MCAT Exam  >  MCAT Tests  >  Test: Chemistry - 2 - MCAT MCQ

Test: Chemistry - 2 - MCAT MCQ


Test Description

15 Questions MCQ Test - Test: Chemistry - 2

Test: Chemistry - 2 for MCAT 2024 is part of MCAT preparation. The Test: Chemistry - 2 questions and answers have been prepared according to the MCAT exam syllabus.The Test: Chemistry - 2 MCQs are made for MCAT 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Chemistry - 2 below.
Solutions of Test: Chemistry - 2 questions in English are available as part of our course for MCAT & Test: Chemistry - 2 solutions in Hindi for MCAT course. Download more important topics, notes, lectures and mock test series for MCAT Exam by signing up for free. Attempt Test: Chemistry - 2 | 15 questions in 10 minutes | Mock test for MCAT preparation | Free important questions MCQ to study for MCAT Exam | Download free PDF with solutions
Test: Chemistry - 2 - Question 1

A cell membrane defines the limits of the cell and serves as the boundary between the cell and its surroundings. It is made of a double layer of lipids that blocks the passage of polar substances. The image below shows a typical cell membrane:

One important concept related to cell membranes is membrane fluidity. Cells need to keep a certain level of flexibility in order to maintain their stability. Increasing temperature, cholesterol content, and unsaturation of the fatty acid tail of the phospholipids in the bilayer increases the membrane fluidity.

Substances pass through the cell membrane by a process called “transport”. Transport can be passive if no energy is consumed or active if energy is required to transport substances across the membrane. The movement of an uncharged solute across a membrane depends on its concentration gradient, while the movement of an ion depends both on its concentration gradient and the electric potential of the membrane. Membranes are said to be polarized if the resting membrane potential is different than zero, depolarized if the membrane potential is higher than the resting membrane potential, and hyperpolarized if the membrane potential is lower than the resting membrane potential.

The following table shows the characteristics of the different types of solute transport across a membrane:

Q. Utilizing the attachment, if an organism needs to stay alive in a cold environment, what needs to change in the composition of its cell membrane?

Detailed Solution for Test: Chemistry - 2 - Question 1

When the organism is in a cold environment, the fluidity of its cell membrane needs to increase. If the percentage of saturated fatty acids in the hydrophobic tails decreases, it means that the percentage of unsaturated fatty acids is increasing. This allows the cell membrane to become more fluid due to the additional “space” created by the rigid double bonds. If the percentage of cholesterol and unsaturated fatty acids decreases, cell fluidity decreases. The polarity of the hydrophilic heads does not have an appreciable effect on the fluidity of the cell membrane.

Test: Chemistry - 2 - Question 2

A cell membrane defines the limits of the cell and serves as the boundary between the cell and its surroundings. It is made of a double layer of lipids that blocks the passage of polar substances. The image below shows a typical cell membrane:

One important concept related to cell membranes is membrane fluidity. Cells need to keep a certain level of flexibility in order to maintain their stability. Increasing temperature, cholesterol content, and unsaturation of the fatty acid tail of the phospholipids in the bilayer increases the membrane fluidity.

Substances pass through the cell membrane by a process called “transport”. Transport can be passive if no energy is consumed or active if energy is required to transport substances across the membrane. The movement of an uncharged solute across a membrane depends on its concentration gradient, while the movement of an ion depends both on its concentration gradient and the electric potential of the membrane. Membranes are said to be polarized if the resting membrane potential is different than zero, depolarized if the membrane potential is higher than the resting membrane potential, and hyperpolarized if the membrane potential is lower than the resting membrane potential.

The following table shows the characteristics of the different types of solute transport across a membrane:

Q. The resting membrane potential of a neuron is about -60 mV. In an experiment the membrane potential of a neuron is measured to be -90 mV. This membrane is ____. (You may consult the attachment.)

Detailed Solution for Test: Chemistry - 2 - Question 2

Since the measured membrane potential is lower (more negative) than the resting membrane potential, the cell membrane of this neuron is hyperpolarized.

1 Crore+ students have signed up on EduRev. Have you? Download the App
Test: Chemistry - 2 - Question 3

A cell membrane defines the limits of the cell and serves as the boundary between the cell and its surroundings. It is made of a double layer of lipids that blocks the passage of polar substances. The image below shows a typical cell membrane:

One important concept related to cell membranes is membrane fluidity. Cells need to keep a certain level of flexibility in order to maintain their stability. Increasing temperature, cholesterol content, and unsaturation of the fatty acid tail of the phospholipids in the bilayer increases the membrane fluidity.

Substances pass through the cell membrane by a process called “transport”. Transport can be passive if no energy is consumed or active if energy is required to transport substances across the membrane. The movement of an uncharged solute across a membrane depends on its concentration gradient, while the movement of an ion depends both on its concentration gradient and the electric potential of the membrane. Membranes are said to be polarized if the resting membrane potential is different than zero, depolarized if the membrane potential is higher than the resting membrane potential, and hyperpolarized if the membrane potential is lower than the resting membrane potential.

The following table shows the characteristics of the different types of solute transport across a membrane:

Q. In bacteria, lactose can be transported inside the cell by a process called symport, in which the transport of lactose against its concentration gradient is coupled with the transport of protons down their concentration gradient from the outside to the inside of the cell. Which of the following is a false statement regarding lactose symport? (You may consult the attachment.)

Detailed Solution for Test: Chemistry - 2 - Question 3

If the membrane is hyperpolarized, it means that the concentration of protons outside the cell is much higher than the concentration of protons inside the cell. That makes the membrane potential to be more negative (more spontaneous) and drives the movement of lactose inside the cell against its concentration gradient.

Test: Chemistry - 2 - Question 4

A cell membrane defines the limits of the cell and serves as the boundary between the cell and its surroundings. It is made of a double layer of lipids that blocks the passage of polar substances. The image below shows a typical cell membrane:

One important concept related to cell membranes is membrane fluidity. Cells need to keep a certain level of flexibility in order to maintain their stability. Increasing temperature, cholesterol content, and unsaturation of the fatty acid tail of the phospholipids in the bilayer increases the membrane fluidity.

Substances pass through the cell membrane by a process called “transport”. Transport can be passive if no energy is consumed or active if energy is required to transport substances across the membrane. The movement of an uncharged solute across a membrane depends on its concentration gradient, while the movement of an ion depends both on its concentration gradient and the electric potential of the membrane. Membranes are said to be polarized if the resting membrane potential is different than zero, depolarized if the membrane potential is higher than the resting membrane potential, and hyperpolarized if the membrane potential is lower than the resting membrane potential.

The following table shows the characteristics of the different types of solute transport across a membrane:

Q. When red blood cells are placed in a solution with a lower concentration of sodium ions, water molecules pass through the cell membrane from the outside to the inside of the cell in order to balance out the concentration of sodium ions. This is an example of what type of transport? (You may consult the attachment.)

Detailed Solution for Test: Chemistry - 2 - Question 4

Since the concentration of sodium ions is being balanced out, this form of transport does not require energy. The transport is specific for water molecules and they are passing through the cell membrane without the help of a membrane protein, so this form of transport is classified as osmosis.

Test: Chemistry - 2 - Question 5

A cell membrane defines the limits of the cell and serves as the boundary between the cell and its surroundings. It is made of a double layer of lipids that blocks the passage of polar substances. The image below shows a typical cell membrane:

One important concept related to cell membranes is membrane fluidity. Cells need to keep a certain level of flexibility in order to maintain their stability. Increasing temperature, cholesterol content, and unsaturation of the fatty acid tail of the phospholipids in the bilayer increases the membrane fluidity.

Substances pass through the cell membrane by a process called “transport”. Transport can be passive if no energy is consumed or active if energy is required to transport substances across the membrane. The movement of an uncharged solute across a membrane depends on its concentration gradient, while the movement of an ion depends both on its concentration gradient and the electric potential of the membrane. Membranes are said to be polarized if the resting membrane potential is different than zero, depolarized if the membrane potential is higher than the resting membrane potential, and hyperpolarized if the membrane potential is lower than the resting membrane potential.

The following table shows the characteristics of the different types of solute transport across a membrane:

Q. To maintain the concentration gradients of Na+ and K+, a special protein commonly known as the sodium-potassium pump is used. For every ATP molecule that is broken down by this protein, 2 K+ ions are moved from the outside to the inside of the cell, and 3 Na+ ions are moved from the inside to the outside of the cell. If there’s a certain condition that prevents the sodium-potassium pump from functioning properly, what will happen to the membrane? (You may consult the attachment.)

Detailed Solution for Test: Chemistry - 2 - Question 5

The sodium-potassium pump polarizes the membrane by creating a difference in the number of charged particles in the outside and the inside of the cell. When it is functioning properly this potential is negative, as there would be fewer positive ions in the inside of the cell. However, if the sodium-potassium pump stops working, the concentration gradient would gradually dissipate and become more positive, depolarizing the cell membrane.

Test: Chemistry - 2 - Question 6

The branch of physics that studies the motion of a body without taking into account the causes of that motion is called kinematics. According to kinematics, the position and velocity of a moving body is described by the following equations:

Where Xo and Xf are the initial and final positions of the body, Vo and Vf are the initial and final velocities of the body, a is the acceleration of the body, and t is the time.
According to classical mechanics, developed by Isaac Newton, the product of the mass and the acceleration of a body can be described by the following equation (Newton’s second law):
m⋅a = ΣF
Where m is the mass, a is the acceleration, and ΣF is the sum of all forces acting on the body.
The following table shows the position at different times of a 80-kg hospital bed with a 40-kg patient on top of it that is being pushed from rest by a doctor on a rough floor that exerts a constant friction force of 600 N.

Q. According to the attached information, the hospital bed is moving according to what type of motion?

Detailed Solution for Test: Chemistry - 2 - Question 6

The hospital bed is moving in a straight line across the floor and its position is increasing in an uniform quadratic fashion. Those are the characteristics of uniformly accelerated motion.

Test: Chemistry - 2 - Question 7

The branch of physics that studies the motion of a body without taking into account the causes of that motion is called kinematics. According to kinematics, the position and velocity of a moving body is described by the following equations:

Where Xo and Xf are the initial and final positions of the body, Vo and Vf are the initial and final velocities of the body, a is the acceleration of the body, and t is the time.
According to classical mechanics, developed by Isaac Newton, the product of the mass and the acceleration of a body can be described by the following equation (Newton’s second law):
m⋅a = ΣF
Where m is the mass, a is the acceleration, and ΣF is the sum of all forces acting on the body.
The following table shows the position at different times of a 80-kg hospital bed with a 40-kg patient on top of it that is being pushed from rest by a doctor on a rough floor that exerts a constant friction force of 600 N.

Q. In the attachment, what is the velocity of the hospital bed at t = 4s?

Detailed Solution for Test: Chemistry - 2 - Question 7

The acceleration can be found by solving the motion equation, considering the initial velocity and position to be zero, for any time. For example, for t = 2s:

After finding the acceleration, the velocity at t = 4s can be found by applying:

Test: Chemistry - 2 - Question 8

The branch of physics that studies the motion of a body without taking into account the causes of that motion is called kinematics. According to kinematics, the position and velocity of a moving body is described by the following equations:

Where Xo and Xf are the initial and final positions of the body, Vo and Vf are the initial and final velocities of the body, a is the acceleration of the body, and t is the time.
According to classical mechanics, developed by Isaac Newton, the product of the mass and the acceleration of a body can be described by the following equation (Newton’s second law):
m⋅a = ΣF
Where m is the mass, a is the acceleration, and ΣF is the sum of all forces acting on the body.
The following table shows the position at different times of a 80-kg hospital bed with a 40-kg patient on top of it that is being pushed from rest by a doctor on a rough floor that exerts a constant friction force of 600 N.

Q. What is the force exerted by the doctor on the bed in the attachment?

Detailed Solution for Test: Chemistry - 2 - Question 8

The acceleration can be found by solving the motion equation, considering the initial velocity and position to be zero, for any time. For example, for t = 2 s:

Then, the force exerted by the doctor, Fd, can be found by applying Newton’s second law on the bed:

Plugging in the appropriate values, and considering the mass to be equal to the sum of the mass of the bed and the mass of the patient:

Fd = 1080 N

Test: Chemistry - 2 - Question 9

The branch of physics that studies the motion of a body without taking into account the causes of that motion is called kinematics. According to kinematics, the position and velocity of a moving body is described by the following equations:

Where Xo and Xf are the initial and final positions of the body, Vo and Vf are the initial and final velocities of the body, a is the acceleration of the body, and t is the time.
According to classical mechanics, developed by Isaac Newton, the product of the mass and the acceleration of a body can be described by the following equation (Newton’s second law):
m⋅a = ΣF
Where m is the mass, a is the acceleration, and ΣF is the sum of all forces acting on the body.
The following table shows the position at different times of a 80-kg hospital bed with a 40-kg patient on top of it that is being pushed from rest by a doctor on a rough floor that exerts a constant friction force of 600 N.

Q. What is the acceleration of the hospital bed in the attachment?

Detailed Solution for Test: Chemistry - 2 - Question 9

The acceleration can be found by solving the motion equation, considering the initial velocity and position to be zero, for any time. For example, for t = 2:

Test: Chemistry - 2 - Question 10

The branch of physics that studies the motion of a body without taking into account the causes of that motion is called kinematics. According to kinematics, the position and velocity of a moving body is described by the following equations:

Where Xo and Xf are the initial and final positions of the body, Vo and Vf are the initial and final velocities of the body, a is the acceleration of the body, and t is the time.
According to classical mechanics, developed by Isaac Newton, the product of the mass and the acceleration of a body can be described by the following equation (Newton’s second law):
m⋅a = ΣF
Where m is the mass, a is the acceleration, and ΣF is the sum of all forces acting on the body.
The following table shows the position at different times of a 80-kg hospital bed with a 40-kg patient on top of it that is being pushed from rest by a doctor on a rough floor that exerts a constant friction force of 600 N.

Q. What forces are acting on the hospital bed in the attachment?

Detailed Solution for Test: Chemistry - 2 - Question 10

If a free body diagram is drawn for the hospital bed, there are five forces acting on the hospital bed: The push by the doctor, pointing to the right; friction, pointing left; weight of the bed and weight of the patient, pointing down; and normal, pointing up.

Test: Chemistry - 2 - Question 11

If a free body diagram is drawn for the hospital bed, there are five forces acting on the hospital bed: The push by the doctor, pointing to the right; friction, pointing left; weight of the bed and weight of the patient, pointing down; and normal, pointing up.

Q. Which of the following compounds is a carbohydrate? (You may consult the attachment.)

Detailed Solution for Test: Chemistry - 2 - Question 11

C3H6O3 follows the general formula (CH2O)n. In this case the formula would be (CH2O)3. Carbohydrates with three carbons are called trioses. The other compounds do not follow the general formula of a carbohydrate.

Test: Chemistry - 2 - Question 12

If a free body diagram is drawn for the hospital bed, there are five forces acting on the hospital bed: The push by the doctor, pointing to the right; friction, pointing left; weight of the bed and weight of the patient, pointing down; and normal, pointing up.

Q. What is the main functional group present in D-ribose? (See the attachment.)

Detailed Solution for Test: Chemistry - 2 - Question 12

The main functional group of a molecule is its most oxidized group. For D-ribose, the most oxidized group is the aldehyde on C′1. It does not have a ketone or carboxylic acid, and it does have hydroxyl radicals but they are more reduced than the aldehyde functional group, making them lower in priority.

Test: Chemistry - 2 - Question 13

DNA (deoxyribonucleic acid) is the information-storing biomolecule of the cell. The process by which the information stored in DNA can be converted into proteins can be broken down into three subprocesses:

Replication: In this process, a parent DNA strand is paired with its complementary strand. Adenine is paired with thymine, cytosine is paired with guanine, and vice-versa. In this way the information stored in DNA is preserved.
Transcription: In this process, DNA is separated and the complementary strand is copied into mRNA. Adenine is paired with uracil, cytosine is paired with guanine, and vice-versa. Translation: In this process, tRNA recognizes sequences of three bases in RNA called codons and transfers an amino acid into the growing protein chain that starts with the codon that codes for methionine. The codons are shown in the image below and are read starting from the center:

Q. Which parent DNA sequence will code for the polypeptide Met-Thr-Asp-Gly-Val? (You may consult the attachment.)

Detailed Solution for Test: Chemistry - 2 - Question 13

One mRNA chain that codes for the given polypeptide is AUGACAGAUGGAGUG. The complementary DNA chain that codes for this mRNA is TACTGTCTACCTCAC, and the parent DNA strand is ATGACAGATGGAGTG.

Test: Chemistry - 2 - Question 14

DNA (deoxyribonucleic acid) is the information-storing biomolecule of the cell. The process by which the information stored in DNA can be converted into proteins can be broken down into three subprocesses:

Replication: In this process, a parent DNA strand is paired with its complementary strand. Adenine is paired with thymine, cytosine is paired with guanine, and vice-versa. In this way the information stored in DNA is preserved.
Transcription: In this process, DNA is separated and the complementary strand is copied into mRNA. Adenine is paired with uracil, cytosine is paired with guanine, and vice-versa. Translation: In this process, tRNA recognizes sequences of three bases in RNA called codons and transfers an amino acid into the growing protein chain that starts with the codon that codes for methionine. The codons are shown in the image below and are read starting from the center:

Q. Using the attachment, how many amino acids would be located on the polypeptide chain made from the sequence ATTATGCGTCAATGAATAAGACTG?

Detailed Solution for Test: Chemistry - 2 - Question 14

The complementary DNA chain for this sequence would be TAATACGCAGTTACTTATTCTGAC, and the mRNA sequence associated with this chain would be AUUAUGCGUCAAUGAAUAAGACUG. This sequence starts at AUG (Which codes for Met and is a START codon) and codes for Met-Arg-Gln. After Gln, the next codon is UGA, which is a STOP codon, signaling the end of the polypeptide chain and its release from the ribosome. This means that the polypeptide chain is 3 amino acids long.

Test: Chemistry - 2 - Question 15

To form DNA, C′2 of ribose undergoes deoxygenation to remove the hydroxyl group. Which of the following diagrams marked in the attachment is the correct structure for deoxyribose?

Detailed Solution for Test: Chemistry - 2 - Question 15

Carbons are counted starting from the one with the main functional group (in this case the aldehyde). The structure that results from removing the hydroxyl group on C′2 and corresponds to deoxyribose is structure A.

Information about Test: Chemistry - 2 Page
In this test you can find the Exam questions for Test: Chemistry - 2 solved & explained in the simplest way possible. Besides giving Questions and answers for Test: Chemistry - 2, EduRev gives you an ample number of Online tests for practice

Top Courses for MCAT

Download as PDF

Top Courses for MCAT