DSSSB PGT Physics Mock Test - 7 - DSSSB TGT/PGT/PRT MCQ

The boy in the photograph is the only son of the son of Suresh's mother i.e., the son of Suresh. Hence, Suresh is the father of boy.

P - M → P is the brother of M

M + N → M is the mother of N

N x Q → N is the sister of Q

Therefore, P is the maternal uncle of Q.

If D is Male, the answer is Nephew.

If D is Female, the answer is Niece.

As the sex of D is not known, hence, the relation between D and A cannot be determined.

Note: Niece - A daughter of one's brother or sister, or of one's brother-in-law or sister-in-law. Nephew - A son of one's brother or sister, or of one's brother-in-law or sister-in-law.

M x N → M is the father of N

N - C → N is the sister of C

and C + F → C is the brother of F.

Hence, M is the father of C or C is the son of M.

The father of the boy's uncle → the grandfather of the boy and daughter of the grandfather → sister of father.

Arrange the word in alphabetical order and compare the pair obtained in the word and in the alphabet. The number of letters between should be equal in both. Here, the pairs obtained from the word SEQUENTIAL are SN, SQ, QN SA, and EA. Hence, five is the answer

L - 5 = G
M - 5 = H
N - 5 = I
O - 5 = J
LMNO → GHIJ

Similarly,
S - 5 = N
T - 5 = O
U - 5 = P
V - 5 = Q
STUV → NOPQ

Here you can see the vowels are not changing, only consonants are changing and they are also changing in the order of -1,-1,-2 

Thus,
DONE AT GATV AT ZOU DAP ⇒ COME AS FAST AS YOU CAN

Letters of the word PREMONITION are coded as follows:

Letters → Code
P → 6
R → 8
E → 5
M → 3
O → 0
N → 4
I → 9
T → 2
I → 9
O → 0
N → 4

Therefore, code for the word MONITOR is 3049208

• IQ = (MA*100)/CA
• and 80 ≤ IQ ≤ 140
• 80 ≤ (MA*100)/CA ≤ 140
• 80 ≤ (MA*100)/12 ≤ 140
• 960 ≤ (MA*100) ≤ 1680
• 9.6 ≤ MA ≤ 16.8

There are 20 divisions in 4 cm of main scale
⇒ 1 cm of main scale will have 20/4 = 5 divisions

Thus,  1 MSD  = 1/5 = 0.2 cm Vernier scale has 10 divisions 
Thus, L.C. = 0.2/10 = 0.02 cm 

The joule (symbol J), is a derived unit of energy in the International System of Units.

It is equal to the energy transferred to (or work done on) an object when a force of one newton acts on that object in the direction of its motion through a distance of one metre (1 newton metre or N⋅m).

The principle of homogeneity of dimensions states that “For an equation to be dimensionally correct, the dimensions of each term on LHS must be equal to the dimensions of each term on RHS.”

As no indication of its precision is given. In this case, all we have to go on is the number of digits contained in the data.

Thus the quantity “0.42 cm” is specified to 0.01 unit in 0.42, or one part in 42.

The implied relative uncertainty in this figure is 1/42, or about 2%.

The smallest value that can be measured by the measuring instrument is called its least count.

Measured values are good only up to this value. The least count error is the error associated with the resolution of the instrument.

We know that 10⁵ dyne = 1N
And 10⁴cm²  = 1 m²
Thus we get 10 dyne / cm² = N / m²
Hence 10⁶ dyne / cm² =10⁵ N / m²

The result of an addition or subtraction in the number having different precisions should be reported to the same number of decimal places as present in the number having the least number of decimal places.

The final result should, therefore, be rounded off to one decimal place, i.e. 663.8

We have  1 unit = x meters
So  1 unit² = x² meter²
Hence, we get  1 meter² = 1/x² unit²

multiply the mass / volume value by 1000

Only electron microscope has resolution of 0.5-0.6 Angstrom which is less than the size of an atom.

The maximum range of water coming out of the fountain,
R_m = v²/g
Total area around fountain,

Maximum speed with which the boy can throw stone is:

Range is maximum when the projectile is thrown at an angle of 45⁰ thus,

As the force is exponentially decreasing, so its acceleration, i.e., rate of increase of velocity will decrease with time. Thus, the graph of velocity will be an increasing curve with decreasing slope with time.

We have given in the information that the person is in his office for two hours hence his position must not vary for two hours, that is the horizontal part in the graph which is only observed in the graph of option c.