In this question, we need to find the increase in the percentage of the given items in comparison to previous years. Instead of checking all the years, we will only check percentage increase for the one given in the option. For laptop 2007, in the previous year, the sales were 30 million while in 2006 it was 25.5 so there is an increase of 4.5 million units. Therefore percentage increase will be 4.5/25.5 x 100 = 18%.
Similarly for TV 2007 it will be, 2.5/22.5 x 100 = 11.11 %. For Laptop 2006 it will be, 7.5/15 x 100 = 50 % and for TV 2009, it will be 5/25 x 100 = 20 %. So for laptop 2006, the percentage increase in sales is the highest. Thus, the correct answer is C.

Test: Radar Graphs - Question 8

Directions: In the question below, the sales of TV and laptop in the subsequent years from 2004 to 2009 is given. The figures given to you is in million. Based on the figure answer the questions below.

Q. Find the ratio of the total number of televisions sold to the total number of laptops sold in all these years.

Detailed Solution for Test: Radar Graphs - Question 8

Here, you only have to add the total number of televisions laptop sold in all these years and compare them to find the ratio. The total number of televisions sold from 2004 to 2009 are 25 + 22.5 + 22.5 + 25 + 25 + 30 = 150. And the total number of laptops sold are: 20 + 15 + 25 .5 + 30 + 20 + 10 = 120.5. Thus the ratio of the is 150: 120.5 = 5: 4. So, the correct answer is C.

Test: Radar Graphs - Question 9

Directions: In the question below, the sales of TV and laptop in the subsequent years from 2004 to 2009 is given. The figures given to you is in million. Based on the figure answer the questions below.

Q. For the data series shown in the above figure, how many years have shown the decrease in sales for both the items in the same year?

Detailed Solution for Test: Radar Graphs - Question 9

We need to find the decrease in sales for both the items given and that too during the same year. This only happens one time in the year 2001 where sales of TV decreases from 20 million to 10 million and sales of laptop decreases from 25 million to 22.5 million. So, the correct answer is A.

Test: Radar Graphs - Question 10

Directions: In the question below, the sales of TV and laptop in the subsequent years from 2004 to 2009 is given. The figures given to you is in million. Based on the figure answer the questions below.

Q. Which year shows the highest percentage decrease in the total sales of the two items?

Detailed Solution for Test: Radar Graphs - Question 10

We need to first calculate the total sales of both the items in each of the years given above. The total sales will be:

Now, from the table, you can see the decrease in sales occurs only thrice during 2005, 2008, and 2009. So we will calculate percentage decrease for only these three years. For 2005 decrease in sales are 7.5 million. So, the percentage decrease from the previous year will be 7.5/45 x 100 = 16.6 %. Sales decreased by 10 million from 2007 to 2008. Thus, the percentage decrease will be 10/55 x 100 = 18.18 %. For 2009 the decrease is 5 million and so the percentage decrease will be, 5/45 x 100 = 11.11 %. So, the highest percentage decrease was noted in 2008 from 2007. So, the correct answer is C.

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