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Test: Ionization of Acids Bases and Water (July 30) - NEET MCQ


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10 Questions MCQ Test - Test: Ionization of Acids Bases and Water (July 30)

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Test: Ionization of Acids Bases and Water (July 30) - Question 1

Which of the following is more acidic? A solution with pH 5 or a solution with pH 3

Detailed Solution for Test: Ionization of Acids Bases and Water (July 30) - Question 1

We know that pH equals to - log[H+] or the value of pH is inversely proportional to the concentration of H+.  So more the value of pH, less the solution be acidic.

Test: Ionization of Acids Bases and Water (July 30) - Question 2

Ionic product of water is

Detailed Solution for Test: Ionization of Acids Bases and Water (July 30) - Question 2

Explanation:

- Ionic Product of Water: The ionic product of water, also known as the dissociation constant of water, is represented by the symbol Kw. It is a measure of the concentration of the ions produced when water undergoes autoionization.

- Constant at a particular temperature: The ionic product of water is constant at a particular temperature. This means that at a specific temperature, the product of the concentrations of the hydrogen ions (H+) and hydroxide ions (OH-) in water remains constant.

- Temperature Dependency: However, it is important to note that the ionic product of water is temperature-dependent. As the temperature changes, the value of Kw also changes. This is because the autoionization of water is an endothermic reaction, meaning it is influenced by temperature.

- Example: At 25°C, the ionic product of water is 1.0 x 10^-14. This means that at this temperature, the concentration of H+ ions multiplied by the concentration of OH- ions in water will always equal 1.0 x 10^-14.

- Conclusion: Therefore, the ionic product of water is constant at a particular temperature, but this value can vary with changes in temperature.

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Test: Ionization of Acids Bases and Water (July 30) - Question 3

 Which one of the following is the approximate pH of 0.01 M solution of NaOH at 298 k?

Detailed Solution for Test: Ionization of Acids Bases and Water (July 30) - Question 3

First off, since NaOH is a strong base, it will dissociate completely into Na+ and OH-. Thus, we know that we have 0.01 M OH-.

However, we do not know anything about the concentration of H+. Fortunately, we do not need to, as pH + pOH = 14. So, if we find pOH, we can solve for pH. p is a mathematical function equivalent to -log. So, pH actually means -log[H+] (Note that brackets indicate concentration of).

pOH = -log 0.01M OH-

pOH = 2

pH + 2 = 14

pH = 12

This result makes sense, since a solution of strong base should have a high pH.

Test: Ionization of Acids Bases and Water (July 30) - Question 4

A 0.10 M solution of a weak acid, HX, is 0.059% ionized. Evaluate Ka for the acid.

Detailed Solution for Test: Ionization of Acids Bases and Water (July 30) - Question 4

Since the acid is only 0.059% ionized, therefore the concentration of ions in solution = 0.1 x 0.059 / 100 = 0.000059

 

Ka = [H+] [X] / [HX] = (0.000059)2 / 0.1 = 3.5 x 10-8

Test: Ionization of Acids Bases and Water (July 30) - Question 5

 In a sample of pure water, only one of the following statements is always true at all conditions of temperature and pressure.

Detailed Solution for Test: Ionization of Acids Bases and Water (July 30) - Question 5

The correct answer is Option D.
The concentration of OH- will always equal the concentration of H3O+.
PV = nRT, where R is a constant, and n is the quantity of gas measured in mols. The pH of a substance is related to the concentration of H+,
so if we raise or lower the Temperature or Pressure of pure water, we will alter the Volume (or concentration) of H3O+ and OH- ions. As we alter the concentrations we alter the pH and pOH. The only answer that is true no matter what the volume or concentration may be is D
 

Test: Ionization of Acids Bases and Water (July 30) - Question 6

The pH of 10-8 molar solution of HCl in water is:

Detailed Solution for Test: Ionization of Acids Bases and Water (July 30) - Question 6

If we use the relation, pH = – log [H3O+], we get pH equal to 8. But this is not correct because an acidic solution cannot have pH greater than 7. It may be noted that in very dilute acidic solution, when H+ concentrations from acid and water are comparable, the concentration of H+ from water cannot be neglected.

Therefore,

Test: Ionization of Acids Bases and Water (July 30) - Question 7

 Which one of the following is correct for a solution in which [H+] = 10-8 M.

Test: Ionization of Acids Bases and Water (July 30) - Question 8

Which one of the following is a wrong derivation?

Test: Ionization of Acids Bases and Water (July 30) - Question 9

Value of pH is determined by

Detailed Solution for Test: Ionization of Acids Bases and Water (July 30) - Question 9
The pH measurement electrode is made of special glass which, due to its surface properties, is particularly sensitive to hydrogen ions. The pH measurement electrode is filled with a buffer solution which has a pH value of 7.
Test: Ionization of Acids Bases and Water (July 30) - Question 10

The pH of a 0.02 M solution of an unknown weak acid is 3.7. What is the pKa of this acid?

Detailed Solution for Test: Ionization of Acids Bases and Water (July 30) - Question 10

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