DSSSB TGT Social Science Mock Test - 2 Free Online Test 2026

Excess demand occurs when the quantity demanded exceeds the quantity supplied at the current market price. This situation arises when:

1. Price is below equilibrium:

   • When the market price is set lower than the equilibrium price, consumers want to buy more (high quantity demanded), but producers are unwilling to supply enough (low quantity supplied).

   • This creates a shortage (excess demand).

2. Graphical representation:

   • On a supply-demand graph, excess demand appears as a gap between the demand curve (above) and supply curve (below) at the artificially low price.

• b) Higher than equilibrium: Leads to excess supply (surplus), not excess demand.

• c) Same as equilibrium: No excess demand or supply; markets clear perfectly.

• d) None of these: Incorrect, as option (a) is the definitive answer.

Key Insight: Excess demand always implies the price is below equilibrium, incentivizing price hikes until balance is restored.

Final Answer: a) Market price is lower than the equilibrium price

Hence, Deepa is sitting right to Pankaj

Logic is:

► 4 × 1.5 = 6,
► 6 × 2 = 12,
► 12 × 2.5 = 30,
► 30 × 3 = 90,
► 90 × 3.5 = 315,
► 315 × 4 = 1260. 

Since all the harmoniums are instruments and all instruments are flutes, then flutes include instruments and harmoniums. And instruments include harmoniums.
(i) All flutes cannot be instruments, because instruments are flutes, but flutes can contain something else as well.
(ii) All the harmoniums are flutes because harmoniums are instruments and instruments are flutes.

some tables are benches, and some benches or all benches can be black.

As Water of a River flows similarly water of Pool is Stagnant.

As, (4)² + 3 = 19

Similarly, (7)² + 3 = 52

The required number is 2 because its common in the three shapes.

1st term = 8
2nd term = 8 x 2 = 16
3rd term = 16 x 3 = 48
4th term = 48 x 2 = 96
5th term = 96 x 3 = 288
6th term = 288 x 2 = 576...

⇒ For every term at even position, the previous term is multiplied by 2.
⇒ For every term at odd position, the previous term is multiplied by 3.

So the missing term is: 576 × 3 = 1728

Clearly, the route is as shown in Figure A. It is given that the person is finally to the north-west of his house. Rotating Figure A 90° anticlockwise, we obtain Figure B satisfying the specified conditions. It is evident from Figure B that the direction of walking in the beginning was west.

• There are 8 letters in the word.
• The coded word can be obtained by taking the immediately following letters of word, expect the first and the last letters of the given word but in the reverse order.
• That means, in the coded form the first and the last letters have been interchanged while the remaining letters are coded by taking their immediate next letters in the reverse order.

The letter is the first half and the letter half of the word are separately reversed to obtain the code.

Given, SI = Rs 929.20
P = ?
T = 5 years
R = 8%
P = (100 x SI) / RT
⇒ (100 x 929.20) / (8 x 5)
⇒ Rs. 2323

Let the number be 100. Then, 200 should be the correct outcome. But instead, the value got is 50.
 Change in value = 200 – 50 = 150.
 The percentage change in the value = 150 X 100 / 200 = 75%.
 Alternatively, you could think of this as the number being ‘x’ and the required result being 2x and the derived result being 0.5x.

 Hence, the percentage change in the result is 1.5x X 100 / 2x. Clearly, the value would be 75%. (Note: In this case, the percentage change in the answer does not depend on the value of ‘x’). 

Alternate solution :
Let the number be x.
Then actual value should be 2x and the measured value is x/2.
Therefore, the percentage error can be calculated as:
Actual value−Measured value/Actual value×100

=2x−x/2/2x×100

=4x−x/2/2x×100

=3x/2×1/2x×100

=3/4×100

=75%

[15000×(1+R/100)² − 15000] - (15000×R×2)/100 = 96
⇒15000[(1+R/100)² − 1 − 2R/100]=96
⇒ 15000[(100+R)² − 10000−(200×R)]/10000 = 96
⇒ R2 = (96×23) = 64
⇒ R = 8
∴ Rate = 8%

Correct Answer :- b

Explanation : M can do 1/12 work in a day.

M and S altogether will do 1/8 work in a day.

Work of M in a day + Work of S in a day

1/M + 1/S = 1/8

1/12 + 1/S = 1/8

1/S = 1/8 – 1/12

1/S = 1/24

S = 24

That means S in one day can do 24 work

The correct is D as
in 2000 , Y had 128000 units
and in 2001 , Y had 107000 units
128000 - 107000 = 21000  , so correct option is D.

Let time taken by b to do the work=2t
:a= t
1 day work of a and b = 1/2t+1/t=1+2/2t
=3/2t_(1)
1day work of a and b =1/12_(2)
1/12=3/2t
t=18
b can do that work alone =18×2=36

According to question,

CP of 200 book = 12000

CP of 1 book =  12000 / 200

= Rs. 60

To get 20 books free

Profit = 20*60 = 1200

i.e. 10% of Rs. 12000

⇒10% gain

Let score of Rahul, Manish, Suresh, Ajay be r, m, s, a respectively 
Average score of Rahul, Manish & Suresh is 63
⇒ Total score of Rahul, Manish & Suresh = 3 x 63 = 189
⇒ r + m + s = 189  —  (i) 
Rahul's score is 15 less than Ajay and 10 more than Manish
r = a - 15 —(2)
r = m + 10 — (3) 
Ajay scored 30 marks more than the average score of Rahul, Manish & Suresh

⇒ 3a = r + m + s + 90 ----(4)
Using the value of r + m + s from (i) in (4)
3a = 189 + 90
a = 93 
Using the value of a in (2)
r = 93 - 15
r = 78 
Using the value of r in (i)
78 + m + 3 = 189
m + s = 111 
i.e., sum of Manish's and Suresh's score = 111

So, the correct option is 'B'

Let T is the time taken by the pipes to fill the tank
(1/12 + 1/18 + 1/24)*(T – 12) + (1/12 + 1/18)*12 = 1
We will get T = 108/13 = 8.(4/13)

50% of 500 = 250
= 500 + 250 = 750
16% of 750 = 120

Discount offer by A = 10 % of 28000 = 2800
Total Discount offer by B = 12% of 20,000 + 8% of 8000 = 3040
Required difference = 3040 – 2800 = 240

2/3 + 8/9 - 21/15 

28/18 - 21/15

140-126/90

7/45 = 0.15

So option A is correct

√? + 43 = √19881
√? = 141 – 43
x = 9604

50*12/60 = 10/60 * (50+x)
600 = 500 + 10x
x = 10 kmph

Here (48 – 38) = 10, (60 – 50) = 10, (72 – 62) = 10, (108 – 98) = 10 & (140 – 130) = 10.
Required number = (L.C.M. of 48, 60, 72, 108, 140) – 10
= 15120 – 10 = 15110

B. 50%
Explanation: 200 + 20% of 200 = 240 240 + 25% of 240 = 300 Required percentage = 300 – 200/200 * 100 = 50%

► When there are 25 boarders, the total expenses are Rs. 1750. When there are 50 borders, the total expenses are Rs. 3000.
► The change in expense due to the coming in of 25 borders is Rs. 1250.
► Hence, expense per boarder is equal to Rs. 50. This also means that when there are 25 borders, the variable cost would be 25 * 50 = Rs.1250.
Hence, Rs.500 must be the fixed expenses.
► So for 100 boarders, the total cost would be: Rs. 500 (fixed) + Rs. 5000 = Rs. 5500 
► Average expense per boarder will be 5500/100 = Rs 55