SSC MTS Mock Test - 1 - SSC MTS / SSC GD MCQ

Time taken by Vijaya to walk both ways =12 hours 20 minutes
= (12×60)+20
= 740 minutes
Time taken by Vijaya to walk one way = 740/2 = 370
Time taken by Vijaya in walking a distance and running back to same place =9 hours 50 minutes
= (9×60)+50
= 590 minutes
Time taken by Vijaya to run one way = 590−370 = 220 minutes
Time taken by her to run back both ways = 220×2 = 440 minutes 
= (7×60)+20
= 7 hours 20 minutes
Therefore, the time taken by her to run both ways is 7 hours 20 minutes.

Given:
Pipe A alone can fill the tank = 8 hrs
Pipe B alone can fill the tank = 12 hrs
Time ratio of Pipe A and B = 8 ∶ 12 = 2 ∶ 3
Concept used:
Efficiency is inversely proportional to time.
Calculation:
Efficiency ratio of pipe A and B = 3 ∶ 2
Total work = 3 × 8 = 24
Both pipes opened alternately for 1 hr.
Total work in 2 hrs = 3 + 2 = 5
Work in 8 hrs = 5 × 4 = 20
Work in next 1 hr (9th) = 20 + 3 = 23
Remaining work = 24 - 23 = 1
B alone can work in 1 hr = 2
B alone can work in 1/2 hr = 1
So, the total work complete in 9(1/2) hrs.

Given,

Required percentage 

∴ Bags sold by C and E together is 30% leas than bags sold by B and D together.

Given :
A TV set selling price in Delhi = Rs. X
The discount is given on TV set in Chandigarh 

Transportation cost = Rs. 600
Selling price = Cost Price 

According to the question

Given,
Total number of questions =90
Marks for every correct answer =5
Marks deducted for every incorrect answer =2
Total marks scored =387
Let the number of incorrect responses be x
Number of correct responses =90−x
Now as we know total marks scored = 387

The perimeter of a rectangle is the total distance of its outer boundary. It is twice the sum of its length and breadth and it is calculated with the help of the formula: Perimeter = 2(length+breadth).

The compound ratio of ratios a ∶ b and c ∶ d is ac ∶ bd.

Similarly,
Compound ratio of ratios (x + y) ∶ 5 and 2 ∶ y = 
Substituting from (1),
⇒ Compound ratio of ratios (x + y) ∶ 5 and 2 ∶ y = 
∴ Compound ratio of ratios (x + y) ∶ 5 and 2 ∶ y = 7 ∶ 15.

Given,
The ratio of imports to exports for the years 1998 and 1999 are 1.25 and 1.40 respectively.
Let the exports in the year 1998 = Rs. x crores.
Then, the exports in the year 1999 = Rs. (500−x) crores.

= 200 [Using ratio for 1998]
Thus, the exports in the year 1999
= Rs. (500−200) crores 
= Rs. 300 crores.
Let the imports in the year 1999 = Rs. y crores.
Then, 1.40 = y/300
⇒ y = (300 x 1.40)
= 420
∴ Imports in the year 1999 = Rs. 420 crores.

Given,
Area of a square shape wire =81 cm²
As we know,
Perimeter of a square with side 'a' =4a
Area of square with side 'a' =a²
Perimeter of a semicircle 

Area of square = 81 cm²

Perimeter of square =4×9=36cm
⇒ Perimeter of square = Perimeter of semicirlce

∴ The radius of the semicircle is 7cm.

Ascending order: 0.101 <0.11<1.01<1.1
Smallest number = 0.101
Greatest number = 1.1
Product =0.101×1.1= 0.1111
∴  The product of smallest decimal number and largest decimal number is 0.1111.

Given:
Cost price of wheat = Rs. 30 per kg
Selling price of 8 kg = Rs. 'x' per kg
Selling price of remaining wheat = Rs. 45 per kg
Overall profit percentage = 10%
Calculation:
Cost price = Rs. 30 per kg
Total cost price = CP = Rs. 30 × x = 30x
Profit must be 10%
So, SP = 30x × 110/100 = 33x
For the first 8 kg of wheat, the selling price is Rs. 'x' per kg.
Selling price of 8 kg = 8 × x = 8x
For the remaining wheat, the selling price is Rs. 45 per kg.
Remaining quantity = (x - 8) Kg
According to the question
33x = 8x + (x - 8)45
33x = 8x + 45x - 8 × 45
x = 18 kg.
Quantity of wheat sold at Rs. 45 per kg = (x - 8) = 18 - 8 = 10 kg
Therefore, Ritika sold 10 kg of wheat at Rs. 45 per kg.
∴ Option 3 is the correct answer.

Given:
Marked price = (M.P) = Rs. 210
Selling price = (S.P) = Rs. 189
Formula used:
If marked price is M.P, selling price is S.P  and discount is D, then
Discount = M.P - S.P
Rate of discount = (100/M.P) × Discount
Calculation:
Discount = 210 - 189 = Rs. 21
So, Rate of discount = (21/210) × 100 = 10 %
∴ The rate of discount is 10 %.

Given:
A is thrice as good a workman as B
Both can complete the work in 32 days
Concept Used:
The efficiency of work done is inversely proportional to the number of days.
Calculation:
Let A takes ‘x’ days to complete the work.
Then, amount of the work completed by Aman in 1 day = 1/x
Then Kamal would take 3x days to complete the work.
Then, amount of the work completed by Kamal in 1 day = 1/3x
Now, it is given that they complete the work together in 32 days.
I.e.,

⇒ 3x = 32 × 4 = 128
Hence, days taken by B to complete the task = 128
∴ Option 4 is the correct answer.

Given:
Speed after repairing = 108 km/hr
Speed before repairing = 72 km/hr
Distance covered after repairing = x km
Time taken after repairing = 3 hours
Concept Used:
Time = Distance/Speed
Distance = Time × Speed
Calculation:
Distance covered after repairing = x km
x = 108 × 3 = 324 km
Distance before repairing = 5x
5 × 324 = 1620
Time before repairing = 1620/72
135/6 = 22 hours 30 minutes
∴ Option 4 is the correct answer.

Given:
Volume ratio = 32 ∶ 9
Ratio of their heights is 8 ∶ 9
Area of the base of the second cylinder is 616 cm²
Concept Used:
Volume of cylinder = πr²h
Calculation:
Volume of the cylinder can be written as 32y and 9y
Height of the cylinder can be written as 8h and 9h
Since we know that the Volume of cylinder is Area of base × height
⇒ Volume of second cylinder = 616 × 9h
Let the radius of first cylinder be r
⇒ base area of first cylinder = πr²
Volume of first cylinder = πr² × 8h
Their ratios can be written as
⇒ 616 × 9h/ (πr² × 8h) = 9/32
Put π = 22/7
⇒  (22r² × 8)/(616 × 9 × 7)/ = 32/9
⇒ r² = (616 × 9 × 32 × 7)/(9 × 22 ×  8)
⇒ r = 28
∴ Radius of first cylinder is 28 cm.
∴ Option 3 is the correct answer.

Given
Principal amount (P) = Rs. 14,000
Time period (t) = 2 years
Rate of interest (r) = 10%
Since the interest is compounded annually, we can use the formula:

where A is the amount after t years, P is the principal amount, r is the rate of interest per annum and t is the time period.
Calculation:

Substituting the given values, we get:

Now, we can find the compound interest by subtracting the principal amount from the amount after 2 years:
Compound interest = A - P
Compound interest = 16940 - 14000
Compound interest = 2940
Therefore, the compound interest on Rs. 14,000 for 2 years at the rate of 10% per annum compounded annually is Rs. 2,940.

Given:
2a + 3b = 8 
ab = 5
Formula used:
(x + y)² = x² + y² + 2xy
Calculations:
Squaring the given equation,
⇒ (2a + 3b)² = 64
⇒ 4a² + 9b² + 12ab = 64
Substituting the value of ab,
⇒ 4a² + 9b² + (12 ×  5) = 64
⇒ 4a² + 9b² = 64 – 60 = 4
∴ The value of 4a² + 9b² is 4.

Given:
Speed of the train = 47 meters/second
Time is taken to cross a signal = 13 seconds
Formula:
Let the length of the train be L meters. Then, we can use the following formula to find the length of the train:
L = (Speed of the train × Time taken to cross the signal)
Solution:
Using the formula for the length of the train, we have:
L = (Speed of the train × Time taken to cross the signal)
L = (47× 13) meters
L = 611 meters
Therefore, the length of the train is 611 meters.

Given:
Ratio of incomes of P and Q is 1:2
Ratio of income of Q and R is 3:2
One-third of P's income is Rs. 4400 less than half of P's income.
Calculation:
P's income = x
Q's income = 2x (since the ratio of P's income to Q's income is 1:2)
R's income = y (since the ratio of Q's income to R's income is 3:2)
According to the given information:
One-third of P's income is Rs. 4400 less than half of P's income.
(1/3)x = (1/2)x - 4400
To simplify the equation, we can multiply both sides by 6 to get rid of the fractions:
6 × (1/3)x = 6 × ((1/2)x - 4400)
2x = 3x - 26400
x = 26400
Now, we can calculate Q's income:
Q's income = 2x = 2 ×  26400 = 52800
Therefore, Q's income is Rs. 52,800.
∴ Option 2 is the correct answer.

Calculation:
Let the maximum mark is x.
According to the question
40 + 20% of x = 40% of x
20% of x = 40
x = 200
Therefore, the maximum marks for the exam are 200.
∴ Option 3 is the correct answer.

According to the English alphabets and their positional values:

The pattern followed in the given series is:

Hence the correct answer is option (1).

Preparing the family tree by using the following symbol:

Given: Pointing to a lady in the photograph, Sonia said, "She is my paternal grandmother's only daughter-in-law"

We can clearly see in the above figure that, Sonia is the daughter of Lady.
Hence, the correct answer is "option (3)".

We have drawn the figure according to the information given in the question,
(Let the turning points as shown in the figure)

AE = DE - DA
AE = 60 - 30 
AE = 30 km
Hence, 30m, South-east is the correct answer.

The least possible diagram for the given statements is as follows

Conclusions:
I. Some humans are animals → False (It is possible but not definite)
II. No reptiles are ants → False (It is possible but not definite)
III. Some animals are ants → True (Some ants are birds and all birds are animals)
IV. Some ants are reptiles → False (It is possible but not definite) Conclusions II and IV forms complementary pairs
Hence, either conclusions II or IV and III follows.
Additional information:
Conditions for the Either Or:
1. Both the conclusion must be Cannot be determined.
2. Both the objects in both the conclusion must be same.
3. If one conclusion is positive, then other should be negative.
Complementary pairs:
1. All - Some not (Positions of the object should be same in the conclusion)
2. Some - No

Given :

Given statement : A - B % C * D + E
So,

• A - B → A is the mother of B.
  
• B % C → B is the brother of C.
  
• C * D → C is the sister of D.
  
• D + E → D is the father of E.
  

Thus, according to the final family tree A is the paternal grandmother i.e father’s mother of E.
Hence, "Father’s mother" is the correct answer.

The logic followed here is:
Given Sequence: WX _ WW _ _ Y _ W _ WXX _ Y _ Y
Now, putting the letters in the blank spaces given in the option one by one:
Option 1) WXXYXWW → WXW / WWXXYY / WXWXXWYWY
Option 2) YXYYWXX → WXY / WWXYYY / WWWXXXYXY
Option 3) YXXYWXY → WXY / WWXXYY / WWWXXXYYY
Here, 'Option 3' followed a pattern.
Option 4) WYXYWXY → WXW /WWYXYY / WWWXXXYYY
Hence, the correct answer is "Option 3".

In Column Wise:
LOGIC: 
(2 × Second Number) - First Number = Third Number
In Column 1:
= (2 × 30) - 12
= 60 - 12
= 48
In Column 2:
= (2 × 31) - 38
= 62 - 24
= 38
Similarly;
In Column 3: 
= (2 × 42) - 26
= 84 - 26
= 58
Hence, the correct answer is "58".

Given:
748, 737, 715, 682, 638,? 
The logic followed here is,
Consecutive multiples of 11 are subtracted from each number in the given series.

Hence, 583 is the solution.

Here, we use the table given below:

The logic followed in the given codes:
'EXEMPT' is coded as 'FYFUQN'→

'FINISH' is coded as 'OJGITJ'→

Similarly, 'EXPIRE' will be coded as:

Here, 'EXPIRE' is coded as 'QYFFSJ'.
Hence, the correct answer is "Option (1)".

The logic here follows is:
First number square = Second number × Third number
Column 1,
(14)² = (7 × 28)
196 = 196
Column 2,
(15)² = (5 × 45)
225 = 225
Similarly,
Column 3,
(9)² = (3 × A)
81 = 3A
A = 81 / 3
A = 27
Hence, the correct answer is "27".