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MAHA TET Exam  >  MAHA TET Tests  >  MAH B.Ed. CET Mock Test - 9 - MAHA TET MCQ

MAH B.Ed. CET Mock Test - 9 - MAHA TET MCQ


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30 Questions MCQ Test - MAH B.Ed. CET Mock Test - 9

MAH B.Ed. CET Mock Test - 9 for MAHA TET 2024 is part of MAHA TET preparation. The MAH B.Ed. CET Mock Test - 9 questions and answers have been prepared according to the MAHA TET exam syllabus.The MAH B.Ed. CET Mock Test - 9 MCQs are made for MAHA TET 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for MAH B.Ed. CET Mock Test - 9 below.
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MAH B.Ed. CET Mock Test - 9 - Question 1
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In this questions, a number series is given with one term missing. Choose the correct alternative that will continue the same pattern and fill in the black spaces.

Q. 5, 9, 17, 29, 45, (____)

Detailed Solution for MAH B.Ed. CET Mock Test - 9 - Question 1

1st term = 5
2nd term = 5 + (4*1) = 5 + 4 = 9
3rd term = 9 + (4*2) = 9 + 8 = 17
4th term = 17 + (4*3) = 17 + 12 = 29
5th term = 29 + (4*4) = 29 + 16 = 45

Thus, the missing number is 6th term = 45 + (4*5) = 45 + 20 = 65

MAH B.Ed. CET Mock Test - 9 - Question 2
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If the first and second digits in the sequence 5 9 8 1 3 2 7 4 3 8 are interchanged, also the third and fourth digits, the fifth and sixth digits and so on, which digit would be the seventh counting to your left?      

Detailed Solution for MAH B.Ed. CET Mock Test - 9 - Question 2

D is the correct option. After changing the positions as per the directions, 8 will be on 4th from right and 7th from the left.

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MAH B.Ed. CET Mock Test - 9 - Question 3
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Study the following letters /cods and answer the questions given below:

L z x 2 m s 3 k e n 4 p q r 5 a b c 6 d f g h 7 u v w 8 y t p o 9 I j

Q. 
In the following number series how many 4’ s are there which are immediately preceded by a pair of numbers whose product is more than the product of the pair of numbers immediately following 4?

8 3 4 2 5 4 5 2 2 4 4 6 8 9 4 7 3 4 2 4 6 4 5 4 3 2 4 4 3 4

Detailed Solution for MAH B.Ed. CET Mock Test - 9 - Question 3

The correct answer is B
 as 4’s = 12 
24 > 20
20 > 10
72 > 21
21 > 8
20 > 6
= 5

MAH B.Ed. CET Mock Test - 9 - Question 4
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Find the odd number / letters / word from the given alternative:
Detailed Solution for MAH B.Ed. CET Mock Test - 9 - Question 4

Except Keyboard, all others are musical instruments.

MAH B.Ed. CET Mock Test - 9 - Question 5
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Find the odd number / letters / word from the given alternative:
Detailed Solution for MAH B.Ed. CET Mock Test - 9 - Question 5

In all other groups, first and third letters as well as forth and second letters are alternate.

MAH B.Ed. CET Mock Test - 9 - Question 6
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Find the odd number / letters / word from the given alternative:
Detailed Solution for MAH B.Ed. CET Mock Test - 9 - Question 6

Let's analyze the pairs to identify the pattern:

  1. 14, 9: The sum of the digits of 14 is 1 + 4 = 5, which is not equal to 9.
  2. 17, 8: The sum of the digits of 17 is 1 + 7 = 8, which matches 8.
  3. 21, 6: The sum of the digits of 21 is 2 + 1 = 3, which does not match 6.
  4. 42, 3: The sum of the digits of 42 is 4 + 2 = 6, which does not match 3.

From the above analysis, Option 2 (17, 8) is the only pair where the sum of the digits of the first number matches the second number.

Therefore, the odd one out based on this pattern is Option 2 (17, 8).

MAH B.Ed. CET Mock Test - 9 - Question 7
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Find out the pair of numbers that does not belong to the group for lack of common property :
Detailed Solution for MAH B.Ed. CET Mock Test - 9 - Question 7

All the rest are in the ratio of 8:9.

MAH B.Ed. CET Mock Test - 9 - Question 8
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Statements:
Some cows are crows.
Some crows are elephants.

Conclusions:
1. Some cows are elephants.
2. All crows are elephants.
Detailed Solution for MAH B.Ed. CET Mock Test - 9 - Question 8

Since the middle term is not distributed in both the premises, no conclusion can be framed. Secondly, if both the premises begin with "Some" no conclusion can be reached.

MAH B.Ed. CET Mock Test - 9 - Question 9
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Directions to Solve

In each of the following questions there are three statements. Which are followed by three or four conclusions. Choose the conclusions which logically follow from the given statements.

Question -

Statements: Some envelops are gums. Some gums are seals. Some seals are adhesives.

Conclusions:

  1. Some envelopes are seals.
  2. Some gums are adhesives.
  3. Some adhesives are seals.
  4. Some adhesives are gums.
Detailed Solution for MAH B.Ed. CET Mock Test - 9 - Question 9

MAH B.Ed. CET Mock Test - 9 - Question 10
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Statement: – No P is Q. All Q are S. Some R are S.
Conclusions: 1) All R being P is a possibility. 2) All S being R is a possibility.
Detailed Solution for MAH B.Ed. CET Mock Test - 9 - Question 10

MAH B.Ed. CET Mock Test - 9 - Question 11
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If PREMONITION is written as 68530492904, how will MONITOR be written?
Detailed Solution for MAH B.Ed. CET Mock Test - 9 - Question 11

Letters of the word PREMONITION are coded as follows:

Letters → Code
P → 6
R → 8
E → 5
M → 3
O → 0
N → 4
I → 9
T → 2
I → 9
O → 0
N → 4

Therefore, code for the word MONITOR is 3049208

MAH B.Ed. CET Mock Test - 9 - Question 12
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If POSTPONE is written as OPTSOPEN, how will RAJASTAN be written?
Detailed Solution for MAH B.Ed. CET Mock Test - 9 - Question 12

Every letter is interchanged by its subsequent second letter.
i.e. POSTPONE → OPTSOPEN

Therefore, RAJASTAN → ARAJTSNA

MAH B.Ed. CET Mock Test - 9 - Question 13
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If in a certain language 943 is coded as BED and 12448 is coded as SWEET. How is 492311 coded in that languages?
Detailed Solution for MAH B.Ed. CET Mock Test - 9 - Question 13

The numbers are coded as shown:
9431 2 8

BEDSWT

i.e. 4 as E,
9 as B,
2 as W,
3 as D and
1 as S.
So, 492311 is coded as EBWDSS.

MAH B.Ed. CET Mock Test - 9 - Question 14
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The consonants of English alphabet have been coded by using Greek alphabets as given in the table and vowels by using different digits.

If any vowel is neither in the beginning nor at the end, it is coded as ‘3’. If any vowel is at the beginning or at the end, it is coded as ‘7’. However, if the same vowel is placed at both beginning and the end, it is coded as ‘9’ respectively.

Q. How will the following letter groups be coded?

UGHIBOCSU    
Detailed Solution for MAH B.Ed. CET Mock Test - 9 - Question 14

As instructed in the question, the same vowels placed at both beginning and end should be coded as 9.

Hence, the code should be:

9εα9δ9γφ9

None of the options match the instruction, hence the answer is option d.

MAH B.Ed. CET Mock Test - 9 - Question 15
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Directions: Read the following information carefully and answer the question that follows.

In a village of Bastar district in Madhya Pradesh, only two types of people live who belong to a tribal class. The first type is known as class A, while the other is known as class B. In that village, there is no other type of person except these two. The activities of both types of people are governed by perfectly patterned norms of social behaviour. Each person of the tribe has to obey the norms. They are rigid about this.

As far as marriage is concerned, the following norms are to be followed:
(A) The people of class A cannot marry any other member of their own class, though they can marry members of class B.
(B) After being married, each male member ceases to be member of that class in which he was born, but automatically he becomes the member of the other class to which his wife belongs.
(C) As far as females are concerned, they remain the members of their own class after being married.
(D) On its birth, the child automatically becomes the member of its mother's class.
(E) When any male member becomes widower or divorcee, then he again belongs to the group in which he was born.
(F) Nobody can marry more than one person according to social laws.

Q. A boy who was born in class B (boy and his wife both can have married and unmarried brothers) can have
Detailed Solution for MAH B.Ed. CET Mock Test - 9 - Question 15

The boy born in class B will marry a girl of class A. So, the daughter will belong to class A. Thus, (1) is false.
Since the boy's daughter will belong to class A, she would marry a boy of class B and so the son-in-law would be from class B. So, (2) is false.
The boy, born in class B, will have mother born in class B and father born in class A. So, his uncle (i.e. mother's brother or father's brother) can be from class A or B.
So, (3) is true.
The boy in class B gets married to a girl in class A and himself becomes of class A.
Their son also belongs to class A, who will marry a girl of class B and himself becomes of class B.
When the son divorces, he reverts to his original class, i.e. A; hence, (4) is false.

MAH B.Ed. CET Mock Test - 9 - Question 16
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Two matrices are shown in the figure below. Their rows and columns are labelled as (0,1,2,3,4) and (5,6,7,8,9) in the manner shown. Find the correct row-column pairs out of the following matrices that decode to the word - YAGI
Detailed Solution for MAH B.Ed. CET Mock Test - 9 - Question 16

Y occurs at: 04 ;11 ;12 ;33 ;44 ;
A occurs at: 00 ;03 ;22 ;24 ;43 ;
G occurs at: 57 ;59 ;76 ;78 ;87 ;
I occurs at: 55 ;56 ;66 ;95 ;97 ;

MAH B.Ed. CET Mock Test - 9 - Question 17
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The rows and columns of the left matrix have been labelled as 0, 1, 2, 3, 4 and I, J, K, L, M, whereas those of the right matrix are 5, 6, 7, 8, 9 and N, O, P, Q, R. Find the correct row-column pairs out of these matrices that decode to the word - ZTWI
Detailed Solution for MAH B.Ed. CET Mock Test - 9 - Question 17

Z occurs at: I4 ;J0 ;K0 ;L0 ;M1 ;
T occurs at: I3 ;K2 ;K4 ;L3 ;M2 ;
W occurs at: N6 ;N9 ;O6 ;O8 ;Q9 ;
I occurs at: N8 ;P9 ;Q8 ;R7 ;R8 ;

MAH B.Ed. CET Mock Test - 9 - Question 18
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The rows and columns of the left matrix have been labelled as 5, 6, 7, 8, 9 and E, F, G, H, I, whereas those of the right matrix are 0, 1, 2, 3, 4 and J, K, L, M, N. Find the correct row-column pairs out of these matrices that decode to the word - 80UC
Detailed Solution for MAH B.Ed. CET Mock Test - 9 - Question 18

8 occurs at: E6 ;E8 ;G6 ;I6 ;I9 ;
0 occurs at: F5 ;F7 ;F8 ;G8 ;H8 ;
U occurs at: K0 ;K3 ;L2 ;M2 ;N1 ;
C occurs at: J1 ;J2 ;J4 ;L1 ;N0 ;

MAH B.Ed. CET Mock Test - 9 - Question 19
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Detailed Solution for MAH B.Ed. CET Mock Test - 9 - Question 19

First a 6-sided figure encloses (6 - 1= 5-sided figure. 
Then a 5-sided figure encloses (5 - 1 = 4-sided figure. 
So, The answer must be a 3-sided figure enclosing a 2-sided figure. 
So answer figure d should be next.

MAH B.Ed. CET Mock Test - 9 - Question 20
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Directions to Solve

In each of the following questions find out the alternative which will replace the question mark.

Question -

Country : President :: State : ?
Detailed Solution for MAH B.Ed. CET Mock Test - 9 - Question 20

As President is the nominal head of a country, similarly Governer is the nominal head of a State.

MAH B.Ed. CET Mock Test - 9 - Question 21
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Directions to Solve

In each of the following questions find out the alternative which will replace the question mark.

Question -

ZRYQ : KCJB :: PWOV : ?
Detailed Solution for MAH B.Ed. CET Mock Test - 9 - Question 21

MAH B.Ed. CET Mock Test - 9 - Question 22
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Directions to Solve
In each of the following questions find out the alternative which will replace the question mark.
Question -
ACEG : ? :: BDFH : KMOQ
Detailed Solution for MAH B.Ed. CET Mock Test - 9 - Question 22

MAH B.Ed. CET Mock Test - 9 - Question 23
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Directions to Solve

In each of the following questions find out the alternative which will replace the question mark.

Question -

123 : 132 :: 235 : ?
Detailed Solution for MAH B.Ed. CET Mock Test - 9 - Question 23

As, 123 → 132

As, 235 → 253

The middle digit of first term becomes power to the next term.

MAH B.Ed. CET Mock Test - 9 - Question 24
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Directions to Solve

In each of the following questions find out the alternative which will replace the question mark.

Question -

144 : 10 :: 169 : ?
Detailed Solution for MAH B.Ed. CET Mock Test - 9 - Question 24

Sure, let's find the correct answer for the given problem.

144 : 10 :: 169 : ?

- 144 is a perfect square (12²) and its square root is 12.
- 12 is then reduced to 10 by subtracting 2 (12 - 2 = 10).
- Similarly, 169 is a perfect square (13²) and its square root is 13.
- Following the same pattern, subtract 2 from 13 (13 - 2 = 11).

Thus, the correct answer is:

B: 11

- 169 : 11

MAH B.Ed. CET Mock Test - 9 - Question 25
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Directions to Solve

In each word of the following questions consists of pair of words bearing a relationship among these, from amongst the alternatives, pick up the pair that best illustrate a similar relationship.

Question -

Rectangle : Pentagon
Detailed Solution for MAH B.Ed. CET Mock Test - 9 - Question 25

Second one had one more side than the first.

MAH B.Ed. CET Mock Test - 9 - Question 26
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Directions to Solve

Each of the following questions has a group. Find out which one of the given alternatives will be another member of the group or of that class.

Question -

Basic, Pascal, Fortran
Detailed Solution for MAH B.Ed. CET Mock Test - 9 - Question 26

These are all the languages of computer.

MAH B.Ed. CET Mock Test - 9 - Question 27
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'Indolence' is related to 'Work' in the same way as 'Taciturn' is related to:
Detailed Solution for MAH B.Ed. CET Mock Test - 9 - Question 27

As 'Indolence' and 'Work' are opposite to each other in the same way 'Taciturn' and 'speak' are opposite to each other.

MAH B.Ed. CET Mock Test - 9 - Question 28
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'Horse' is related to 'Hoof' in the same way as 'Eagle' is related to:
Detailed Solution for MAH B.Ed. CET Mock Test - 9 - Question 28

As the foot of the 'Horse' is called 'Hoof' in the same way the foot of the 'Eagle' is called 'Claw'.

MAH B.Ed. CET Mock Test - 9 - Question 29
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Below are depicted the three different positions of a dice. Find the number of dots on the face opposite to the face with one dot.
Detailed Solution for MAH B.Ed. CET Mock Test - 9 - Question 29

From figures (i), (ii) and (iii), we conclude that 1, 3, 5 and 6 dots appear adjacent to the face with 2 dots. Therefore, 4 dots will appear opposite to 2 dots. Now, from figures (i) and (ii), we conclude that 2, 3 and 5 dots appear adjacent to 1 dot Therefore, either 4 or 6 dots will appear opposite to 1 dot. But since, 4 dots appear opposite to 2 dots it follows that 6 dots will appear opposite 1 dots.

MAH B.Ed. CET Mock Test - 9 - Question 30
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A dice is rolled twice and the two positions are shown in the figure below. What is the number of dots at the bottom face when the dice is in position (i)?
Detailed Solution for MAH B.Ed. CET Mock Test - 9 - Question 30
From figures (i) and (ii) we conclude that 3, 4, 1 and 5 dots appear adjacent to 2 dots. Therefore, 6 dots must appear opposite 2 dots. Since, there are 2 dots on the top face when the dice is in position (i), therefore, the number of dots at the bottom face must be 6.
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