Class 8 Exam  >  Class 8 Tests  >  Test: Calendar - 1 - Class 8 MCQ

Test: Calendar - 1 - Class 8 MCQ


Test Description

10 Questions MCQ Test - Test: Calendar - 1

Test: Calendar - 1 for Class 8 2024 is part of Class 8 preparation. The Test: Calendar - 1 questions and answers have been prepared according to the Class 8 exam syllabus.The Test: Calendar - 1 MCQs are made for Class 8 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Calendar - 1 below.
Solutions of Test: Calendar - 1 questions in English are available as part of our course for Class 8 & Test: Calendar - 1 solutions in Hindi for Class 8 course. Download more important topics, notes, lectures and mock test series for Class 8 Exam by signing up for free. Attempt Test: Calendar - 1 | 10 questions in 15 minutes | Mock test for Class 8 preparation | Free important questions MCQ to study for Class 8 Exam | Download free PDF with solutions
Test: Calendar - 1 - Question 1

Which calendar was used again in the year 1856?

Detailed Solution for Test: Calendar - 1 - Question 1

Given year 1856, when divided by 4 leaves a remainder of 0.
NOTE: When remainder is 0, 28 is subtracted to the given year to get the result.
So, 1856 - 28 = 1828

Test: Calendar - 1 - Question 2

What was the day on 9th May, 2001?

Detailed Solution for Test: Calendar - 1 - Question 2

9th May, 2001 = (2000 years + Period from 1.1.2001 to 9.5.2001)
Odd days in 1600 years = 0
Odd days in 400 years = 0
Jan.   Feb.   March   April   May
(31 + 28 + 31 + 30 + 9) = 129 days
129 days = (18 weeks + 3 day) = 3 odd day
Total number of odd days = (0 + 0 + 3 ) = 3 odd day
Given day is Wednesday.

1 Crore+ students have signed up on EduRev. Have you? Download the App
Test: Calendar - 1 - Question 3

In a year, Holi was enjoyed on 6th March 9 AM and Deepawali (Diwali) was celebrated on 11th November 8 PM. The total time interval (in hours) between the two was?

Detailed Solution for Test: Calendar - 1 - Question 3

From March 6th to November 11th,
there are 250 days and
Thus 250 x 24 hours
So from Mar 6th 9AM to Nov 11th 8PM, there will be
250 x 24 + 11
hours = 6011 hrs.

Test: Calendar - 1 - Question 4

Which century year is a leap year?

Detailed Solution for Test: Calendar - 1 - Question 4

For an century year,it is divided by 400,when leaves a remainder 0 then it is a leap year. So, 1600.

Test: Calendar - 1 - Question 5

What was the day on 16th June,1993?

Detailed Solution for Test: Calendar - 1 - Question 5

16 June, 1993 = (1992 years + Period from 1.1.1993 to 16.6.1993)
Odd days in 1600 years = 0
Odd days in 300 years = 1
92 years = (69 ordinary years + 23 leap year) = (69 x 1 + 23 x 2)= 3 odd days
Jan. Feb. March April May June
(31 + 28 + 31 + 30 + 31 + 16 ) = 167 days
167 days = (23 weeks + 6 days) =6 odd days.
Total number of odd days = (0 + 1 + 3 + 6) = 3 odd days.
Given day is Wednesday.

Test: Calendar - 1 - Question 6

What was the day on 2nd Jan 1901?

Detailed Solution for Test: Calendar - 1 - Question 6

2nd Jan 1901 means
(1900 years and 2 day)
Now, 1600 years have 0 odd day
300 years have 1 odd day
2 days has 2 odd day
Total no. of odd days = 0 + 1 + 2 = 3 days
Hence, the day on 2nd Jan 1901 was Wednesday.

Test: Calendar - 1 - Question 7

If I was born in 1995, How old I am in 2024?

Detailed Solution for Test: Calendar - 1 - Question 7

Calculating Age has 2 conditions. Let your Birthday is on January 1st.
1. If the month in which you are born is completed in the present year i.e, your birthday, then
Your Age = Present year - Year you are born
As of now, present year = 2024
i.e, Age = 2024 - 1995 = 29 years.
2. If the month in which you are born is not completed in the present year i.e, your birthday, then
Your Age = Last year - Year you are born
As of now, present year = 2024
i.e, Age = 2024 - 1995 = 29 years.

Test: Calendar - 1 - Question 8

What is two weeks from today?

Detailed Solution for Test: Calendar - 1 - Question 8

We know that the day repeats every 7 days, 14 days, 21 days, .........
So if today is Monday, after 7 days it is again Monday, after 14 days again it is Monday.
Hence, after 2 weeks i.e, 14 days the day repeats and is the same day.

Test: Calendar - 1 - Question 9

The calendar of year 1939 is same as which year?

Detailed Solution for Test: Calendar - 1 - Question 9

Given year 1939, when divided by 4 leaves a remainder of 3.
NOTE: When remainder is 3, 11 is added to the given year to get the result.
So, 1939 + 11 = 1950.

Test: Calendar - 1 - Question 10

How many seconds in 10 years?

Detailed Solution for Test: Calendar - 1 - Question 10

We know that,
1 year = 365 days
1 day = 24 hours
1 hour = 60 minutes
1 minute = 60 seconds.
Then, 1 year = 365 x 24 x 60 x 60 seconds. = 8760 x 3600
1 year = 31536000 seconds.
Hence, 10 years = 31536000 x 10 = 315360000 seconds.

Information about Test: Calendar - 1 Page
In this test you can find the Exam questions for Test: Calendar - 1 solved & explained in the simplest way possible. Besides giving Questions and answers for Test: Calendar - 1, EduRev gives you an ample number of Online tests for practice

Top Courses for Class 8

Download as PDF

Top Courses for Class 8