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Test: Archimedes Principle (Old Syllabus) - Class 9 MCQ


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15 Questions MCQ Test - Test: Archimedes Principle (Old Syllabus)

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Test: Archimedes Principle (Old Syllabus) - Question 1

An object weighing 5 N in air, weighs 4.5 N a liquid. The buoyant force experienced by the object is 

Detailed Solution for Test: Archimedes Principle (Old Syllabus) - Question 1

The buoyant force experienced by the object is:- The buoyant force is in opposite direction to the weight of the object. Hence, if the object weighs 4.5 N in liquid then 0.5 N buoyant force will act on the object.

Test: Archimedes Principle (Old Syllabus) - Question 2

The same body is immersed in two liquids A and B in succession. The extent to which the body sinks in liquid B is less then in liquid A. What are the conclusions that could be derived from such an observation

Detailed Solution for Test: Archimedes Principle (Old Syllabus) - Question 2

The density of liquid B is more than the liquid A as more upthrust is exerted on the body in liquid B and hence it sinks less.

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Test: Archimedes Principle (Old Syllabus) - Question 3

A sample of milk diluted with water has density 1036kgm−3. if pure milk has a density 1080kgm−3 what is the percentage of water by volume in milk ?

Detailed Solution for Test: Archimedes Principle (Old Syllabus) - Question 3

Test: Archimedes Principle (Old Syllabus) - Question 4

A student lowers a body in a liquid filled in a container. He finds that there is a maximum apparent loss in weight of the body when

Detailed Solution for Test: Archimedes Principle (Old Syllabus) - Question 4
Explanation:

  • When the body is completely immersed in the liquid: This is when the maximum apparent loss in weight of the body will be observed. When the body is completely immersed in the liquid, the weight of the displaced liquid is equal to the weight of the body. This results in the maximum apparent loss in weight.

  • When the body just touches the surface of the liquid: At this point, the apparent loss in weight will not be at its maximum as the body has not displaced enough liquid to equal its weight.

  • When the body is partially immersed and also touches the sides of the container: This scenario will not result in the maximum apparent loss in weight as the body is not completely submerged in the liquid.

  • When the body is partially immersed in the liquid: Similar to when the body touches the sides of the container, this scenario will not result in the maximum apparent loss in weight as the body is not completely submerged in the liquid.

Test: Archimedes Principle (Old Syllabus) - Question 5

The density of copper is 9 g/cm3. Then the volume of 90 g copper is​

Detailed Solution for Test: Archimedes Principle (Old Syllabus) - Question 5

Density of copper = 9 gm/cm^3
Mass of copper  =  90 g
We know;  Density =  mass / volume
⇒ volume  = mass / density
⇒    90 / 9
⇒ Volume  = 10 cm3

Test: Archimedes Principle (Old Syllabus) - Question 6

The sea water is denser than fresh water due to

Detailed Solution for Test: Archimedes Principle (Old Syllabus) - Question 6

Density is defined as the mass per unit volume. In seawater, the salts are dissolved in water resulting in an increase in their mass per unit volume. Hence, seawater is denser than freshwater because of the dissolved salts in seawater, its density increases.

Test: Archimedes Principle (Old Syllabus) - Question 7

Instrument used for measuring the density or relative density of liquids is known as

Detailed Solution for Test: Archimedes Principle (Old Syllabus) - Question 7
Hydrometer

  • Definition: A hydrometer is an instrument used to measure the density or relative density of liquids.


  • Working Principle: Hydrometers work on the principle of buoyancy. The density of a liquid affects the buoyancy force acting on the hydrometer, causing it to float at different levels in liquids of different densities.


  • Construction: A typical hydrometer consists of a weighted glass tube with a scale inside. The scale is calibrated to read the density or specific gravity of the liquid being measured.


  • Usage: Hydrometers are commonly used in various industries such as the food and beverage industry, chemical industry, and pharmaceutical industry to measure the density of liquids accurately.


  • Types: There are different types of hydrometers available for specific applications, such as alcohol hydrometers for measuring alcohol content in beverages or battery hydrometers for measuring the specific gravity of battery acid.

Test: Archimedes Principle (Old Syllabus) - Question 8

A packet of 400 g and volume 200 cm3 is put in a water tank. The relative density of packet is

Detailed Solution for Test: Archimedes Principle (Old Syllabus) - Question 8
Explanation:

  • Volume of packet: 200 cm3

  • Mass of packet: 400 g

  • Density formula: Density = Mass/Volume

  • Substitute values: Density = 400g / 200cm3 = 2 g/cm3

  • Relative density formula: Relative density = Density of substance / Density of water

  • Considering density of water: 1 g/cm3

  • Substitute values: Relative density = 2 g/cm3 / 1 g/cm3 = 2

Test: Archimedes Principle (Old Syllabus) - Question 9

An object of weight 500 N is floating in a liquid. The magnitude of buoyant force acting on it is

Detailed Solution for Test: Archimedes Principle (Old Syllabus) - Question 9
As we know that the buoyant force acting on a floating body in a liquid is equal to the weight of the floating body,
Buoyant force acting on the body of weight 200N floating in  liquid = 200N
Test: Archimedes Principle (Old Syllabus) - Question 10

If relative density is 11.3, the density of the substance in SI units is

Detailed Solution for Test: Archimedes Principle (Old Syllabus) - Question 10
Relative Density Calculation

  • Relative density is the ratio of the density of a substance to the density of a reference substance.

  • Relative density is a dimensionless quantity.

  • Given relative density = 11.3


Density Calculation

  • The density of a substance is calculated by multiplying the relative density by the density of the reference substance.

  • The density of water at 4 degrees Celsius is 1000 kg/m^3.

  • So, density of the substance = Relative density x Density of water = 11.3 x 1000 kg/m^3 = 11300 kg/m^3


Final Answer

  • The density of the substance in SI units is 11.3 x 10^3 kg/m^3

Test: Archimedes Principle (Old Syllabus) - Question 11

If the density of the object placed in a liquid is equal to the density of the liquid, the object will:

Detailed Solution for Test: Archimedes Principle (Old Syllabus) - Question 11

If the density of the object placed in liquid is equal to the density of the liquid, then :- It would float submerged in the liquid. Some part of the solid would be above the liquid surface and part would be inside the liquid surface.

Test: Archimedes Principle (Old Syllabus) - Question 12

The mass of water displaced by a solid of mass 400 g and volume 150 cm3 is​

Detailed Solution for Test: Archimedes Principle (Old Syllabus) - Question 12
Test: Archimedes Principle (Old Syllabus) - Question 13

Three objects A, B, and C having density 1.12 g cm-3, 0.92 g cm-3 and 2.02 g cm-3 respectively, are placed in a water tank. Which object will sink in water tank?​

Detailed Solution for Test: Archimedes Principle (Old Syllabus) - Question 13
Explanation:

  • Density of Object A: 1.12 g cm-3

  • Density of Object B: 0.92 g cm-3

  • Density of Object C: 2.02 g cm-3


Reasoning:

  • When an object is placed in water, it will float if its density is less than the density of water (1 g/cm3).

  • Object A has a density of 1.12 g/cm3, which is greater than the density of water.

  • Object B has a density of 0.92 g/cm3, which is less than the density of water.

  • Object C has a density of 2.02 g/cm3, which is greater than the density of water.

  • Therefore, Object A and Object C will sink in the water tank, while Object B will float.


Conclusion:

  • Object A and Object C will sink in the water tank.

  • Object B will float in the water tank.

  • Hence, the correct answer is A and C.

Test: Archimedes Principle (Old Syllabus) - Question 14

When a solid body is fully immersed in a liquid, the volume of the displaced liquid is:

Detailed Solution for Test: Archimedes Principle (Old Syllabus) - Question 14
According to Archimedes’ principle, the volume of liquid displaced is equal to the volume of the solid.
Test: Archimedes Principle (Old Syllabus) - Question 15

If we want to determine the volume of a solid by immersing it in water, the solid should be

Detailed Solution for Test: Archimedes Principle (Old Syllabus) - Question 15
It should be heavier than water and insoluble in it, so that it sinks and displaces the water and also it does not mix in the water.

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