NEET Exam  >  NEET Tests  >  Test: Units and Measurements (April 10) - NEET MCQ

Test: Units and Measurements (April 10) - NEET MCQ


Test Description

20 Questions MCQ Test - Test: Units and Measurements (April 10)

Test: Units and Measurements (April 10) for NEET 2024 is part of NEET preparation. The Test: Units and Measurements (April 10) questions and answers have been prepared according to the NEET exam syllabus.The Test: Units and Measurements (April 10) MCQs are made for NEET 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Units and Measurements (April 10) below.
Solutions of Test: Units and Measurements (April 10) questions in English are available as part of our course for NEET & Test: Units and Measurements (April 10) solutions in Hindi for NEET course. Download more important topics, notes, lectures and mock test series for NEET Exam by signing up for free. Attempt Test: Units and Measurements (April 10) | 20 questions in 40 minutes | Mock test for NEET preparation | Free important questions MCQ to study for NEET Exam | Download free PDF with solutions
Test: Units and Measurements (April 10) - Question 1

In case of measurement of ‘g’, if error in measurement of length of pendulum is 2%, the percentage error in time period is1 %. The maximum error in measurement of g is

Detailed Solution for Test: Units and Measurements (April 10) - Question 1

Time period of oscillation of pendulam 

where L is length of pendulam and g is acceleration due to gravity.
hence we have  ...........................(1)
hence 

Test: Units and Measurements (April 10) - Question 2

Which of the following is not the unit of energy?

Detailed Solution for Test: Units and Measurements (April 10) - Question 2

F = ma
[F] = kg m/s2

1 Crore+ students have signed up on EduRev. Have you? Download the App
Test: Units and Measurements (April 10) - Question 3

The dimensional formula of RT is same as that of:

Detailed Solution for Test: Units and Measurements (April 10) - Question 3

The vander Waals gas equation is 

where P is the pressure, V is molar volume and T is the temperature of the given sample of gas. R is called mola gas constant, a and b are called vander Waals constants.

Test: Units and Measurements (April 10) - Question 4

Two physical quantities whose dimensions are not same, cannot be :

Detailed Solution for Test: Units and Measurements (April 10) - Question 4

The two physical quantities which do not have the same dimensions can’t be added or subtracted in the same expression because doing so would lead to equating two quantities of different dimensions, which is non possible. Ex [F]  [P].

Test: Units and Measurements (April 10) - Question 5

Force F is given in terms of time t and distance x by

F = A sin C t + B cos D x

Then the dimensions of  and  are given by

Detailed Solution for Test: Units and Measurements (April 10) - Question 5

Dimension of [A]=[MLT-2]
Dimension of [B]=[MLT-2]
 
 [A]/[B]= [ M0L0T0]
CT=1
Dimension of  [C]=1/[T]=[T-1]
DL=1
Dimension of  [D]=1/[L]=[L-1]
[C][D] =[T-1]/[L-1]
=LT-1
 
A/B=Force/Force=[M0L0T0]
Ct=∠⇒C=Angle/Time=1/T=T-1
Dx=∠⇒D=Angle/Distance=1/L=L-1
∴C/D=T-1L-1 =[M0 LT-1 ]

Test: Units and Measurements (April 10) - Question 6

What is the physical quantity whose dimensions are M L2 T-2 ?

Detailed Solution for Test: Units and Measurements (April 10) - Question 6

Dimension of KE is ML2T-2
That of pressure is ML-2T-2
That of momentum is ML/T 
That of power is ML2T-3

Test: Units and Measurements (April 10) - Question 7

The unit of impulse is the same as that of :

Detailed Solution for Test: Units and Measurements (April 10) - Question 7

The newton second (also newton-second, symbol N s or N.s) is the derived SI unit of impulse. It is dimensionally equivalent to the momentum unit kilogram metre per second (kg.m/s). One newton second corresponds to a one-newton force applied for one second.

Test: Units and Measurements (April 10) - Question 8

Planck's constant has the dimensions of :

Detailed Solution for Test: Units and Measurements (April 10) - Question 8

We know that E = hv , where E is energy and v is frequency.
Thus we get h = E/v
And [h] = [E/v] = ML2T-2 / T-1
= ML2T-1
[P] = MLT-1
[F] = MLT-2
[Angular momentum] = [P x r] = ML2T-1

Test: Units and Measurements (April 10) - Question 9

Which pair of following quantities has dimensions different from each other

Detailed Solution for Test: Units and Measurements (April 10) - Question 9

Moment of inertia =1/2​×mass×(Radius of gyration)2=[M1L2T0]
Moment of force = torque =N.m=[M1L2T−2]
Both are different from each other.

Test: Units and Measurements (April 10) - Question 10

Choose the correct statement (S)

Detailed Solution for Test: Units and Measurements (April 10) - Question 10

Correct Answer :- d

Explanation : a) A topological sort of a directed acyclic graph (DAG) is any ordering m1, m2, …, mn of the nodes

of the graph, such that if mimj is an edge then mi appears before mj . Any topological sort of a

the dependency graph gives a valid evaluation order for the semantic rules. 

b) The parse tree can be annotated with synthesized or inherited attributes. The parse tree can also be indicated with an arrow mark to indicate the manner in which the value gets propagated between the nodes of the parse tree. This graph is called as dependency graph as it indicates the dependency between nodes for deriving the values. This graph is an acyclic graph which doesn’t have a cycle. The presence of a cycle indicates that the graph is incorrect as the dependence of nodes for deriving values cannot be predicted. Edges in the dependence graph show the evaluation order for attribute values and thus the graph is a directed one.

Test: Units and Measurements (April 10) - Question 11

Electron volt is a unit of

Test: Units and Measurements (April 10) - Question 12

If a and b are two physical quantities having different dimensions then which of the following can denote a new physical quantity

Detailed Solution for Test: Units and Measurements (April 10) - Question 12

Quantities with different dimensions cant be added or subtracted. Also the dimension of the product of the quantities in power is always one. But when two quantities are multiplied the dimension of the product is the product of the dimensions of the initial quantities.

Test: Units and Measurements (April 10) - Question 13

If the unit of length is micrometer and the unit of time is microsecond, the unit of velocity will be :

Detailed Solution for Test: Units and Measurements (April 10) - Question 13

Unit of velocity = m/s
1m = 106  Micro meter
And 1 sec = 106  Micro sec
Thus 1 m/s = 106 106  micro meter /micro second

Test: Units and Measurements (April 10) - Question 14

A unitless quantity :

Detailed Solution for Test: Units and Measurements (April 10) - Question 14

A dimensionless quantity can have unit. for example angle (radian). But oppisite is not true. A unitless quantity can never have dimensions.it is the unit that give dimensions.

Test: Units and Measurements (April 10) - Question 15

Which of the following is not the unit of time

Detailed Solution for Test: Units and Measurements (April 10) - Question 15

Parallactic second is the unit of distance because parallactic second is an abbreviation of parsec. Parsec = Parsec is the Unit for larger distances.It is the distance at which a star would make parallax of one Second of arc.

Test: Units and Measurements (April 10) - Question 16

 The Van der Waal equation for 1 mole of a real gas is

where P is the pressure, V is the volume, T is the absolute temperature, R is the molar gas constant and a, b are Van dar Waal constants. The dimensions of a are the same as those of

Detailed Solution for Test: Units and Measurements (April 10) - Question 16

The answer is PV2
Solution,
As we know the Vander Waals equation is {P+(a/V2)} (V−b) =RT
Then,
The dimension of a is,
(a/V2) = (P)
Or, a=PV2

Test: Units and Measurements (April 10) - Question 17

The velocity 'v' (in cm/s) of a particle is given in terms of time 't' (in s) by the equation

v = at + 

The dimensions of a, b and c are

Detailed Solution for Test: Units and Measurements (April 10) - Question 17

As v = at + b / (t + c)
We get that v, at and b / (t+c) have the same dimensions as they are equated and added.
Similarly c and t have also same dimensions, [c] = T and [a] = L/T
 And [b] = L

Test: Units and Measurements (April 10) - Question 18

Which of the following sets cannot enter into the list of fundamental quantities in any system of units ?

Detailed Solution for Test: Units and Measurements (April 10) - Question 18

We define length and time separately as it is not possible to define velocity without using these quantities. This means that one fundamental quantity depends on the other. So, these quantities cannot be listed as fundamental quantities in any system of units.

Test: Units and Measurements (April 10) - Question 19

The time dependence of a physical quantity ?

P = P0exp(_at2)

where a is a constant and t is time. The constant a

Detailed Solution for Test: Units and Measurements (April 10) - Question 19

We know that any quantity in power as a dimension of 1, thus [at2] = 1
Thus we get [a] = T-2

Test: Units and Measurements (April 10) - Question 20

If the error in measurement of radius of sphere is 1% , what will be the error in measurement of volume 

Detailed Solution for Test: Units and Measurements (April 10) - Question 20

Volume=4πR3/3
ΔV/V×100=3∆R/R×100
=3×1/100​×100
=3
∴ Percentage error in volume is 3%

Information about Test: Units and Measurements (April 10) Page
In this test you can find the Exam questions for Test: Units and Measurements (April 10) solved & explained in the simplest way possible. Besides giving Questions and answers for Test: Units and Measurements (April 10), EduRev gives you an ample number of Online tests for practice

Top Courses for NEET

Download as PDF

Top Courses for NEET