JEE Exam  >  JEE Tests  >  Test: Differential Equations- 2 - JEE MCQ

Test: Differential Equations- 2 - JEE MCQ


Test Description

25 Questions MCQ Test - Test: Differential Equations- 2

Test: Differential Equations- 2 for JEE 2024 is part of JEE preparation. The Test: Differential Equations- 2 questions and answers have been prepared according to the JEE exam syllabus.The Test: Differential Equations- 2 MCQs are made for JEE 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Differential Equations- 2 below.
Solutions of Test: Differential Equations- 2 questions in English are available as part of our course for JEE & Test: Differential Equations- 2 solutions in Hindi for JEE course. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free. Attempt Test: Differential Equations- 2 | 25 questions in 25 minutes | Mock test for JEE preparation | Free important questions MCQ to study for JEE Exam | Download free PDF with solutions
Test: Differential Equations- 2 - Question 1

The degree of the equation 

Detailed Solution for Test: Differential Equations- 2 - Question 1

2

Test: Differential Equations- 2 - Question 2

General solution of 

Detailed Solution for Test: Differential Equations- 2 - Question 2


1 Crore+ students have signed up on EduRev. Have you? Download the App
Test: Differential Equations- 2 - Question 3

In a bank, principal increases continuously at the rate of 5% per year. An amount of Rs1000 is deposited with this bank, how much will it worth after 10 years (e0.5= 1.648).

Detailed Solution for Test: Differential Equations- 2 - Question 3



When P = 1000 and t = 0 ., then ,
c = 1000, therefore, we have :

Test: Differential Equations- 2 - Question 4

At any point (x, y) of a curve, the slope of the tangent is twice the slope of the line segment joining the point of contact to the point (– 4, –3). Find the equation of the curve given that it passes through (–2, 1).

Detailed Solution for Test: Differential Equations- 2 - Question 4

Slope of the line segment joining the point of contact P (x , y) to the point (- 4 , - 3) = 



Test: Differential Equations- 2 - Question 5

Solution of 

Detailed Solution for Test: Differential Equations- 2 - Question 5

Test: Differential Equations- 2 - Question 6

Find the order and degree of  

Detailed Solution for Test: Differential Equations- 2 - Question 6

Order = 3 , degree not defined ,because the function y’ present in exponential form.

Test: Differential Equations- 2 - Question 7

Detailed Solution for Test: Differential Equations- 2 - Question 7

Test: Differential Equations- 2 - Question 8

Detailed Solution for Test: Differential Equations- 2 - Question 8

Test: Differential Equations- 2 - Question 9

Solution of x dy− ydx = 

Detailed Solution for Test: Differential Equations- 2 - Question 9



Test: Differential Equations- 2 - Question 10

 

Detailed Solution for Test: Differential Equations- 2 - Question 10



Test: Differential Equations- 2 - Question 11

Determine order and degree (if defined) of  

Detailed Solution for Test: Differential Equations- 2 - Question 11

Order = 4 , degree not defined , because the function y’’’ present in the angle of sine function.

Test: Differential Equations- 2 - Question 12

General solution of sec2 x tany dx + sec2y tan x dy = 0 is

Detailed Solution for Test: Differential Equations- 2 - Question 12


Test: Differential Equations- 2 - Question 13

Find the particular solution for (x + y) dy + (x –y) dx = 0; y = 1 when x = 1

Detailed Solution for Test: Differential Equations- 2 - Question 13






Test: Differential Equations- 2 - Question 14

Variable separation method can be used to solve First Order, First Degree Differential Equations in which y’ is of the form.

Detailed Solution for Test: Differential Equations- 2 - Question 14

Variable separation method can be used to solveFirst Order, First Degree Differential Equations in which y’ is of the form. y’ = h(x)g(y) i.e 

Test: Differential Equations- 2 - Question 15

Detailed Solution for Test: Differential Equations- 2 - Question 15

Test: Differential Equations- 2 - Question 16

Determine order and degree (if defined) of y’ + 5y = 0

Detailed Solution for Test: Differential Equations- 2 - Question 16

Order = 1 , degree = 1.

Test: Differential Equations- 2 - Question 17

General Solution of (ex + e-x) dy - (ex - e-x) dx = 0

Detailed Solution for Test: Differential Equations- 2 - Question 17

Test: Differential Equations- 2 - Question 18

General solution of x 

Detailed Solution for Test: Differential Equations- 2 - Question 18




Test: Differential Equations- 2 - Question 19

solution of {x cos (y/x) + ysin(y/x)} ydx = {ysin(y/x) - x cos (y/x)} xdy is 

Detailed Solution for Test: Differential Equations- 2 - Question 19




Test: Differential Equations- 2 - Question 20

Detailed Solution for Test: Differential Equations- 2 - Question 20



Test: Differential Equations- 2 - Question 21

Determine order and degree (if defined) of 

Detailed Solution for Test: Differential Equations- 2 - Question 21

Order = 2 , degree = 1.

Test: Differential Equations- 2 - Question 22

General solution of y log y dx – x dy = 0

Detailed Solution for Test: Differential Equations- 2 - Question 22


Test: Differential Equations- 2 - Question 23

To form a differential equation from a given function

Detailed Solution for Test: Differential Equations- 2 - Question 23

To form a differential equation from a given functionDifferentiate thefunction successively as many times as the number of arbitrary constants inthe given function and eliminate the arbitrary constants.i.e. the differential equation should be free from arbitrary constants.

Test: Differential Equations- 2 - Question 24

A differential equation of the form y' = F(x,y) is homogeneous if

Detailed Solution for Test: Differential Equations- 2 - Question 24

A differential equation of the form y' = F(x,y) is homogeneous if F(x,y) is a homogeneous function of degree zero.

Test: Differential Equations- 2 - Question 25

General solution of(1+x2) dy+2xy dx = cot x dx(x ≠ 0) is

Detailed Solution for Test: Differential Equations- 2 - Question 25


Information about Test: Differential Equations- 2 Page
In this test you can find the Exam questions for Test: Differential Equations- 2 solved & explained in the simplest way possible. Besides giving Questions and answers for Test: Differential Equations- 2, EduRev gives you an ample number of Online tests for practice

Top Courses for JEE

Download as PDF

Top Courses for JEE