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Test: The Concept of Potential Energy (June 28) - NEET MCQ


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10 Questions MCQ Test - Test: The Concept of Potential Energy (June 28)

Test: The Concept of Potential Energy (June 28) for NEET 2024 is part of NEET preparation. The Test: The Concept of Potential Energy (June 28) questions and answers have been prepared according to the NEET exam syllabus.The Test: The Concept of Potential Energy (June 28) MCQs are made for NEET 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: The Concept of Potential Energy (June 28) below.
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Test: The Concept of Potential Energy (June 28) - Question 1

The potential energy of a body at height h is mgh. Then its kinetic energy just before hitting the ground is

Detailed Solution for Test: The Concept of Potential Energy (June 28) - Question 1

From the law of conservation of mechanical energy, the potential energy of a body at height h is converted into kinetic energy when it falls down. So, the magnitude of kinetic energy just before hitting the ground is equal to the potential energy at height h which is mgh.

Test: The Concept of Potential Energy (June 28) - Question 2

Which of the following force is non-conservative

Detailed Solution for Test: The Concept of Potential Energy (June 28) - Question 2

Force between two stationary mass is gravitational force which is conservative. between two charge is electrostatic. muscular force is non conservative because we did work it lost or appear in form of heat and we need to eat food to gain energy for work done.

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Test: The Concept of Potential Energy (June 28) - Question 3

You are in a lift moving from the 3rd floor to the 12th floor, through a height H. If the elevator moves at a constant speed without stopping, what is the work performed on you by the elevator? Take your body mass as M.

Detailed Solution for Test: The Concept of Potential Energy (June 28) - Question 3

According to Newton's third law of motion, the force exerted on the floor by the person is equal and opposite the force exerted on the person by the floor.
According to the second law of Newton's law of motion, the net force exerted on the person is equal to the person’s mass times the person’s acceleration.
The net force exerted on the person = Force exerted by the floor+ Force exerted by gravity.
If the elevator goes up with acceleration g, the same is the person inside the elevator.
The work done on the man by the floor is the sum of the change in potential energy and kinetic
energy.
i.e W = Δ P.E + Δ K.E
But the elevator moves at a constant speed, so K.E =0.
W = Δ P.E
The work performed on you by the elevator is force times displacement = -Mgh
Negative sign shows it is moving upwards, i.e., against g.
 

Test: The Concept of Potential Energy (June 28) - Question 4

What is the dimension of k/m where k is the force constant and m is the mass of the oscillating object?

Detailed Solution for Test: The Concept of Potential Energy (June 28) - Question 4

F=k x (compression in string).
X=L.
a=LT-2.
F=ma.
ma= k L.
LT-2/L=k/m.
T-2=k/m.

Test: The Concept of Potential Energy (June 28) - Question 5

A hawk of mass 10 kg dives to catch a mouse. During dive it loses 500 J of its potential energy. The height from where it begins its dive is (take g = 10 m/s2)

Detailed Solution for Test: The Concept of Potential Energy (June 28) - Question 5

Change in GPE (Gravitational Potential energy) = mass x gravity x change in height
500 = 10 x 10 x change in height 

500 / 100 = change in height 

So, height from where it begins its dive = 5 m

Test: The Concept of Potential Energy (June 28) - Question 6

A vehicle of 50 quintal climbs up a hill of 10 m. The potential energy gained by it is (take g = 10 m/s2)

Detailed Solution for Test: The Concept of Potential Energy (June 28) - Question 6

mass = 50 x 100 = 5000 kg, g = 10 m/s2,  h = 10 m
Potential energy gained = mgh = 5000 x 10 x 10 = 5 x 105 J

Test: The Concept of Potential Energy (June 28) - Question 7

You are in a lift moving from the 3rd floor to the 12th floor, having a height difference of H = 40 m. Your mass is M = 80 kg and the acceleration due to gravity is g = 10 m/s2. If the elevator moves at a constant speed without stopping, what is the total work performed by all of the forces together (the net force) acting on you?

Detailed Solution for Test: The Concept of Potential Energy (June 28) - Question 7

As the final velocity after the action of all forces is 0, therefore the person has 0 net acceleration.

And, as we know that

Fnet = m.anet

Therefore, the net force is 0 and hence, the net work done is also 0.

Test: The Concept of Potential Energy (June 28) - Question 8

An elastic spring of force constant k is compressed by an amount x. Then its potential energy will be

Detailed Solution for Test: The Concept of Potential Energy (June 28) - Question 8

Test: The Concept of Potential Energy (June 28) - Question 9

Which of the following is not a kind of potential energy?

Detailed Solution for Test: The Concept of Potential Energy (June 28) - Question 9

Potential Energy is any type of stored energy. It can be chemical, nuclear, gravitational, or mechanical. Kinetic Energy is found in movement. Nuclear power plants change the nuclear potential energy of uranium or plutonium into electricity too.

Test: The Concept of Potential Energy (June 28) - Question 10

For a varying force work done can be expressed as a

Detailed Solution for Test: The Concept of Potential Energy (June 28) - Question 10

For a variable force, the work done can be expressed as a definite integral of force over displacement for any system.In case of a variable force, the is calculated with the help of integration. For example, in the case of a spring, the force acting upon any object attached to a horizontal spring can be given as Fs = -kx, where k is the spring constant and x is the displacement of the object attached. We can see that this force is proportional to the displacement of the object from the equilibrium position, hence the force acting at each instant during the compression and extension of the spring will be different. Thus, the infinitesimally small contributions of work done during each instant are to be counted in order to calculate the total work done.

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