DSSSB TGT Natural Science Mock Test - 8 - DSSSB TGT/PGT/PRT MCQ

Answer: c

Exp: The Third Anglo-Maratha War (1817–1818) was the final and decisive conflict between the British East India Company and the Maratha Empire in India. The troops were led by the Governor General Hastings and he was supported by a force under General Thomas Hislop. It resulted in the formal end of the Maratha Empire and firm establishment of the British East India Company in entire India.

Rajasthan is the largest state of the Republic of India by area. It covers 10.4 % of India. Next to follow in terms of area are: Madhya Pradesh, Maharashtra, Andhra Pradesh and Uttar Pradesh 

The year 1921 marked the start of consistent population growth as revealed by the census. It was preceded by a decadal decline in growth rate during 1911-1921 which saw a net decrease of 0.3 per cent for the century as a whole. The year 1921 turned out to be demographic divide as in the post-1921 period; the population began to show signs of steady increase.

Uniform civil code of India is a term referring to the concept of an overarching Civil Law Code in India. A uniform civil code administers the same set of secular civil laws to govern all people irrespective of their religion, caste and tribe. In the small state of Goa, a civil code based on the old Portuguese Family Laws exists, and Muslim Personal Law is prohibited. This is a result of the liberation of Goa in 1961 by India, when the Indian government promised the people that their laws would be left intact.

A state of emergency was declared in Chile after forest fires killed 23 people.

"Mero Rukh Mero Santati" 'New Green Initiative' was launched by the state of Sikkim.

All others denote various feelings.

Only daughter of my mother → myself.

Hence, the woman is the mother of the man.

Mary is sitting immediate right to Reeta.

The digits on either side of the letter in each of the groups 1P6, 2T0, 1M3 and 1R8 indicate the place value of the letter in the alphabet.

This pattern is not followed by 2Y4.

C is one step ahead of B and the code for CAT is 1 more than that for BAT. Thus, the letters are coded by numerals denoting their position in the English alphabet.
i.e A = 1, B = 2,……….., Z = 26.
So, BALL = B + A + L + L = 2 + 1 + 12 + 12 = 27.

Clearly, each letter is represented by the numeral denoting its position form the end of the English alphabet i.e. Z = 1, Y = 2,………, M = 14,………..,B = 25, A = 26.
Then, SUN = S + U + N = 8 + 6 + 13 = 27.
So, CAT = C + A + T = 24 + 26 + 7 = 57.

Following the final seating arrangement, we can say that between I and H only one person sitting between them, if the counting is done from right of H.
Hence, the correct answer is option D.

Common Explanation:
Reference:
O is sitting second to the left of U and third to right of H.

Inference:
 
Reference:
D and I are immediate neighbors of  each other but one of them is an immediate neighbor of O. 
V is sitting second to the right of B.

Inference:
Here, we can place D and I as follows:

Reference:
G is sitting second to the left of D.
 
Inference:
To fix these two positions, we will have to place D to the immediate right of H. Thus, we get the final arrangement as:

The correct answer is C 
Let the incomes in 2000 of Companies X and Y be 3x and 4x respectively.
And let the expenditures in 2000 of Companies X and Y be E1 and E2 respectively.
Then, for Company X we have:
65 =[( 3x - E1 )/E1]×100 =>65/100 = (3x/E1) - 1 
=> E1 = 3x×( 100/165 ) .... (i)
For Company Y we have:
50 = [(4x - E2 )/E2]x 100 =>50/100= (4x/E1) - 1 => E2 = 4x×( 100/150 ) .... (ii)
From (i) and (ii), we get:
E1/E2=[3x ×(100/165)]/[4x×(100/150)]
E1/E2=15/22 (required ratio)

The value would increase by 4% per year. To go to 5 times it’s original value, it would require an increment of 400%. At 4% SI it would take 100 years.

It would take another 5 years to double again. Thus, a total of 10 years to become four fold.

x = 48 * 8 = 384

So Option C is correct

LCM (15, 12, 21) = 420 second = 7 minutes

Answer – c) 20000 Explanation : (70/100)*T*(50/100)*(60/100) = 4200

►Efficiency of A = 20% = 100 / 5

►Efficiency of B = 10% = 100 / 10

►Efficiency of A,B and C = 50%

►∴ Efficiency of C = (Efficiency of A,B and C) – (Efficiency of A and B) = (50) - (20 + 10) = 20%

►∴ Number of days required by C to work alone = 100 / 20 = 5 days

►Alternatively: Go through options and satisfy the values.

The consecutive even numbers are a, b, c, d, e.
Clearly, b = a + 2, c = a + 4, d = a + 6, e = a + 8

Note: Whenever difference between any two consecutive terms is constant (means the series is an arithmetic series), the average of all the numbers is

(i) the middle number if the number of terms is odd.

(ii) the average of the middle two numbers if the number of terms is even.

Cost ∝ Weight²
Let original weight = 10x
Then, original cost = 100x²k (where k is proportionality constant)
After breakage weight = 1x + 2x + 3x + 4x
After breakage cost = kx²(1 + 4 + 9 + 16) = 30x²k
Now, (100 - 30)x²k = 70,000
Or, 70x²k = 70,000
Or, x²k = 1,000
Hence, original cost = 100x²k
= 100 × 1,000 = Rs. 1,00,000

Suppose after the reduction of Rs. 25, the shares of A, B and C are x, 3x and 2x, respectively.
Total money = 6x (after reduction)
Initially, share (A) + share (B) + share (C) = 735 … (1)
After reduction,
share (A) - 25 + share (B) - 25 + share (C) - 25 = 6x
⇒ share (A) + share (B) + share (C) - 75 = 6x ... (2)
From (1) and (2), we get
⇒ 735 - 75 = 6x
⇒ x = 660/6 = 110
Now, after deduction, C has, 2x = 2 × 110 = Rs. 220.
Before deduction, C had, 220 + 25 = Rs. 245

(i) Curved surface area of the frustum of the cone

(ii) Total surface area of the frustum of the cone

Let h be the height.
Given:
ℓ = slant height
'a' and 'b' are the two base radii of the frustum of the cone.