Solutions - Free MCQ Practice Test with solutions, JEE Chemistry

For Gases, solubility decreases as temperature increases. The physical reason for this is that when most gases dissolve in solution, the process is exothermic. This means that heat is released as the gas dissolves.

NH₃ forms hydrogen Bonding with water.

Molarity is number of moles per unit volume of the solution and molality is number of moles per unit mass of solvent. Volume is temperature dependent where as mass is constant at all temperatures. So, molality remains constant but molarity changes with temperature. Hence , molality is preferred over molarity.

The amount of dissolved oxygen in water decreases with rise in the water's temperature. Cold water has more dissolved oxygen per unit area than warm water. This the reason why aquatic animals are more comfortable in cold water than warm water.

Molal depression constant : It is defined as the depression in freezing point when the molality of the solution is unity, i.e., one mole of the solute is dissolved in 1000 gram or 1 kilogram of the solvent.

Addition of non volatile solute decreases the vapour pressure.

As temperature increases volume also increases and so Molarity decrease.

Solution is Homogeneous mixture of Solute and Solvent.

Solute is mercury( liquid) and solvent is sodium.

Methanol and Water both are Polar. There is intermolecular Hydrogen Bonding interaction.

Hydrated salts have water molecule of hydration as solute.

Pumice stone is example of gas in Solid.

Both are Non Polar.

m = moles of solute / mass of solvent. M = moles of solute / volume of solution.

Size of Helium is small so does not causes “Bents” to divers when the dive back to surface.

Adding ethylene glycol to water reduces the freezing point of water. Water freezes at temperatures much less than 0 degree Celsius when ethylene glycol is added to it. It is used as an anti-freeze

The correct answer is option A
1 M H₂SO₄ solution is more concentrated than 1 N acid solution. Actually 1M solution of acid is prepared by dissolving 98 g of the acid (1 gram mole) per litre of the solution while 1 N solution of acid is prepared by dissolving 49 g of the acid (1 gram equivalent) in the same volume of the solution.

They show positive deviation.

Sugar solution has i=1 so ΔTf minimum so Tf will be maximum.

A solution showing a large positive deviation from ideal behaviour shows lower boiling point than both the components.

Hydrogen (solute , gas ) and solvent is palladium (solid).

It is independent of volume hence independent of Temperature.

v₂ = 40 ml

NaCl has i = 2 while urea and glucose will have i = 1

Ba(OH)₂ + 2HCI → BaCl₂ + 2H₂O

M₁V₁X₁ →  M₂V₂X₂