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Test: Functions - 1 - EmSAT Achieve MCQ

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30 Questions MCQ Test - Test: Functions - 1

Test: Functions - 1 for EmSAT Achieve 2024 is part of EmSAT Achieve preparation. The Test: Functions - 1 questions and answers have been prepared according to the EmSAT Achieve exam syllabus.The Test: Functions - 1 MCQs are made for EmSAT Achieve 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Functions - 1 below.

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Test: Functions - 1 - Question 1

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Which of the following best describes a function in C++?

A.
A data type
B.
A loop statement
C.
A set of instructions grouped together to perform a specific task
D.
A library of pre-defined functions

Detailed Solution for Test: Functions - 1 - Question 1

Functions in C++ are used to group a set of instructions together to perform a specific task. They allow code reuse and modularization.

Test: Functions - 1 - Question 2

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What is a function parameter in C++?

A.
A variable used to store the return value of a function
B.
An input value passed to a function
C.
A variable declared inside a function
D.
A variable that holds the function's address in memory

Detailed Solution for Test: Functions - 1 - Question 2

A function parameter in C++ is an input value passed to a function. It allows the function to accept different values for processing.

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Test: Functions - 1 - Question 3

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In C++, which keyword is used to indicate the end of a function's execution and return a value?

A.
break
B.
return
C.
end
D.
finish

Detailed Solution for Test: Functions - 1 - Question 3

The return keyword is used in C++ to indicate the end of a function's execution and to return a value back to the caller.

Test: Functions - 1 - Question 4

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What is function overloading in C++?

A.
Writing multiple functions with the same name but different return types
B.
Writing multiple functions with the same name and the same parameter types
C.
Writing multiple functions with the same name but different parameter types
D.
Writing multiple functions with different names and the same parameter types

Detailed Solution for Test: Functions - 1 - Question 4

Function overloading in C++ involves writing multiple functions with the same name but different parameter types. This allows the same function name to be used for different variations of the function's behavior.

Test: Functions - 1 - Question 5

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Which of the following statements is true regarding function overloading in C++?

A.
Overloaded functions must have the same return type
B.
Overloaded functions must have different return types
C.
Overloaded functions must have the same number of parameters
D.
Overloaded functions must have different parameter types

Detailed Solution for Test: Functions - 1 - Question 5

Overloaded functions can have different parameter types, but they must have a different number of parameters or parameters of different types to be distinguishable.

Test: Functions - 1 - Question 6

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How is a function called in C++?

A.
By using the function's return value
B.
By writing the function's name followed by parentheses
C.
By declaring a variable inside the function
D.
By using the function's parameter

Detailed Solution for Test: Functions - 1 - Question 6

A function is called in C++ by writing its name followed by parentheses. Arguments can be passed inside the parentheses if the function expects any.

Test: Functions - 1 - Question 7

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Which of the following is not a valid function declaration in C++?

A.
int myFunction(int a, int ;b)
B.
int myFunction(int a, int b) {}
C.
int myFunction();
D.
void myFunction(int a, int b);

Detailed Solution for Test: Functions - 1 - Question 7

This is not a valid function declaration in C++. Function definitions should have a body enclosed in curly braces. The correct declaration should be: int myFunction(int a, int b);

Test: Functions - 1 - Question 8

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What is the purpose of a function prototype in C++?

A.
To define the implementation of a function
B.
To declare the existence of a function
C.
To specify the return type of a function
D.
To provide an alternative name for a function

Detailed Solution for Test: Functions - 1 - Question 8

A function prototype in C++ is used to declare the existence of a function, specifying its name, return type, and parameter types. It provides information about the function before its actual definition.

Test: Functions - 1 - Question 9

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Which of the following is an example of a recursive function?

A.
A function that calls itself
B.
A function that returns a value
C.
A function that takes no arguments
D.
A function that performs a loop

Detailed Solution for Test: Functions - 1 - Question 9

A recursive function is a function that calls itself during its execution. This can be useful for solving problems that can be broken down into smaller subproblems.

Test: Functions - 1 - Question 10

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What is the scope of a variable declared inside a function in C++?

A.
Local to the function
B.
Global to the program
C.
Local to the block where it is declared
D.
Global to the function

Detailed Solution for Test: Functions - 1 - Question 10

A variable declared inside a function in C++ has local scope, which means it is only accessible within that function. It cannot be accessed from outside the function.

Test: Functions - 1 - Question 11

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What will be the output of the following code?

#include <iostream>

int myFunction(int x, int y) {
return x + y;
}

int main() {
int result = myFunction(5, 3);
std::cout << result << std::endl;
return 0;
}

A.
8
B.
5
C.
3
D.
Compilation error

Detailed Solution for Test: Functions - 1 - Question 11

The code defines a function myFunction that takes two integers and returns their sum. In main, the function is called with arguments 5 and 3, and the result is assigned to result. The value of result is then printed, which is 8.

Test: Functions - 1 - Question 12

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What will be the output of the following code?

#include <iostream>

void myFunction(int x) {
std::cout << "Value: " << x << std::endl;
}

int main() {
int value = 10;
myFunction(value);
return 0;
}

A.
Value: 10
B.
10
C.
Value: x
D.
Compilation error

Detailed Solution for Test: Functions - 1 - Question 12

The code defines a function myFunction that takes an integer x and prints its value. In main, an integer variable value is declared and assigned a value of 10. The function myFunction is then called with value as an argument, resulting in the output "Value: 10".

Test: Functions - 1 - Question 13

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What will be the output of the following code?

#include <iostream>

int add(int x, int y) {
return x + y;
}

int multiply(int x, int y) {
return x * y;
}

int main() {
int result = add(2, multiply(3, 4));
std::cout << result << std::endl;
return 0;
}

A.
14
B.
20
C.
26
D.
Compilation error

Detailed Solution for Test: Functions - 1 - Question 13

The code defines two functions: add and multiply, both taking two integers as parameters. In main, the function add is called with arguments 2 and the result of multiply(3, 4) (which is 12). The returned value, 14, is then printed.

Test: Functions - 1 - Question 14

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What will be the output of the following code?

#include <iostream>

int myFunction(int& x) {
x += 5;
return x;
}

int main() {
int value = 10;
int result = myFunction(value);
std::cout << result << std::endl;
return 0;
}

A.
15
B.
10
C.
20
D.
Compilation error

Detailed Solution for Test: Functions - 1 - Question 14

The code defines a function myFunction that takes an integer reference x and increments its value by 5. In main, an integer variable value is declared and assigned a value of 10. The function myFunction is called with value as an argument, modifying its value to 15. The modified value is then assigned to result and printed, resulting in the output "15".

Test: Functions - 1 - Question 15

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What will be the output of the following code?

#include <iostream>

int add(int x, int y) {
return x + y;
}

int add(int x, int y, int z) {
return x + y + z;
}

int main() {
int result = add(2, 3);
std::cout << result << std::endl;
return 0;
}

A.
5
B.
6
C.
7
D.
Compilation error

Detailed Solution for Test: Functions - 1 - Question 15

The code defines two functions named add. The first add function takes two integers as parameters and returns their sum. The second add function takes three integers as parameters and returns their sum. In main, the first add function is called with arguments 2 and 3, resulting in a sum of 5. The value of 5 is then printed.

Test: Functions - 1 - Question 16

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What will be the output of the following code?

#include <iostream>

int myFunction(int x) {
return x * 2;
}

int myFunction(int x, int y) {
return x + y;
}

int main() {
int result1 = myFunction(2);
int result2 = myFunction(2, 3);
std::cout << result1 << " " << result2 << std::endl;
return 0;
}

A.
4 2
B.
4 5
C.
2 5
D.
Compilation error

Detailed Solution for Test: Functions - 1 - Question 16

The code defines two functions named myFunction. The first myFunction takes an integer x and returns its doubled value. The second myFunction takes two integers x and y and returns their sum. In main, the first myFunction is called with an argument of 2, resulting in a value of 4. The second myFunction is called with arguments 2 and 3, resulting in a value of 5. The values 4 and 5 are then printed.

Test: Functions - 1 - Question 17

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What will be the output of the following code?

#include <iostream>

void myFunction(int x) {
if (x <= 0)
return;

std::cout << x << std::endl;
myFunction(x - 1);
}

int main() {
myFunction(5);
return 0;
}

A.
1 2 3 4 5
B.
5 4 3 2 1
C.
1
D.
Compilation error

Detailed Solution for Test: Functions - 1 - Question 17

The code defines a function myFunction that takes an integer x. Inside the function, it checks if x is less than or equal to 0 and returns if true. Otherwise, it prints the value of x and calls itself recursively with x decremented by 1. In main, myFunction is called with an argument of 5. During the recursive calls, the values 5, 4, 3, 2, and 1 are printed.

Test: Functions - 1 - Question 18

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What will be the output of the following code?

#include <iostream>

int myFunction(int x) {
if (x <= 1)
return x;

return myFunction(x - 1) + x;
}

int main() {
int result = myFunction(4);
std::cout << result << std::endl;
return 0;
}

A.
4
B.
6
C.
10
D.
24

Detailed Solution for Test: Functions - 1 - Question 18

The code defines a function myFunction that takes an integer x. Inside the function, it checks if x is less than or equal to 1 and returns x if true. Otherwise, it calls itself recursively with x decremented by 1 and adds x to the result. In main, myFunction is called with an argument of 4. The recursive calls result in the calculation 4 + 3 + 2 + 1, which equals 10. The value 10 is then printed.

Test: Functions - 1 - Question 19

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What will be the output of the following code?

#include <iostream>

int myFunction(int x) {
if (x <= 1)
return x;

return myFunction(x - 1) * x;
}

int main() {
int result = myFunction(4);
std::cout << result << std::endl;
return 0;
}

A.
4
B.
6
C.
10
D.
24

Detailed Solution for Test: Functions - 1 - Question 19

The code defines a function myFunction that takes an integer x. Inside the function, it checks if x is less than or equal to 1 and returns x if true. Otherwise, it calls itself recursively with x decremented by 1 and multiplies the result by x. In main, myFunction is called with an argument of 4. The recursive calls result in the calculation 4 * 3 * 2 * 1, which equals 24. The value 24 is then printed.

Test: Functions - 1 - Question 20

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What will be the output of the following code?

#include <iostream>

void myFunction(int x) {
std::cout << "Value: " << x << std::endl;
}

int main() {
int value = 10;
myFunction(value++);
return 0;
}

A.
Value: 10
B.
Value: 11
C.
Value: 12
D.
Compilation error

Detailed Solution for Test: Functions - 1 - Question 20

The code defines a function myFunction that takes an integer x and prints its value. In main, an integer variable value is declared and assigned a value of 10. The myFunction is then called with value++ as an argument. The value of value++ is temporarily stored as 10, and the myFunction is called with that value. The value 10 is printed inside the function. After the function call, the value of value is incremented to 11. Finally, the incremented value of value is printed outside the function, resulting in the output "Value: 12".

Test: Functions - 1 - Question 21

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What will be the output of the following code?

#include <iostream>

int myFunction(int x) {
return x * x;
}

int myFunction(int& x) {
return ++x;
}

int main() {
int value = 5;
int result = myFunction(value);
std::cout << result << std::endl;
return 0;
}

A.
25
B.
6
C.
Compilation error
D.
Undefined behavior

Detailed Solution for Test: Functions - 1 - Question 21

The code defines two overloaded functions named myFunction. The first myFunction takes an integer x and returns its square. The second myFunction takes an integer reference x and increments its value. In main, an integer variable value is declared and assigned a value of 5. The first myFunction is called with value as an argument, resulting in a return value of 25. The value 25 is then printed.

Test: Functions - 1 - Question 22

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What will be the output of the following code?

#include <iostream>

int myFunction(int x, int y) {
return x - y;
}

int main() {
int result = myFunction(5, 3) * 2;
std::cout << result << std::endl;
return 0;
}

A.
2
B.
4
C.
6
D.
8

Detailed Solution for Test: Functions - 1 - Question 22

The code defines a function myFunction that takes two integers x and y and returns their difference. In main, the function myFunction is called with arguments 5 and 3, resulting in a difference of 2. The difference is then multiplied by 2, resulting in the output of 8.

Test: Functions - 1 - Question 23

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What will be the output of the following code?

#include <iostream>

void myFunction(int x) {
std::cout << "Value: " << x << std::endl;
}

void myFunction(int* x) {
std::cout << "Pointer: " << *x << std::endl;
}

int main() {
int value = 10;
myFunction(&value);
return 0;
}

A.
Value: 10
B.
Pointer: 10
C.
Compilation error
D.
Undefined behavior

Detailed Solution for Test: Functions - 1 - Question 23

The code defines two overloaded functions named myFunction. The first myFunction takes an integer x and prints its value. The second myFunction takes an integer pointer x and prints the value pointed to by x. In main, an integer variable value is declared and assigned a value of 10. The address of value is passed to the second myFunction, resulting in the output "Pointer: 10".

Test: Functions - 1 - Question 24

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What will be the output of the following code?

#include <iostream>

int myFunction(int x) {
if (x == 0)
return 0;

return x + myFunction(x - 1);
}

int main() {
int result = myFunction(4);
std::cout << result << std::endl;
return 0;
}

A.
10
B.
6
C.
4
D.
Compilation error

Detailed Solution for Test: Functions - 1 - Question 24

The code defines a recursive function myFunction that takes an integer x. Inside the function, it checks if x is equal to 0 and returns 0 if true. Otherwise, it adds x to the result of the recursive call with x decremented by 1. In main, myFunction is called with an argument of 4. The recursive calls result in the calculation 4 + 3 + 2 + 1 + 0, which equals 10. The value 10 is then printed.

Test: Functions - 1 - Question 25

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What will be the output of the following code?

#include <iostream>

void myFunction(int x) {
if (x <= 0)
return;

myFunction(x - 1);
std::cout << x << " ";
}

int main() {
myFunction(5);
return 0;
}

A.
1 2 3 4 5
B.
5 4 3 2 1
C.
5 4 3 2 1 1 2 3 4 5
D.
Compilation error

Detailed Solution for Test: Functions - 1 - Question 25

The code defines a recursive function myFunction that takes an integer x. Inside the function, it checks if x is less than or equal to 0 and returns if true. Otherwise, it calls itself recursively with x decremented by 1 and prints x before the recursive call. In main, myFunction is called with an argument of 5. The recursive calls result in the printing of the values 5, 4, 3, 2, and 1 in that order.

Test: Functions - 1 - Question 26

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What will be the output of the following code?

#include <iostream>

int myFunction(int x) {
if (x <= 1)
return x;

return myFunction(x - 1) + myFunction(x - 2);
}

int main() {
int result = myFunction(5);
std::cout << result << std::endl;
return 0;
}

A.
5
B.
8
C.
10
D.
15

Detailed Solution for Test: Functions - 1 - Question 26

The code defines a recursive function myFunction that calculates the Fibonacci sequence. The function takes an integer x and returns the sum of the two previous Fibonacci numbers. In main, myFunction is called with an argument of 5. The recursive calls result in the calculation of the 5th Fibonacci number, which is 8. The value 8 is then printed.

Test: Functions - 1 - Question 27

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What will be the output of the following code?

#include <iostream>

int myFunction(int x) {
if (x <= 0)
return 1;

return myFunction(x - 1) * x;
}

int main() {
int result = myFunction(0);
std::cout << result << std::endl;
return 0;
}

A.
1
B.
0
C.
Compilation error
D.
Undefined behavior

Detailed Solution for Test: Functions - 1 - Question 27

The code defines a recursive function myFunction that takes an integer x. Inside the function, it checks if x is less than or equal to 0 and returns 1 if true. Otherwise, it multiplies x with the result of the recursive call with x decremented by 1. In main, myFunction is called with an argument of 0. Since the initial value of x is 0, the function immediately returns 1. The value 1 is then printed.

Test: Functions - 1 - Question 28

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What will be the output of the following code?

#include <iostream>

void myFunction(int& x) {
x *= 2;
}

int main() {
const int value = 10;
myFunction(value);
std::cout << value << std::endl;
return 0;
}

A.
10
B.
20
C.
Compilation error
D.
Undefined behavior

Detailed Solution for Test: Functions - 1 - Question 28

The code defines a function myFunction that takes an integer reference x and doubles its value. In main, a constant integer variable value is declared and assigned a value of 10. Since value is declared as const, its value cannot be modified. The attempt to modify value inside myFunction results in a compilation error. The original value of value, 10, is then printed.

Test: Functions - 1 - Question 29

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What will be the output of the following code?

#include <iostream>

void myFunction(int* x) {
*x = 20;
}

int main() {
int value = 10;
myFunction(&value);
std::cout << value << std::endl;
return 0;
}

A.
10
B.
20
C.
Compilation error
D.
Undefined behavior

Detailed Solution for Test: Functions - 1 - Question 29

The code defines a function myFunction that takes an integer pointer x and modifies the value pointed to by x to 20. In main, an integer variable value is declared and assigned a value of 10. The address of value is passed to myFunction, attempting to modify its value to 20. However, value is not declared as a pointer, and passing its address to myFunction results in a compilation error.

Test: Functions - 1 - Question 30

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What will be the output of the following code?

#include <iostream>

int myFunction(int x) {
if (x == 0)
return 0;

return x + myFunction(x - 1);
}

int main() {
int result = myFunction(0);
std::cout << result << std::endl;
return 0;
}

A.
0
B.
1
C.
Compilation error
D.
Undefined behavior

Detailed Solution for Test: Functions - 1 - Question 30

The code defines a recursive function myFunction that takes an integer x. Inside the function, it checks if x is equal to 0 and returns 0 if true. Otherwise, it adds x to the result of the recursive call with x decremented by 1. In main, myFunction is called with an argument of 0. Since the initial value of x is 0, the function immediately returns 0. The value 0 is then printed.

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