MAHATRANSCO AE Electrical Mock Test - 5 - Electrical Engineering (EE) MCQ

By Leibnitz rule :

f'(x) = [e^x(x - 1)(x - 2)] - 0 < 0 

= (x - 1)(x - 2) < 0

= x > 1 and x < 2

= x ∈ (1, 2)

The above expression is for XOR gate 

Case (a) repeated roots (α,α,β)

Note that the graph of f(x) cannot be like the one given below

3real rootsnot possible

• IQ = (MA*100)/CA
• and 80 ≤ IQ ≤ 140
• 80 ≤ (MA*100)/CA ≤ 140
• 80 ≤ (MA*100)/12 ≤ 140
• 960 ≤ (MA*100) ≤ 1680
• 9.6 ≤ MA ≤ 16.8

X is towards the east wrt to P

(2)² + (4)² = 20

and (3)² + (9)² = 90

Therefore (1)² + (5)² = 26.

(7 x 3) = 21 and (9 x 3) = 27

and (4 x 9) = 36 and (2 x 9) = 18

Therefore (9 x 6) = 54 and (4 x 6) = 24.

(16 + 13) = (14 + 15)

and (28 + 12) = (10 + 30)

Therefore (29 + 16) = (15 + 30).

(15 - 12) + (10 - 9) = 4

(28 - 12) + (16 - 20) = 12

Similarly, (23 -11) + (15- 16) = 11.

He returned after 8 o'clock but before 9 o'clock, at such a time when both the minute hand and the hour hand were found to be coinciding.
In a simple way, we need to calculate the time when the angle between the minute hand and the hour hand is zero.
Angle between the minute hand and the hour hand at 8 o'clock = 8 × 30 = 240°
We can reduce the difference of 5.5 degree in 1 min,
Required time = 8 hrs + 240 × 2 ÷ 11

According to given information:

Statements: M ≤ N = O ; M ≤ P ; O < Q

Combining the statement: P > M ≤ N = O < Q

Here, P is greater than or equal to M which is less than or equal to N equal to O which is less than Q.

Conclusions:

I.  Q > N → True (In the given statement, P > M ≤ N = O < Q ,It clearly mentioned Q is greater than O which is equal to N .So, Q is greater than N too. Thus, the conclusion I is true).

II. M ≥ O → False (In the given statement, M ≤ N = O, It is clearly mentioned that M is less than or equal to N which is equal to O. So, M can never be greater than O. Thus, conclusion II is a false).

Hence, "Option b" is the correct answer.

The given statement is: J = K ≥ L > X ≥ Y ;  J ≥ P ; P ≥ Z 

Combining the statement: Z < P < J = K ≥ L > X ≥ Y 

Here, Z is smaller than or equal to P which is Smaller than or equal to J which is equal to K which is greater than or equal to L which is greater than X and X is greater than or equal to Y.

Conclusions:

I: J < L → False (as J = K ≥ L gives as J = K and K ≥ L which implies that J ≥ L and J cannot be less than L . Thus, Conclusion I is false.).

II:  P ≤ Y → False (as Z < P < J = K ≥ L > X ≥ Y  → clear relationship between P and Y cannot be determined. Thus, Conclusion II is false.)

Hence, the "Option c" is the correct answer.

Given: A > B, B > C and C > D

After combining the operators,

we get: A > B > C > D

Now, checking the options:

Option A: A > D → True (As, A > B > C > D gives A > D)

Option B: A > C → True (As, A > B > C > D gives A > C)

Option C: D > A → False (As, A > B > C > D gives A > D)

Option D: B > D → True (As, A > B > C > D gives B > D)

So, Option C, D > A is definitely wrong.

Hence, the correct answer is "Option c".

As the result of Race is Fatigue similarly the result of Fast is Hunger.

As opposite meaning of peace is chaos similarly opposite meaning of creation is destruction.

As magnet has poles similarly battery has terminals.

The man in the photograph is the daughter of the only son of Lata's grandfather i.e., the girl is the daughter of Lata's father. Hence, the girl is the sister of Lata.

Given: D is the brother of B.

From statement 1, we can detect that D is son of C (son of D is the grandson of C).

From statement 2, we can detect that B is 'Female' (sister of D).

Therefore, B is daughter of C.

M x N → M is the mother of N

N % S → N is the wife of S

and S + T → is the father of T.

Hence, M is the maternal grandmother of T.

A number is repeated. Then it is reduced by 13 and the result is repeated.

► The next number is 27-13=14.

Ratio of amounts with Sam : Michael : Puma = 100 : 60 : 40 = 5 : 3 : 2
Let us assume that amounts spent are 5x, 3x and 2x, respectively.
A = 5x - 3x = 2x
B = 3x - 2x = x
Hence, A : B = 2 : 1 (Total expense is the redundant data in the question)

Let the price of a saree and a shirt be Rs. x and Rs. y respectively.

Then, 2x + 4y = 1600 .... (i)

    and x + 6y = 1600 .... (ii)

Divide equation (i) by 2, we get the below equation. => x + 2y = 800. --- (iii)

Therefore, y = 200. Now apply value of y in (iii) => x + 2 x 200 = 800 => x + 400 = 800 Therefore x = 400

Solving (i) and (ii) we get x = 400, y = 200.

∴ Cost of 12 shirts = Rs. (12 x 200) = Rs. 2400.

X+(1/X) = 2 ;

(X^2+ 1)/ X = 2 ;

X^2+1 = 2X ;

X^2 - 2X + 1= 0 ;

By factorisation method ,

X = 1 ;

Now substitute X= 1 in X +(-1/X) ;

we get , 1 - 1/1 = 0 ;

Therefore , X = 0 ;

D. 78%
Explanation: Consider Total no of students = 100 Ratio is 3:2 i.e Boys=60 and Girls=40 20% of boys who get scholarship = 60*20/100=12% 25% of girls who get scholarship = 40*25/100 =10% Therefore % of students who do not get scholarship =100-(12+10) = 78%

Let
P's capital = p,
Q's capital = q and
R's capital = r.
Then

मन्वंतर या शब्दाची संधी मनु + अंतर ही होईल.

मन्वंतर या शब्दाची संधी उ किंवा ऊ पुढे विजातीय स्वर आल्यास उ किंवा ऊ बद्दल व याप्रमाणे होईल.

मन्वंतर हे यणादेश स्वरसंधीचे उदाहरण आहे.

मन्वंतर = मनु + अंतर = उ + अ = व् + अ = व

यणादेश स्वरसंधी - इ, उ, ऋ (ह्रस्व किंवा दीर्घ) यांच्या पुढे विजातीय स्वर आल्यास इ/ई बद्दल य्, उ/ऊ बद्दल व् तर ऋ बद्दल र् वर्ण येतात आणि त्यात पुढील स्वर मिसळून संधी तयार होते. अशाप्रकारे य्, व्, र् असे बदल होतात त्याला यणादेश असे म्हणतात.

Important Points

संधी - जोडशब्द तयार करताना पहिल्या शब्दातील शेवटचा वर्ण व दुसऱ्या शब्दातील पहिला वर्ण हे एकमेकांमध्ये मिसळतात व त्या दोन्हीबद्दल एक वर्ण तयार होतो. वर्णाच्या अशा एकत्र होण्याच्या प्रकाराला संधी असे म्हणतात.

संधीचे तीन प्रकार आहेत.

1. स्वरसंधी
2. व्यंजनसंधी
3. विसर्गसंधी

स्वरसंधी - एकमेकांच्या शेजारी येणारे वर्ण हे जर स्वरांनी जोडले असतील तर त्यांना स्वरसंधी असे म्हणतात.

स्वर + स्वर असे याचे स्वरूप असते.​ उदा. विद्या + अर्थी = विद्यार्थी  (आ + अ = आ)

व्यंजनसंधी - जवळ जवळ येणाऱ्या या दोन वर्णांपैकी दोन्ही वर्ण व्यंजने असतील किंवा पहिला वर्ण व्यंजन व दुसरा वर्ण स्वर असेल तर त्याला व्यंजनसंधी असे म्हणतात.

व्यंजन + व्यंजन किंवा स्वर असे त्याचे स्वरूप असते. उदा. सत् + आचार = सदाचार (त् + आ)

विसर्गसंधी - एकत्र येणाऱ्या वर्णातील पहिला विसर्ग व दुसरा वर्ण व्यंजन किंवा स्वर असेल तर तेव्हा त्यास विसर्ग संधी असे म्हणतात. 

विसर्ग + व्यंजन किंवा विसर्ग + स्वर असे त्याचे स्वरूप असते. उदा. नि: + अंतर = निरंतर