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JEE Exam  >  JEE Tests  >  Test: Inverse Trigonometry- 2 - JEE MCQ

Test: Inverse Trigonometry- 2 - JEE MCQ


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25 Questions MCQ Test - Test: Inverse Trigonometry- 2

Test: Inverse Trigonometry- 2 for JEE 2024 is part of JEE preparation. The Test: Inverse Trigonometry- 2 questions and answers have been prepared according to the JEE exam syllabus.The Test: Inverse Trigonometry- 2 MCQs are made for JEE 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Inverse Trigonometry- 2 below.
Solutions of Test: Inverse Trigonometry- 2 questions in English are available as part of our course for JEE & Test: Inverse Trigonometry- 2 solutions in Hindi for JEE course. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free. Attempt Test: Inverse Trigonometry- 2 | 25 questions in 25 minutes | Mock test for JEE preparation | Free important questions MCQ to study for JEE Exam | Download free PDF with solutions
Test: Inverse Trigonometry- 2 - Question 1
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cos2θ is not equal to

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cos 2θ is equal to cos2θ - sin2θ = 2cos2θ - 1

Test: Inverse Trigonometry- 2 - Question 2
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 is equal to 

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sin-1√3/5 = A
Sin A = √3/5 , cos A = √22/5 
Therefore Cos-1√3/5 = B
Cos B = √3/5 , sin B = √22/5  
sin(A+B) = sinA cosB + cosA sinB
= √3/5 * √3/5 + √22/5 * √22/5
= 3/25 * 22/25
= 25/25 
= 1

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Test: Inverse Trigonometry- 2 - Question 3
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2cos−1x = cos−1(2x2−1)holds true for all

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This is true for all real values of x ∈ [0,1].

Test: Inverse Trigonometry- 2 - Question 4
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none of these  : 7/25

Test: Inverse Trigonometry- 2 - Question 5
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If sin A + cos A = 1, then sin 2A is equal to
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(Sin A + Cos A)2 = sin2A + cos2A + 2 sinAcosA

1 = 1 + Sin 2A

so, Sin 2A = 0

Hence A = 0 

Test: Inverse Trigonometry- 2 - Question 6
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When x = π/2, then tan x, is
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tan π/2 = n.d.i.e. not defined.

Test: Inverse Trigonometry- 2 - Question 7
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The value of the expression sinθ+cosθ lies between
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Minimum value   

and maximum value = 

Test: Inverse Trigonometry- 2 - Question 8
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cos−1(cosx) = x is satisfied by ,
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cos−1(cosx) = x if, 
0⩽x⩽ π i.e. if , x∈ [0,π]

Test: Inverse Trigonometry- 2 - Question 9
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Test: Inverse Trigonometry- 2 - Question 10
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If ƒ(x) = tan(x), then f-1(1/√(3)) =
Detailed Solution for Test: Inverse Trigonometry- 2 - Question 10

Let F(x) = tanx = y
f(-1) = tany = x
f(-1)(1/√3), tany = 1/√3
y = tan-(1/√3)
=π/6

Test: Inverse Trigonometry- 2 - Question 11
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tan x is periodic with period 
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The values of tan x repeats after an interval of π.

Test: Inverse Trigonometry- 2 - Question 12
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Test: Inverse Trigonometry- 2 - Question 13
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 is equal to 
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Test: Inverse Trigonometry- 2 - Question 14
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Test: Inverse Trigonometry- 2 - Question 15
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The correct option is B.

Test: Inverse Trigonometry- 2 - Question 16
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The period of the function f(x) = tan 3x is
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f(x) = tan 3x, as the period of tan x = π. 3x = x = π/3.

Test: Inverse Trigonometry- 2 - Question 17
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The range of tan−1 x is
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The range of tan−1x is given by -π/2 to π/2

Test: Inverse Trigonometry- 2 - Question 18
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The value of   is (a, b > 0)
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Test: Inverse Trigonometry- 2 - Question 19
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The solution of the equation 

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But , x= -1/2 does not satisfy the given equation.

Test: Inverse Trigonometry- 2 - Question 20
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 is equal to 
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= tan-1 a - tan-1 b + tan-1c + tan-1c - tan-1a

Test: Inverse Trigonometry- 2 - Question 21
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sin2250+sin2650 is equal to
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sin2250 + sin2650 = cos2650 + sin2650 = 1

Test: Inverse Trigonometry- 2 - Question 22
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If θ = tan−1x then sin 2θ is equal to
Detailed Solution for Test: Inverse Trigonometry- 2 - Question 22

As we know that : sin 2θ = , now if  θ = tan-1x ⇒ x = tan θ ⇒ sin 2θ = 

Test: Inverse Trigonometry- 2 - Question 23
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if x > 0, then tan-1x + tan-1(1/x) is equal to
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Test: Inverse Trigonometry- 2 - Question 24
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Test: Inverse Trigonometry- 2 - Question 25
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If and x + y + z = xyz, then a value of tan−1x+tan−1y+tan−1z is
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