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IBPS RRB Clerk Mains Mock Test - 9 - Bank Exams MCQ


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30 Questions MCQ Test - IBPS RRB Clerk Mains Mock Test - 9

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IBPS RRB Clerk Mains Mock Test - 9 - Question 1

Eight people C, D, E, F, G, H, I and J are sitting around a circular table. Some of them are facing the center of the circle. While some of them are facing opposite to the center of the circle. Each person has a different lucky number from 1 to 9.

The direction of E is opposite to D. The person whose lucky number is 3 is second to the left of C. The difference between the lucky numbers of G and J is three. H is immediately right of the one whose lucky number is an even prime number who is not an immediate neighbour of F. The sum of the lucky number is J and H is equal to the lucky number of F. The immediate neighbours of the person whose lucky number is 4 face opposite directions to each other. The person whose lucky number is the multiple of 5 is third to the left of I whose immediate neighbours face opposite directions to each other. F is second to the left of one whose lucky number is the cubic number but not 1. The difference between the lucky numbers of E and G is one. The lucky numbers of J and C are not a prime number. The lucky number of E is not an even number. G sits exactly between F and H. The person whose lucky number is 3 does not face the center of the table. E is immediately right of C and both of them face the same direction. Two people are sitting between F and J who is third to the right of H. One person is sitting between the person whose lucky number is 5 and G.

Q. Which of the following statements are true?

(i) The person whose lucky number is 9 is fourth to the left of the person whose lucky number is 3.

(ii) No one has 7 as a lucky number.

(iii) One person is sitting between D and I.

Detailed Solution for IBPS RRB Clerk Mains Mock Test - 9 - Question 1
F is second to the left of one whose lucky number is the cubic number but not 1. Two people are sitting between F and J who is third to the right of H. H is immediately right of the one whose lucky number is an even prime number who is not an immediate neighbour of F. G sits exactly between F and H. One person is sitting between the person whose lucky number is 5 and G.

As per the above given conditions, there are four possible cases which are given below in Case(i), Case(ii), Case(iii) and Case(iv).

The person whose lucky number is the multiple of 5 is third to the left of I whose immediate neighbours face opposite directions to each other. The lucky number of E is not an even number. E is immediately right of C and both of them face the same direction. The direction of E is opposite to D.

In Case(iii) and Case(iv), the lucky number of E is 5. But after that C is not possible as per the above given condition. So these cases are eliminated.

The person whose lucky number is 3 is second to the left of C. The person whose lucky number is 3 does not face the center of the table.

In Case(ii), the person whose lucky number is 3 faces the center of the table which is not possible as per the condition. So this case is eliminated.

The difference between the lucky numbers of E and G is one.

(E-G) = 1 or (G-E) = 1.

So the values of G can be either 4 or 6.

The difference between the lucky numbers of G and J is three.

(G-J) = 3 or (J-G) = 3

If the lucky number of G is 4, then the lucky number of J will be either 1 or 7.

If the lucky number of G is 6, then the lucky number of J will be either 9 or 3. But 3 have already been taken by I. So the lucky number of J can be 9.

There are two possible lucky numbers for G which are given below in Case(i)(a) and Case(i)(b).

The lucky numbers of J and C are not a prime number. The sum of the lucky number is J and H is equal to the lucky number of F.

In Case(i)(a), as per the first condition, the lucky number of J will not be 7.

Here J + H = F.

In Case(i)(a) 1 + 8 = F. So F = 9.

In Case(i)(b) 9 + 8 = F. So F = 17 which is not possible. So this case is eliminated.

The immediate neighbours of the person whose lucky number is 4 face opposite directions to each other.

Now 6 and 7 are remaining. So the lucky number of C will be 6. Because the lucky number of C should not be a prime number as per the above given condition.

Therefore, we got the final arrangement which is given above.

Hence, option c is the correct answer.

IBPS RRB Clerk Mains Mock Test - 9 - Question 2

Eight people C, D, E, F, G, H, I and J are sitting around a circular table. Some of them are facing the center of the circle. While some of them are facing opposite to the center of the circle. Each person has a different lucky number from 1 to 9.

The direction of E is opposite to D. The person whose lucky number is 3 is second to the left of C. The difference between the lucky numbers of G and J is three. H is immediately right of the one whose lucky number is an even prime number who is not an immediate neighbour of F. The sum of the lucky number is J and H is equal to the lucky number of F. The immediate neighbours of the person whose lucky number is 4 face opposite directions to each other. The person whose lucky number is the multiple of 5 is third to the left of I whose immediate neighbours face opposite directions to each other. F is second to the left of one whose lucky number is the cubic number but not 1. The difference between the lucky numbers of E and G is one. The lucky numbers of J and C are not a prime number. The lucky number of E is not an even number. G sits exactly between F and H. The person whose lucky number is 3 does not face the center of the table. E is immediately right of C and both of them face the same direction. Two people are sitting between F and J who is third to the right of H. One person is sitting between the person whose lucky number is 5 and G.

Q. Which of the following people has the largest lucky number?

Detailed Solution for IBPS RRB Clerk Mains Mock Test - 9 - Question 2
F is second to the left of one whose lucky number is the cubic number but not 1. Two people are sitting between F and J who is third to the right of H. H is immediately right of the one whose lucky number is an even prime number who is not an immediate neighbour of F. G sits exactly between F and H. One person is sitting between the person whose lucky number is 5 and G.

As per the above given conditions, there are four possible cases which are given below in Case(i), Case(ii), Case(iii) and Case(iv).

The person whose lucky number is the multiple of 5 is third to the left of I whose immediate neighbours face opposite directions to each other. The lucky number of E is not an even number. E is immediately right of C and both of them face the same direction. The direction of E is opposite to D.

In Case(iii) and Case(iv), the lucky number of E is 5. But after that C is not possible as per the above given condition. So these cases are eliminated.

The person whose lucky number is 3 is second to the left of C. The person whose lucky number is 3 does not face the center of the table.

In Case(ii), the person whose lucky number is 3 faces the center of the table which is not possible as per the condition. So this case is eliminated.

The difference between the lucky numbers of E and G is one.

(E-G) = 1 or (G-E) = 1.

So the values of G can be either 4 or 6.

The difference between the lucky numbers of G and J is three.

(G-J) = 3 or (J-G) = 3

If the lucky number of G is 4, then the lucky number of J will be either 1 or 7.

If the lucky number of G is 6, then the lucky number of J will be either 9 or 3. But 3 have already been taken by I. So the lucky number of J can be 9.

There are two possible lucky numbers for G which are given below in Case(i)(a) and Case(i)(b).

The lucky numbers of J and C are not a prime number. The sum of the lucky number is J and H is equal to the lucky number of F.

In Case(i)(a), as per the first condition, the lucky number of J will not be 7.

Here J + H = F.

In Case(i)(a) 1 + 8 = F. So F = 9.

In Case(i)(b) 9 + 8 = F. So F = 17 which is not possible. So this case is eliminated.

The immediate neighbours of the person whose lucky number is 4 face opposite directions to each other.

Now 6 and 7 are remaining. So the lucky number of C will be 6. Because the lucky number of C should not be a prime number as per the above given condition.

Therefore, we got the final arrangement which is given above.

According to the above arrangement, F has the largest lucky number.

Hence, option d is the correct answer.

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IBPS RRB Clerk Mains Mock Test - 9 - Question 3

Eight people C, D, E, F, G, H, I and J are sitting around a circular table. Some of them are facing the center of the circle. While some of them are facing opposite to the center of the circle. Each person has a different lucky number from 1 to 9.

The direction of E is opposite to D. The person whose lucky number is 3 is second to the left of C. The difference between the lucky numbers of G and J is three. H is immediately right of the one whose lucky number is an even prime number who is not an immediate neighbour of F. The sum of the lucky number is J and H is equal to the lucky number of F. The immediate neighbours of the person whose lucky number is 4 face opposite directions to each other. The person whose lucky number is the multiple of 5 is third to the left of I whose immediate neighbours face opposite directions to each other. F is second to the left of one whose lucky number is the cubic number but not 1. The difference between the lucky numbers of E and G is one. The lucky numbers of J and C are not a prime number. The lucky number of E is not an even number. G sits exactly between F and H. The person whose lucky number is 3 does not face the center of the table. E is immediately right of C and both of them face the same direction. Two people are sitting between F and J who is third to the right of H. One person is sitting between the person whose lucky number is 5 and G.

Q. If all the people are arranged in alphabetical order around the circular table starting from C in the anticlockwise direction, then the position of how many people remain unchanged (except C).

Detailed Solution for IBPS RRB Clerk Mains Mock Test - 9 - Question 3
F is second to the left of one whose lucky number is the cubic number but not 1. Two people are sitting between F and J who is third to the right of H. H is immediately right of the one whose lucky number is an even prime number who is not an immediate neighbour of F. G sits exactly between F and H. One person is sitting between the person whose lucky number is 5 and G.

As per the above given conditions, there are four possible cases which are given below in Case(i), Case(ii), Case(iii) and Case(iv).

The person whose lucky number is the multiple of 5 is third to the left of I whose immediate neighbours face opposite directions to each other. The lucky number of E is not an even number. E is immediately right of C and both of them face the same direction. The direction of E is opposite to D.

In Case(iii) and Case(iv), the lucky number of E is 5. But after that C is not possible as per the above given condition. So these cases are eliminated.

The person whose lucky number is 3 is second to the left of C. The person whose lucky number is 3 does not face the center of the table.

In Case(ii), the person whose lucky number is 3 faces the center of the table which is not possible as per the condition. So this case is eliminated.

The difference between the lucky numbers of E and G is one.

(E-G) = 1 or (G-E) = 1.

So the values of G can be either 4 or 6.

The difference between the lucky numbers of G and J is three.

(G-J) = 3 or (J-G) = 3

If the lucky number of G is 4, then the lucky number of J will be either 1 or 7.

If the lucky number of G is 6, then the lucky number of J will be either 9 or 3. But 3 have already been taken by I. So the lucky number of J can be 9.

There are two possible lucky numbers for G which are given below in Case(i)(a) and Case(i)(b).

The lucky numbers of J and C are not a prime number. The sum of the lucky number is J and H is equal to the lucky number of F.

In Case(i)(a), as per the first condition, the lucky number of J will not be 7.

Here J + H = F.

In Case(i)(a) 1 + 8 = F. So F = 9.

In Case(i)(b) 9 + 8 = F. So F = 17 which is not possible. So this case is eliminated.

The immediate neighbours of the person whose lucky number is 4 face opposite directions to each other.

Now 6 and 7 are remaining. So the lucky number of C will be 6. Because the lucky number of C should not be a prime number as per the above given condition.

Therefore, we got the final arrangement which is given above.

Hence, option b is the correct answer.

IBPS RRB Clerk Mains Mock Test - 9 - Question 4

Eight people C, D, E, F, G, H, I and J are sitting around a circular table. Some of them are facing the center of the circle. While some of them are facing opposite to the center of the circle. Each person has a different lucky number from 1 to 9.

The direction of E is opposite to D. The person whose lucky number is 3 is second to the left of C. The difference between the lucky numbers of G and J is three. H is immediately right of the one whose lucky number is an even prime number who is not an immediate neighbour of F. The sum of the lucky number is J and H is equal to the lucky number of F. The immediate neighbours of the person whose lucky number is 4 face opposite directions to each other. The person whose lucky number is the multiple of 5 is third to the left of I whose immediate neighbours face opposite directions to each other. F is second to the left of one whose lucky number is the cubic number but not 1. The difference between the lucky numbers of E and G is one. The lucky numbers of J and C are not a prime number. The lucky number of E is not an even number. G sits exactly between F and H. The person whose lucky number is 3 does not face the center of the table. E is immediately right of C and both of them face the same direction. Two people are sitting between F and J who is third to the right of H. One person is sitting between the person whose lucky number is 5 and G.

Q. What is the lucky number of C?

Detailed Solution for IBPS RRB Clerk Mains Mock Test - 9 - Question 4
F is second to the left of one whose lucky number is the cubic number but not 1. Two people are sitting between F and J who is third to the right of H. H is immediately right of the one whose lucky number is an even prime number who is not an immediate neighbour of F. G sits exactly between F and H. One person is sitting between the person whose lucky number is 5 and G.

As per the above given conditions, there are four possible cases which are given below in Case(i), Case(ii), Case(iii) and Case(iv).

The person whose lucky number is the multiple of 5 is third to the left of I whose immediate neighbours face opposite directions to each other. The lucky number of E is not an even number. E is immediately right of C and both of them face the same direction. The direction of E is opposite to D.

In Case(iii) and Case(iv), the lucky number of E is 5. But after that C is not possible as per the above given condition. So these cases are eliminated.

The person whose lucky number is 3 is second to the left of C. The person whose lucky number is 3 does not face the center of the table.

In Case(ii), the person whose lucky number is 3 faces the center of the table which is not possible as per the condition. So this case is eliminated.

The difference between the lucky numbers of E and G is one.

(E-G) = 1 or (G-E) = 1.

So the values of G can be either 4 or 6.

The difference between the lucky numbers of G and J is three.

(G-J) = 3 or (J-G) = 3

If the lucky number of G is 4, then the lucky number of J will be either 1 or 7.

If the lucky number of G is 6, then the lucky number of J will be either 9 or 3. But 3 have already been taken by I. So the lucky number of J can be 9.

There are two possible lucky numbers for G which are given below in Case(i)(a) and Case(i)(b).

The lucky numbers of J and C are not a prime number. The sum of the lucky number is J and H is equal to the lucky number of F.

In Case(i)(a), as per the first condition, the lucky number of J will not be 7.

Here J + H = F.

In Case(i)(a) 1 + 8 = F. So F = 9.

In Case(i)(b) 9 + 8 = F. So F = 17 which is not possible. So this case is eliminated.

The immediate neighbours of the person whose lucky number is 4 face opposite directions to each other.

Now 6 and 7 are remaining. So the lucky number of C will be 6. Because the lucky number of C should not be a prime number as per the above given condition.

Therefore, we got the final arrangement which is given above.

According to the above arrangement, the lucky number of C is 6.

Hence, option b is the correct answer.

IBPS RRB Clerk Mains Mock Test - 9 - Question 5

Eight people C, D, E, F, G, H, I and J are sitting around a circular table. Some of them are facing the center of the circle. While some of them are facing opposite to the center of the circle. Each person has a different lucky number from 1 to 9.

The direction of E is opposite to D. The person whose lucky number is 3 is second to the left of C. The difference between the lucky numbers of G and J is three. H is immediately right of the one whose lucky number is an even prime number who is not an immediate neighbour of F. The sum of the lucky number is J and H is equal to the lucky number of F. The immediate neighbours of the person whose lucky number is 4 face opposite directions to each other. The person whose lucky number is the multiple of 5 is third to the left of I whose immediate neighbours face opposite directions to each other. F is second to the left of one whose lucky number is the cubic number but not 1. The difference between the lucky numbers of E and G is one. The lucky numbers of J and C are not a prime number. The lucky number of E is not an even number. G sits exactly between F and H. The person whose lucky number is 3 does not face the center of the table. E is immediately right of C and both of them face the same direction. Two people are sitting between F and J who is third to the right of H. One person is sitting between the person whose lucky number is 5 and G.

Q. The direction of how many people cannot be determined definitely.

Detailed Solution for IBPS RRB Clerk Mains Mock Test - 9 - Question 5
F is second to the left of one whose lucky number is the cubic number but not 1. Two people are sitting between F and J who is third to the right of H. H is immediately right of the one whose lucky number is an even prime number who is not an immediate neighbour of F. G sits exactly between F and H. One person is sitting between the person whose lucky number is 5 and G.

As per the above given conditions, there are four possible cases which are given below in Case(i), Case(ii), Case(iii) and Case(iv).

The person whose lucky number is the multiple of 5 is third to the left of I whose immediate neighbours face opposite directions to each other. The lucky number of E is not an even number. E is immediately right of C and both of them face the same direction. The direction of E is opposite to D.

In Case(iii) and Case(iv), the lucky number of E is 5. But after that C is not possible as per the above given condition. So these cases are eliminated.

The person whose lucky number is 3 is second to the left of C. The person whose lucky number is 3 does not face the center of the table.

In Case(ii), the person whose lucky number is 3 faces the center of the table which is not possible as per the condition. So this case is eliminated.

The difference between the lucky numbers of E and G is one.

(E-G) = 1 or (G-E) = 1.

So the values of G can be either 4 or 6.

The difference between the lucky numbers of G and J is three.

(G-J) = 3 or (J-G) = 3

If the lucky number of G is 4, then the lucky number of J will be either 1 or 7.

If the lucky number of G is 6, then the lucky number of J will be either 9 or 3. But 3 have already been taken by I. So the lucky number of J can be 9.

There are two possible lucky numbers for G which are given below in Case(i)(a) and Case(i)(b).

The lucky numbers of J and C are not a prime number. The sum of the lucky number is J and H is equal to the lucky number of F.

In Case(i)(a), as per the first condition, the lucky number of J will not be 7.

Here J + H = F.

In Case(i)(a) 1 + 8 = F. So F = 9.

In Case(i)(b) 9 + 8 = F. So F = 17 which is not possible. So this case is eliminated.

The immediate neighbours of the person whose lucky number is 4 face opposite directions to each other.

Now 6 and 7 are remaining. So the lucky number of C will be 6. Because the lucky number of C should not be a prime number as per the above given condition.

Therefore, we got the final arrangement which is given above.

According to the above arrangement, the direction of only one person G cannot be determined definitely.

Hence, option a is the correct answer.

IBPS RRB Clerk Mains Mock Test - 9 - Question 6

Read the following information carefully and answer the question given below:23th

There are 10 persons – P, Q, R, S, T, U, V, W, X and Y had exams on dates 9th, 14th, 23th

and 26th of each month – March, April, May and June but not necessarily in the same order. Not more than three persons have exam on same date and same month. Each person had different score viz. 16, 19, 21, 8, 9 and 10 but not necessarily in the same order.

The one who had exam on even number date scored 21. The one who had exam in March had a score of 8. P had exam on 23th. T scored two times that of W but does not have exam in same month. Q had exam on even number month. V’s exam was not in May. Only Y had exam in the month of June on 26th and scored 10 marks. Neither X nor W had exam in March. R had exam on 14th and had a score equal to the square of month number. S had exam on even date and in even month. T had exam on prime date and in prime number month. W had scored 6 marks less than his date of exam. The one who had exam on 23th had a prime score. The one who had exam earlier than Q had scored 5 marks more than its month number. X had scored same as sum of T’s score and its month number. The one who had exam after W had scored two times that of W. U had exam on date such that it is the square of earlier month number.

Q. Who among the following had exam in May?

Detailed Solution for IBPS RRB Clerk Mains Mock Test - 9 - Question 6
Persons – P, Q, R, S, T, U, V, W, X and Y

Date – 9, 14, 23 and 26

Month – March, April, May and June

Score – 16, 19, 21, 8, 9 and 10

1. Only Y had exam in the month of June on 26 and scored 10 marks. P had exam on 23. R had exam on 14 and had a score equal to the square of month number.

2. T scored two times that of W but not in same month. T had exam on prime date and in prime number month.

Hence, T scored 16 marks and W scored 8 marks. T had exam on 23.

S had exam on even date and in even month.

Hence, S had exam on 14th and in April.

Q had exam on even number month.

Hence, Q had exam in April.

3. W had scored 6 marks less than date of exam.

Hence, W scored 8 marks and had exam on 14.

The one who had exam on even number date scored 21. R had exam on 14 and had a score equal to the square of month number.

Hence, S scored 21 marks and R scored 9 marks and had exam in March

4. U had exam on date such that it is the square of earlier month number.

Hence, U had exam on 9th April.

5. V’s exam was not in May. Neither X nor W had exam in March.

Hence, V’s exam was in March and X and W had exam in May. Q exam was on 23. V and X exam was on 9.

6. The one who had exam earlier than Q had scored 5 marks more than its month number.

As Q had exam on 23rd April and U had exam on 9th April. So, U scored 9 marks.

T scored two times that of W but not in same month.

Hence, T had exam in March.

7. The one who had exam after W had scored two times that of W.

As W exam was on 14th May so P scored 16 marks.

The one who had exam in March had a score of 8.

Hence, V scored 8 marks.

X had scored same as sum of T’s score and its month number.

Hence, X scored 16 + 5 = 21 marks.

The one who had exam on 23 had a prime score.

Hence, Q scored 19 marks.

The one who had exam earlier than Q had scored 5 marks more than its month number.

Hence, U had exam earlier than Q and scored 5 + 4 = 9 marks.

Hence, X had exam in May.

IBPS RRB Clerk Mains Mock Test - 9 - Question 7

Read the following information carefully and answer the question given below:23th

There are 10 persons – P, Q, R, S, T, U, V, W, X and Y had exams on dates 9th, 14th, 23th

and 26th of each month – March, April, May and June but not necessarily in the same order. Not more than three persons have exam on same date and same month. Each person had different score viz. 16, 19, 21, 8, 9 and 10 but not necessarily in the same order.

The one who had exam on even number date scored 21. The one who had exam in March had a score of 8. P had exam on 23th. T scored two times that of W but does not have exam in same month. Q had exam on even number month. V’s exam was not in May. Only Y had exam in the month of June on 26th and scored 10 marks. Neither X nor W had exam in March. R had exam on 14th and had a score equal to the square of month number. S had exam on even date and in even month. T had exam on prime date and in prime number month. W had scored 6 marks less than his date of exam. The one who had exam on 23th had a prime score. The one who had exam earlier than Q had scored 5 marks more than its month number. X had scored same as sum of T’s score and its month number. The one who had exam after W had scored two times that of W. U had exam on date such that it is the square of earlier month number.

Q. Who among the following had exam on same date as W?

Detailed Solution for IBPS RRB Clerk Mains Mock Test - 9 - Question 7
Persons – P, Q, R, S, T, U, V, W, X and Y

Date – 9, 14, 23 and 26

Month – March, April, May and June

Score – 16, 19, 21, 8, 9 and 10

1. Only Y had exam in the month of June on 26 and scored 10 marks. P had exam on 23. R had exam on 14 and had a score equal to the square of month number.

2. T scored two times that of W but not in same month. T had exam on prime date and in prime number month.

Hence, T scored 16 marks and W scored 8 marks. T had exam on 23.

S had exam on even date and in even month.

Hence, S had exam on 14th and in April.

Q had exam on even number month.

Hence, Q had exam in April.

3. W had scored 6 marks less than date of exam.

Hence, W scored 8 marks and had exam on 14.

The one who had exam on even number date scored 21. R had exam on 14 and had a score equal to the square of month number.

Hence, S scored 21 marks and R scored 9 marks and had exam in March

4. U had exam on date such that it is the square of earlier month number.

Hence, U had exam on 9th April.

5. V’s exam was not in May. Neither X nor W had exam in March.

Hence, V’s exam was in March and X and W had exam in May. Q exam was on 23. V and X exam was on 9.

6. The one who had exam earlier than Q had scored 5 marks more than its month number.

As Q had exam on 23rd April and U had exam on 9th April. So, U scored 9 marks.

T scored two times that of W but not in same month.

Hence, T had exam in March.

7. The one who had exam after W had scored two times that of W.

As W exam was on 14th May so P scored 16 marks.

The one who had exam in March had a score of 8.

Hence, V scored 8 marks.

X had scored same as sum of T’s score and its month number.

Hence, X scored 16 + 5 = 21 marks.

The one who had exam on 23 had a prime score.

Hence, Q scored 19 marks.

The one who had exam earlier than Q had scored 5 marks more than its month number.

Hence, U had exam earlier than Q and scored 5 + 4 = 9 marks.

Hence, R had exam on same date as W.

IBPS RRB Clerk Mains Mock Test - 9 - Question 8

Read the following information carefully and answer the question given below:23th

There are 10 persons – P, Q, R, S, T, U, V, W, X and Y had exams on dates 9th, 14th, 23th

and 26th of each month – March, April, May and June but not necessarily in the same order. Not more than three persons have exam on same date and same month. Each person had different score viz. 16, 19, 21, 8, 9 and 10 but not necessarily in the same order.

The one who had exam on even number date scored 21. The one who had exam in March had a score of 8. P had exam on 23th. T scored two times that of W but does not have exam in same month. Q had exam on even number month. V’s exam was not in May. Only Y had exam in the month of June on 26th and scored 10 marks. Neither X nor W had exam in March. R had exam on 14th and had a score equal to the square of month number. S had exam on even date and in even month. T had exam on prime date and in prime number month. W had scored 6 marks less than his date of exam. The one who had exam on 23th had a prime score. The one who had exam earlier than Q had scored 5 marks more than its month number. X had scored same as sum of T’s score and its month number. The one who had exam after W had scored two times that of W. U had exam on date such that it is the square of earlier month number.

Q. Who among the following had exam on 14th April?

Detailed Solution for IBPS RRB Clerk Mains Mock Test - 9 - Question 8
Persons – P, Q, R, S, T, U, V, W, X and Y

Date – 9, 14, 23 and 26

Month – March, April, May and June

Score – 16, 19, 21, 8, 9 and 10

1. Only Y had exam in the month of June on 26 and scored 10 marks. P had exam on 23. R had exam on 14 and had a score equal to the square of month number.

2. T scored two times that of W but not in same month. T had exam on prime date and in prime number month.

Hence, T scored 16 marks and W scored 8 marks. T had exam on 23.

S had exam on even date and in even month.

Hence, S had exam on 14th and in April.

Q had exam on even number month.

Hence, Q had exam in April.

3. W had scored 6 marks less than date of exam.

Hence, W scored 8 marks and had exam on 14.

The one who had exam on even number date scored 21. R had exam on 14 and had a score equal to the square of month number.

Hence, S scored 21 marks and R scored 9 marks and had exam in March

4. U had exam on date such that it is the square of earlier month number.

Hence, U had exam on 9th April.

5. V’s exam was not in May. Neither X nor W had exam in March.

Hence, V’s exam was in March and X and W had exam in May. Q exam was on 23. V and X exam was on 9.

6. The one who had exam earlier than Q had scored 5 marks more than its month number.

As Q had exam on 23rd April and U had exam on 9th April. So, U scored 9 marks.

T scored two times that of W but not in same month.

Hence, T had exam in March.

7. The one who had exam after W had scored two times that of W.

As W exam was on 14th May so P scored 16 marks.

The one who had exam in March had a score of 8.

Hence, V scored 8 marks.

X had scored same as sum of T’s score and its month number.

Hence, X scored 16 + 5 = 21 marks.

The one who had exam on 23 had a prime score.

Hence, Q scored 19 marks.

The one who had exam earlier than Q had scored 5 marks more than its month number.

Hence, U had exam earlier than Q and scored 5 + 4 = 9 marks.

Hence, S had exam on 14th April.

IBPS RRB Clerk Mains Mock Test - 9 - Question 9

Read the following information carefully and answer the question given below:23th

There are 10 persons – P, Q, R, S, T, U, V, W, X and Y had exams on dates 9th, 14th, 23th

and 26th of each month – March, April, May and June but not necessarily in the same order. Not more than three persons have exam on same date and same month. Each person had different score viz. 16, 19, 21, 8, 9 and 10 but not necessarily in the same order.

The one who had exam on even number date scored 21. The one who had exam in March had a score of 8. P had exam on 23th. T scored two times that of W but does not have exam in same month. Q had exam on even number month. V’s exam was not in May. Only Y had exam in the month of June on 26th and scored 10 marks. Neither X nor W had exam in March. R had exam on 14th and had a score equal to the square of month number. S had exam on even date and in even month. T had exam on prime date and in prime number month. W had scored 6 marks less than his date of exam. The one who had exam on 23th had a prime score. The one who had exam earlier than Q had scored 5 marks more than its month number. X had scored same as sum of T’s score and its month number. The one who had exam after W had scored two times that of W. U had exam on date such that it is the square of earlier month number.

Q. How many persons had exam before X?

Detailed Solution for IBPS RRB Clerk Mains Mock Test - 9 - Question 9
Persons – P, Q, R, S, T, U, V, W, X and Y

Date – 9, 14, 23 and 26

Month – March, April, May and June

Score – 16, 19, 21, 8, 9 and 10

1. Only Y had exam in the month of June on 26 and scored 10 marks. P had exam on 23. R had exam on 14 and had a score equal to the square of month number.

2. T scored two times that of W but not in same month. T had exam on prime date and in prime number month.

Hence, T scored 16 marks and W scored 8 marks. T had exam on 23.

S had exam on even date and in even month.

Hence, S had exam on 14th and in April.

Q had exam on even number month.

Hence, Q had exam in April.

3. W had scored 6 marks less than date of exam.

Hence, W scored 8 marks and had exam on 14.

The one who had exam on even number date scored 21. R had exam on 14 and had a score equal to the square of month number.

Hence, S scored 21 marks and R scored 9 marks and had exam in March

4. U had exam on date such that it is the square of earlier month number.

Hence, U had exam on 9th April.

5. V’s exam was not in May. Neither X nor W had exam in March.

Hence, V’s exam was in March and X and W had exam in May. Q exam was on 23. V and X exam was on 9.

6. The one who had exam earlier than Q had scored 5 marks more than its month number.

As Q had exam on 23rd April and U had exam on 9th April. So, U scored 9 marks.

T scored two times that of W but not in same month.

Hence, T had exam in March.

7. The one who had exam after W had scored two times that of W.

As W exam was on 14th May so P scored 16 marks.

The one who had exam in March had a score of 8.

Hence, V scored 8 marks.

X had scored same as sum of T’s score and its month number.

Hence, X scored 16 + 5 = 21 marks.

The one who had exam on 23 had a prime score.

Hence, Q scored 19 marks.

The one who had exam earlier than Q had scored 5 marks more than its month number.

Hence, U had exam earlier than Q and scored 5 + 4 = 9 marks.

Hence, six persons had exam before X.

IBPS RRB Clerk Mains Mock Test - 9 - Question 10

Read the following information carefully and answer the question given below:23th

There are 10 persons – P, Q, R, S, T, U, V, W, X and Y had exams on dates 9th, 14th, 23th

and 26th of each month – March, April, May and June but not necessarily in the same order. Not more than three persons have exam on same date and same month. Each person had different score viz. 16, 19, 21, 8, 9 and 10 but not necessarily in the same order.

The one who had exam on even number date scored 21. The one who had exam in March had a score of 8. P had exam on 23th. T scored two times that of W but does not have exam in same month. Q had exam on even number month. V’s exam was not in May. Only Y had exam in the month of June on 26th and scored 10 marks. Neither X nor W had exam in March. R had exam on 14th and had a score equal to the square of month number. S had exam on even date and in even month. T had exam on prime date and in prime number month. W had scored 6 marks less than his date of exam. The one who had exam on 23th had a prime score. The one who had exam earlier than Q had scored 5 marks more than its month number. X had scored same as sum of T’s score and its month number. The one who had exam after W had scored two times that of W. U had exam on date such that it is the square of earlier month number.

Q. Who among the following scored 16 marks?

Detailed Solution for IBPS RRB Clerk Mains Mock Test - 9 - Question 10
Persons – P, Q, R, S, T, U, V, W, X and Y

Date – 9, 14, 23 and 26

Month – March, April, May and June

Score – 16, 19, 21, 8, 9 and 10

1. Only Y had exam in the month of June on 26 and scored 10 marks. P had exam on 23. R had exam on 14 and had a score equal to the square of month number.

2. T scored two times that of W but not in same month. T had exam on prime date and in prime number month.

Hence, T scored 16 marks and W scored 8 marks. T had exam on 23.

S had exam on even date and in even month.

Hence, S had exam on 14th and in April.

Q had exam on even number month.

Hence, Q had exam in April.

3. W had scored 6 marks less than date of exam.

Hence, W scored 8 marks and had exam on 14.

The one who had exam on even number date scored 21. R had exam on 14 and had a score equal to the square of month number.

Hence, S scored 21 marks and R scored 9 marks and had exam in March

4. U had exam on date such that it is the square of earlier month number.

Hence, U had exam on 9th April.

5. V’s exam was not in May. Neither X nor W had exam in March.

Hence, V’s exam was in March and X and W had exam in May. Q exam was on 23. V and X exam was on 9.

6. The one who had exam earlier than Q had scored 5 marks more than its month number.

As Q had exam on 23rd April and U had exam on 9th April. So, U scored 9 marks.

T scored two times that of W but not in same month.

Hence, T had exam in March.

7. The one who had exam after W had scored two times that of W.

As W exam was on 14th May so P scored 16 marks.

The one who had exam in March had a score of 8.

Hence, V scored 8 marks.

X had scored same as sum of T’s score and its month number.

Hence, X scored 16 + 5 = 21 marks.

The one who had exam on 23 had a prime score.

Hence, Q scored 19 marks.

The one who had exam earlier than Q had scored 5 marks more than its month number.

Hence, U had exam earlier than Q and scored 5 + 4 = 9 marks.

Hence, P scored 16 marks.

IBPS RRB Clerk Mains Mock Test - 9 - Question 11

Read the following information carefully and answer the question given below:23th

There are 10 persons – P, Q, R, S, T, U, V, W, X and Y had exams on dates 9th, 14th, 23th

and 26th of each month – March, April, May and June but not necessarily in the same order. Not more than three persons have exam on same date and same month. Each person had different score viz. 16, 19, 21, 8, 9 and 10 but not necessarily in the same order.

The one who had exam on even number date scored 21. The one who had exam in March had a score of 8. P had exam on 23th. T scored two times that of W but does not have exam in same month. Q had exam on even number month. V’s exam was not in May. Only Y had exam in the month of June on 26th and scored 10 marks. Neither X nor W had exam in March. R had exam on 14th and had a score equal to the square of month number. S had exam on even date and in even month. T had exam on prime date and in prime number month. W had scored 6 marks less than his date of exam. The one who had exam on 23th had a prime score. The one who had exam earlier than Q had scored 5 marks more than its month number. X had scored same as sum of T’s score and its month number. The one who had exam after W had scored two times that of W. U had exam on date such that it is the square of earlier month number.

Q. What is the sum of scores of U and P?

Detailed Solution for IBPS RRB Clerk Mains Mock Test - 9 - Question 11
Persons – P, Q, R, S, T, U, V, W, X and Y

Date – 9, 14, 23 and 26

Month – March, April, May and June

Score – 16, 19, 21, 8, 9 and 10

1. Only Y had exam in the month of June on 26 and scored 10 marks. P had exam on 23. R had exam on 14 and had a score equal to the square of month number.

2. T scored two times that of W but not in same month. T had exam on prime date and in prime number month.

Hence, T scored 16 marks and W scored 8 marks. T had exam on 23.

S had exam on even date and in even month.

Hence, S had exam on 14th and in April.

Q had exam on even number month.

Hence, Q had exam in April.

3. W had scored 6 marks less than date of exam.

Hence, W scored 8 marks and had exam on 14.

The one who had exam on even number date scored 21. R had exam on 14 and had a score equal to the square of month number.

Hence, S scored 21 marks and R scored 9 marks and had exam in March

4. U had exam on date such that it is the square of earlier month number.

Hence, U had exam on 9th April.

5. V’s exam was not in May. Neither X nor W had exam in March.

Hence, V’s exam was in March and X and W had exam in May. Q exam was on 23. V and X exam was on 9.

6. The one who had exam earlier than Q had scored 5 marks more than its month number.

As Q had exam on 23rd April and U had exam on 9th April. So, U scored 9 marks.

T scored two times that of W but not in same month.

Hence, T had exam in March.

7. The one who had exam after W had scored two times that of W.

As W exam was on 14th May so P scored 16 marks.

The one who had exam in March had a score of 8.

Hence, V scored 8 marks.

X had scored same as sum of T’s score and its month number.

Hence, X scored 16 + 5 = 21 marks.

The one who had exam on 23 had a prime score.

Hence, Q scored 19 marks.

The one who had exam earlier than Q had scored 5 marks more than its month number.

Hence, U had exam earlier than Q and scored 5 + 4 = 9 marks.

Hence, the sum of scores of U and P is 25.

IBPS RRB Clerk Mains Mock Test - 9 - Question 12

Nine people K, L, M, N, O, P, Q, R and S are working in nine different companies namely Google, Facebook, Twitter, IBM, TCS, Myntra, Flipkart, Amazon and AJIO. Each person likes different fruits namely Apple, Banana, Grapes, Mango, Cherry, Litchi, Guava, Papaya and Orange. The one who is working in AJIO likes Grapes. R is working in TCS but doesn't like Guava. N likes Cherry but he is not working in Google. The one who likes Apple is not working in Myntra. Neither O nor K likes Apple. Either L or Q is working in Twitter. The one who likes Orange is working in Amazon. P is working in Myntra. S likes Banana. The one who likes Apple is not working in a company whose name starts with ‘T’. Neither M nor K is working in a company whose name starts with ‘A’. Neither K nor P likes Guava. Neither P nor R likes Mango. Both the one who likes Mango and the one who likes Apple are not working in Google. S is not working in Facebook. Neither K nor N is working in Flipkart. L doesn't like Guava.

Q. N is working in which of the following companies?

Detailed Solution for IBPS RRB Clerk Mains Mock Test - 9 - Question 12
R is working in TCS but doesn't like Guava. N likes Cherry but he is not working in Google. Neither O nor K likes Apple. P is working in Myntra. S likes Banana.

The one who likes Apple is not working in Myntra. Neither K nor P likes Guava. Neither P nor R likes Mango. S is not working in Facebook. Neither K nor N is working in Flipkart. Neither M nor K is working in a company whose name starts with ‘A’.

Either L or Q is working in Twitter. The one who likes Apple is not working in a company whose name starts with ‘T’.

There are two possible cases for L and Q which are given below in Case(i) and Case(ii).

The one who likes Orange is working in Amazon. The one who is working in AJIO likes Grapes.

Now M likes Apple. Because that is only possible.

Now we can place Twitter with Guava in both the cases.

Now K likes Mango as per the given conditions.

L doesn't like Guava.

In Case(i) L likes Guava which is not possible as per the above given condition. So this case is eliminated.

Now Litchi and Papaya are remaining which will be placed in blank spaces in either or form.

Both the one who likes Mango and the one who likes Apple are not working in Google.

Then S is the only remaining person who is working in Google.

Now IBM and Facebook are remaining which will be placed in either form on the blank spaces.

Therefore, we got the final arrangement which is given above.

According to the above arrangement, N is working in either IBM or Facebook.

Hence, option c is the correct answer.

IBPS RRB Clerk Mains Mock Test - 9 - Question 13

Nine people K, L, M, N, O, P, Q, R and S are working in nine different companies namely Google, Facebook, Twitter, IBM, TCS, Myntra, Flipkart, Amazon and AJIO. Each person likes different fruits namely Apple, Banana, Grapes, Mango, Cherry, Litchi, Guava, Papaya and Orange. The one who is working in AJIO likes Grapes. R is working in TCS but doesn't like Guava. N likes Cherry but he is not working in Google. The one who likes Apple is not working in Myntra. Neither O nor K likes Apple. Either L or Q is working in Twitter. The one who likes Orange is working in Amazon. P is working in Myntra. S likes Banana. The one who likes Apple is not working in a company whose name starts with ‘T’. Neither M nor K is working in a company whose name starts with ‘A’. Neither K nor P likes Guava. Neither P nor R likes Mango. Both the one who likes Mango and the one who likes Apple are not working in Google. S is not working in Facebook. Neither K nor N is working in Flipkart. L doesn't like Guava.

Q. The one who is working in TCS likes which of the following fruits?

Detailed Solution for IBPS RRB Clerk Mains Mock Test - 9 - Question 13
R is working in TCS but doesn't like Guava. N likes Cherry but he is not working in Google. Neither O nor K likes Apple. P is working in Myntra. S likes Banana.

The one who likes Apple is not working in Myntra. Neither K nor P likes Guava. Neither P nor R likes Mango. S is not working in Facebook. Neither K nor N is working in Flipkart. Neither M nor K is working in a company whose name starts with ‘A’.

Either L or Q is working in Twitter. The one who likes Apple is not working in a company whose name starts with ‘T’.

There are two possible cases for L and Q which are given below in Case(i) and Case(ii).

The one who likes Orange is working in Amazon. The one who is working in AJIO likes Grapes.

Now M likes Apple. Because that is only possible.

Now we can place Twitter with Guava in both the cases.

Now K likes Mango as per the given conditions.

L doesn't like Guava.

In Case(i) L likes Guava which is not possible as per the above given condition. So this case is eliminated.

Now Litchi and Papaya are remaining which will be placed in blank spaces in either or form.

Both the one who likes Mango and the one who likes Apple are not working in Google.

Then S is the only remaining person who is working in Google.

Now IBM and Facebook are remaining which will be placed in either form on the blank spaces.

Therefore, we got the final arrangement which is given above.

According to the above arrangement, the one who is working in TCS likes either Litchi or Papaya.

Hence, option e is the correct answer.

IBPS RRB Clerk Mains Mock Test - 9 - Question 14

Nine people K, L, M, N, O, P, Q, R and S are working in nine different companies namely Google, Facebook, Twitter, IBM, TCS, Myntra, Flipkart, Amazon and AJIO. Each person likes different fruits namely Apple, Banana, Grapes, Mango, Cherry, Litchi, Guava, Papaya and Orange. The one who is working in AJIO likes Grapes. R is working in TCS but doesn't like Guava. N likes Cherry but he is not working in Google. The one who likes Apple is not working in Myntra. Neither O nor K likes Apple. Either L or Q is working in Twitter. The one who likes Orange is working in Amazon. P is working in Myntra. S likes Banana. The one who likes Apple is not working in a company whose name starts with ‘T’. Neither M nor K is working in a company whose name starts with ‘A’. Neither K nor P likes Guava. Neither P nor R likes Mango. Both the one who likes Mango and the one who likes Apple are not working in Google. S is not working in Facebook. Neither K nor N is working in Flipkart. L doesn't like Guava.

Q. Which of the following statements is/are definitely true?

(i) O is working in Amazon.

(ii) P likes Papaya.

(iii) M is working in either Flipkart or Facebook.

Detailed Solution for IBPS RRB Clerk Mains Mock Test - 9 - Question 14
R is working in TCS but doesn't like Guava. N likes Cherry but he is not working in Google. Neither O nor K likes Apple. P is working in Myntra. S likes Banana.

The one who likes Apple is not working in Myntra. Neither K nor P likes Guava. Neither P nor R likes Mango. S is not working in Facebook. Neither K nor N is working in Flipkart. Neither M nor K is working in a company whose name starts with ‘A’.

Either L or Q is working in Twitter. The one who likes Apple is not working in a company whose name starts with ‘T’.

There are two possible cases for L and Q which are given below in Case(i) and Case(ii).

The one who likes Orange is working in Amazon. The one who is working in AJIO likes Grapes.

Now M likes Apple. Because that is only possible.

Now we can place Twitter with Guava in both the cases.

Now K likes Mango as per the given conditions.

L doesn't like Guava.

In Case(i) L likes Guava which is not possible as per the above given condition. So this case is eliminated.

Now Litchi and Papaya are remaining which will be placed in blank spaces in either or form.

Both the one who likes Mango and the one who likes Apple are not working in Google.

Then S is the only remaining person who is working in Google.

Now IBM and Facebook are remaining which will be placed in either form on the blank spaces.

Therefore, we got the final arrangement which is given above.

Hence, option e is the correct answer.

IBPS RRB Clerk Mains Mock Test - 9 - Question 15

Nine people K, L, M, N, O, P, Q, R and S are working in nine different companies namely Google, Facebook, Twitter, IBM, TCS, Myntra, Flipkart, Amazon and AJIO. Each person likes different fruits namely Apple, Banana, Grapes, Mango, Cherry, Litchi, Guava, Papaya and Orange. The one who is working in AJIO likes Grapes. R is working in TCS but doesn't like Guava. N likes Cherry but he is not working in Google. The one who likes Apple is not working in Myntra. Neither O nor K likes Apple. Either L or Q is working in Twitter. The one who likes Orange is working in Amazon. P is working in Myntra. S likes Banana. The one who likes Apple is not working in a company whose name starts with ‘T’. Neither M nor K is working in a company whose name starts with ‘A’. Neither K nor P likes Guava. Neither P nor R likes Mango. Both the one who likes Mango and the one who likes Apple are not working in Google. S is not working in Facebook. Neither K nor N is working in Flipkart. L doesn't like Guava.

Q. Who among the following likes Mango?

Detailed Solution for IBPS RRB Clerk Mains Mock Test - 9 - Question 15
R is working in TCS but doesn't like Guava. N likes Cherry but he is not working in Google. Neither O nor K likes Apple. P is working in Myntra. S likes Banana.

The one who likes Apple is not working in Myntra. Neither K nor P likes Guava. Neither P nor R likes Mango. S is not working in Facebook. Neither K nor N is working in Flipkart. Neither M nor K is working in a company whose name starts with ‘A’.

Either L or Q is working in Twitter. The one who likes Apple is not working in a company whose name starts with ‘T’.

There are two possible cases for L and Q which are given below in Case(i) and Case(ii).

The one who likes Orange is working in Amazon. The one who is working in AJIO likes Grapes.

Now M likes Apple. Because that is only possible.

Now we can place Twitter with Guava in both the cases.

Now K likes Mango as per the given conditions.

L doesn't like Guava.

In Case(i) L likes Guava which is not possible as per the above given condition. So this case is eliminated.

Now Litchi and Papaya are remaining which will be placed in blank spaces in either or form.

Both the one who likes Mango and the one who likes Apple are not working in Google.

Then S is the only remaining person who is working in Google.

Now IBM and Facebook are remaining which will be placed in either form on the blank spaces.

Therefore, we got the final arrangement which is given above.

According to the above arrangement, K likes Mango.

Hence, option b is the correct answer.

IBPS RRB Clerk Mains Mock Test - 9 - Question 16

Nine people K, L, M, N, O, P, Q, R and S are working in nine different companies namely Google, Facebook, Twitter, IBM, TCS, Myntra, Flipkart, Amazon and AJIO. Each person likes different fruits namely Apple, Banana, Grapes, Mango, Cherry, Litchi, Guava, Papaya and Orange. The one who is working in AJIO likes Grapes. R is working in TCS but doesn't like Guava. N likes Cherry but he is not working in Google. The one who likes Apple is not working in Myntra. Neither O nor K likes Apple. Either L or Q is working in Twitter. The one who likes Orange is working in Amazon. P is working in Myntra. S likes Banana. The one who likes Apple is not working in a company whose name starts with ‘T’. Neither M nor K is working in a company whose name starts with ‘A’. Neither K nor P likes Guava. Neither P nor R likes Mango. Both the one who likes Mango and the one who likes Apple are not working in Google. S is not working in Facebook. Neither K nor N is working in Flipkart. L doesn't like Guava.

Q. Who among the following is working in AJIO?

Detailed Solution for IBPS RRB Clerk Mains Mock Test - 9 - Question 16
R is working in TCS but doesn't like Guava. N likes Cherry but he is not working in Google. Neither O nor K likes Apple. P is working in Myntra. S likes Banana.

The one who likes Apple is not working in Myntra. Neither K nor P likes Guava. Neither P nor R likes Mango. S is not working in Facebook. Neither K nor N is working in Flipkart. Neither M nor K is working in a company whose name starts with ‘A’.

Either L or Q is working in Twitter. The one who likes Apple is not working in a company whose name starts with ‘T’.

There are two possible cases for L and Q which are given below in Case(i) and Case(ii).

The one who likes Orange is working in Amazon. The one who is working in AJIO likes Grapes.

Now M likes Apple. Because that is only possible.

Now we can place Twitter with Guava in both the cases.

Now K likes Mango as per the given conditions.

L doesn't like Guava.

In Case(i) L likes Guava which is not possible as per the above given condition. So this case is eliminated.

Now Litchi and Papaya are remaining which will be placed in blank spaces in either or form.

Both the one who likes Mango and the one who likes Apple are not working in Google.

Then S is the only remaining person who is working in Google.

Now IBM and Facebook are remaining which will be placed in either form on the blank spaces.

Therefore, we got the final arrangement which is given above.

According to the above arrangement, either O or L is working in AJIO.

Hence, option d is the correct answer.

IBPS RRB Clerk Mains Mock Test - 9 - Question 17

Read the following information carefully and answer the question given below:

There seven family members T, U, V, W, X, Y and Z lives on different floors of a building in which the first floor is numbered 1 and the topmost floor is numbered 7. Each member has different age 65, 70, 45, 40, 35, 30 and 25. Each member has different profession Architecture, Engineer, Doctor, Lawyer, Teacher and Singer.

Manager is elder to Lawyer. Z is brother of T, who is Architect. One who lives on sixth floor is the oldest in the family. The one who is a Doctor lives on 3rd floor and unmarried also. W is sister of T, who is five year younger to his brother and lives in odd numbered floor but not immediately above Singer. Age of an Engineer is 45 years, and he is a son-in-law of Y who lives on 2nd floor. The one who is Teacher is brother-in-law of V who has a son whose profession is Doctor. U is a Manager, and he has two sons and one daughter. X is a female and is neither a Teacher nor a Singer. The one who is an Engineer lives in odd numbered floor, and he is ten years older to his brother-in-law. Z is not an Engineer nor lives on floor number more than 3. The singer is married and her age is ten times the number floor where she/he lives. The one who is the Teacher is the maternal uncle of X whose age is a perfect square and lives on immediately above who is Lawyer. Y is Lawyer and married to U who lives on even numbered floor above 3. Difference between the age of Manager and Lawyer is 5. The one who is Teacher is younger to Singer but older to one who is Architecture. There are only three females in the family and two married couples. Both Y and U whose age is LCM of a fourteen and five don’t have siblings.

Q. Which of the following combination is true?

Detailed Solution for IBPS RRB Clerk Mains Mock Test - 9 - Question 17
Y is Lawyer and married to U who lives on even numbered floor above 3. One who lives on sixth floor is oldest in the family. The one who is a Doctor lives on 3rd floor and he is unmarried.

Case I

Case2

Age of an Engineer is 45 years, and he is son-in-law of Y who lives on 2nd floor.

Case 1

Case2

Only V is left means he is husband of W and brother-in-law of Z and T. Age of an Engineer is 45 years, and he is son-in-law of Y who lives on 2nd floor. The one who is an Engineer lives on odd numbered floor, and he is ten year older to his brother-in-law.

Age of Engineer means V is 45 years then age of Z or T can be 35 years. W is sister of T, who is five years younger to his brother and lives in even numbered floor.

Age of Z–Age of T = 5

Means Z elder to T and Z is 10 years younger to his brother-in-law V whose age is 45.

Z’s age is 35 and age of T would be 30 years. The one who is Teacher is younger to Singer but older to one who is Architecture means age of a singer can be 40, 70 and 65

As age U is LCM of fourteen and five means 70 hence the age of Singer can be 40. The Singer is married and her age is ten times the number floor where she/he lives, and she lives on 4th floor. Age of Y is 65 years and she is Lawyer. Since, Manager is elder to Lawyer.

Case 1

Case 2 is eliminated since W lives on 4th floor.

Case 2

Case1

Z is not an Engineer nor lives on floor more than 3. So, Z lives on floor 1. X lives immediately above the person one who is Lawyer. T cannot immediately above the floor of Singer. Final arrangement as follows.

IBPS RRB Clerk Mains Mock Test - 9 - Question 18

Read the following information carefully and answer the question given below:

There seven family members T, U, V, W, X, Y and Z lives on different floors of a building in which the first floor is numbered 1 and the topmost floor is numbered 7. Each member has different age 65, 70, 45, 40, 35, 30 and 25. Each member has different profession Architecture, Engineer, Doctor, Lawyer, Teacher and Singer.

Manager is elder to Lawyer. Z is brother of T, who is Architect. One who lives on sixth floor is the oldest in the family. The one who is a Doctor lives on 3rd floor and unmarried also. W is sister of T, who is five year younger to his brother and lives in odd numbered floor but not immediately above Singer. Age of an Engineer is 45 years, and he is a son-in-law of Y who lives on 2nd floor. The one who is Teacher is brother-in-law of V who has a son whose profession is Doctor. U is a Manager, and he has two sons and one daughter. X is a female and is neither a Teacher nor a Singer. The one who is an Engineer lives in odd numbered floor, and he is ten years older to his brother-in-law. Z is not an Engineer nor lives on floor number more than 3. The singer is married and her age is ten times the number floor where she/he lives. The one who is the Teacher is the maternal uncle of X whose age is a perfect square and lives on immediately above who is Lawyer. Y is Lawyer and married to U who lives on even numbered floor above 3. Difference between the age of Manager and Lawyer is 5. The one who is Teacher is younger to Singer but older to one who is Architecture. There are only three females in the family and two married couples. Both Y and U whose age is LCM of a fourteen and five don’t have siblings.

Q. Which of the following statement/s are true?

Detailed Solution for IBPS RRB Clerk Mains Mock Test - 9 - Question 18
Y is Lawyer and married to U who lives on even numbered floor above 3. One who lives on sixth floor is oldest in the family. The one who is a Doctor lives on 3rd floor and he is unmarried.

Case I

Case2

Age of an Engineer is 45 years, and he is son-in-law of Y who lives on 2nd floor.

Case 1

Case2

Only V is left means he is husband of W and brother-in-law of Z and T. Age of an Engineer is 45 years, and he is son-in-law of Y who lives on 2nd floor. The one who is an Engineer lives on odd numbered floor, and he is ten year older to his brother-in-law.

Age of Engineer means V is 45 years then age of Z or T can be 35 years. W is sister of T, who is five years younger to his brother and lives in even numbered floor.

Age of Z–Age of T = 5

Means Z elder to T and Z is 10 years younger to his brother-in-law V whose age is 45.

Z’s age is 35 and age of T would be 30 years. The one who is Teacher is younger to Singer but older to one who is Architecture means age of a singer can be 40, 70 and 65

As age U is LCM of fourteen and five means 70 hence the age of Singer can be 40. The Singer is married and her age is ten times the number floor where she/he lives, and she lives on 4th floor. Age of Y is 65 years and she is Lawyer. Since, Manager is elder to Lawyer.

Case 1

Case 2 is eliminated since W lives on 4th floor.

Case 2

Case1

Z is not an Engineer nor lives on floor more than 3. So, Z lives on floor 1. X lives immediately above the person one who is Lawyer. T cannot immediately above the floor of Singer. Final arrangement as follows.

IBPS RRB Clerk Mains Mock Test - 9 - Question 19

Read the following information carefully and answer the question given below:

There seven family members T, U, V, W, X, Y and Z lives on different floors of a building in which the first floor is numbered 1 and the topmost floor is numbered 7. Each member has different age 65, 70, 45, 40, 35, 30 and 25. Each member has different profession Architecture, Engineer, Doctor, Lawyer, Teacher and Singer.

Manager is elder to Lawyer. Z is brother of T, who is Architect. One who lives on sixth floor is the oldest in the family. The one who is a Doctor lives on 3rd floor and unmarried also. W is sister of T, who is five year younger to his brother and lives in odd numbered floor but not immediately above Singer. Age of an Engineer is 45 years, and he is a son-in-law of Y who lives on 2nd floor. The one who is Teacher is brother-in-law of V who has a son whose profession is Doctor. U is a Manager, and he has two sons and one daughter. X is a female and is neither a Teacher nor a Singer. The one who is an Engineer lives in odd numbered floor, and he is ten years older to his brother-in-law. Z is not an Engineer nor lives on floor number more than 3. The singer is married and her age is ten times the number floor where she/he lives. The one who is the Teacher is the maternal uncle of X whose age is a perfect square and lives on immediately above who is Lawyer. Y is Lawyer and married to U who lives on even numbered floor above 3. Difference between the age of Manager and Lawyer is 5. The one who is Teacher is younger to Singer but older to one who is Architecture. There are only three females in the family and two married couples. Both Y and U whose age is LCM of a fourteen and five don’t have siblings.

Q. Who is architect and by how much year he is younger to the person who is singer?

Detailed Solution for IBPS RRB Clerk Mains Mock Test - 9 - Question 19
Y is Lawyer and married to U who lives on even numbered floor above 3. One who lives on sixth floor is oldest in the family. The one who is a Doctor lives on 3rd floor and he is unmarried.

Case I

Case2

Age of an Engineer is 45 years, and he is son-in-law of Y who lives on 2nd floor.

Case 1

Case2

Only V is left means he is husband of W and brother-in-law of Z and T. Age of an Engineer is 45 years, and he is son-in-law of Y who lives on 2nd floor. The one who is an Engineer lives on odd numbered floor, and he is ten year older to his brother-in-law.

Age of Engineer means V is 45 years then age of Z or T can be 35 years. W is sister of T, who is five years younger to his brother and lives in even numbered floor.

Age of Z–Age of T = 5

Means Z elder to T and Z is 10 years younger to his brother-in-law V whose age is 45.

Z’s age is 35 and age of T would be 30 years. The one who is Teacher is younger to Singer but older to one who is Architecture means age of a singer can be 40, 70 and 65

As age U is LCM of fourteen and five means 70 hence the age of Singer can be 40. The Singer is married and her age is ten times the number floor where she/he lives, and she lives on 4th floor. Age of Y is 65 years and she is Lawyer. Since, Manager is elder to Lawyer.

Case 1

Case 2 is eliminated since W lives on 4th floor.

Case 2

Case1

Z is not an Engineer nor lives on floor more than 3. So, Z lives on floor 1. X lives immediately above the person one who is Lawyer. T cannot immediately above the floor of Singer. Final arrangement as follows.

IBPS RRB Clerk Mains Mock Test - 9 - Question 20

Read the following information carefully and answer the question given below:

There seven family members T, U, V, W, X, Y and Z lives on different floors of a building in which the first floor is numbered 1 and the topmost floor is numbered 7. Each member has different age 65, 70, 45, 40, 35, 30 and 25. Each member has different profession Architecture, Engineer, Doctor, Lawyer, Teacher and Singer.

Manager is elder to Lawyer. Z is brother of T, who is Architect. One who lives on sixth floor is the oldest in the family. The one who is a Doctor lives on 3rd floor and unmarried also. W is sister of T, who is five year younger to his brother and lives in odd numbered floor but not immediately above Singer. Age of an Engineer is 45 years, and he is a son-in-law of Y who lives on 2nd floor. The one who is Teacher is brother-in-law of V who has a son whose profession is Doctor. U is a Manager, and he has two sons and one daughter. X is a female and is neither a Teacher nor a Singer. The one who is an Engineer lives in odd numbered floor, and he is ten years older to his brother-in-law. Z is not an Engineer nor lives on floor number more than 3. The singer is married and her age is ten times the number floor where she/he lives. The one who is the Teacher is the maternal uncle of X whose age is a perfect square and lives on immediately above who is Lawyer. Y is Lawyer and married to U who lives on even numbered floor above 3. Difference between the age of Manager and Lawyer is 5. The one who is Teacher is younger to Singer but older to one who is Architecture. There are only three females in the family and two married couples. Both Y and U whose age is LCM of a fourteen and five don’t have siblings.

Q. Which of the flowing pairs represents two husbands of married couples?

Detailed Solution for IBPS RRB Clerk Mains Mock Test - 9 - Question 20
Y is Lawyer and married to U who lives on even numbered floor above 3. One who lives on sixth floor is oldest in the family. The one who is a Doctor lives on 3rd floor and he is unmarried.

Case I

Case2

Age of an Engineer is 45 years, and he is son-in-law of Y who lives on 2nd floor.

Case 1

Case2

Only V is left means he is husband of W and brother-in-law of Z and T. Age of an Engineer is 45 years, and he is son-in-law of Y who lives on 2nd floor. The one who is an Engineer lives on odd numbered floor, and he is ten year older to his brother-in-law.

Age of Engineer means V is 45 years then age of Z or T can be 35 years. W is sister of T, who is five years younger to his brother and lives in even numbered floor.

Age of Z–Age of T = 5

Means Z elder to T and Z is 10 years younger to his brother-in-law V whose age is 45.

Z’s age is 35 and age of T would be 30 years. The one who is Teacher is younger to Singer but older to one who is Architecture means age of a singer can be 40, 70 and 65

As age U is LCM of fourteen and five means 70 hence the age of Singer can be 40. The Singer is married and her age is ten times the number floor where she/he lives, and she lives on 4th floor. Age of Y is 65 years and she is Lawyer. Since, Manager is elder to Lawyer.

Case 1

Case 2 is eliminated since W lives on 4th floor.

Case 2

Case1

Z is not an Engineer nor lives on floor more than 3. So, Z lives on floor 1. X lives immediately above the person one who is Lawyer. T cannot immediately above the floor of Singer. Final arrangement as follows.

IBPS RRB Clerk Mains Mock Test - 9 - Question 21

Read the following information carefully and answer the question given below:

There seven family members T, U, V, W, X, Y and Z lives on different floors of a building in which the first floor is numbered 1 and the topmost floor is numbered 7. Each member has different age 65, 70, 45, 40, 35, 30 and 25. Each member has different profession Architecture, Engineer, Doctor, Lawyer, Teacher and Singer.

Manager is elder to Lawyer. Z is brother of T, who is Architect. One who lives on sixth floor is the oldest in the family. The one who is a Doctor lives on 3rd floor and unmarried also. W is sister of T, who is five year younger to his brother and lives in odd numbered floor but not immediately above Singer. Age of an Engineer is 45 years, and he is a son-in-law of Y who lives on 2nd floor. The one who is Teacher is brother-in-law of V who has a son whose profession is Doctor. U is a Manager, and he has two sons and one daughter. X is a female and is neither a Teacher nor a Singer. The one who is an Engineer lives in odd numbered floor, and he is ten years older to his brother-in-law. Z is not an Engineer nor lives on floor number more than 3. The singer is married and her age is ten times the number floor where she/he lives. The one who is the Teacher is the maternal uncle of X whose age is a perfect square and lives on immediately above who is Lawyer. Y is Lawyer and married to U who lives on even numbered floor above 3. Difference between the age of Manager and Lawyer is 5. The one who is Teacher is younger to Singer but older to one who is Architecture. There are only three females in the family and two married couples. Both Y and U whose age is LCM of a fourteen and five don’t have siblings.

Q. How is doctor related to the person who lives on 5th floor of the building?

Detailed Solution for IBPS RRB Clerk Mains Mock Test - 9 - Question 21
Y is Lawyer and married to U who lives on even numbered floor above 3. One who lives on sixth floor is oldest in the family. The one who is a Doctor lives on 3rd floor and he is unmarried.

Case I

Case2

Age of an Engineer is 45 years, and he is son-in-law of Y who lives on 2nd floor.

Case 1

Case2

Only V is left means he is husband of W and brother-in-law of Z and T. Age of an Engineer is 45 years, and he is son-in-law of Y who lives on 2nd floor. The one who is an Engineer lives on odd numbered floor, and he is ten year older to his brother-in-law.

Age of Engineer means V is 45 years then age of Z or T can be 35 years. W is sister of T, who is five years younger to his brother and lives in even numbered floor.

Age of Z–Age of T = 5

Means Z elder to T and Z is 10 years younger to his brother-in-law V whose age is 45.

Z’s age is 35 and age of T would be 30 years. The one who is Teacher is younger to Singer but older to one who is Architecture means age of a singer can be 40, 70 and 65

As age U is LCM of fourteen and five means 70 hence the age of Singer can be 40. The Singer is married and her age is ten times the number floor where she/he lives, and she lives on 4th floor. Age of Y is 65 years and she is Lawyer. Since, Manager is elder to Lawyer.

Case 1

Case 2 is eliminated since W lives on 4th floor.

Case 2

Case1

Z is not an Engineer nor lives on floor more than 3. So, Z lives on floor 1. X lives immediately above the person one who is Lawyer. T cannot immediately above the floor of Singer. Final arrangement as follows.

IBPS RRB Clerk Mains Mock Test - 9 - Question 22

There are nine members P, Q, R, S, T, D, E, F and G in a family. R is the paternal grandfather of D. Q is the mother-in-law of P who has two children. E is the mother of S who is the sister of D. T who is the child of F is the brother-in-law of P. No one in the first generation is unmarried. The number of males are more than the number of females in the family. P has no sibling. Each couple is having at least one child.

Q. How is D related to T?

Detailed Solution for IBPS RRB Clerk Mains Mock Test - 9 - Question 22
In the following Blood relation diagrams,

Square is represented as Male.

Circle is represented as Female.

Double horizontal line is represented as couples.

Single horizontal line is represented as siblings.

Vertical line is represented as Mother/Father/Son/Daughter.

D is the Nephew of T.

Hence, option a is the correct answer.

IBPS RRB Clerk Mains Mock Test - 9 - Question 23

There are nine members P, Q, R, S, T, D, E, F and G in a family. R is the paternal grandfather of D. Q is the mother-in-law of P who has two children. E is the mother of S who is the sister of D. T who is the child of F is the brother-in-law of P. No one in the first generation is unmarried. The number of males are more than the number of females in the family. P has no sibling. Each couple is having at least one child.

Q. How many males are unmarried in the family?

Detailed Solution for IBPS RRB Clerk Mains Mock Test - 9 - Question 23
In the following Blood relation diagrams,

Square is represented as Male.

Circle is represented as Female.

Double horizontal line is represented as couples.

Single horizontal line is represented as siblings.

Vertical line is represented as Mother/Father/Son/Daughter.

Two males (D and T) are unmarried in the family

Hence, option b is the correct answer.

IBPS RRB Clerk Mains Mock Test - 9 - Question 24

There are nine members P, Q, R, S, T, D, E, F and G in a family. R is the paternal grandfather of D. Q is the mother-in-law of P who has two children. E is the mother of S who is the sister of D. T who is the child of F is the brother-in-law of P. No one in the first generation is unmarried. The number of males are more than the number of females in the family. P has no sibling. Each couple is having at least one child.

Q. How F is related to E?

Detailed Solution for IBPS RRB Clerk Mains Mock Test - 9 - Question 24
In the following Blood relation diagrams,

Square is represented as Male.

Circle is represented as Female.

Double horizontal line is represented as couples.

Single horizontal line is represented as siblings.

Vertical line is represented as Mother/Father/Son/Daughter.

F is the father of E.

Hence, option c is the correct answer.

IBPS RRB Clerk Mains Mock Test - 9 - Question 25

Read the following information carefully and answer the question given below-

There are six children A, B, C, D, E and F playing in a park. Each of them is sitting in a row at a certain distance facing north but not necessarily in the same order. The total length of the row is 98 m. A and B sit at the extreme ends of the row. A doesn’t sit to right of D. Only two children sit between C and B. The distance between C and B is 58 m. The distance between A and D is same as the distance between C and D. The distance between C and E is 6 m more than the distance between B and F. sits to the right of C but not immediate right. The distance between E and F is 2 m less than the distance between C and E.

Q. If B walks 8m south to reach point Y, then in which direction is Y with respect to F?

Detailed Solution for IBPS RRB Clerk Mains Mock Test - 9 - Question 25
The total length of the row is 98m. A and B sit at the extreme ends of the row. A doesn’t sit to right of D.

Only two children sit between C and B. The distance between C and B is 58m. The distance between A and D is same as the distance between C and D.

The distance between C and E is 6m more than the distance between B and F. F sits to the right of D but not immediate right.

(C – E ) - (B-F) = 6m

(C – E ) – ( E – F ) = 2m

Only Possiblity for the above condition to follow is: If Distance between C and E is 22m , E and F is 20m and F and B is 16m. Case 1 is invalid since these conditions are not valid for Case 1 We have Case 2 and final arrangement would be as follows.

Thus point Y is in south east of point F.

IBPS RRB Clerk Mains Mock Test - 9 - Question 26

Read the following information carefully and answer the question given below-

There are six children A, B, C, D, E and F playing in a park. Each of them is sitting in a row at a certain distance facing north but not necessarily in the same order. The total length of the row is 98 m. A and B sit at the extreme ends of the row. A doesn’t sit to right of D. Only two children sit between C and B. The distance between C and B is 58 m. The distance between A and D is same as the distance between C and D. The distance between C and E is 6 m more than the distance between B and F. sits to the right of C but not immediate right. The distance between E and F is 2 m less than the distance between C and E.

Q. If D walks 15m south, turn left to his left and walks 42m to reach Z, then what is the shortest distance between Z and F.

Detailed Solution for IBPS RRB Clerk Mains Mock Test - 9 - Question 26
The total length of the row is 98m. A and B sit at the extreme ends of the row. A doesn’t sit to right of D.

Only two children sit between C and B. The distance between C and B is 58m. The distance between A and D is same as the distance between C and D.

The distance between C and E is 6m more than the distance between B and F. F sits to the right of D but not immediate right.

(C – E ) - (B-F) = 6m

(C – E ) – ( E – F ) = 2m

Only Possiblity for the above condition to follow is: If Distance between C and E is 22m , E and F is 20m and F and B is 16m. Case 1 is invalid since these conditions are not valid for Case 1 We have Case 2 and final arrangement would be as follows.

If D walks 15m south ,turn left to his left and walks 42m to reach Z.

IBPS RRB Clerk Mains Mock Test - 9 - Question 27

Read the following information carefully and answer the question given below-

There are six children A, B, C, D, E and F playing in a park. Each of them is sitting in a row at a certain distance facing north but not necessarily in the same order. The total length of the row is 98 m. A and B sit at the extreme ends of the row. A doesn’t sit to right of D. Only two children sit between C and B. The distance between C and B is 58 m. The distance between A and D is same as the distance between C and D. The distance between C and E is 6 m more than the distance between B and F. sits to the right of C but not immediate right. The distance between E and F is 2 m less than the distance between C and E.

Q. If E walks 20m north and turn left, after walking 62m he reach point W. He is in which direction respect with respect to point A and what is the distance between A and W.

Detailed Solution for IBPS RRB Clerk Mains Mock Test - 9 - Question 27

The total length of the row is 98m. A and B sit at the extreme ends of the row. A doesn’t sit to right of D.

Only two children sit between C and B. The distance between C and B is 58m. The distance between A and D is same as the distance between C and D.

The distance between C and E is 6m more than the distance between B and F. F sits to the right of D but not immediate right.

(C – E ) - (B-F) = 6m

(C – E ) – ( E – F ) = 2m

Only Possiblity for the above condition to follow is: If Distance between C and E is 22m , E and F is 20m and F and B is 16m. Case 1 is invalid since these conditions are not valid for Case 1 We have Case 2 and final arrangement would be as follows.

W is in North direction with respect to A and Distance between D and A is 20 m

IBPS RRB Clerk Mains Mock Test - 9 - Question 28

Read the following information carefully and answer the question given below-

There are six children A, B, C, D, E and F playing in a park. Each of them is sitting in a row at a certain distance facing north but not necessarily in the same order. The total length of the row is 98 m. A and B sit at the extreme ends of the row. A doesn’t sit to right of D. Only two children sit between C and B. The distance between C and B is 58 m. The distance between A and D is same as the distance between C and D. The distance between C and E is 6 m more than the distance between B and F. sits to the right of C but not immediate right. The distance between E and F is 2 m less than the distance between C and E.

Q. If E walks 10m north, turns to his left and walks 22m to reach point X, then what is the shortest between X and D?

Detailed Solution for IBPS RRB Clerk Mains Mock Test - 9 - Question 28
The total length of the row is 98m. A and B sit at the extreme ends of the row. A doesn’t sit to right of D.

Only two children sit between C and B. The distance between C and B is 58m. The distance between A and D is same as the distance between C and D.

The distance between C and E is 6m more than the distance between B and F. F sits to the right of D but not immediate right.

(C – E ) - (B-F) = 6m

(C – E ) – ( E – F ) = 2m

Only Possiblity for the above condition to follow is: If Distance between C and E is 22m , E and F is 20m and F and B is 16m. Case 1 is invalid since these conditions are not valid for Case 1 We have Case 2 and final arrangement would be as follows.

IBPS RRB Clerk Mains Mock Test - 9 - Question 29

Twelve people O, P, Q, R, S, T, U, V, W, X, Y and Z are sitting around a hexagonal table. Six people sit at the corner of the table and face the center. While the remaining six people sit at the middle of the side of the table and face opposite to the center. S and W are immediate neighbours of each other. U is not an immediate neighbour of R. Two people are sitting between Y and Q. One person is sitting between T and X who is an immediate neighbour of O. P faces Z who is third to the left of T. Three people are sitting between O and R who is second to the right of Y.

Q. Who among the following sits opposite to T?

Detailed Solution for IBPS RRB Clerk Mains Mock Test - 9 - Question 29
P faces Z who is third to the left of T. One person is sitting between T and X who is an immediate neighbour of O.

Here X is possible in two places which are given below in Case(i) and Case(ii).

Three people are sitting between O and R who is second to the right of Y.

In Case(i), Y is not possible as per the above given condition. So this case is eliminated.

Two people are sitting between Y and Q. S and W are immediate neighbours of each other.

In Case(ii), Q is possible in two places which are given below in Case(ii)(a) and Case(ii)(b).

In Case(ii)(a), immediate places for S and W are not available as per the given condition. So this case is eliminated.

U is not an immediate neighbour of R.

Now only V is remaining which will be placed on the blank space.

Therefore, we got the final arrangement which is given above.

According to the above arrangement, V sits opposite to T.

Hence, option b is the correct answer.

IBPS RRB Clerk Mains Mock Test - 9 - Question 30

Twelve people O, P, Q, R, S, T, U, V, W, X, Y and Z are sitting around a hexagonal table. Six people sit at the corner of the table and face the center. While the remaining six people sit at the middle of the side of the table and face opposite to the center. S and W are immediate neighbours of each other. U is not an immediate neighbour of R. Two people are sitting between Y and Q. One person is sitting between T and X who is an immediate neighbour of O. P faces Z who is third to the left of T. Three people are sitting between O and R who is second to the right of Y.

Q. Which of the following is odd?

Detailed Solution for IBPS RRB Clerk Mains Mock Test - 9 - Question 30
P faces Z who is third to the left of T. One person is sitting between T and X who is an immediate neighbour of O.

Here X is possible in two places which are given below in Case(i) and Case(ii).

Three people are sitting between O and R who is second to the right of Y.

In Case(i), Y is not possible as per the above given condition. So this case is eliminated.

Two people are sitting between Y and Q. S and W are immediate neighbours of each other.

In Case(ii), Q is possible in two places which are given below in Case(ii)(a) and Case(ii)(b).

In Case(ii)(a), immediate places for S and W are not available as per the given condition. So this case is eliminated.

U is not an immediate neighbour of R.

Now only V is remaining which will be placed on the blank space.

Therefore, we got the final arrangement which is given above.

According to the above arrangement, except Y, all the people given in the option faces outside the center.

Hence, option e is the correct answer.

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