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MCQ Test: Numerical Coding - 2 - Banking Exams MCQ


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20 Questions MCQ Test - MCQ Test: Numerical Coding - 2

MCQ Test: Numerical Coding - 2 for Banking Exams 2024 is part of Banking Exams preparation. The MCQ Test: Numerical Coding - 2 questions and answers have been prepared according to the Banking Exams exam syllabus.The MCQ Test: Numerical Coding - 2 MCQs are made for Banking Exams 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for MCQ Test: Numerical Coding - 2 below.
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MCQ Test: Numerical Coding - 2 - Question 1
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If in a certain code language 'RAMAN' is written as '23.5' and 'CAP' is written as '10', then how will 'CAPACITY' be written in that code?

Detailed Solution for MCQ Test: Numerical Coding - 2 - Question 1

The place value alphabets  A to Z are shown below

 

The logic followed here is:

The sum of alphabet's place value ÷ 2 = Number.

'RAMAN' is written as '23.5'

R(18) + A(1) + M(13) + A(1) + N(14) → 18 + 1 + 13 + 1 + 14 → 47 → 47 ÷ 2 → 23.5

‘CAP' is written as '10'

C(3) + A(1) + P(16) → 3 + 1 + 16 → 20 → 20 ÷ 2 → 10

Similarly, CAPACITY is coded as;

C(3) + A(1) + P(16) + A(1) + C(3) + I(9) + T(20) + Y(25) → 3 + 1 + 16 + 1 + 3 + 9 + 20 + 25 → 78 → 78 ÷ 2 → 39

Therefore, CAPACITY is coded as '39'.

Hence, the correct answer is "Option (4)".

MCQ Test: Numerical Coding - 2 - Question 2
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If in a certain code language 'JNU' is written as '101714132106', then how will 'PUSA' be written in that language?

Detailed Solution for MCQ Test: Numerical Coding - 2 - Question 2

Let's decode how 'JNU' is written as '101714132106'.

  • 'J' is the 10th letter of the alphabet.
  • 'N' is the 14th letter of the alphabet.
  • 'U' is the 21st letter of the alphabet.

If we follow the pattern:

  1. Each letter seems to be replaced by its positional value in the alphabet.
  2. After each positional value, there is a sequence of numbers.

Let's split the given code '101714132106' to match 'JNU':

  • J (10) N (14) U (21)
  • 10 is followed by 17
  • 14 is followed by 13
  • 21 is followed by 06

So it looks like the pattern is:
Letter Position→Two digits added to positional value

Applying the same pattern to 'PUSA':

  1. P is the 16th letter.
  2. U is the 21st letter.
  3. S is the 19th letter.
  4. A is the 1st letter.

Now adding the following pairs:

  • For 'P' (16): 16 followed by 16 + 1 (1 digit, assuming consistency with original pattern)
  • For 'U' (21): 21 followed by 21 + 1 (assumed based on pattern)
  • For 'S' (19): 19 followed by 08
  • For 'A' (1): 01 followed by 26

Hence, the correct answer is: 1611210619080126

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MCQ Test: Numerical Coding - 2 - Question 3
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If 'MACHINE' is coded as 19-7-9-14-15-20-11, then how will you code 'DANGER' in the same code?

Detailed Solution for MCQ Test: Numerical Coding - 2 - Question 3

MCQ Test: Numerical Coding - 2 - Question 4
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If in a certain code language 'TOMATO' is written as '264126', 'NET' is written as '552', then how will 'TRACTOR' be written in that language?
Detailed Solution for MCQ Test: Numerical Coding - 2 - Question 4




 

So, the required code is 2913269.

Hence, this is the correct answer.

MCQ Test: Numerical Coding - 2 - Question 5
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If 'FLARE' is coded as 21, 15, 26, 9, 22, then how would 'BREIF' be coded in the same language?
Detailed Solution for MCQ Test: Numerical Coding - 2 - Question 5

MCQ Test: Numerical Coding - 2 - Question 6
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If A = 1 and ANT = 35, then PAT = ?
Detailed Solution for MCQ Test: Numerical Coding - 2 - Question 6

A=1
ANT=1+14+20=35
PAT=16+1+20=37

MCQ Test: Numerical Coding - 2 - Question 7
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If E = 5 and AMENDMENT = 89, then SECRETARY = ?
Detailed Solution for MCQ Test: Numerical Coding - 2 - Question 7

Let's find the solution step by step:

Given:

  • E=5
  • AMENDMENT=89

Step 1: Analyze the pattern

The word "AMENDMENT" should add up to 89 if we assign each letter its position in the alphabet and sum them:

 

MCQ Test: Numerical Coding - 2 - Question 8
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If A = 1 and LOT = 47, then MAT = ?
MCQ Test: Numerical Coding - 2 - Question 9
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If C = 3 and POLISH = 79, then POINTER = ?
MCQ Test: Numerical Coding - 2 - Question 10
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If E = 5 and HEN = 27, then PET =?
MCQ Test: Numerical Coding - 2 - Question 11
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Directions: In a certain code, the letters of English alphabet (consonants and vowels) are coded as given for some words. The numeric code for each letter is given in bracket under coded form and corresponds to the letter in the word in the same serial order. Study the coded forms of the given words and find out the rules for their codification.

Applying those rules, answer the questions that follow in two sets.

In questions, find out the coded form of each of the given words.

Q: AGED
Detailed Solution for MCQ Test: Numerical Coding - 2 - Question 11

Rule VII

MCQ Test: Numerical Coding - 2 - Question 12
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Directions: In a certain code, the letters of English alphabet (consonants and vowels) are coded as given for some words. The numeric code for each letter is given in bracket under coded form and corresponds to the letter in the word in the same serial order. Study the coded forms of the given words and find out the rules for their codification.

Applying those rules, answer the questions that follow in two sets.

In questions, find out the coded form of each of the given words.

Q: DATA
Detailed Solution for MCQ Test: Numerical Coding - 2 - Question 12

Rule VI

MCQ Test: Numerical Coding - 2 - Question 13
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Directions: In a certain code, the letters of English alphabet (consonants and vowels) are coded as given for some words. The numeric code for each letter is given in bracket under coded form and corresponds to the letter in the word in the same serial order. Study the coded forms of the given words and find out the rules for their codification.

Applying those rules, answer the questions that follow in two sets.

In questions, find out the coded form of each of the given words.

Q: SIP
Detailed Solution for MCQ Test: Numerical Coding - 2 - Question 13

Rule IV

MCQ Test: Numerical Coding - 2 - Question 14
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Directions: In a certain code, the letters of English alphabet (consonants and vowels) are coded as given for some words. The numeric code for each letter is given in bracket under coded form and corresponds to the letter in the word in the same serial order. Study the coded forms of the given words and find out the rules for their codification.

Applying those rules, answer the questions that follow in two sets.

In questions, find out the coded form of each of the given words.

Q: EVE
Detailed Solution for MCQ Test: Numerical Coding - 2 - Question 14

Rule V

MCQ Test: Numerical Coding - 2 - Question 15
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Directions: In a certain code, the letters of English alphabet (consonants and vowels) are coded as given for some words. The numeric code for each letter is given in bracket under coded form and corresponds to the letter in the word in the same serial order. Study the coded forms of the given words and find out the rules for their codification.

Applying those rules, answer the questions that follow in two sets.

In questions, find out the coded form of each of the given words.

Q: DOSE
Detailed Solution for MCQ Test: Numerical Coding - 2 - Question 15

[5] [25] [5] [25] by Rule VI

MCQ Test: Numerical Coding - 2 - Question 16
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Directions: In each of the questions given below, a group of digits followed by four combinations of letter codes labelled (a), (b), (c) and (d) are given. You have to find out which of the combinations is correct coded form of the group of digits as per the following codes and conditions. If none of these four combinations is correct, give your answer as (e). i.e., 'None of these' as the answer.

Conditions:

  1. If the first digit is an odd number and the last digit is an even number, both are to be coded as 'X'.
  2. If the first digit is an even number and the last digit is an odd number, both are to be coded as 'Y'.
  3. If either the first or the last digit is 0, then 0 is to be coded as 'W'.

Q: 631420
Detailed Solution for MCQ Test: Numerical Coding - 2 - Question 16

Since the last digit is 0, so 0 shall be coded as W. 6 is coded as T, 3 as E, 1 as K, 4 as D, 2 as B.

So, the code for 631420 is TEKDBW.

MCQ Test: Numerical Coding - 2 - Question 17
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Directions: In each of the questions given below, a group of digits followed by four combinations of letter codes labelled (a), (b), (c) and (d) are given. You have to find out which of the combinations is correct coded form of the group of digits as per the following codes and conditions. If none of these four combinations is correct, give your answer as (e). i.e., 'None of these' as the answer.

Conditions:

  1. If the first digit is an odd number and the last digit is an even number, both are to be coded as 'X'.
  2. If the first digit is an even number and the last digit is an odd number, both are to be coded as 'Y'.
  3. If either the first or the last digit is 0, then 0 is to be coded as 'W'.

Q: 893561
Detailed Solution for MCQ Test: Numerical Coding - 2 - Question 17

Since the given number-group begins with an even number and ends with an odd number,

so both the first and last digits

i.e. 8 and 1 shall be coded as Y.

9 is coded as M, 3 as E, 5 as R, 6 as T.

So, the code for 893561 is YMERTY.

MCQ Test: Numerical Coding - 2 - Question 18
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Directions: In each of the questions given below, a group of digits followed by four combinations of letter codes labelled (a), (b), (c) and (d) are given. You have to find out which of the combinations is correct coded form of the group of digits as per the following codes and conditions. If none of these four combinations is correct, give your answer as (e). i.e., 'None of these' as the answer.

Conditions:

  1. If the first digit is an odd number and the last digit is an even number, both are to be coded as 'X'.
  2. If the first digit is an even number and the last digit is an odd number, both are to be coded as 'Y'.
  3. If either the first or the last digit is 0, then 0 is to be coded as 'W'.

Q: 328469
Detailed Solution for MCQ Test: Numerical Coding - 2 - Question 18

3 is coded as E, 2 as B, 8 as N, 4 as D, 6 as T, 9 as M.

MCQ Test: Numerical Coding - 2 - Question 19
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Directions: In each of the questions given below, a group of digits followed by four combinations of letter codes labelled (a), (b), (c) and (d) are given. You have to find out which of the combinations is correct coded form of the group of digits as per the following codes and conditions. If none of these four combinations is correct, give your answer as (e). i.e., 'None of these' as the answer.

Conditions:

  1. If the first digit is an odd number and the last digit is an even number, both are to be coded as 'X'.
  2. If the first digit is an even number and the last digit is an odd number, both are to be coded as 'Y'.
  3. If either the first or the last digit is 0, then 0 is to be coded as 'W'.

Q: 743506
Detailed Solution for MCQ Test: Numerical Coding - 2 - Question 19

Since the first digit is an odd number and the last digit is an even number,

so both 7 and 6 shall be coded as X.

4 is coded as D, 3 as E, 5 as R, 0 as J.

So, the code for 743506 is XDERJX.

MCQ Test: Numerical Coding - 2 - Question 20
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Directions: In each of the questions given below, a group of digits followed by four combinations of letter codes labelled (a), (b), (c) and (d) are given. You have to find out which of the combinations is correct coded form of the group of digits as per the following codes and conditions. If none of these four combinations is correct, give your answer as (e). i.e., 'None of these' as the answer.

Conditions:

  1. If the first digit is an odd number and the last digit is an even number, both are to be coded as 'X'.
  2. If the first digit is an even number and the last digit is an odd number, both are to be coded as 'Y'.
  3. If either the first or the last digit is 0, then 0 is to be coded as 'W'.

Q: 640598
Detailed Solution for MCQ Test: Numerical Coding - 2 - Question 20

6 is coded as T, 4 as D, 0 as J, 5 as R, 9 as M, 8 as N.

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