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JEE Main 2020 January 8 Shift 2 Question Paper & Solutions - JEE MCQ


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30 Questions MCQ Test - JEE Main 2020 January 8 Shift 2 Question Paper & Solutions

JEE Main 2020 January 8 Shift 2 Question Paper & Solutions for JEE 2024 is part of JEE preparation. The JEE Main 2020 January 8 Shift 2 Question Paper & Solutions questions and answers have been prepared according to the JEE exam syllabus.The JEE Main 2020 January 8 Shift 2 Question Paper & Solutions MCQs are made for JEE 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for JEE Main 2020 January 8 Shift 2 Question Paper & Solutions below.
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JEE Main 2020 January 8 Shift 2 Question Paper & Solutions - Question 1

A uniform sphere of mass 500 g rolls without slipping on a plane horizontal surface with its centre moving at a speed of 5.00 cm/s. Its kinetic energy is

Detailed Solution for JEE Main 2020 January 8 Shift 2 Question Paper & Solutions - Question 1



KE = 8.75 × 10-4 Joule

JEE Main 2020 January 8 Shift 2 Question Paper & Solutions - Question 2

In the given circuit, value of Y:

Detailed Solution for JEE Main 2020 January 8 Shift 2 Question Paper & Solutions - Question 2



Y = 0 + 0 = 0

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JEE Main 2020 January 8 Shift 2 Question Paper & Solutions - Question 3

Consider a mixture of n moles of helium gas and 2n moles of oxygen gas (molecules taken to be rigid) as an ideal gas. Its Cp/Cv value will be

Detailed Solution for JEE Main 2020 January 8 Shift 2 Question Paper & Solutions - Question 3

JEE Main 2020 January 8 Shift 2 Question Paper & Solutions - Question 4

An object is gradually moving away from the focal point of a concave mirror along the axis of the mirror. The graphical representation of the magnitude of linear magnification (m) versus distance of the object from the mirror (x) is correctly given by:
(Graphs are drawn schematically and are not to scale)

Detailed Solution for JEE Main 2020 January 8 Shift 2 Question Paper & Solutions - Question 4

At focus, magnification is ∞.
And at x = 2f, magnification is 1.

JEE Main 2020 January 8 Shift 2 Question Paper & Solutions - Question 5

A transverse wave travels on a taut steel wire with a velocity of v when tension in it is 2.06 × 104 N. When the tension is changed to T, the velocity changed to v/2. The value of T is close to

Detailed Solution for JEE Main 2020 January 8 Shift 2 Question Paper & Solutions - Question 5


⇒ T2 = 5.15 × 103 N

JEE Main 2020 January 8 Shift 2 Question Paper & Solutions - Question 6

A galvanometer having a coil resistance 100 Ω gives a full scale deflection when a current of 1 mA is passed through it. What is the value of the resistance which can convert this galvanometer into a voltmeter giving full scale deflection for a potential difference of 10 V?

Detailed Solution for JEE Main 2020 January 8 Shift 2 Question Paper & Solutions - Question 6

V = 10 volts
When 1 mA current will be flowing,
10 = 1 × 10-3 (100 + R0)
⇒ 10,000 - 100 = 9900 Ω = R0
⇒ R0 = 9.9 kΩ

JEE Main 2020 January 8 Shift 2 Question Paper & Solutions - Question 7

A Carnot engine having an efficiency of 1/10 is being used as a refrigerator. If the work done on the refrigerator is 10 J, the amount of heat absorbed from the reservoir at lower temperature is:

Detailed Solution for JEE Main 2020 January 8 Shift 2 Question Paper & Solutions - Question 7



⇒ 100 - 10 =   = 90 J

JEE Main 2020 January 8 Shift 2 Question Paper & Solutions - Question 8

As shown in the figure, a battery of emf E is connected to an inductor L and resistance R in series. The switch is closed at t = 0. The total charge that flows from the battery, between t = 0 and t = tC (tC is the time constant of the circuit) is:

Detailed Solution for JEE Main 2020 January 8 Shift 2 Question Paper & Solutions - Question 8



JEE Main 2020 January 8 Shift 2 Question Paper & Solutions - Question 9

Two liquids of densities are filled up behind a square wall of side 10 m as shown in figure. Each liquid has a height of 5 m. The ratio of the forces due to these liquids exerted on upper part MN to that at the lower part NO is: (Assume that the liquids are not mixing)

Detailed Solution for JEE Main 2020 January 8 Shift 2 Question Paper & Solutions - Question 9


JEE Main 2020 January 8 Shift 2 Question Paper & Solutions - Question 10

A particle of mass m is dropped from a height h above the ground. At the same time, another particle of the same mass is thrown vertically upwards from the ground with a speed of . If they collide head-on completely inelastically, the time taken for the combined mass to reach the ground, in units of , is

Detailed Solution for JEE Main 2020 January 8 Shift 2 Question Paper & Solutions - Question 10


Time of collision:

Speed of (A) just before collision v1 ↓ = gt0
And speed of (B) just before collision v2 ↑ = 
After collision, velocity of centres of mass,

So, from there, time of fall 't':

JEE Main 2020 January 8 Shift 2 Question Paper & Solutions - Question 11

A simple pendulum is being used to determine the value of gravitational acceleration g at a certain place. The length of the pendulum is 25.0 cm and a stopwatch with 1 s resolution measures the time taken for 40 oscillation to be 50 s. The accuracy in g is

Detailed Solution for JEE Main 2020 January 8 Shift 2 Question Paper & Solutions - Question 11

l = 25.0 cm
Time of 40 oscillations is 50 sec.

JEE Main 2020 January 8 Shift 2 Question Paper & Solutions - Question 12

A particle of mass m and charge q is released from rest in a uniform electric field. If there is no other force on the particle, the dependence of its speed v on the distance x travelled by it is correctly given by: (Graphs are schematic and not drawn to scale.)

Detailed Solution for JEE Main 2020 January 8 Shift 2 Question Paper & Solutions - Question 12


JEE Main 2020 January 8 Shift 2 Question Paper & Solutions - Question 13

A capacitor is made of two square plates each of side 'a' making a very small angle α between them, as shown in figure. The capacitance will be close to

Detailed Solution for JEE Main 2020 January 8 Shift 2 Question Paper & Solutions - Question 13

Assume small elements dx at a distance x from  left end

Capacitance for a small element dx is 

JEE Main 2020 January 8 Shift 2 Question Paper & Solutions - Question 14

Consider two charged metallic spheres S1 and S2 of radii R1 and R2, respectively. The electric fields E1 (on S1) and E2 (on S2) on their surfaces are such that E1/E2 = R1/R2. Then the ratio V1(on S1)/V2(on S2) of the electrostatic potentials on each sphere is

Detailed Solution for JEE Main 2020 January 8 Shift 2 Question Paper & Solutions - Question 14

Let ρ1 and ρ2 be the charge densities of two spheres.
Then,

JEE Main 2020 January 8 Shift 2 Question Paper & Solutions - Question 15

A plane electromagnetic wave of frequency 25 GHz is propagating in vacuum along the z-direction. At a particular point in space and time, the magnetic field is given by . The corresponding electric field  is: (Speed of light, c = 3 × 108 ms-1)

Detailed Solution for JEE Main 2020 January 8 Shift 2 Question Paper & Solutions - Question 15


= 5 × 10-8 × 3 × 108 = 15 N/C

JEE Main 2020 January 8 Shift 2 Question Paper & Solutions - Question 16

In a double-slit experiment, at a certain point on the screen, the path difference between the two interfering waves is 1/8th of a wavelength. The ratio of the intensity of light at that point to that at the centre of a bright fringe is

Detailed Solution for JEE Main 2020 January 8 Shift 2 Question Paper & Solutions - Question 16


JEE Main 2020 January 8 Shift 2 Question Paper & Solutions - Question 17

A very long wire ABDMNDC is shown in figure carrying current I. AB and BC parts are straight, long and at right angles. At D, wire forms a circular turn DMND of radius R. AB, BC parts are tangential to circular turn at N and D. Magnetic field at the centre of circle is

Detailed Solution for JEE Main 2020 January 8 Shift 2 Question Paper & Solutions - Question 17






JEE Main 2020 January 8 Shift 2 Question Paper & Solutions - Question 18

As shown in fig., when a spherical cavity (centred at O) of radius 1 is cut out of a uniform sphere of radius R (centred at C), the centre of mass of remaining (shaded) part of sphere is at G, i.e. on the surface of the cavity. R can be determined by the equation:

Detailed Solution for JEE Main 2020 January 8 Shift 2 Question Paper & Solutions - Question 18




⇒  R4 – 2R3 + 1 = 0
∵ R ≠1
∴ R3 – R2 – R – 1 = 0
∴ (R2 + R + 1)(2 – R) = 1

JEE Main 2020 January 8 Shift 2 Question Paper & Solutions - Question 19

A particle moves such that its position vector r(t) = cos ωt i + sin ωt j, where ω is a constant and t is time. Then which of the following statements is true for the velocity vector v(t) and acceleration vector a(t) of the particle?

Detailed Solution for JEE Main 2020 January 8 Shift 2 Question Paper & Solutions - Question 19


 is perpendicular to  and  is directed towards the origin.

JEE Main 2020 January 8 Shift 2 Question Paper & Solutions - Question 20

An electron (mass m) with initial velocity  is in an electric field . If  is initial de Broglie wavelength of electron, its de Broglie wavelength at time t is given by

Detailed Solution for JEE Main 2020 January 8 Shift 2 Question Paper & Solutions - Question 20


Initially,

Now,

*Answer can only contain numeric values
JEE Main 2020 January 8 Shift 2 Question Paper & Solutions - Question 21

Three containers C1, C2 and C3 have water at different temperatures. The table below shows the final temperature T when different amounts of water (given in litres) are taken from each container and mixed (assume no loss of heat during the process).

The value of θ (in °C, to the nearest integer) is _______.


Detailed Solution for JEE Main 2020 January 8 Shift 2 Question Paper & Solutions - Question 21

According to table and applying law of calorimetry


Adding (1) + (2) + (3)

Hence, 
T1 + T2 + T3 = (1 + 1 + 1)θ
150 = 3θ
θ = 50oC

*Answer can only contain numeric values
JEE Main 2020 January 8 Shift 2 Question Paper & Solutions - Question 22

An asteroid is moving directly towards the centre of the earth. When at a distance of 10 R (R is the radius of the earth) from the earth's centre, it has a speed of 12 km/s. Neglecting the effect of earth's atmosphere, what will be the speed of the asteroid when it hits the surface of the earth (escape velocity from the earth is 11.2 km/s)? Give your answer to the nearest integer in kilometres/s.


Detailed Solution for JEE Main 2020 January 8 Shift 2 Question Paper & Solutions - Question 22

U1 + K1 + U2 + K2


v2 = 112.896 + 144
v = 16.027
v = 16 km/s

*Answer can only contain numeric values
JEE Main 2020 January 8 Shift 2 Question Paper & Solutions - Question 23

The series combination of two batteries, both of the same emf 10 V but different internal resistances of 20 Ω and 5Ω , is connected to the parallel combination of two resistors 30Ω  and R Ω. The voltage difference across the battery of internal resistance 20Ω  is zero, the value of R (in Ω) is _______.


Detailed Solution for JEE Main 2020 January 8 Shift 2 Question Paper & Solutions - Question 23


E1 = E - ir
E2 = E - ir
= 10 - i20 = 0
= 10 - 0.5 x 5
i = 0.5 A
= 7.5 V
Enet = E1 + E2 = 7.5V
i = i1 + i2
0.5  = (7.5/x) + (7.5/30)
x = 30 Ω

*Answer can only contain numeric values
JEE Main 2020 January 8 Shift 2 Question Paper & Solutions - Question 24

The first member of the Balmer series of hydrogen atom has a wavelength of 6561 . The wavelength of the second member of the Balmer series (in nm) is _______.
(Answer up to the nearest integer)


Detailed Solution for JEE Main 2020 January 8 Shift 2 Question Paper & Solutions - Question 24

For Balmer series

λ2 = 20/27 x +6561
λ2 = 4860
= 486 nm

*Answer can only contain numeric values
JEE Main 2020 January 8 Shift 2 Question Paper & Solutions - Question 25

A ball is dropped from the top of a 100 m high tower on a planet. In the last 1/2s before hitting the ground, it covers a distance of 19 m. Acceleration due to gravity (in ms–2) near the surface on that planet is _______.(Nearest Integer)


Detailed Solution for JEE Main 2020 January 8 Shift 2 Question Paper & Solutions - Question 25

Time to travel 81m is t sec.
Time to travel 100 m is t +(1/2)sec.

a = 8 m/s2

JEE Main 2020 January 8 Shift 2 Question Paper & Solutions - Question 26

Among the compounds A and B with molecular formula C9H18O3, A is having a higher boiling point than B. The possible structures of A and B are:

Detailed Solution for JEE Main 2020 January 8 Shift 2 Question Paper & Solutions - Question 26

A exhibits intermolecular H-bonding and has a higher boiling point than B which does not exhibit intermolecular H-bonding.
Hence, option(d) is correct.

JEE Main 2020 January 8 Shift 2 Question Paper & Solutions - Question 27

Which of the following compounds is likely to show both Frenkel and Schottky defects in its crystalline form?

Detailed Solution for JEE Main 2020 January 8 Shift 2 Question Paper & Solutions - Question 27

AgBr shows both, Frenkel as well as Schottky defects. Schottky defect in AgBr is exhibited due to precipitation of both cations and anions. Also, since the Ag+ ion is small in size in AgBr, it can move from the lattice point to occupy interstitial sites. Hence, it shows both Frenkel and Schottky defects.

JEE Main 2020 January 8 Shift 2 Question Paper & Solutions - Question 28

Among the reactions (a) - (d), the reaction(s) that does/do not occur in the blast furnace during the extraction of iron is/are:
(a) CaO + SiO2 → CaSiO3
(b) 3Fe2O3 + CO → 2Fe3O4 + CO2
(c) FeO + SiO2 → FeSiO3
(d) 

Detailed Solution for JEE Main 2020 January 8 Shift 2 Question Paper & Solutions - Question 28

(c) FeO + SiO2 → FeSiO3
(d) 
Reactions (c) and (d) do not occur in the blast furnace in the metallurgy of iron.

JEE Main 2020 January 8 Shift 2 Question Paper & Solutions - Question 29

The increasing order of the atomic radii of the following elements is:
(a) C
(b) O
(c) F
(d) CI
(e) Br

Detailed Solution for JEE Main 2020 January 8 Shift 2 Question Paper & Solutions - Question 29


Correct increasing order of atomic radii is:
F < O < C < Cl < Br

JEE Main 2020 January 8 Shift 2 Question Paper & Solutions - Question 30

The radius of the second Bohr orbit, in terms of the Bohr radius a0, in Li2+ is:

Detailed Solution for JEE Main 2020 January 8 Shift 2 Question Paper & Solutions - Question 30


Bohr's radius for hydrogen atom (a0) = 0.529 
Bohr's radius of Li+2 ion (for n = 2)

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