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Morrison & Boyd Test: Some Basic Principles - NEET MCQ


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25 Questions MCQ Test - Morrison & Boyd Test: Some Basic Principles

Morrison & Boyd Test: Some Basic Principles for NEET 2024 is part of NEET preparation. The Morrison & Boyd Test: Some Basic Principles questions and answers have been prepared according to the NEET exam syllabus.The Morrison & Boyd Test: Some Basic Principles MCQs are made for NEET 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Morrison & Boyd Test: Some Basic Principles below.
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Morrison & Boyd Test: Some Basic Principles - Question 1

Write the state of hybridisation of carbon in H2C=O.

Detailed Solution for Morrison & Boyd Test: Some Basic Principles - Question 1

C in H2C=O is sp2 hybridised and geometry is planar.

Morrison & Boyd Test: Some Basic Principles - Question 2

What is the correct order of decreasing stability of the following cations.

Detailed Solution for Morrison & Boyd Test: Some Basic Principles - Question 2

 

Stability of carbocation increases with the dispersal of positive charge by the donation of eletron density through   effect The groups showing effect are  thus the correct stability order of the given carbocations is 

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Morrison & Boyd Test: Some Basic Principles - Question 3

C4H10O represents methoxypropane (CH3OC3H7) and ethoxyethane (C2H5O C2H5)

Detailed Solution for Morrison & Boyd Test: Some Basic Principles - Question 3

rearrangement of carbon atoms around the functional group is known as metamerism.

Morrison & Boyd Test: Some Basic Principles - Question 4

Electrophilic addition reactions proceed in two steps. The first step involves the addition of an electrophile. Name the type of intermediate formed in the first step of the following addition reaction. 

H3C−−−HC = CH2+ H+→?

Detailed Solution for Morrison & Boyd Test: Some Basic Principles - Question 4

A secondary carbocation is formed.

Morrison & Boyd Test: Some Basic Principles - Question 5

During estimation of nitrogen present in an organic compound by Kjeldahl’s method, the ammonia evolved from 0.5 g of the compound, neutralized 10 mL of 1 M H2SO4.Find out the percentage of nitrogen in the compound.

Detailed Solution for Morrison & Boyd Test: Some Basic Principles - Question 5

moles of NH3= moles of N= 2 × 10 ×1/1000 = 0.02 moles Mass of N = 0.02 × 14 % = 0.02 x 14 × 100/0.5 = 56%

Morrison & Boyd Test: Some Basic Principles - Question 6

The IUPAC name for

Detailed Solution for Morrison & Boyd Test: Some Basic Principles - Question 6

1-Chloro-4-methyl-2-nitrobenzene is the iupac name of the given compound.

Morrison & Boyd Test: Some Basic Principles - Question 7

What is the type of hybridisation of each carbon in the compound (CH3)2CO?

Detailed Solution for Morrison & Boyd Test: Some Basic Principles - Question 7

C in CH3 is sp3 and C of C=O bond is sp2.

Morrison & Boyd Test: Some Basic Principles - Question 8

The organic compound given below is one of the four options given below. Choose the most appropriate one. 

Detailed Solution for Morrison & Boyd Test: Some Basic Principles - Question 8

this is aliphatic heterocyclic compound.

Morrison & Boyd Test: Some Basic Principles - Question 9

In general, in the molecules containing multiple bonds,_____ provide the most reactive centres. Choose the most appropriate one.

Detailed Solution for Morrison & Boyd Test: Some Basic Principles - Question 9

pie bonds are the most reactive centers.

Morrison & Boyd Test: Some Basic Principles - Question 10

Which of the following is the correct IUPAC name?

Detailed Solution for Morrison & Boyd Test: Some Basic Principles - Question 10

 While writing IUPAC name, the alkyl groups are written in alphabetical order. Thus lower locant 3 is assigned to ethyl. Prefix, di, tri, and tetra are not included in alphabetical order.

Morrison & Boyd Test: Some Basic Principles - Question 11

In a π (pi) bond formation, is necessary for one of the below criteria. Choose the appropriate one.

Detailed Solution for Morrison & Boyd Test: Some Basic Principles - Question 11

parallel orientataion of p orbitals are necessary for proper overlapping and formation of pie bond.

Morrison & Boyd Test: Some Basic Principles - Question 12

Alkyl radical (Methyl, Ethyl, Isopropyl, Tert-butyl free radical) stability in the increasing order is:

Detailed Solution for Morrison & Boyd Test: Some Basic Principles - Question 12

tertiary radical is more than secondary and primary.

Morrison & Boyd Test: Some Basic Principles - Question 13

The order of decreasing priority for some functional groups in the naming of an organic compound is:

Detailed Solution for Morrison & Boyd Test: Some Basic Principles - Question 13

COOR (R=alkyl group), -COCl, -CONH2, -CN,-HC=O, >C=O, -OH, −NH2 is the decreasing order of priority

Morrison & Boyd Test: Some Basic Principles - Question 14

Covalent bond can undergo fission in two different ways. The correct representation involving a heterolytic fission of CH3−−−Br is

Detailed Solution for Morrison & Boyd Test: Some Basic Principles - Question 14

arrows are shown in the direction of movement of electrons.

Morrison & Boyd Test: Some Basic Principles - Question 15

When inductive and electromeric effects operate in opposite directions, what happens?

Detailed Solution for Morrison & Boyd Test: Some Basic Principles - Question 15

When inductive and electromeric effects operate in opposite directions then electomeric effect predominates

Morrison & Boyd Test: Some Basic Principles - Question 16

In general, in the molecules containing multiple bonds,_____ provide the most reactive centres. Choose the most appropriate one.

Detailed Solution for Morrison & Boyd Test: Some Basic Principles - Question 16

pie bonds are the most reactive centers.

Morrison & Boyd Test: Some Basic Principles - Question 17

The nitrogen containing organic compound, when heated with copper oxide in an atmosphere of carbon dioxide, yields:

Detailed Solution for Morrison & Boyd Test: Some Basic Principles - Question 17

The nitrogen containing organic compound, when heated with copper oxide in an atmosphere of carbon dioxide, yields free nitrogen

Morrison & Boyd Test: Some Basic Principles - Question 18

Which of the following statement is not correct for a nucleophile? 

Detailed Solution for Morrison & Boyd Test: Some Basic Principles - Question 18

Nucleophile is not Lewis acid. Lewis acids are those substances which accept lone pairs. However, nucleophiles itself are lone pair donors.

Morrison & Boyd Test: Some Basic Principles - Question 19

The addition of HCl to an alkene proceeds in two steps. The first step is the attack of H+ ion to portion which can be shown as

Detailed Solution for Morrison & Boyd Test: Some Basic Principles - Question 19

It is the correct representation since double bond has

high electron density, it provides electron pair for attack on H+. A carbocation results.

Morrison & Boyd Test: Some Basic Principles - Question 20

What does the following diagram showing Lewis structures depict?

Detailed Solution for Morrison & Boyd Test: Some Basic Principles - Question 20

they are resonating structures of nitromethane

Morrison & Boyd Test: Some Basic Principles - Question 21

Which of the following compounds contain all the carbon atoms in the same hybridisation state?

Detailed Solution for Morrison & Boyd Test: Some Basic Principles - Question 21

In A all Carbon atoms are sp hybridized

Morrison & Boyd Test: Some Basic Principles - Question 22

A known mass of an organic compound is heated with fuming nitric acid in the presence of silver nitrate is:

Detailed Solution for Morrison & Boyd Test: Some Basic Principles - Question 22

This is known as carius method.

Morrison & Boyd Test: Some Basic Principles - Question 23

For testing halogens in an organic compound with AgNO3 solution, sodium extract (Lassaigne’s test) is acidified with dilute HNO3.What will happen if a student acidifies the extract with dilute H2SO4 in place of dilute HNO3?

Detailed Solution for Morrison & Boyd Test: Some Basic Principles - Question 23

white precipitate of Ag2SO4 is formed.

Morrison & Boyd Test: Some Basic Principles - Question 24

Nucleophile is a species that should have:

Detailed Solution for Morrison & Boyd Test: Some Basic Principles - Question 24

nucleophile should have negative charge or pair of electron to donate.

Morrison & Boyd Test: Some Basic Principles - Question 25

Delocalisation of σ electrons of C -H bond of an alkyl group directly attached to an atom of unsaturated system or to an atom with an unshared p orbital is called :

Detailed Solution for Morrison & Boyd Test: Some Basic Principles - Question 25

Delocalisation of σ electrons of C -H bond of an alkyl group directly attached to an atom of unsaturated system or to an atom with an unshared p orbital is known as Hyperconjugation

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