MCQ Test: Bar Graphs - 2 - Banking Exams MCQ

12% of total outlay = 26,400

Outlay = 220,000 = Rs. 2.2 lac crores

Amount spent towards transport and communication = 40% of 33% of 2.2 lac crores

= 0.4 × 33/100 × 2,20,000 = Rs. 29040 crores

Hence, Option A is correct.

Percentage increase in agriculture sector

From the above it can be seen that the second fraction 220/16 will be the same for all four sectors. Hence, the highest percentage increase will be for the sector that has the highest value of the first fraction.

For agriculture it is 25/20 = 1.25
For Energy it is 30/25 = 1.2
For industry it is 12/10 = 1.2
For others it is a decrease.
Agriculture has the maximum percentage increase.
Hence, Option A is correct.

Alternate solution:

The increase of allotments of funds from fifth plan to sixth plan is {30% of 1 lakh – 20%of 40,000} crores
= Rs. (30,000 – 8,000) crores = Rs. 22,000 crores
% increase = 22000 × 100/8000 = 22 × 12.5 = 275%
Hence, Option C is correct.

Amount spent towards Agriculture in fifth plan = 20% of total outlay
 Private investment = 5,200
 65% of 20% of total outlay = 5,200
 Total outlay = Rs.  40,000 crores
 Hence, Option C is correct.

By simple observation, we can see that none of the given sectors has shown a consistent trend in allocation. 
 
Hence, Option A is correct.

Following the common explanation, we get

Average score of Physics, Chemistry and English

Hence, option E is correct.

Common explanation :

Score in Maths = 70% (150) = 105
 
Similarly calculating for each subject we get

Following the common explanation, we get

Total marks deducted in Maths and Hindi = 45 + 39 = 84

Hence, option C is correct.

Common explanation :

Score in Maths = 70% (150) = 105
 
Similarly calculating for each subject we get

Following the common explanation, we get

Total score in all the subjects combined = 501

Total maximum marks = 5 × 150 = 750

Aggregate % score = 501/750 × 100 = 66.8%

Hence, option C is correct.

Common explanation :

Score in Maths = 70% (150) = 105
 
Similarly calculated for each subject we get

Following the common explanation, we get

Total score of Physics and Chemistry = 97.5 + 67.5 = 165

Reqd. % = 165/120 × 100 = 137.5%

Hence, option B is correct.

Common explanation :

Score in Maths = 70% (150) = 105
 
Similarly calculating for each subject we get

Following the common explanation, we get

Difference between the obtained score in English and Maths = 120 – 105 = 15

Difference between the deducted score in Physics and Chemistry = 82.5 – 52.5 = 30

Reqd. % = 15/30 × 100 = 50%

Hence, option E is correct.

Common explanation :

Score in Maths = 70% (150) = 105
 
Similarly calculated for each subject we get

Calculation:

Percentage increase in sales of mobile phones in 2004 = 35

Percentage increase in sales of mobile phones in 2008 = 70

Percentage increase in sales of mobile phones from 2004 to 2008 = (70 –  35)/35 × 100

⇒ 35/35 × 100

⇒ 100%

∴ The required percentage is 100%

Given:

There are the exports of cars of type A and B (in Rs. millions) from 2014 to 2018 in the given bar graph.

Total number of years = 5

Concept used:

Average = The sum of the terms/Number of terms

Calculation:

The average exports (per year) of cars of type B (in Rs. millions) = (225 + 250 + 200 + 275 + 325)/5 = 1275/5 = 255 (in Rs. millions)

The exports of cars of type A in 2014 (in Rs. millions) = 200

Here, 255 - 55 = 200 (in Rs. millions)

Therefore, The exports of cars of type A in 2014 is Rs. 55 million less than the average exports (per year) of cars of type B over the five years

Average exports = (500 + 750 + 1000 + 1200 + 1100 + 900 + 1300)/7

∴ Average Exports from years Y1 to Y7 = 6750/7 = 964.28

Total number of employee = 2262 + 3485 + 4342 + 4801 + 5326 + 5918 + 6426 + 7028 = 39588

So, the average number of employee = 39588/8

∴ The average number of employees per year is 4948.5

Calculations:

The articles sold by company A in 2014 = 1,59,000

The articles sold by company B in 2014 = 1,48,000

Difference between articles sold by company A and company B in 2014 = 1,59,000 – 1,48,000 = 11,000

According to the question,

The number of articles sold by company B in 2015 = 11,000 × 178/100 = 19,580

Decrease in numbers = 1,48,000 – 19,580 = 1,28,420 

Decrease % = (1,28,420/1,48,000) × 100 = 86.77% ≈ 87% 

∴ The articles sold by company B in 2015 has decreased by approx 87% from previous year.

Calculation:

Rise in 2015-16 = 53 – 51 = 2

Rise in 2016-17 = 65 – 53 = 12

Rise in 2017-18 = 76 – 65 = 11

Rise in 2019-20 = 68 – 58 = 10

Rise in 2020-21 = 73 – 68 = 5

∴ Maximum rise in production of wool with respect to previous year is in 2016-17

⇒ Total sales of all branches in 2010 = 49 + 83 + 57 + 52 + 79 = 320

∴ Required average = 320/5 = 64 

Calculation:

Number of students who scored more than 60% = 25 + 9 = 34

Total students = 2 + 2 + 12 + 25 + 9 = 50

Now, the required % = 34/50 × 100% = 68%
∴ 68% of total students scored more than 60%.

Difference in the number of students who opted English = 80 – 70 = 10
Difference in the number of students who opted Maths = 100 – 80 = 20
Difference in the number of students who opted Physics = 90 – 70 = 20
Difference in the number of students who opted Chemistry = 70 – 60 = 10
Difference in the number of students who opted Biology = 80 – 50 = 30
Maximum difference is for Biology.
Hence, option D is correct.

Average of the students who opted for Biology for both the years

Average of the students who opted for English and Maths in 2020

Reqd. ratio =

Hence, option D is correct.