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Banking Exams Exam  >  Banking Exams Tests  >  Test: Line Graph - Banking Exams MCQ

Test: Line Graph - Banking Exams MCQ


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10 Questions MCQ Test - Test: Line Graph

Test: Line Graph for Banking Exams 2024 is part of Banking Exams preparation. The Test: Line Graph questions and answers have been prepared according to the Banking Exams exam syllabus.The Test: Line Graph MCQs are made for Banking Exams 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Line Graph below.
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Test: Line Graph - Question 1
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Study the following line chart carefully and answer the questions given beside.

In the line graph, total members enrolled in different years from 2010 to 2014 in two Zumba classes A and B are given.

If in the year 2015, there is 20% increase in total number of members enrolled than in 2014 by both classes, then find the total number of members enrolled in 2015?

Detailed Solution for Test: Line Graph - Question 1

In Zumba A
 
In 2014, number of members enrolled = 70
 
In 2015, number of members enrolled = 70 (1.2) = 84
 
In Zumba B,
 
In 2014, number of members enrolled = 150
 
In 2015, number of members enrolled = 150 (1.2) = 180
 
Total = 84 + 180 = 264
 
Hence, option D is correct.

Test: Line Graph - Question 2
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Study the following line chart carefully and answer the questions given beside.

In the line graph, total members enrolled in different years from 2010 to 2014 in two Zumba classes A and B are given.

The number of members enrolled in 2015 is 10% more than the members enrolled in 2014 in both the classes. If 40 members from Zumba A and 30 members from Zumba B cancelled their enrolment in 2015, then find the total number of members enrolled in 2015 in both the classes together?

Detailed Solution for Test: Line Graph - Question 2

Zumba A,
 
In 2014, the number of members enrolled = 70
 
In 2015, the number of members enrolled = 70 (1.1) = 77
 
40 members cancelled their enrolment, so the number of members enrolled = 77 – 40 = 37
 
Zumba B,
 
In 2014, the number of members enrolled = 150
 
In 2015, the number of members enrolled = 150 (1.1) = 165
 
30 members cancelled their enrolment, so the number of members enrolled = 165 – 30 = 135
 
Total members enrolled from both classes = 37 + 135 = 172
 
Hence, option E is correct.

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Test: Line Graph - Question 3
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Study the graph and answer the following questions.

Following Line Graph shows number of Employees over four different cities of a company. 

The ratio of the total employees of the company in Bangalore to the total employees of the company in four cities is –

Detailed Solution for Test: Line Graph - Question 3

Given,

Total number of male employees of a company over four cities

= 5500 + 4000 + 9500 + 8500 = 27500

Total number of female employees of a company over four cities

= 4500 + 6000 + 2000 + 6000 = 18500

Number of male and female employee in Bangalore is 8500 and 6000 respectively.

Required ratio = (6000 + 8500) : (27500 + 18500)

= 14500 : 46000 = 29 : 92

Test: Line Graph - Question 4
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Study the graph and answer the following questions.

Following Line Graph shows number of Employees over four different cities of a company. 

Q. Which city has the lowest male to female ratio?
Detailed Solution for Test: Line Graph - Question 4

Given,

For Mumbai: 5500/4500 = 11/9 = 1.22

For Pune: 4000/6000 = 2/3 = 0.66

For Delhi: 9500/2000 = 19/4 = 4.75

For Bangalore: 8500/6000 = 17/12 = 1.41

From above, Pune has the lowest male to female ratio.

Test: Line Graph - Question 5
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Study the graph and answer the following questions.

The graph below shows percentage profit earned by a shopkeeper on different articles.

Q. If the profit earned by the shopkeeper in article D is equal to Rs 144 then the find the marked price of article D, if 20% discount was allowed?
Detailed Solution for Test: Line Graph - Question 5

Hence, Option B is correct.

Test: Line Graph - Question 6
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Study the graph and answer the following questions.

The graph below shows percentage profit earned by a shopkeeper on different articles.

Q. If the marked price of article A is Rs.640 while the discount allowed in article A is 10% then find the cost price of article A?
Detailed Solution for Test: Line Graph - Question 6

Hence, Option B is correct.

Test: Line Graph - Question 7
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Study the graph and answer the following questions.

The graph below shows percentage profit earned by a shopkeeper on different articles.

Q. 12% discount was allowed on article B which is equal to Rs.240, then find the profit percentage, if no discount is allowed in article B.
Detailed Solution for Test: Line Graph - Question 7

Profit when no discount was allowed= 2000 – 1408 = Rs. 592

Hence, Option B is correct.

Test: Line Graph - Question 8
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Study the line graph and answer the question that follows.

The line graph represents the number of vehicles (in thousands) manufactured by two automobile companies A and B over the years from 2010 to 2015. The X-axis represents the years and the Y-axis represents number of vehicles in thousands.

(The data shown here is only for mathematical exercise. They do not represent the actual figures of the country.)

Q. The average value of the vehicles manufactured by Company A is what per cent of the average value of the vehicles manufactured by Company B during 2010 to 2015?
Detailed Solution for Test: Line Graph - Question 8

Total value of vehicles manufactured by company A during 2010 - 2015 = 260 + 218 + 224 + 179 + 266 + 348 = 1495

Average value of vehicles manufactured by company A during 2010 - 2015 = 1495/6 = 249.16 (in thousands)

Total value of vehicles manufactured by company B during 2010 - 2015 = 307 + 270 + 250 + 289 + 310 + 416 = 1842

Average value of vehicles manufactured by company B during 2010 - 2015 = 1842/6 = 307 (in thousands)

Required percentage = 249.16/307 × 100 = 81.2%

Test: Line Graph - Question 9
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Study the line graph and answer the question that follows.

Below the pair of five trains are given. The sum of length of each pair and the time taken to cross each other when travelling in opposite direction of each pair is given in the line graph.    

Length (in decametre) and Time (in sec) taken to cross each other when travelling to opposite direction

Q. Find the time taken by train A to pass train C if they are travelling in the same direction.
Detailed Solution for Test: Line Graph - Question 9

Let, length (in metres) of train A, train B, train C, train D, and train E be ‘a’, ’b’, ‘c’, ‘d’, and ‘e’, respectively.

And, speed (in m/s) of train A, train B, train C, train D, and train E be ‘p’, ‘q’, ‘r’, ‘s’, and ‘t’, respectively.

2 × (a + b + c + d + e) = 3380

⇒2 × (630 + 700 + e) = 3380

⇒e = 360 m

a = 660 – 360 = 300 m

b = 630 – 300 = 330 m

c = 840 – 330 = 510 m

d = 700 – 510 = 190 m

⇒ q + r = 35

Similarly,

r + s = 25

s + t = 40

p + t = 45

So, 2 × (p + q + r + s + t) = 190

⇒ p + q + r + s + t = 85

⇒ 45 + r + 40 = 95

⇒ r = 10

So, s = 15, t = 25, p = 20, q = 25

Hence, option C is correct.

Test: Line Graph - Question 10
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Study the line graph and answer the question that follows.

Below the pair of five trains are given. The sum of length of each pair and the time taken to cross each other when travelling in opposite direction of each pair is given in the line graph.    

Length (in decametre) and Time (in sec) taken to cross each other when travelling to opposite direction

Q. Train A was travelling from Patna to Delhi while train D was travelling from Delhi to Patna. Train A started after 2 hours of train D. If both trains meet at a distance of 405 km from Delhi then find the distance between Patna to Delhi. 
Detailed Solution for Test: Line Graph - Question 10

Correct Option: A
Let, length (in metres) of train A, train B, train C, train D, and train E be ‘a’, ’b’, ‘c’, ‘d’, and ‘e’, respectively.

And, speed (in m/s) of train A, train B, train C, train D, and train E be ‘p’, ‘q’, ‘r’, ‘s’, and ‘t’, respectively.

2 × (a + b + c + d + e) = 3380

⇒2 × (630 + 700 + e) = 3380

⇒e = 360 m

a = 660 – 360 = 300 m

b = 630 – 300 = 330 m

c = 840 – 330 = 510 m

d = 700 – 510 = 190 m

⇒ q + r = 35

Similarly,

r + s = 25

s + t = 40

p + t = 45

So, 2 × (p + q + r + s + t) = 190

⇒p + q + r + s + t = 85

⇒45 + r + 40 = 95

⇒r = 10

So, s = 15, t = 25, p = 20, q = 25

Distance travelled by train A to meet train D = 90  ×  5.5 = 495 km (We have multiplied by 5.5 as train A travelled 2 hrs less than train D)
 
Required distance = 405 + 495 = 900 km
 
Hence, option A is correct.

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