IBPS Clerk Mains Mock Test - 9 - Banking Exams MCQ

2nd letter = E; 4th letter = I; 5th letter = S; 8th letter = D

Letters given: EISD

Words possible starting with S: SIDE

Hence, only 1 such word is possible.

Conclusions:

I. Some water is river → False (This is possible but not definite)

II. Some pond is not tree → True (Part of the pond that is riven is not the tree)

III. All water being jungle is possibility → True

So, only II and III follow.

There is one person between E and P. E is not the immediate neighbor of X.

This is not possible in case 1. So, case 2 is correct.

3. The number of persons who sit on the left side of E is one less than the number of persons who sit on the right side of E.

So, 5 persons sit on the left side of E. So 6 persons sit on the right side of E.

4. There are four persons between W and Z who do not sit to the left of E. There are two persons between R and W. There are more than two persons between Q and T who sit to the left of W. Q sits on the left side of X.

5. F does not sit on the extreme ends. Neither N nor M is the neighbor of X.

So, five persons sit between Q and W.

There is one person between E and P. E is not the immediate neighbor of X.

This is not possible in case 1. So, case 2 is correct.

3. The number of persons who sit on the left side of E is one less than the number of persons who sit on the right side of E.

So, 5 persons sit on the left side of E. So 6 persons sit on the right side of E.

4. There are four persons between W and Z who do not sit to the left of E. There are two persons between R and W. There are more than two persons between Q and T who sit to the left of W. Q sits on the left side of X.

5. F does not sit on the extreme ends. Neither N nor M is the neighbor of X.

So, except WR second person sits the immediate right of the first person.

There is one person between E and P. E is not the immediate neighbor of X.

This is not possible in case 1. So, case 2 is correct.

3. The number of persons who sit on the left side of E is one less than the number of persons who sit on the right side of E.

So, 5 persons sit on the left side of E. So 6 persons sit on the right side of E.

4. There are four persons between W and Z who do not sit to the left of E. There are two persons between R and W. There are more than two persons between Q and T who sit to the left of W. Q sits on the left side of X.

5. F does not sit on the extreme ends. Neither N nor M is the neighbor of X.

So, eight persons sit between X and Z.

There is one person between E and P. E is not the immediate neighbor of X.

This is not possible in case 1. So, case 2 is correct.

3. The number of persons who sit on the left side of E is one less than the number of persons who sit on the right side of E.

So, 5 persons sit on the left side of E. So 6 persons sit on the right side of E.

4. There are four persons between W and Z who do not sit to the left of E. There are two persons between R and W. There are more than two persons between Q and T who sit to the left of W. Q sits on the left side of X.

5. F does not sit on the extreme ends. Neither N nor M is the neighbor of X.

So, either N or M sits on the immediate left of V.

There is one person between E and P. E is not the immediate neighbor of X.

This is not possible in case 1. So, case 2 is correct.

3. The number of persons who sit on the left side of E is one less than the number of persons who sit on the right side of E.

So, 5 persons sit on the left side of E. So 6 persons sit on the right side of E.

4. There are four persons between W and Z who do not sit to the left of E. There are two persons between R and W. There are more than two persons between Q and T who sit to the left of W. Q sits on the left side of X.

5. F does not sit on the extreme ends. Neither N nor M is the neighbor of X.

So, the position of the two persons is not known.

They all have some sticks with them that is 1, 2, 3, 4, 5, 6, 7, 8 and 9.

1) E is standing third from one of the ends. but there are two possibilities for the position of E.

2) Difference between the Sticks of G and E is 3 and E has a stick which is a prime number. There are three students standing between G and E. G is standing immediate left of Q. So we will take 2 cases,

Case 1-

Case 2-

3) The number of students standing between K and O is exactly the same as the number of students standing between O and Q. O is standing to the left of Q.

4) Difference between sticks of M and O is 2 and both have even number of sticks. M has less sticks than O. Sum of sticks of A and I is 3.

Here Case 2 will be cancelled because we cannot place K and O according to the statement.

5) M is not adjacent to G. A is standing just near to K who has 5 sticks.

6) More than 5 students stand between A and I. The Sum of sticks of A and I is 3 C has sticks which is one by third of the sticks Q has.

G and Q are adjacent to each other.

They all have some sticks with them that is 1, 2, 3, 4, 5, 6, 7, 8 and 9.

1) E is standing third from one of the ends. but there are two possibilities for the position of E.

2) Difference between the Sticks of G and E is 3 and E has a stick which is a prime number. There are three students standing between G and E. G is standing immediate left of Q. So we will take 2 cases,

Case 1-

Case 2-

3) The number of students standing between K and O is exactly the same as the number of students standing between O and Q. O is standing to the left of Q.

4) Difference between sticks of M and O is 2 and both have even number of sticks. M has less sticks than O. Sum of sticks of A and I is 3.

Here Case 2 will be cancelled because we cannot place K and O according to the statement.

5) M is not adjacent to G. A is standing just near to K who has 5 sticks.

6) More than 5 students stand between A and I. The Sum of sticks of A and I is 3 C has sticks which is one by third of the sticks Q has.

G and Q are adjacent to each other.

They all have some sticks with them that is 1, 2, 3, 4, 5, 6, 7, 8 and 9.

1) E is standing third from one of the ends. but there are two possibilities for the position of E.

2) Difference between the Sticks of G and E is 3 and E has a stick which is a prime number. There are three students standing between G and E. G is standing immediate left of Q. So we will take 2 cases,

Case 1-

Case 2-

3) The number of students standing between K and O is exactly the same as the number of students standing between O and Q. O is standing to the left of Q.

4) Difference between sticks of M and O is 2 and both have even number of sticks. M has less sticks than O. Sum of sticks of A and I is 3.

Here Case 2 will be cancelled because we cannot place K and O according to the statement.

5) M is not adjacent to G. A is standing just near to K who has 5 sticks.

6) More than 5 students stand between A and I. The Sum of sticks of A and I is 3 C has sticks which is one by third of the sticks Q has.

G and Q are adjacent to each other.

They all have some sticks with them that is 1, 2, 3, 4, 5, 6, 7, 8 and 9.

1) E is standing third from one of the ends. but there are two possibilities for the position of E.

2) Difference between the Sticks of G and E is 3 and E has a stick which is a prime number. There are three students standing between G and E. G is standing immediate left of Q. So we will take 2 cases,

Case 1-

Case 2-

3) The number of students standing between K and O is exactly the same as the number of students standing between O and Q. O is standing to the left of Q.

4) Difference between sticks of M and O is 2 and both have even number of sticks. M has less sticks than O. Sum of sticks of A and I is 3.

Here Case 2 will be cancelled because we cannot place K and O according to the statement.

5) M is not adjacent to G. A is standing just near to K who has 5 sticks.

6) More than 5 students stand between A and I. The Sum of sticks of A and I is 3 C has sticks which is one by third of the sticks Q has.

G and Q are adjacent to each other.

They all have some sticks with them that is 1, 2, 3, 4, 5, 6, 7, 8 and 9.

1) E is standing third from one of the ends. but there are two possibilities for the position of E.

2) Difference between the Sticks of G and E is 3 and E has a stick which is a prime number. There are three students standing between G and E. G is standing immediate left of Q. So we will take 2 cases,

Case 1-

Case 2-

3) The number of students standing between K and O is exactly the same as the number of students standing between O and Q. O is standing to the left of Q.

4) Difference between sticks of M and O is 2 and both have even number of sticks. M has less sticks than O. Sum of sticks of A and I is 3.

Here Case 2 will be cancelled because we cannot place K and O according to the statement.

5) M is not adjacent to G. A is standing just near to K who has 5 sticks.

6) More than 5 students stand between A and I. The Sum of sticks of A and I is 3 C has sticks which is one by third of the sticks Q has.

G and Q are adjacent to each other.

P #& Z → P is North East to Z → False

S ¥ Z → S is South to Z → False

K #& Z → K is North East to Z → False

Z ¥ C → Z is South to C. → Possibly True

So, Z ¥ C is possibly true.

Given that

Four subjects: History, Geography, Economics and Computer were taught in four consecutive periods of one hour each starting from 9.00 a.m.

From statement I: Economics period ended at 11.00 a.m. which was preceded by Computer.

We cannot determine with the statement.

Therefore, Statement I alone is not sufficient to answer the question.

From statement II: History was scheduled in the last period.

We cannot determine with the statement.

Therefore, Statement II alone is not sufficient to answer the question.

From statement III: Economics period was immediately followed by Geography.

We cannot determine with the statement.

Therefore, Statement III alone is not sufficient to answer the question.

By combining I and II

We conclude that Economics period began at 10.00 a.m. and Computer period began at 9.00 a.m. and History period began at 12 p.m.

So, the Geography period began at 11.00 a.m.

Therefore, the statements I and II together are sufficient to answer the question.

By combining I and III

We conclude that Economics period ended and Geography period began at 11.00 a.m.

Therefore, the statements I and III together are sufficient to answer the question.

By combining II and III

No relation between the two statements.

Therefore, the statements II and III together are not sufficient to answer the question

Therefore, the statements I and III together are sufficient to answer the question.

By combining II and III

No relation between the two statements.

Therefore, the statements II and III together are not sufficient to answer the question.

Hence, the statements either only I and II or only I and III are sufficient

So, A is the mother-in-law of X. So, the statement I alone is sufficient.

From II: A is the wife of D, X is the wife of K, D is the father of J and K.

So, A is the mother-in-law of X. So, statement II alone is sufficient.

Therefore, the data either in statement I alone or in statement II alone are sufficient to answer the question.

So, A is mother-in-law of X. Hence, statement I alone is sufficient.

From II; A is wife of D, X is wife of K, D is father of J and K.

So, A is mother-in-law of X. Hence, statement II alone is sufficient.

Step 1: If the symbol followed by a number, then that number is interchanged with the alphabet according to the alphabetical series.

The required order is: Symbol → Number

Terms satisfying given condition are:

Left End: 8 $ 7 P 5 I 8 9 A % 2 D & O * 5 D 2 Q U 8 ! E W R 9 # ) 8 P C 1 P 8 : Right end

So, 7 → G, 2 → B, 5 → E, 8 → H

After changing:

Left end: 8 $ G P 5 I 8 9 A % B D & O * E D 2 Q U 8 ! E W R 9 # )H P C 1 P 8:Right end

Step 2: After completing step 1, we apply step 2, which is,

If the vowel is followed by the number and preceded by a consonant, then the vowel counted according to the alphabetical series is change to its next third alphabet according to the alphabetical series. (ex- if I, is given then its place according to alphabetical series is 9, then its next third letter is 9 + 3 = 12, so 12th alphabet in alphabetical series is L.)

The required order is: Consonant → Vowel → Number

Left end: 8 $ G P 5 I 8 9 A % B D & O * E D 2 Q U 8 ! E W R 9 # ) H P C 1 P 8 : Right end

So, Q U 8 → vowel → U → position of U in alphabetical series → 21

After applying the given condition U → 21 + 3 → 24

24th position letter in alphabetical series → X

After changing, series becomesL

Left end: 8 $ G P 5 I 8 9 A % B D & O * E D 2 Q X8 ! E W R 9 # ) H P C 1 P 8 : Right end

Step 3: After completing step 2, we apply step 3, which is-

If two letters are given between any two symbols, then the position of those symbols is interchanged.

Given condition is satisfied in,

Left end: 8 $ G P 5 I 8 9 A % B D & O * E D 2 Q X 8 ! E W R 9 # ) H P C 1 P 8: Right end

So, two letters between any two symbols are-

% B D &

On applying the given step 3-

Required order-

% → &

& → %

After interchanging,

Left end: 8 $ G P 5 I 8 9 A & B D % O * E D 2 Q X8 ! E W R 9 # ) H P C 1 P 8 : Right end

Step 4: After completing step 3, we apply step 4, which is,

Consonant preceded by number is interchanged to its opposite letter according to the alphabetical series in the English alphabet.

The required order is: Number → Consonant

Terms which follow the given condition are,

Left end: 8 $ G P 5 I 8 9 A & B D % O * E D 2 Q X 8 ! E W R 9 # ) H P C 1 P 8 : Right end

Consonant preceded by a number-

2Q, 1P

So,

Q → J (Opposite letter)

P → K (Opposite letter)

After interchanging-

Left end: 8 $ G P 5 I 8 9 A & B D % O * E D 2 J X 8 ! E W R 9 # ) H P C 1 K 8 : Right end

So, the final arrangement is-

Left end: 8 $ G P 5 I 8 9 A & B D % O * E D 2 J X 8 ! E W R 9 # ) H P C 1 K 8: Right end

So, the third vowel from left = O

The fourth number from right = 8

Left end: 8 $ G P 5 I 8 9 A & B D %O * E D 2 Q U8 ! E W I 9# ) H P X 1 P 8 : Right end

Characters between them = 6

Step 1: If the symbol followed by a number, then that number is interchanged with the alphabet according to the alphabetical series.

The required order is: Symbol → Number

Terms satisfying given condition are:

Left End: 8 $ 7 P 5 I 8 9 A % 2 D & O * 5 D 2 Q U 8 ! E W R 9 # ) 8 P C 1 P 8 : Right end

So, 7 → G, 2 → B, 5 → E, 8 → H

After changing:

Left end: 8 $ G P 5 I 8 9 A % B D & O * E D 2 Q U 8 ! E W R 9 # )H P C 1 P 8:Right end

Step 2: After completing step 1, we apply step 2, which is,

If the vowel is followed by the number and preceded by a consonant, then the vowel counted according to the alphabetical series is change to its next third alphabet according to the alphabetical series. (ex- if I, is given then its place according to alphabetical series is 9, then its next third letter is 9 + 3 = 12, so 12th alphabet in alphabetical series is L.)

The required order is: Consonant → Vowel → Number

Left end: 8 $ G P 5 I 8 9 A % B D & O * E D 2 Q U 8 ! E W R 9 # ) H P C 1 P 8 : Right end

So, Q U 8 → vowel → U → position of U in alphabetical series → 21

After applying the given condition U → 21 + 3 → 24

24th position letter in alphabetical series → X

After changing, series becomesL

Left end: 8 $ G P 5 I 8 9 A % B D & O * E D 2 Q X8 ! E W R 9 # ) H P C 1 P 8 : Right end

Step 3: After completing step 2, we apply step 3, which is-

If two letters are given between any two symbols, then the position of those symbols is interchanged.

Given condition is satisfied in,

Left end: 8 $ G P 5 I 8 9 A % B D & O * E D 2 Q X 8 ! E W R 9 # ) H P C 1 P 8: Right end

So, two letters between any two symbols are-

% B D &

On applying the given step 3-

Required order-

% → &

& → %

After interchanging,

Left end: 8 $ G P 5 I 8 9 A & B D % O * E D 2 Q X8 ! E W R 9 # ) H P C 1 P 8 : Right end

Step 4: After completing step 3, we apply step 4, which is,

Consonant preceded by number is interchanged to its opposite letter according to the alphabetical series in the English alphabet.

The required order is: Number → Consonant

Terms which follow the given condition are,

Left end: 8 $ G P 5 I 8 9 A & B D % O * E D 2 Q X 8 ! E W R 9 # ) H P C 1 P 8 : Right end

Consonant preceded by a number-

2Q, 1P

So,

Q → J (Opposite letter)

P → K (Opposite letter)

Final arrangement-

Left end: 8 $ G P 5 I 8 9 A &B D % O * E D 2 J X8 ! E W R 9 # )H P C 1 K 8 : Right end

Total number of consonants = 13

So, 13 is the correct answer. As 13 is not given in any option, then none of these is the correct answer.

Step 1: If the symbol followed by a number, then that number is interchanged with the alphabet according to the alphabetical series.

The required order is: Symbol → Number

Terms satisfying given condition are:

Left End: 8 $ 7 P 5 I 8 9 A % 2 D & O * 5 D 2 Q U 8 ! E W R 9 # ) 8 P C 1 P 8 : Right end

So, 7 → G, 2 → B, 5 → E, 8 → H

After changing:

Left end: 8 $ G P 5 I 8 9 A % B D & O * E D 2 Q U 8 ! E W R 9 # )H P C 1 P 8:Right end

Step 2: After completing step 1, we apply step 2, which is,

If the vowel is followed by the number and preceded by a consonant, then the vowel counted according to the alphabetical series is change to its next third alphabet according to the alphabetical series. (ex- if I, is given then its place according to alphabetical series is 9, then its next third letter is 9 + 3 = 12, so 12th alphabet in alphabetical series is L.)

The required order is: Consonant → Vowel → Number

Left end: 8 $ G P 5 I 8 9 A % B D & O * E D 2 Q U 8 ! E W R 9 # ) H P C 1 P 8 : Right end

So, Q U 8 → vowel → U → position of U in alphabetical series → 21

After applying the given condition U → 21 + 3 → 24

24th position letter in alphabetical series → X

After changing, series becomesL

Left end: 8 $ G P 5 I 8 9 A % B D & O * E D 2 Q X8 ! E W R 9 # ) H P C 1 P 8 : Right end

Step 3: After completing step 2, we apply step 3, which is-

If two letters are given between any two symbols, then the position of those symbols is interchanged.

Given condition is satisfied in,

Left end: 8 $ G P 5 I 8 9 A % B D & O * E D 2 Q X 8 ! E W R 9 # ) H P C 1 P 8: Right end

So, two letters between any two symbols are-

% B D &

On applying the given step 3-

Required order-

% → &

& → %

After interchanging,

Left end: 8 $ G P 5 I 8 9 A & B D % O * E D 2 Q X8 ! E W R 9 # ) H P C 1 P 8 : Right end

Step 4: After completing step 3, we apply step 4, which is,

Consonant preceded by number is interchanged to its opposite letter according to the alphabetical series in the English alphabet.

The required order is: Number → Consonant

Terms which follow the given condition are,

Left end: 8 $ G P 5 I 8 9 A & B D % O * E D 2 Q X 8 ! E W R 9 # ) H P C 1 P 8 : Right end

Consonant preceded by a number-

2Q, 1P

So,

Q → J (Opposite letter)

P → K (Opposite letter)

After applying step 2-

Left end: 8 $ G P 5 I 8 9 A % B D & O * E D 2 Q U 8 ! E W R 9 # ) H P C 1 P 8 :Right end

13th from the right = !

Fourth to the left = P

According to the rule-

Add the number if directions are different-

Right + Left = right

So, fourth to the left of thirteen from the right = 17th from the right = 2

Left end: 8 $ G P 5 I 8 9 A % B D & O * E D 2 Q U 8 ! E W R 9 # ) H P C 1 P 8 : Right end

So, 2 is the correct answer.

Step 1: If the symbol followed by a number, then that number is interchanged with the alphabet according to the alphabetical series.

The required order is: Symbol → Number

Terms satisfying given condition are:

Left End: 8 $ 7 P 5 I 8 9 A % 2 D & O * 5 D 2 Q U 8 ! E W R 9 # ) 8 P C 1 P 8 : Right end

So, 7 → G, 2 → B, 5 → E, 8 → H

After changing:

Left end: 8 $ G P 5 I 8 9 A % B D & O * E D 2 Q U 8 ! E W R 9 # )H P C 1 P 8:Right end

Step 2: After completing step 1, we apply step 2, which is,

If the vowel is followed by the number and preceded by a consonant, then the vowel counted according to the alphabetical series is change to its next third alphabet according to the alphabetical series. (ex- if I, is given then its place according to alphabetical series is 9, then its next third letter is 9 + 3 = 12, so 12th alphabet in alphabetical series is L.)

The required order is: Consonant → Vowel → Number

Left end: 8 $ G P 5 I 8 9 A % B D & O * E D 2 Q U 8 ! E W R 9 # ) H P C 1 P 8 : Right end

So, Q U 8 → vowel → U → position of U in alphabetical series → 21

After applying the given condition U → 21 + 3 → 24

24th position letter in alphabetical series → X

After changing, series becomesL

Left end: 8 $ G P 5 I 8 9 A % B D & O * E D 2 Q X8 ! E W R 9 # ) H P C 1 P 8 : Right end

Step 3: After completing step 2, we apply step 3, which is-

If two letters are given between any two symbols, then the position of those symbols is interchanged.

Given condition is satisfied in,

Left end: 8 $ G P 5 I 8 9 A % B D & O * E D 2 Q X 8 ! E W R 9 # ) H P C 1 P 8: Right end

So, two letters between any two symbols are-

% B D &

On applying the given step 3-

Required order-

% → &

& → %

After interchanging,

Left end: 8 $ G P 5 I 8 9 A & B D % O * E D 2 Q X8 ! E W R 9 # ) H P C 1 P 8 : Right end

Step 4: After completing step 3, we apply step 4, which is,

Consonant preceded by number is interchanged to its opposite letter according to the alphabetical series in the English alphabet.

The required order is: Number → Consonant

Terms which follow the given condition are,

Left end: 8 $ G P 5 I 8 9 A & B D % O * E D 2 Q X 8 ! E W R 9 # ) H P C 1 P 8 : Right end

Consonant preceded by a number-

2Q, 1P

So,

Q → J (Opposite letter)

P → K (Opposite letter)

After applying step 1-

Left end: 8 $ G P 5 I 8 9 A % B D & O * E D 2 Q U 8 ! E W R 9 # ) H P C 1 P 8:Right end

Symbols preceded by a number = 8$, 8!, 9#

So, three is the answer.

Number: Numbers are arranged in ascending order from left to right after adding 2 to the odd digit and subtracted 1 from even digit within the number.

Word: Words in the given input are arranged in reverse dictionary order from left to right after replacing the vowel to next letter according to the alphabetical series and consonants remains the same.

Note: A number and word are arranged simultaneously in each step.

Step I: First the smallest number is considered then 2 is added to the odd digits of the number and 1 is subtracted from the even digits and are placed on the leftmost end.

The last word that would appear in the dictionary is considered next and the vowels are changed to next alphabet according to the alphabetical series and consonants are left as it is and the word is placed to the immediate right of the initially arranged number and all the other elements (words/numbers) are shifted accordingly.

The same process is followed till all the numbers and words are rearranged.

Now given,

Input: 632 euo 756 bdu mpe 125 468 noq vua 241 xtv 845

Step I: 317 xtv 632 euo 756 bdu mpe 468 noq vua 241 845

Step II: 133 vvb 317 xtv 632 euo 756 bdu mpe 468 noq 845

Step III: 357 npq 133 vvb 317 xtv 632 euo 756 bdu mpe 845

Step IV: 551 mpf 357 npq 133 vvb 317 xtv euo 756 bdu 845

Step V: 975 fvp 551 mpf 357 npq 133 vvb 317 xtv bdu 845

Step VI: 737 bdv 975 fvp 551 mpf 357 npq 133 vvb 317 xtv

Number: Numbers are arranged in ascending order from left to right after adding 2 to the odd digit and subtracted 1 from even digit within the number.

Word: Words in the given input are arranged in reverse dictionary order from left to right after replacing the vowel to next letter according to the alphabetical series and consonants remains the same.

Note: A number and word are arranged simultaneously in each step.

Step I: First the smallest number is considered then 2 is added to the odd digits of the number and 1 is subtracted from the even digits and are placed on the leftmost end.

The last word that would appear in the dictionary is considered next and the vowels are changed to next alphabet according to the alphabetical series and consonants are left as it is and the word is placed to the immediate right of the initially arranged number and all the other elements (words/numbers) are shifted accordingly.

The same process is followed till all the numbers and words are rearranged.

Now given,

Input: 632 euo 756 bdu mpe 125 468 noq vua 241 xtv 845

Step I: 317 xtv 632 euo 756 bdu mpe 468 noq vua 241 845

Step II: 133 vvb 317 xtv 632 euo 756 bdu mpe 468 noq 845

Step III: 357 npq 133 vvb 317 xtv 632 euo 756 bdu mpe 845

Step IV: 551 mpf 357 npq 133 vvb 317 xtv euo 756 bdu 845

Step V: 975 fvp 551 mpf 357 npq 133 vvb 317 xtv bdu 845

Step VI: 737 bdv 975 fvp 551 mpf 357 npq 133 vvb 317 xtv

Last but one means the second last step, here it is step V.

The word which is fourth from the left is ‘mpf’ and the word which is third from the right is ‘xtv’, first letter of ‘mpf’ is m and last letter of ‘xtv’ is x.

Vowels in alphabetical series are: A, E, I, O and U.

Vowels between M and X are O and U.

Number: Numbers are arranged in ascending order from left to right after adding 2 to the odd digit and subtracted 1 from even digit within the number.

Word: Words in the given input are arranged in reverse dictionary order from left to right after replacing the vowel to next letter according to the alphabetical series and consonants remains the same.

Note: A number and word are arranged simultaneously in each step.

Step I: First the smallest number is considered then 2 is added to the odd digits of the number and 1 is subtracted from the even digits and are placed on the leftmost end.

The last word that would appear in the dictionary is considered next and the vowels are changed to next alphabet according to the alphabetical series and consonants are left as it is and the word is placed to the immediate right of the initially arranged number and all the other elements (words/numbers) are shifted accordingly.

The same process is followed till all the numbers and words are rearranged.

Now given,

Input: 632 euo 756 bdu mpe 125 468 noq vua 241 xtv 845

Step I: 317 xtv 632 euo 756 bdu mpe 468 noq vua 241 845

Step II: 133 vvb 317 xtv 632 euo 756 bdu mpe 468 noq 845

Step III: 357 npq 133 vvb 317 xtv 632 euo 756 bdu mpe 845

Step IV: 551 mpf 357 npq 133 vvb 317 xtv euo 756 bdu 845

Step V: 975 fvp 551 mpf 357 npq 133 vvb 317 xtv bdu 845

Step VI: 737 bdv 975 fvp 551 mpf 357 npq 133 vvb 317 xtv

Number: Numbers are arranged in ascending order from left to right after adding 2 to the odd digit and subtracted 1 from even digit within the number.

Word: Words in the given input are arranged in reverse dictionary order from left to right after replacing the vowel to next letter according to the alphabetical series and consonants remains the same.

Note: A number and word are arranged simultaneously in each step.

Step I: First the smallest number is considered then 2 is added to the odd digits of the number and 1 is subtracted from the even digits and are placed on the leftmost end.

The last word that would appear in the dictionary is considered next and the vowels are changed to next alphabet according to the alphabetical series and consonants are left as it is and the word is placed to the immediate right of the initially arranged number and all the other elements (words/numbers) are shifted accordingly.

The same process is followed till all the numbers and words are rearranged.

Now given,

Input: 632 euo 756 bdu mpe 125 468 noq vua 241 xtv 845

Step I: 317 xtv 632 euo 756 bdu mpe 468 noq vua 241 845

Step II: 133 vvb 317 xtv 632 euo 756 bdu mpe 468 noq 845

Step III: 357 npq 133 vvb 317 xtv 632 euo 756 bdu mpe 845

Step IV: 551 mpf 357 npq 133 vvb 317 xtv euo 756 bdu 845

Step V: 975 fvp 551 mpf 357 npq 133 vvb 317 xtv bdu 845

Step VI: 737 bdv 975 fvp 551 mpf 357 npq 133 vvb 317 xtv

Number: Numbers are arranged in ascending order from left to right after adding 2 to the odd digit and subtracted 1 from even digit within the number.

Word: Words in the given input are arranged in reverse dictionary order from left to right after replacing the vowel to next letter according to the alphabetical series and consonants remains the same.

Note: A number and word are arranged simultaneously in each step.

Step I: First the smallest number is considered then 2 is added to the odd digits of the number and 1 is subtracted from the even digits and are placed on the leftmost end.

The last word that would appear in the dictionary is considered next and the vowels are changed to next alphabet according to the alphabetical series and consonants are left as it is and the word is placed to the immediate right of the initially arranged number and all the other elements (words/numbers) are shifted accordingly.

The same process is followed till all the numbers and words are rearranged.

Now given,

Input: 632 euo 756 bdu mpe 125 468 noq vua 241 xtv 845

Step I: 317 xtv 632 euo 756 bdu mpe 468 noq vua 241 845

Step II: 133 vvb 317 xtv 632 euo 756 bdu mpe 468 noq 845

Step III: 357 npq 133 vvb 317 xtv 632 euo 756 bdu mpe 845

Step IV: 551 mpf 357 npq 133 vvb 317 xtv euo 756 bdu 845

Step V: 975 fvp 551 mpf 357 npq 133 vvb 317 xtv bdu 845

Step VI: 737 bdv 975 fvp 551 mpf 357 npq 133 vvb 317 xtv

I. No Ship is Sea → False (Possible but not definite)

II. Some Boat are not Sea → False (Possible but not definite)

So, Neither conclusion I nor II follows.

Option 1 can be inferred because as indicated the schemes have not been able to meet their objective, which clearly suggests a reassessment/re-evaluation needs to be done.

Option 2 cannot be inferred because, no such data indicating year, population rate, etc. have been given. It is an assumption and not an inference.

Option 3 cannot be inferred because it is beyond the scope of what has been stated and way too general.

Option 4 cannot be inferred because passage talks about those below the poverty index from the supplied information we cannot deduce about the other lot of population.

Conclusions:

I. Some people are weak → False (It is possible but not definite)

II. No strong is weak → True (No weak is strong)

III. Some males are weak → True (Only a few males are weak)

IV. All weak are male → False (It is possible but not definite)

Thus, only conclusions II and III follow.

The government cannot just consider the imposition of lockdown once again unless the situation is dire. Health indeed is important but the Economy, which has already taken a hit cannot be neglected. Therefore, course of action I does not follow.

Covid being a communicable disease is spread by coming in contact with people who are infected and do not take necessary precautions. So, both the infected and the healthy ones should abide by the guidelines else be punished. Therefore,course of action II follows.

(1) B is taller than only D.

D is heavier than at least three people but definitely lighter than B.

(2) Position of A in the height table is the same as the position of B in the weight table.

F is taller than at least two people but heavier than at least 4.

There is a difference of four positions of E in both the columns.

(3) Position of C in the height and weight table cannot be the same.

So, the final arrangement is drawn below:

So, E is the lightest person.