Test: Calendar - Class 8 MCQ

The day of the week repeats every 7 days.
Given today is Friday. Again Friday is repeated on the 7^th day, 14^th,... on 7 multiple days.
Hence, Friday is on the 63^rd day, as 63 is multiple of 7.
Now, the required day of the week on the 65^th day is Sunday.

The year 1985 is an ordinary year. So, it has 1 odd day.
So, the day on 19^th June, 1985 will be 1 day after the day on 19^th June, 1984.
But, 19^th June,1984 is Monday
So, 19^th June, 1985 is Tuesday.

Given year 2003, when divided by 4 leaves a remainder of 3.
NOTE: When remainder is 3, 11 is added to the given year to get the result.
So, 2003 + 11 = 2014.

The year 2006 is an ordinary year. So, it has 1 odd day.
So, the day on 24^th Nov, 2007 will be 1 day beyond the day on 24
th Nov, 2006.
But, 24^th Nov, 2007 is Thursday.
24 - 10 = 14 days.
Therefore, 2 weeks ago it is same day.
Thus, 10^th Nov, 2006 is one day before 10^th Nov, 2007 i.e. it is Wednesday.

When a century year leaves a remainder 0, when divided by 400 then it is a leap year (366 days).
So, 1200 has 366 days.

The year 1996 is a leap year. So, it has 2 odd days. But 17th March comes after 29th February.
So, the day on 17^th March, 1997 will be 1 day beyond the day on 17^th March,1996.
Here 17^th March, 1997 is Monday. So, 17^th March, 1996 is Sunday.

Given that the month begins on a Friday and has 31 days
Sundays = 3^rd, 10^th, 17^th, 24^th, 31^st
⇒ Total Sundays = 5
Every second & fourth Saturday is holiday. 2^nd & 4^th Saturday in every month = 2
Total days in the month = 31
Total working days = 31 - (5 + 2) = 24 days.

We know that, After every 400 years, the same day occurs.
Thus, if 9^th August 2016 is Saturday, before 400 years
i.e., on 9^th August 1616 has to be Saturday.

We already know that the calendar after a leap year repeats again after 28 years.
Here 1988 is a Leap year, then the same calendar will be in the year = 1988 + 28 = 2016.

350 days = 350/7 = 50 weeks, i.e No odd days,
So it will be a Saturday.